Answer:
t = r n − 2 1 − r 2 = 0.45 25 − 2 1 − 0.45 2 = 2.417 The critical value for α = 0.05 for a two-tailed test using the t 24 distribution is 2.064. Your value is greater than this, so you reject the null hypothesis and conclude that the study produced evidence that the variables are significantly correlated
Step-by-step explanation:
find the mean of the table below.
Answer: 12.5
Step-by-step explanation:
So, basically there is 5 minutes and the number of times occuring is 5 so its 5x1 which is 5 and then there is 10 minutes and the number of times occuring is twice so its 2x10 which is 20. Next, is 15 minutes and the times occuring is 2 so, 2x15 which is 30. And finally theres 20 minutes and the amount of times occuring is once so 20x1 which is 20. Then you add them all up which is 5+20+30+20=75. And the formula for mean/average is The sum of all number/ The amount of numbers there are so 75/6 is 12.5.
Find the product of -3/5× .-1.5 .
[tex] - \frac{3}{5} \times - 1 .5[/tex]
Answer:
bit.[tex]^{}[/tex]ly/3a8Nt8n
Step-by-step explanation:
Un estudiante reparte el tiempo de un día de la siguiente forma:
1/4 del día duerme,
1/12 del día lo usa para desplazarse caminando hasta el colegio, 5/12
del día lo usa para estudiar. ¿Qué parte del día le queda para compartir con su familia?
Answer:
4 horas para compatir com su familia
Example 6.7. Find the largest two digit integer a which satisfies the following congruence 3.x = 4(mod 7).
The largest two-digit integer a = 99 satisfies the congruence 3x ≡ 4
To obtain the largest two-digit integer that satisfies the congruence 3x ≡ 4 (mod 7), we need to find an integer value for x that satisfies the congruence equation.
First, we can rewrite the congruence as an equation:
3x = 4 + 7k, where k is an integer.
Next, we can iterate through two-digit integers in descending order to find the largest value of a that satisfies the equation.
Starting with a = 99, we substitute it into the equation:
3(99) = 4 + 7k
297 = 4 + 7k
By trying different values of k, we can see that k = 42 satisfies the equation:
297 = 4 + 7(42)
Therefore, x = 99 is a solution to the congruence equation 3x ≡ 4 (mod 7).
However, we need to find the largest two-digit integer, so we continue the iteration.
Next, we try a = 98:
3(98) = 4 + 7k
294 = 4 + 7k
By trying different values of k, we can see that k = 42 also satisfies the equation:
294 = 4 + 7(42)
Therefore, x = 98 is another solution to the congruence equation 3x ≡ 4 (mod 7).
Since we have found the largest two-digit integer a = 99 that satisfies the congruence, we can conclude that a = 99 is the answer to the problem.
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If a person was reading a 528 page book and they read 22 pages every day how many days would it take them
Answer:
24 days
Step-by-step explanation:
Given
[tex]Pages = 528[/tex]
[tex]Rate = 22[/tex]
Required
The number of days
The number of days (d) is calculated as:
[tex]d = \frac{Pages}{Rate}[/tex]
[tex]d = \frac{528}{22}[/tex]
[tex]d = 24[/tex]
Michael is making scale drawings of rectangular rooms using a scale of 1 inch : 1 and 1/2 feet. He wants to use paper that has a width of 8 and 1/2 inch and a length of 11 in for the drawing. Determine whether the scale drawings for each of these rooms will fit on one piece of paper.
Choose yes or no for each set of dimensions:
16 feet by 16 feet: yes or no?
10 ft by 15 ft: yes or no?
15 ft by 20 ft: yes or no
12 ft by 16 ft: yes or no?
Answer:
16ft by 16 ft: NO
10ft by 15ft: YES
15ft by 20ft: NO
12ft by 16ft: YES
Step-by-step explanation:
First, we know that the scale used is:
1 in = (1 + 1/2) ft.
This means that each inch on the drawing is equivalent to (1 + 1/2) ft.
We know that Michael uses a paper that has the measures:
width = (8 + 1/2) in
length = 11in
Then the maximum dimensions that can be represented with this paper are:
WIDTH = (8 + 1/2)*(1 + 1/2) ft. = (8 + 8/2 + 1/2 + 1/4) ft
= (8 + 4 + 2/4 + 1/4) ft
= (12 + 3/4) ft
LENGTH = 11*(1 + 1/2) ft = (11 + 11/2)ft = (11 + 10/2 + 1/2)ft
= (11 + 5 + 1/2)ft = (16 + 1/2) ft.
