The diagram shows a simple circuit. Which change would cause the light-bulb to get brighter?
A) Increase the length of the wire between the switch and the battery.
B) Decrease the length of the wire between the switch and the battery.
C) Reverse the direction of the battery.
D) Swap the positions of the lightbulb and the switch.

From the information provided and the calculations, the energy of the drop is 1.51 eV

The Rydberg formula is used to obtain the energy of a photon or the wavelength of a photon.

Thus;

1/λ = 1.097 * 10^7 (1/3^2 - 1/5^2)

1/λ = 1.097 * 10^7(0.11 - 0.04)

λ = 1.3 * 10^-6 m

Since;

E = hc/λ

E = 6.6 * 10^-34 * 3 * 10^8/1.3 * 10^-6

E = 1.51 * 10^-19 J or 1.51 eV

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Answer:

0.97eV

Explanation:

The energy emitted during n=5 is 0.54 eV

The energy emitted during n=3 is 1.51 eV
(This information is on the Physics Reference Table 2006 edition)

We find the change in the energy level which is:  

1.51eV-0.54eV = 0.97eV

Therefore the energy emitted by the photon is 0.97eV.

The change that would enable to drop of the staples in the scrap metal bin after picking up several staples with the device is removing the battery.

A battery is a device that helps us to store electricity to be used accordingly when it is required for a machine.

Moreover, a device may be defined as any tool developed to perform a specific type of work.

In conclusion, the change that would enable to drop of the staples in the scrap metal bin after picking up several staples with the device is removing the battery.

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Answer:

0.1 mm

Explanation:

60 sheets = 6 mm

We want 1 sheet so we divide both sides by 60 :

1 sheet = 6/60 mm

1 sheet = 1/10 mm

1 sheet is 0.1 mm

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The net force on the -4.0μC object as a result of this net field will be -10.4 N.

The matter has an electric charge when it is exposed to an electromagnetic field is known as a charge.

The electric field intensity is found as the force per unit charge.

Electric field intensity on the positive charge:

[tex]\rm E_1 = \frac{F_1}{Q} \\\\\ \rm 1.2 N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_1 = - 4.8 \ N[/tex]

Electric field intensity on the negative charge:

[tex]\rm E_2 = \frac{F_2}{Q} \\\\\ \rm 1.4 \ N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_2 = - 5.6 \ N[/tex]

The net charge is the algebraic sum of the two charges;

[tex]\rm F_{net}=F_1+F_2 \\\\ F_{net}= -4.8 -5.6 \\\\ F_{net}=-10.4 \ N[/tex]

Hence, as a result of this net field, the net force on the -4.0C object will be -10.4 N.

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Answer:

The law of conservation of mass states that the total energy of an isolated system remains constant over time.

Explanation: Hope it helps you :))))

Have a good day

Answer:

16

Explanation:

Answer:

75kg dining table

Explanation:

its the heaviest

more force would be required to push it

so it has greater inertia

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Answer:

C.

Explanation:

EDGE 2023

Answer:

200

Explanatio

sample ananswer

The person that produces more power is Person A because its power is 50watts.

For person A = Power= ,work done/ time

But work done = force × distance

person A = 100×3/6

= 300/6

= 50watts

For person B = 100×5/20

= 500/20

= 25watts

Therefore, the person that produces more power is Person A because its power is 50watts.

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Recall the formula of refractive index

[tex]\sf \mu =\dfrac{sini}{sinr}[/tex]

As per the diagram

At AD angle of incidence i is

[tex]\\ \rm\Rrightarrow \gamma=sin^{-1}\left(\dfrac{1}{\dfrac{n_1}{n_2}}\right)[/tex]

[tex]\\ \rm\Rrightarrow \gamma=sin^{-1}\left(\dfrac{n_2}{n_1}\right)[/tex]

At AB's imaginary boundary line

Use snell's law

[tex]\\ \rm\Rrightarrow \dfrac{\mu_1}{\mu_2}=\dfrac{sin\alpha}{sin\beta}[/tex]

