Answer:
SI unit of density is kg/m^3
Using unit conversion:
density = 19.3 * 1000 kg/m^3
Explanation:
I assume that you are asking for the density conversion to SI, sorry if this isn't what you were asking.
i) Give two practical
application of static friction
1). Walking / Driving
If there were no static friction between the soles of your shoes and the ground, then you could move your feet back and forth but your body would never go anywhere.
Same for using tires to move a car, a bus, a bicycle or a motorcycle.
2). Sleeping
If there were no static friction between your jammies and the sheet, you would slide right off of the bed whenever there was the slightest breeze of air in the room.
What is the potential energy of a puppy that weighs 18 N istting in a high chair 2 m high?
Answer:
Potential energy =mass* acceleration due to gravity * height
mass*acceleration due to gravity =weight
hence potential energy of the puppy= weight * height
=18*2
=36 joule
Which Energy transformation will occur when this rubber band is let go elastic energy -chemical energy mechanical energy -electrical energy chemical energy -mechanical energy elastic energy mechanical- energy elastict
Elastic Energy - Mechanical Energy
In Einstein’s theory of gravitation, gravity is due to:
A)the acceleration of the universe
B)the presence of mass
C)the rotation of the universe
D)the curvature of spacetime
E)the speed of light
Answer:
B, caused by the presence of mass
Explanation:
The ___ of a wave is the reciprocal of its frequency.
Answer:
time period of the wave
Answer:
The Frequency of a wave is the reciprocal of its Period
The Period of a wave is the reciprocal of its frequency
Explanation:
A P E X
What makes the atmosphere an important part of Earth’s system?
Answer:
water exchange carbon dioxide is taken away and oxygen is made
what happens at a transform boundary
Answer:
Answer is "two tectonic plates slide past eachother" ( for a pe x)
Explanation:
A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process?
A.
velocity and wavelength
OB.
velocity and frequency
Ο Ο Ο Ο
OC.
frequency and wavelength
OD.
frequency and phase
E.
wavelength and phase
Answer:
Velocity and frequency
Explanation:
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.70 m. The ball is going 7.33 m/s.
If the speed is tripled, what happens to its centripetal force?
a)The new centripetal force is 1/3 what it was
b)The new centripetal force is 9 times more
c)The new centripetal force is 1/9 what it was
d)The new centripetal force is 3 times more
Answer:
b)The new centripetal force is 9 times more
Explanation:
The formula to apply in this case is that of tension force on a spring which is equal to the centripetal force.
T= mv²/r --------i
where T is the tension on the spring
v= velocity/speed of the ball = 7.33 m/s
m= mass of the ball , 0.015 kg
r= radius of circle , 0.70 m
Use the values in the formula as;
T= {0.015 * 7.33² } / 0.70
T= 0.8059335 / 0.70
T= 1.15 N ---------i
If the speed is tripled then;
v= 21.99 m/s
T= 0.015 * 21.99² / 0.70
T= 10.36 N ------ii
Check the changes by dividing i and ii as ;
10.36 / 1.15 = 9.01
This is 9 times more hence if the speed is tripled ,the new centripetal force is 9 times more.
A barge is pulled by two tugboats. If the resultant of the forces exerted by the
tugboats is 5kN force directed along the axis of the barge, determine the tension in
each of the ropes for α = 45
Answer:
Approximately [tex]3.5\; \rm kN[/tex] in each of the two ropes.
Explanation:
Let [tex]F_1[/tex] and [tex]F_2[/tex] denote the tension in each of the two ropes.
Refer to the diagram attached. The tension force in each rope may be decomposed in two directions that are normal to one another.
The first direction is parallel to resultant force on the barge.
The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \cos(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \cos(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].These two components would be in the same direction. The resultant force in that direction would be the sum of these two components: [tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}}[/tex]. That force should be equal to [tex]5\; \rm kN[/tex].
The second direction is perpendicular to the resultant force on the barge.
The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \sin(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \sin(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].These two components would be in opposite directions. The resultant force in that direction would be the difference of these two components: [tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}}[/tex]. However, the net force on the barge is normal to this direction. Therefore, the resultant force should be equal to zero.
That gives a system of two equations and two unknowns:
[tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}} = 5\; \rm kN[/tex], and[tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}} = 0[/tex].The second equation suggests that [tex]F_1 = F_2[/tex]. Hence, replace the [tex]F_2[/tex] in the first equation with [tex]F_1[/tex] and solve for [tex]F_1\![/tex]:
[tex]F_1 = \displaystyle \frac{5\; \rm kN}{2\, \sqrt{2}} \approx 3.5\; \rm kN[/tex].
Because [tex]F_1 = F_2[/tex] (as seen in the second equation,) [tex]F_2 = F_1 \approx 3.5\; \rm kN[/tex].
In other words, the tension in each of the two ropes is approximately [tex]3.5\; \rm kN[/tex].
The tension in each of the rope is 3,535.5 N
The given expression:
the resultant force, R = 5 kN = 5000 N
the angle in between the forces, α = 45
To find:
the tension in each of the ropesThe tension in each of the ropes is calculated as follows;
The tension in vertical direction
[tex]F_y = F \times sin(\alpha)\\\\F_y = 5000 \times sin(45)\\\\F_y = 5000 \times 0.7071\\\\F_y = 3,535.5 \ N[/tex]
The tension in horizontal direction;
[tex]F_x = F \times cos(\alpha)\\\\F_x = 5000 \times cos(45)\\\\F_x = 5000 \times 0.7071\\\\F_x = 3,535.5 \ N[/tex]
Thus, the tension in each of the rope is 3,535.5 N
Learn more here:https://brainly.com/question/11194858
A small truck has a mass of 2085 kg. How much work is required to decrease the speed of the vehicle from 22.0 m/s to 13.0 m/s on a level road?
Answer:
Work required is 328387.5 Joules.
Explanation:
Given the following data;
Mass = 2085kg
Initial velocity, Vi = 13m/s
Final velocity, Vf =22m/s
To find the workdone;
We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.
Mathematically, it is given by the equation;
W = Kf - Ki
Where;
W is the work required.
Kf is the final kinetic energy possessed by the object.
Ki is the initial kinetic energy possessed by the object.
But Kinetic energy = ½MV²
W = ½MVf² - ½MVi²
Substituting into the equation, we have;
W = ½(2085)*22² - ½(2085)*13²
Simplifying the equation, we have;
W = 1042.5 * 484 - 1042.5 * 169
W = 504570 - 176182.5
W = 328387.5J
Therefore, the work required to decrease the speed of the vehicle is 328387.5 Joules.
A 2 kg block slides with constant velocity along a horizontal tabletop. A horizontal applied force of 10 N and a downward applied force of 5 N act on the block, as shown. The coefficient of friction between the block and tabletop is most nearly...
Answer:
huh
Explanation:
Answer:
what are we finding?
Explanation:
Read each scenario below. Then select the answer choices that complete the sentences,
A car engine has
power than a house because a car engine does the same amount of work in
time,
Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height
and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,
Raj applied
power than Yaskrin because his stacking took turve to do the same amount of
Answer:
Higher
Lesser
Lesser
Longer
Explanation:
Search...
54
ryanzl6659
14 hours ago
Physics
College
Read each scenario below. Then select the answer choices that complete the sentences,
A car engine has HIGHER power than a house because a car engine does the same amount of work in LESSER time,
Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,
Raj applied LESSER power than Yaskrin because his stacking took LONGER to do the same amount of
Answer:
More
Less
Less
More
Explanation:
i got all correct
Harry is reading an online summary of the law of reflection. The site states that after light hits a mirror, the angle of reflection is the angle between the reflected ray and the normal, which is the surface of the mirror.
Which statement corrects an error on the site?
Answer:
A
Explanation:
“An object completely submerged in a fluid displaces its ovn volume of fluid". This is:
Answer:
Archimedes' principle
Explanation:
An object completely submerged in a fluid displaces its own volume of fluid is postulate from the Archimedes' principle.
If a fluid, the liquid supports the body by a buoyant force. The buoyant force is the reaction to the imposed weight exerted by the object placed in the medium. The upward force on the body is the upthrust.what is an emergent curriculum
Answer:
Emergent curriculum is an early education approach where teachers design projects unique to a child or group of kids.
an inclinded plane makes work easier by increasing the distance and blank the force
Hi! I believe your answer is decreasing. An inclined plane makes work easier by decreasing the amount of effort force needed, but increases the distance. I hope this helps you! Good luck and have a great day. ❤️✨
Let the force of the Moon on the Earth be F1. Let the force of the Earth pulling on the Moon be F2. Which of the following is greater?
given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone bridge is in equilibrium and then calculate voltages and currents as for reference exercise.
Answer:
The balanced condition for Wheat stones bridge is
Q
P
=
S
R
as is obvious from the given values.
No, current flows through galvanometer is zero.
Now, P and R are in series, so
Resistance,R
1
=P+R
=10+15=25Ω
Similarly, Q and S are in series, so
Resistance R
2
=R+S
=20+30=50Ω
Net resistance of the network as R
1
and R
2
are in parallel
i=
R
V
=
50
6×3
=0.36 A.
Explanation:
A crane lifts a 425 kg steel beam vertically upward a distance of 614.4 m
How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s2? Neglect frictional forces.
PHYSICS
*not sure about the answer but here we go*
Mass = 425 kg
distance = 614.4 m
acceleration = 1.8 m/s²
Answer :
Count Force first.
[tex]f \: = m \: \times a[/tex]
F = 425 × 1,8
F = 765 N ✅
Now let's count Work.
[tex]w \: = \: f \: \times s[/tex]
W = 765 × 614.4
W = 470016 J ✅
Elizabeth .........................................................................
Answer:
who's elizabeth? haha
Answer:
What about it?
Explanation:
George got a bad grade on the test because he decided he would rather sleep than study. this is an example of a __ attribution
the right answer for this question would be dispositional
Answer:
dispositional
Explanation:
which of the following statements about ocean waves a true?