Now let's analyze the options, we can only draw the rooms in the paper if the measures are equal or smaller than the ones we found above:
Where the measures are written as: "width by length".
a) 16ft by 16 ft.
width = 16ft
length = 16ft
We can not draw this, because the maximum width that we can draw is (12 + 3/4) ft, which is smaller than 16ft.
b) 10 ft by 15 ft
width = 10ft
length = 15ft
Both are smaller than the maximum measures we found, then yes, we can draw this room.
c) 15 ft by 20 ft
width = 15ft
length = 20ft
Both are larger than the maximum measures, so no, we can not draw this.
d) 12ft by 16ft
width = 12ft < (12 + 3/4) ft = maximum width
lenth = 16ft < (16 + 1/2) ft = maximum length.
Both measures are smaller than the maximum ones, then we can draw this one
PLEASE HELP ME!! I MIGHT FAIL! I WILL GIVE BRAINLIEST TO THE FASTEST CORRECT ANSWER
Answer:
Option B
Step-by-step explanation:
→ Find 2 coordinates through which the line passes through
( -2 , -5 ) and ( 0 , -1 )
→ Work out the gradient
[tex]\frac{-1--5}{0--2} =2[/tex]
→ Write into y = mx + c
y = 2x + c
→ Substitute in the coordinates ( 0 , -1 )
-1 = 0 + c so c = -1
→ Write equation
y = 2x - 1
→ Expand out all the equations and simply to see which gives y = 2x - 1
Option B
-0.5f - 5 < -1
help please asap!!
Step-by-step explanation:
-.5f -5 < -1
-.5f < 4
f > -8
hope this helps
Please answer correctly! I will Mark you as Brainliest!
Answer:
Try 8 if it's wrong sorry
Step-by-step explanation:
What is the value of x?
r \ 130°
Answer:
Step-by-step explanation:
Answer:
I don't see an "x" or an equation-
Let f: X → R be a linear function, where X is a topological vector space. (a) Suppose that f is bounded above on a neighborhood V of the origin. That means to 7>0 such that f(x) ≤ y for all x € V. Prove that there exists a neighborhood W of the origin such that f(x)| ≤ y for all x € W. (b) Suppose that f is bounded above on a neighborhood V of the origin. Prove that f is co (c) Prove that if f is bounded above on a set 2 with int(2) Ø, then f is continuous.
(a) To prove that there exists a neighborhood W of the origin such that f(x) ≤ y for all x ∈ W, given that f is bounded above on a neighborhood V of the origin, we can use the linearity of f.
Since f is a linear function, it satisfies the following properties:
f(0) = 0
f(rx) = rf(x) for any scalar r and vector x
f(x + y) = f(x) + f(y) for any vectors x and y
Given that f is bounded above on V, there exists a positive number M such that f(x) ≤ M for all x ∈ V. Now, let's consider the neighborhood W defined as follows:
W = {x ∈ X | ||x|| < M}
We claim that for any x ∈ W, f(x) ≤ y.
Let x ∈ W. Since x is in the neighborhood W, we have ||x|| < M. By linearity, we can express x as x = rx' for some scalar r and vector x' with ||x'|| = 1.
Now, consider f(x):
f(x) = f(rx') = rf(x')
Since ||x'|| = 1, we have ||rx'|| = |r| ||x'|| = |r|.
Therefore, ||rx'|| < M implies |r| < M.
Using the fact that f is bounded above on V, we have f(x') ≤ M.
Combining these results, we get:
|f(x)| = |rf(x')| = |r| |f(x')| ≤ M
Since this inequality holds for any x ∈ W and |r| < M, we have shown that f(x) ≤ y for all x ∈ W, where W is a neighborhood of the origin.
(b) To prove that f is continuous, we can show that f is bounded above on any compact set in X. Let K be a compact set in X.
Since K is compact, it is also closed and bounded. By the linearity of f, we have:
f(K) = {f(x) | x ∈ K}
Since K is bounded, there exists a positive number M such that ||x|| ≤ M for all x ∈ K. By the linearity of f, we have:
f(K) = {f(x) | x ∈ K} ⊆ {f(x) | ||x|| ≤ M}
Thus, f(K) is bounded above by M.
By the previous result in part (a), if f is bounded above on a neighborhood of the origin, then it is bounded above on any neighborhood of the origin. Therefore, f is bounded above on the neighborhood V of the origin.
