Answer:
0.0432 m^3/s
Explanation:
Internal diameter of smaller pipes = 2.5 cm = 0.025 m
pipa wall thickness = 3 mm = 0.003 m
internal diameter of larger pipes = 8 cm = 0.8 m
velocity of region between smaller and larger pipe = 10 m/s
Calculate discharge in m^3/s
First we calculate the area of the smaller pipe
A = [tex]\pi Dt[/tex] = [tex]\pi ( 0.025 ) ( 0.003 )[/tex] = 0.00023571 m^2
next we calculate area of fluid between the smaller pipes and larger pipe
A = [tex][\frac{\pi }{4} D^{2} _{L} ] - 3(A_{s})[/tex]
= [tex][ \frac{\pi }{4} (0.08 )^2 - 3 ( 0.00023571 )][/tex]
= [ 0.00502857 - 0.00070713 ]
= 0.00432144 m^2
hence the discharge in m^3/s
Q = AV
= 0.00432144 * 10
= 0.0432 m^3/s
will mark brainliest if correct
When a tractor is driving on a road, it must have a SMV sign prominently displayed.
True
False
Answer: true
Explanation:
An aluminum rod is press fitted onto an aluminum collar. The collar has an inner radius of 1 cm and an outer radius of 2 cm. Given the rod has a diameter of 2.01cm and the young's modulus of aluminum is 69 GPa
The question is incomplete. The complete question is --
An aluminum rod is press fitted onto an aluminum collar. The collar has an inner radius of 1 cm and an outer radius of 2 cm. Given the rod has a diameter of 1.01 cm and the young's modulus of aluminum is 69 GPa, determine the following :
1. the interference value, i
2. the radial pressure at the interference of the collar and the rod
3. the maximum effective stress in the collar
4. if the yield strength of aluminium is 200 MPa and assume a safety factor of 1.5, will the aluminium collar break
Solution:
Given :
Inner radius of the collar = 1 cm
So, inner diameter, [tex]$d_1$[/tex] = 2 cm
Outer radius of the collar = 12 cm
So, outer diameter, [tex]$d_2$[/tex] = 4 cm
The aluminium rod diameter, d = 1.01 cm
Now, from the figure, we can see that there will be no interference and so the rod will easily insert inside the collar.
1. So, the interference , i =0
2. The radial pressure is also 0.
3. There will be no stress developed. So the maximum effective stress is 0
4. The collar will not break
what do you expect the future trends of an operating system in terms of (a) cost (b) size (c) multitasking (d) portability (e) simplicity
Answer:
plz follow in titkok
Explanation:
A typical printed page of text contains 50 lines of 80 characters each. Imagine that a certain printer can print 6 pages per minute and that the time to write a character to the printer’s output register is so short it can be ignored. Does it make sense to run this printer using interrupt‐driven I/O if each printer requires an interrupt that takes 50 µsec all‐in to service?
Solution :
Given
The number of line that can be written by printer per page = 50 lines
The number of characters that can be written by printer per page = 80 characters.
Number of pages that can be written per minute = 6 pages
The speed for writing characters to the printer can be found by
= 50 x 80 x 6
= 400 characters per sec
In one second the printer has the writing speed of 400 character.
Now each of the character uses = 50 µsec of the CPU time for interrupt.
So in each second, the interrupt overhead = 20 msec
Now using the interrupt driven input/output, 980 msec time can be available for other work.
Thus, the interrupt overhead charges only 2 percent of the CPU, that will hardly affect the program to run.
What is the process of a Diesel engine uses to convert fuel to mechanical energy
Answer:
A diesel engine is a type of heat engine that uses the internal combustion process to convert the energy stored in the chemical bonds of the fuel into useful mechanical energy. ... First, the fuel reacts chemically (burns) and releases energy in the form of heat.
What should be a concern as a weldment becomes larger as more parts are added?
Select four items that an industrial engineer must obtain in order to practice in the field.