[tex]\\ \rm\Rrightarrow \mu_1sin\alpha=\mu_2sin\beta[/tex]

[tex]\\ \rm\Rrightarrow n_2sin\alpha=n_1sin\left(\dfrac{\pi}{2}-\gamma\right)[/tex]

[tex]\\ \rm\Rrightarrow n_2sin\alpha=n_1cos\left(sin^{-1}\left(\dfrac{n_2}{n_1}\right)\right)[/tex]

[tex]\\ \rm\Rrightarrow sin\alpha=\dfrac{n_1}{n_2}cos\left(sin^{-1}\dfrac{n_2}{n_1}\right)[/tex]

[tex]\\ \rm\Rrightarrow \underline{\boxed{\bf{\alpha=sin^{-1}\left[\dfrac{n_1}{n_2}cos\left(sin^{-1}\dfrac{n_2}{n_1}\right)\right]}}}[/tex]

Option A

The density of the metal sphere is 2 times the density of the liquid as proved.

The net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;

F =  σVg - ρVg

ma =  σVg - ρVg  

where;

σV(a) =  σVg  - ρVg

σ(a) = σg  - ρg

σ(g/2) = σg -  ρg  

g(σ/2) = g(σ -  ρ)

σ/2 = σ -  ρ

σ/2 - σ = -  ρ

-σ/2 = -  ρ

σ = 2ρ

Thus, the density of the metal sphere is 2 times the density of the liquid as proved.

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Explanation:

P.E. = mgh

PE = 40 × 10 × 10

PE = 4000 Joule

The mass of the box is 8.5 kg.

Mass can be defined as the quantity of matter contained in a body.

To calculate the mass of the box, we use the formula

Formula:

Where:

Make m the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the mass of the box is 8.5 kg.

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A truck is moving with less velocity in the direction in which the truck is moving earlier because the truck has more momentum.

A truck is moving with the velocity of 10 m/s in the same direction in which the truck is moving earlier because the truck has more mass so it has more momentum. Due to collision, the velocity of the truck is slow down but can't be stopped because of high momentum in the truck.

So we can conclude that a truck is moving with less velocity in the direction in which the truck is moving earlier because the truck has more momentum.

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The acceleration will be 1.9166 m/s². According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The rate of change of velocity with respect to time is known as acceleration.

Given data:

u(Initial velocity)=2.50m/s

v(Final velocity)=8.25m/s

t(time period)= 3.00s

The acceleration of the Allura will be :

[tex]\rm a = \frac{v-u}{t} \\\\ a= \frac{8.25-2.50 }{3.00 }\\\\ a= 1.9166 \ m/s^2[/tex]

Hence, the acceleration will be 1.9166 m/s².

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The  mass of the large truck is determined as 5680 kg.

The mass of the truck is calculated as follows;

P = mv

where;

m = P/v

m = 125000/22

m = 5680 kg

Thus, the  mass of the large truck is determined as 5680 kg.

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Answer:

C. 5680

Explanation:

edg2023

Within the visible spectrum, our experience of red is associated with a longer wavelength of light.

The electromagnetic spectrum is seen as colors: violet, indigo, blue, green, yellow, orange, and red.  Blue light has a very short wavelength, and so produces a higher amount of energy.

In the visible spectrum, the longer wavelengths that we perceive as red are followed by intermediate wavelengths for green and shorter wavelengths for blue and violet.

Our perception of red is connected to a longer wavelength of light within the visible spectrum.

Hence longer wavelength is the correct answer for blanks.

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The earth tilt about 23 degrees which leads to the formation of seasons on earth.

This is tilted at 23 degrees from the vertical. The northern hemisphere is in the winter season.

This is the path as the earth revolves around the sun. It takes 1 year to complete this path.

This is the path as the earth rotates around its.

So we can conclude that the earth tilt about 23 degrees which leads to the formation of seasons on earth.