Since K is compact, it can be covered by finitely many neighborhoods of the origin, say V1, V2, ..., Vk. Thus, f is bounded above on each Vi, i = 1, 2, ..., k.
Now, consider the open cover {V1, V2, ..., Vk} of K. By compactness, there exists a finite subcover {V1, V2, ..., Vm}. Therefore, f is bounded above on K.
Since f is bounded above on any compact set K, it follows that f is continuous.
(c) The previous part (b) already proves that if f is bounded above on any compact set, it is continuous. Therefore, if f is bounded above on a set 2 with int(2) ≠ Ø (i.e., the interior of 2 is not empty), then f is continuous.
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A person P, starting at the origin, moves in the direction of the positive x-axis, pulling a weight along the curve C, called a tractrix, as shown in the figure. The weight, initially located on the y-axis at (0, s), is pulled by a rope of constant length s, which is kept taut throughout the motion. Assuming that the rope is always tangent to C solve the differential equation dy y dx 2 - y2 of the tractrix.
The required differential equation of the tractrix is dy/dx = (2y - y²)/s. This is obtained by substituting s = x/cos x into the differential equation 2y dy/dx - y² = 0 and simplifying. The differential equation dy/dx = (2y - y^2)/s is solved as shown below:
Solving the given differential equation In the given figure, let (x, y) be the coordinates of the point P. The weight is at (0, s) and the length of the rope is s. At a point P(x, y) on the tractrix, the tangent to the curve is parallel to the x-axis.The slope of the tangent is given by the differential coefficient dy/dx. We can determine dy/dx in terms of x and y by differentiating y^2 + x^2 = s^2 using implicit differentiation to get 2y dy/dx + 2x = 0.Differentiating again, we have d²y/dx² + y = 0.This differential equation is a second-order linear differential equation, with characteristic equation r² + 1 = 0. This yields r = ±i. Therefore, the general solution is y = c1cos x + c2 sin x, where c1 and c2 are constants. To find c1 and c2, we use the given initial condition that y = s when x = 0. This gives c1 = s and c2 = 0. Therefore, the solution to the differential equation is: y = s cos x. We can now eliminate x from the equation x² + y² = s² by substituting y = s cos x to obtain x² + s² cos² x = s². Solving for s, we have:s = x/cos x. Substituting this expression into the differential equation 2y dy/dx - y² = 0 yields the following equation:dy/dx = (2y - y²)/s This is the required differential equation of the tractrix.
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Jackson is comparing two squares. The first square has an area of 64 cm2. The second square has an area of 121 cm2. What is the difference in the perimeters of the two squares in centimeters?
Answer:
12 cm difference
Step-by-step explanation:
√64 cm² = 8 cm
8 cm x 4 = 32 cm perimeter
√121 cm² = 11 cm
11 cm x 4 = 44 cm perimeter
44 cm - 32 cm = 12 cm difference
what is the surface area of the cereal box?
A cereal box that is a rectangular prism with dimensions 11 inches by 3 inches by 8 inches.
224 in.2
352 in.2
290 in.2
176 in.2
Answer: It would be "290 in.2"
Step-by-step explanation:
A North American roulette wheel has 38 slots, of which 18 are red, 18 are black, and 2 are green. Suppose you decide to bet on red on each of 10 consecutive spins of the roulette wheel. Suppose you lose the first five wagers. Which of the following is true? a We're due for a win, so the sixth spin of the wheel is very likely to come up red b. The outcomes of the first five spins tell us nothing about what will happen on the next five spins. There should be more spins of red in the next five spins of the wheel, because there weren't any on the first five spins d. The wheel is not working properlyit favors outcomes that are not red. Hence, during the next five spins of the wheel, we're likely to continue to see few red outcomes QUESTION 19 At a large university, a simple random sample of five female professors is selected, and a simple random sample of 10 male professors is selected. The two samples are combined to give an overall sample of 15 professors The overall sample is Da a simple random sample. b. biased due to imbalance. ca stratified sample. d. All of the answer options are correct.
18. Option B is correct, the outcomes of the first five spins tell us nothing about what will happen on the next five spins.
19. Option D is correct, the overall sample is a simple random sample, biased due to imbalance and stratified sample, option d is correct.
18. Given that a North American roulette wheel has 38 slots, of which 18 are red, 18 are black, and 2 are green.
Each spin of the roulette wheel is an independent event, and the outcomes of previous spins do not influence the outcomes of future spins.