A. they travel on the surface of the water
B. they travel deep underwater
C. they are secondary waves
D. they are primary waves
The assertion that ocean waves move on the water's surface is accurate. Therefore, choice A is right.
What is the ocean waves?A wind wave, water wave, or tornado water wave is a surface wave that develops on a body of water's free surface as a result of the air flowing over the ocean's surface. The fetch is the distance at which two objects come into touch when facing the wind.
The wind is the most frequent source of waves. The friction between the wind and the surface of the water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake.
The statements about ocean waves a true will be they travel on the surface of the water.
Thus, option A is correct.
More about the ocean waves link is given below.
https://brainly.com/question/101258
#SPJ6
А A pool of water of refractive index
4/3! is 60cm deep. Find its apparent
depth when viewed vertically through
air.
Answer:
Apparent depth = 45 cm
Explanation:
The refractive index of water in a pool, n = 4/3
Real depth, d = 60 cm
We need to find its apparent depth when viewed vertically through air. The ratio of real depth to the apparent depth is equal to the refractive index of the material. Let the apparent depth is d'. So,
[tex]n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{60}{\dfrac{4}{3}}\\\\d'=45\ cm[/tex]
So, the apparent depth is 45 cm.
help please! thank you! please dont plagiarism my teacher checks for plagiarism ;-;
Answer:
the reason why the crate won't move to the direction of the force being applied (F app). is because the (Fgravity) is pulling it down making it heavy to move
Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.
Answer:
K = ρL²g
Explanation:
Consider L as the length of the raft inside the water when the raft is displaced through additional distance y;
Then:
F = upthrust ( restoring force) = weight of the liquid displaced.
[tex]F = V_{\omega} \rho_{\omega} g= A y \rho_{\omega} g[/tex]
where;
A = L²
[tex]\rho_{\omega} = \rho[/tex]
F = ky.
Then,
[tex]Ay \rho g = ky[/tex]
[tex]L^2y \rho g = ky[/tex]
Divide both sides by y
K = ρL²g
When you use a
spray bottle, you force air over
a small tube inside the bottle.
Explain why the liquid inside
the bottle comes out.
Answer: Spray bottles are an extremely useful type of machine and an excellent demonstration of basic plumbing principles. A spray-bottle head is made up of only a few parts. It has a trigger lever, which activates a small pump. This pump is attached to a plastic tube that draws cleaning fluid from the bottom of the reservoir. The pump forces this liquid down a narrow barrel and out a small hole at the gun's muzzle. The hole, or nozzle, serves to focus the flowing liquid so that it forms a concentrated stream.
The only complex element in this design is the fluid pump, and it's about as simple as they come. The main moving element is a piston, housed inside a cylinder. Inside the cylinder, there is a small spring. To operate the pump, you pull the trigger back, pushing the piston into the cylinder. The moving piston compresses the spring, so when you release the trigger, the piston is pushed back out of the cylinder. These two strokes of the piston, into the cylinder and out again, constitute the entire pump cycle.
Explanation:
Awnser: The liquid comes out because you're using your hand to squeeze the handle, which forces it out.
List four safety measures one should take when there is a cyclone warning.
Answer:
I'm gonna give you more than 4 So u can choose.
Turn off all electricity, gas and water.
Unplug all electrical appliances.
Keep your emergency kit close at hand.
If the building starts to collapse, protect yourself with mattresses, rugs.
Stay tuned to the radio for updates.
Stay inside until told it is safe to go outside.
A value that describes how heavy an object is and is related to the force of gravity is:
The weight of an object
Answer: B) weight
Got it right on E2020
A 3.35 kg object initially moving in the positive x direction with a velocity of 4.90 m s collides with and sticks to a 1.88 kg object initially moving in the negative y direction with a velocity of 3.12 m/s. Find the final components of velocity of the composite object.
Answer:
The final components of velocity of the composite object is 3.33 m/s.
Explanation:
Given;
mass of the first object, m₁ = 3.35 kg
initial velocity of the first object, u₁ = 4.90 m/s in positive x-direction
mass of the second object, m₂ = 1.88 kg
initial velocity of the second object, u₂ = 3.12 m/s in negative y-direction
initial momentum of the first object, P₁ = 3.35 x 4.9 = 16.415 kgm/s
initial momentum of the second object, P₂ = 1.88 x 3.12 = 5.8656 kgm/s
The resultant velocity of the two objects is given by;
R² = 16.415² + 5.8656²
R² = 303.858
R = √303.858
R = 17.432 kgm/s
Apply the principle of conservation of linear momentum for inelastic collision;
total initial momentum before = total final momentum after collision
P₁(x) + P₂(y) = Pf
R = Pf
R = v(m₁ + m₂)
17.432 = v(m₁ + m₂)
where;
v is the final components of velocity of the composite object
[tex]v = \frac{17.432}{m_1 + m_2} \\\\v = \frac{17.432}{3.35+1.88} \\\\v = 3.33 \ m/s[/tex]
Therefore, the final components of velocity of the composite object is 3.33 m/s.