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The magnitude of the sum of the frictional forces acting on the bike and its rider is 400N.

The friction force is the opposing force which acts on the object which is in relative motion.

The driving force is equal and opposite to the friction force acting between road and bicycle.

Friction force = 400N

The friction force between rider and bike is zero.

So the magnitude of sum of friction force = 400N +0 = 400N

Thus, the magnitude of the sum of the frictional forces acting on the bike and its rider.

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Answer:

108680.6 days

Explanation:

1 day = 24 hours there is 3600 seconds in 1 hour

so 24 * 3600 = 86400 so there is 86400 second in a day

so the take t = time s = seconds

t = 9.39 * 10^9s * 86400

t = 108680.6 days

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The net force needed to lift a full grocery sack uniformly is 32.115 N.

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

Given the weight of sack W = 210N and the acceleration a = 1.5m/s².

The mass of the sack will be

m = Weight / acceleration due to gravity

m = 210 N/9.81 m/s²

m = 21.41 kg

Using Newton's second law, the net force will be

F = mass x acceleration

F= 21.41 x 1.5

F = 32.115 N

Thus, the net force is 32.115 N.

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If the man DECREASES the force of his push on the cart, the cart slows down.

The force applied to an object is determined by applying Newton's second law of motion.

F = ma

where;

a = Δv/t

F = (mΔv)/t

mΔv = Ft

Δv = Ft/m

From the equation above, when the applied force decreases, the change in velocity decreases.

Thus, if the man DECREASES the force of his push on the cart, the cart slows down.

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Answer:

pound of bricks

meh wrong ? XD

Answer:

neither is heavier.both are equal

Explanation:

since 1 pound equals 16 oz.(1 pound=16 oz.).,both are equal too!

Answer:

xhxzguztyayrayhNzxlhhlिगजि

Maria throws two stones from the top edge of a building at a speed of 20 m/s, The time is mathematically given as

t=4.5 sec.

Generally, the equation for speed  is mathematically given as

V = u+at

Therefore

0 = 22-9.8xt.

t = 22 /9.8 sec

t = 2.24489.

The same time will be taken from max^m height to point O

The extra time is taken

t=4.49 sec.

t=4.5 sec.

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The work done by the applied force on the block against the frictional force is 15.75 J.

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is a 4 kg block is pushed 2m at an acceleration of 0.2 meter per second square up a vertical wall by constant force f applied at an angle of 37 degree with the horizontal if the coefficient of kinetic friction, μ between the block and the wall is 0.30.

From the equilibrium of forces acting on the block, we have

F - f = ma

where, F is applied force, f is frictional force, m is the mass and a is the acceleration.

Frictional force f =  μmgsinθ

Substitute the values, we get

Fcos(37) - μmgsin(37) = ma

Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)

0.799F - 7.077 = 0.8

F = 9.86 N

Work done by the applied force is

W = Fdcosθ

W = 9.86 x 2 x cos(37)

W = 15.75 J

Thus, the work done by the applied force on the block against the frictional force is 15.75 J.

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Answer:

about 1.5 bars

Titan's atmosphere is similar to Earth's both in the predominance of nitrogen gas and in surface pressure, which is about 1.5 bars, or 50 percent higher than sea-level pressure on Earth.

Explanation:

Julia walks from the park, which is six blocks east of her house, to the store, which is three blocks east of her house. Julia walks for 5 minutes. This walk's average speed will be 1.2 blocks per minute. Option B is correct.

Displacement is defined as the shortest distance between the two points. Distance is the horizontal length covered by the body. While displacement is the shortest distance between the two points.

Displacement is a vector quantity .its unit is m.

The average velocity on this walk will be;

[tex]\rm v_{avg}= \frac{d}{t} \\\\ \rm v_{avg}= \frac{6 \ block+ 3 \ block }{5 \ minute } \\\\ v_{avg}=1.4 \ block /min[/tex]

Hence option B is correct.

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