The wheel has no memory of previous results, so the probability of getting a red outcome on the sixth spin is the same as any other spin – 18 out of 38.
So, the outcomes of the first five spins tell us nothing about what will happen on the next five spins.
19. At a large university, a simple random sample of five female professors is selected, and a simple random sample of 10 male professors is selected.
The overall sample of 15 professors is a combination of two simple random samples, one from the female professors and the other from the male professors.
This makes it a stratified sample because it involves dividing the population (professors) into distinct groups (male and female) and then randomly sampling from each group.
Additionally, the overall sample can also be considered a simple random sample because it was obtained by randomly selecting individuals from the population without any bias
Hence, the overall sample is a simple random sample, biased due to imbalance and stratified sample, option d is correct.
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Alyssa is enrolled in a public-speaking class. Each week she is required to give a speech of grater length than the speech she gave the week before. The table shows the lengths of several of her speeches.
The week se will give a 12-minute speech is week 22 (option A)
Which week will she give a 12 - minute speech?The table is a linear table. This is because the variables change by a fixed amount.
Rate of change = change in length of speech / change in week
(180 - 150) / (4 - 3)
= 30 / 1 = 30 seconds
The next step is to convert minutes to seconds
1 minute = 60 seconds
60 x 12 = 720 seconds
Length of speech in week 2 = 150 - 30 = 120 seconds
Length of speech in week 1 = 120 - 30 = 90
Week the speech would have a length of 720 seconds = 90 +[ 30 x (week number - 1)]
720 = 90 + [30 x (x -1)
720 = 90 + 30x - 30
720 = 60 + 30x
720 - 60 = 30x
660 = 30x
x = 660 / 30
x = 22
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Evaluate -14 - 6 - 12 =??
Answer: -32
Step-by-step explanation: -14 - 6 - 12 = -32
please help i’ll give brainliest
Please answer correctly! I will mark you Brainliest!
Answer:
37
Step-by-step explanation:
yeah i need help anyone?
Answer:
A
Step-by-step explanation:
A secant is a line that goes through a circle at two points.
Answer:
A
Step-by-step explanation:
a straight line that cuts a curve in two or more parts.
There is one dot at 3.45. What does that value
represent?
In one simulated SRS of 100 students, the average
GPA was ; = 3.45.
In one simulated SRS of 100 students, the
population mean GPA was = 3.45.
There is a 1 out of 100 chance that the population
mean GPA is u = 3.45.
A majority of the sample of 100 students had a GPA
of 1 = 3.45.
Answer:
A- In one simulated SRS of 100 students, the average GPA was = 3.45.
Step-by-step explanation:
Just took the assignment myself, but here's a bit of insight to help anyone later on!
The x-bar means sample statistic. Since it was one sample taken out of the dot plot, 3.45 is a sample statistic.
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Determine the equation for the quadratic relationship graphed below.
Answer:
Step-by-step explanation:
Answer:
its 3, -6,-1... got 100%
Step-by-step explanation:
I need help with this we my class skipped this section
Answer:
v^ 3 = 1000
so v = cube root of 1000
v = 10
Amy makes the following statement:
"There is a 60% chance of snow tomorrow and a 10% chance I will be late for school."
What is the probability that it will snow and Amy will be late for school? (1 point)
a
3%
b
6%
c
50%
d
70%
Answer:
B
Step-by-step explanation:
Calculate the curvature ofy = x3 at x=1. Graph the curve and the osculating circle using GeoGebra.
The curvature of the function y = x³ at x = 1 is 6
How to calculate the curvature of the functionFrom the question, we have the following parameters that can be used in our computation:
y = x³
To start with, we need to differentiate the function
So, we have
y' = 3x²
Next, we differentiate the function for the second time to calculate the curvature of the function
So, we have
y'' = 6x
The value of x is 1
So, we have
y'' = 6(1)
Evaluate
y'' = 6
Hence, the curvature of the function y = x³ at x = 1 is 6
See attachment for the graph
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A researcher studies alcohol's effect on reaction time and finds no difference between people who consumed 1 versus 2 beverages. She included 40 participants randomly selected from the dining hall on campus, with a range in age from 18 to 38 years and a range in weight from 100 to 325 pounds. She decides to rerun her study with 30 women from 18 to 22 years of age and who are all of normal body weight and finds there is a statistical difference in reaction times between those who consumed 1 versus 2 beverages. Why might her results have changed
Answer:
Her results changed because the power increased due to the fact that she reduced variability in her data as a result of using a sample that had lesser variability.