Answer:
agriculture,defense,industry,science
Explanation:
Edg 2021
Two routes connect an origin and a destination. Routes 1 and 2 have performance functions t1 = 2 + X1 and t2 = 1 + X2, where the t's are in minutes and the x's are in thousands of vehicles per hour. The travel times on the routes are known to be in user equilibrium. If an observation for route 1 finds that the gaps between 30% of the vehicles are less than 6 seconds. Estimate the volume and average travel times for the two routes
Solution :
Given
[tex]$t_1=2+x_1$[/tex]
[tex]$t_2=1+x_2$[/tex]
Now,
[tex]$P(h<5)=1-P(h \geq5)$[/tex]
[tex]$0.4=1-P(h \geq5)$[/tex]
[tex]$0.6=P(h \geq5)$[/tex]
[tex]$0.6= e^{\frac{-x_1 5}{3600}}$[/tex]
Therefore, [tex]$x_1=368 \ veh/h$[/tex]
[tex]$=\frac{368}{1000} = 0.368$[/tex]
Given, [tex]$t_1=2+x_1$[/tex]
= 2 + 0.368
= 2.368 min
At user equilibrium, [tex]$t_2=t_1$[/tex]
∴ [tex]$t_2$[/tex] = 2.368 min
[tex]$t_2=1+x_2$[/tex]
[tex]$2.368=1+x_2$[/tex]
[tex]$x_2 = 1.368$[/tex]
[tex]$x_2 = 1.368 \times 1000$[/tex]
= 1368 veh/h
A rigid, insulated vessel is divided into two equal-volume compartments connected by a valve. Initially, one compartment con tains 1 m3 of water at 20°C, x = 50%, and the other is evacuated. The valve is opened and the water is allowed to fill the entire volume. For the water, determine the final temperature, in °C, and the amount of entropy produced, in kJ/K.
Solution :
Given
Volume, [tex]$V_1 = 1 \ m^3$[/tex]
Temperature, [tex]$T_1=20 \ ^\circ C[/tex]
[tex]$x_1=0.5$[/tex]
From the saturated water table, corresponding to [tex]$T_1=20 \ ^\circ C[/tex], we get the saturated liquid, vapor specific and the entropy.
[tex]$v_f=1.0010 \ m^3/kg$[/tex]
[tex]$v_g=57.791 \ m^3/kg$[/tex]
[tex]$s_f=0.2966 \ kJ/kg-K$[/tex]
[tex]$s_g=8.6672 \ kJ/kg-K$[/tex]
Now calculating the initial specific volume
[tex]$v_1=v_f+x_1 \cdot(v_g-v_f)$[/tex]
[tex]$=1.0018+05 \cdot(57.791-1.0018)$[/tex]
[tex]$= 29.8973 \ m^3/kg$[/tex]
Calculating the initial specific entropy:
[tex]$s_1=s_f+x+1 \cdot (s_g-s_f)$[/tex]
[tex]$=0.2966+0.5 \cdot (8.6673 - 0.2966)$[/tex]
[tex]$= 4.48 \ kJ/kg-K$[/tex]
So final volume of the vessel is two times bigger as the initial volume
[tex]$V_2=2 .V_1$[/tex]
[tex]$= 2 \times 29.8973 = 59.8 \ m^3/kg$[/tex]
If we interpolate the values from tables between [tex]$v_g=57.791 \ m^3/kg$[/tex] and [tex]$v_g=61.293 \ m^3/kg$[/tex], we can get final temperature and specific entropy corresponding to value of [tex]$v_2$[/tex] :
Final temperature, [tex]$T_2= 19.6 ^\circ C$[/tex]
and [tex]$s_2 = 8.68 \ kJ/kg-K$[/tex]
Calculating change in entropy
[tex]$\Delta s = s_2-s_1$[/tex]
[tex]$=8.68-4.48 = 4.2 \ kJ/kg-K$[/tex]
10. Which one of the following items would you expect to find on a floor framing plan?
ОООО
A. Sizes of joists
O B. Height of objects
C. Location of plumbing features
D. Arrangement of heating features
Answer:
c
Explanation:
the pluming usually is on the bottom floor plan
A metal shear can be used to cut flat stock , round stock , channel iron and which of the following?
Answer:
Angle Iron
Explanation:
Mark brainliest please.
Tech a says you should push the wrench when braking a fastener loose. Tech b says that you should pull the wrench when braking a fastener loose. Who is correct?
Answer:
tech b because gut feeling
Explanation:
What did the US and USSR agree on in the INF Treaty? They agreed to reduce nuclear weapons. They agreed that new European nations would be democratic. They agreed to tear down the Berlin Wall. They agreed that the USSR should break into several countries.