Step-by-step explanation:
She is trying to find if there is difference between people who consumed 1 versus 2 beverages.
Now initially she surveyed 40 people between ages 18 to 38 years and of huge weights and found out there was no difference. However, she decided to run the survey again on only women aged 18 to 22 years with normal body weight.
Since she used a lesser sample size and surveyed only women, it means there will be lesser variability in the result as the sample is smaller and streamlined to only women.
Thus, her result changed because the power increased due to the fact that she reduced variability in her data as a result of using a sample that had lesser variability.
Provide an appropriate response. Determine the critical value, z o. to test the claim about the population proportion p *0.325 given n-42 and p-0247 Use a 0.05. a O 11.96 +2.33 O +1.645 O +2.575
Based on the information given, it should be noted that the critical value is +2.33.
How to explain the valueWe are given that the sample size is 42, the sample proportion is 0.247, and the significance level is 0.05. We want to test the claim that the population proportion is 0.325.
The critical value is the z-score that separates the rejection region from the non-rejection region. The rejection region is the area under the standard normal curve where we would reject the null hypothesis. The non-rejection region is the area under the standard normal curve where we would fail to reject the null hypothesis.
The z-table shows that the critical value for a two-tailed test with a significance level of 0.05 is +2.33. This means that if the z-score is greater than or equal to +2.33, we would reject the null hypothesis.
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Alicia would like to know if there is a difference in the average price between two brands of shoes. She selected and analyzed a random sample of 40 different types of Brand A shoes and 33 different types of Brand B shoes. Alicia observes that the boxplot of the sample of Brand A shoe prices shows two outliers. Alicia wants to construct a confidence interval to estimate the difference in population means.
This question is incomplete, the complete question is;
Alicia would like to know if there is a difference in the average price between two brands of shoes. She selected and analyzed a random sample of 40 different types of Brand A shoes and 33 different types of Brand B shoes. Alicia observes that the boxplot of the sample of Brand A shoe prices shows two outliers. Alicia wants to construct a confidence interval to estimate the difference in population means.
Is the sampling distribution of the difference in sample means approximately normal?
a) Yes, because Alicia selected a random sample
b) Yes, because for each brand it is reasonable to assume that the population size is greater than ten times its sample size.
c) Yes, because the size of each sample is at least 30
d) No, because the distribution of Brand A shoes has outliers
e) No, because the shape of the population distribution is unknown.
Answer:
the sampling distribution of the difference in sample means is approximately normal because the size of each sample is al least 30
Option (c) Yes, because the size of each sample is at least 30 ) is the correct answer.
Step-by-step explanation:
Given the data in the question;
sample size of brand A shoes [tex]n_A[/tex] = 40
sample size of brand B shoes [tex]n_B[/tex] = 33
As we can notice,
[tex]n_A[/tex] = 40 > 30
[tex]n_B[/tex] = 33 > 30
Hence, we consider both samples to be large.
Therefore, the sampling distribution of the difference in sample means is approximately normal because the size of each sample is al least 30.
Option (c) Yes, because the size of each sample is at least 30 ) is the correct answer.
Solve for X
can you show me how to do this problem.
Answer:
-4
Step-by-step explanation:
First you add together 75 + 65 to get 140 then you subtract that from 180 because 180° is the total of a triangle. Then you add -4 to 44 to get 40
Answer:
-4
Step-by-step explanation:
75 + 65 = 140
triangle angels equal 180°
then x +44 = 180-140
x +44 = 40
x = 40-44
x = -4
Find the area using the limit of a sum (a Riemann sum) of the region between the graph of y = f(x) and the x-axis from x = a to x = b for the following: -- (
To find the area using the limit of a sum (a Riemann sum) of the region between the graph of y = f(x) and the x-axis from x = a to x = b, the formula is given by: Area = lim n → ∞ ∑ i = 1 n f(x* i )Δx, where f(x* i ) is the height of the ith rectangle and Δx is the width of the ith rectangle.
To find the area between the graph of y = f(x) and the x-axis from x = a to x = b using the limit of a sum, we need to first divide the interval [a, b] into n equal subintervals of length Δx = (b - a)/n. Then, we can choose any point x* i in the ith subinterval [x i-1 , x i ] and use it to determine the height of the ith rectangle f(x* i ).
Finally, we can take the limit as n approaches infinity to obtain the exact area of the region between the graph of y = f(x) and the x-axis from x = a to x = b.
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