Answer:
they agreed to reduce nuclear weapons
Answer:
A
Explanation:
Edu 2023
Find the minimum sum of products expression using Quine-McCluskey method of the function. F(A,B,C,D)= Σ m(1,5,7,8,9,13,15)+ Σ d(4,6,11)
Answer:
Digital electronics deals with the discrete-valued digital signals. In general, any electronic system based on the digital logic uses binary notation (zeros and ones) to represent the states of the variables involved in it. Thus, Boolean algebraic simplification is an integral part of the design and analysis of a digital electronic system.
Explanation:
Hi please follow me also I you can and thanks for the points. Have a good day.
2) The switch in the circuit below has been closed a long time. At t=0, it is opened.
Find the inductor current for il(t) for t> 0.
Answer:
il(t) = e^(-100t)
Explanation:
The current from the source when the switch is closed is the current through an equivalent load of 15 + 50║50 = 15+25 = 40 ohms. That is, it is 80/40 = 2 amperes. That current is split evenly between the two parallel 50-ohm resistors, so the initial inductor current is 2/2 = 1 ampere.
The time constant is L/R = 0.20/20 = 0.01 seconds. Then the decaying current is described by ...
il(t) = e^(-t/.01)
il(t) = e^(-100t) . . . amperes
How are glasses a form of technology and how do they involve engineering aspects?
Please help!!!!
How to connect the wind turbines to the grid? Give advantages and disadvantages to your answer.
Answer:
Electricity from the wind turbine generator travels to a transmission substation where it is converted into extremely high voltage, between 155,000 and 765,000 volts, for long distance transmission on the transmission grid. This grid comprises a series of power lines that connect the power sources to demand centers.The advantages of wind energy are more apparent than the disadvantages. The main advantages include an unlimited, free, renewable resource (the wind itself), economic value, maintenance cost, and placement of wind harvesting facilities.
1. Every employer shall keep the records of all accidents, dangerous occurrences, occupation
diseases and occupational poisoning at the workplace for
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sup 100 point for you
Answer:
thanks! :D
Have a good day!
Answer:
Yay, :)
Thank you!!!
A well is located in a 20.1-m thick confined aquifer with a conductivity of 14.9 m/day and a storativity of 0.0051. If the well is pumped at a constant rate of 500 gpm, what is the drawdown at a distance of 7.0 m from the well after 1 day of pumping?
Answer:
S = 5.7209 M
Explanation:
Given data:
B = 20.1 m
conductivity ( K ) = 14.9 m/day
Storativity ( s ) = 0.0051
1 gpm = 5.451 m^3/day
calculate the Transmissibility ( T ) = K * B
= 14.9 * 20.1 = 299.5 m^2/day
Note :
t = 1
U = ( r^2* S ) / (4*T* t )
= ( 7^2 * 0.0051 ) / ( 4 * 299.5 * 1 ) = 2.0859 * 10^-4
Applying the thesis method
W(u) = -0.5772 - In(U)
= 7.9
next we calculate the pumping rate from well ( Q ) in m^3/day
= 500 * 5.451 m^3 /day
= 2725.5 m^3 /day
Finally calculate the drawdown at a distance of 7.0 m form the well after 1 day of pumping
S = [tex]\frac{Q}{4\pi T} * W (u)[/tex]
where : Q = 2725.5
T = 299.5
W(u) = 7.9
substitute the given values into equation above
S = 5.7209 M
A 0.5 m rod of some material elongates 0.1 mm on heating from 20 to 112°C. Determine the value of the linear coefficient of thermal expansion [in (°C)-1] for this material.
Answer:linear coefficient of thermal expansion of the rod =2.17 x10^-6(°C)^-1
Explanation:
The Linear thermal expansion is calculated as
ΔL = αLΔT,
where ΔL = change in length L,
ΔT = the change in temperature,
α is the coefficient of linear expansion
Change in length ΔL= 0.1 mm =0.1/1000= 0.0001m
change in temperature,ΔT= Final - Initial temperature
= (112- 20)°C=92°C
Solving, we have that
ΔL = αLΔT
α=ΔL/LΔT
= 0.0001 / 0.5 x 92
=0.0001/46
=2.17 x10^-6 / °C
The linear coefficient of thermal expansion of the rod, α =2.17 x10^-6(°C)^-1
Explain the major differences between designing buildings for earthquake resistance and for wind resistance.
Answer:
Earthquake's put vibration and seismic load on a building while wind puts a continuous force throughout the whole structure.
Explanation:
The most important difference between the design of a building that's resistent to earthquakes and resistant to high speed winds is that earthquake's put vibration and seismic load on a building while wind puts a continuous force throughout the whole structure.
Earthquake resistent building are equipped with a base that is isolated from the buildings with several layers of different material which absorb the vibration of the seismic waves and prevent them from reaching to the building.
Wind resistent buildings must have strong foundations and a sturdy structure/material that can withstand high pressure that the wind applies during events such as hurricanes.
I hope this answer helps.
How does a project differ from an ongoing work effort?
Answer:
Projects have a fixed budget, while operations have to earn a profit to run the business. Projects are executed to start a new business objective and terminated when it is achieved, while operational work does not produce anything new and is ongoing.
Hope this helped!
A 360 kg/min stream of steam enters a turbine at 40 bar pressure and 100 degrees of superheat. The steam exits the turbine as a 100% saturated vapor at a pressure of 5 bar. Write and simplify the appropriate energy balance and then determine the energy generated by the steam as it passes through the turbine in kW.
What are ethics in the engineering sector?
Answer:
Engineering ethics is the field of a system of moral principles that apply to the practice of engineering. The field examines and sets the obligations by engineers to society, to their clients, and to the profession.
Explanation:
The set of line styles and line thickness used on drawings used on drawings are referred to as the ____.
Answer:
I think it's referred as the outline
How are you today First to awnser is brainlyest.
Answer:
Happy
Explanation:
A room is filled with saturated moist air at 25°C and a total pressure of 100 kPa. If the mass of dry air in the room is 100 kg, the mass of water vapor is:_______
a. 0.52 kg
b. 1.97 kg
c. 2.96 kg
d. 2.04 kg
e. 3.17 kg
Answer:the mass of water vapor is=d. 2.04 kg
Explanation:
The humidity ratio by mass is given as
x = mw / ma (1)
where
mw = mass of water vapor
ma = mass of dry air
And also humidity ratio by pressure by Ideal Gas Law is given as
x = 0.62198 pw / (pa - pw) (2)
where
pw = partial pressure of water vapor in moist air
pa = atmospheric pressure of moist air
Equating both equation we have that
Humidity ratio = 0.62198 pw / (pa - pw)= mw / ma (3)
From the from the water table at 25°C,
water vapor partial pressure = 23.8 torr
1 atm =760 torr.
1 atm = 101.325 kPa,
So, 760 torr =101.325 kPa,
Therefore 23.8 torr =3.173kPa
Humidity ratio = 0.62198 pw / (pa - pw)= mw / ma
0.62198 x 3.173 / (100-3.173)= mw / 100
1.9736 /96.827=mw/100
0.0204=mw/100
mw=2.04kg
For a Cu-Ni alloy containing 53 wt.% Ni and 47 wt.% Cu at 1300°C, calculate the wt.% of the alloy that is solid and wt.% of alloy that is liquid.
Answer:
Hello your question is incomplete attached below is the complete question
answer: wt.% of alloy that is solid = 61.5%
wt.% of allot that is liquid = 38.5%
Explanation:
To determine the wt.% of the alloy that is solid
= [tex]\frac{R}{R +S } * 100[/tex]
= [tex]\frac{53-45}{58-45} * 100[/tex] = 61.5%
To determine the wt.% of the alloy that is liquid
= [tex]\frac{S}{S+R} * 100\\[/tex]
= [tex]\frac{58-53}{58-45} *100[/tex] = 38.5%
attached below is a free hand sketch as well
Which option identifies the step skipped in the following scenario?
Eric is a newly hired engineer who has just ruined a prototype of a very expensive jet plane made from steel. He was short on time, so he rushed the molds of the body of the jet, causing them to crack. The cost incurred put the project far over budget.
He deviated from the design plans of the project.
He did not use the proper materials for the project.
He did not pay attention to the cost analysis of the project.
He did not allow the metal to cool properly when making molds.
Answer:
he didn't use the proper material
Answer:
A. He did not allow the metal to cool properly when making molds.
Explanation: