The blue segment below is a radius of oo. What is the length of the diameterof the circle?

Answer:

1 and 2/4 I think

Step-by-step explanation:

Answer: 24

Step-by-step explanation: 4•(1/4)=1

4•6=24

Answer:

2.9375 inches or 2 15/16"

Step-by-step explanation:

23 1/2 feet equals 282 inches

(1/8 ÷ 12) = (x ÷ 282)

cross-multiply:

35.25 = 12x

x = 2.9375 or 2 15/16 inches

Answer: The Y-intercept would be positive 3, and your slope would be for every single risen coordinate on the Y axis, you move on the X-axis by 4.

Answer: The answer for this question is "A": 5 + 15h

Answer:

yes, there are fewer numbers to compute.

It's just one length x the number of sides.

Step-by-step explanation:

Answer:

1078m²

Step-by-step explanation:

Formulas:

Total Surface Area  = 2B + Ph

Area = 1/2bh

Solve:

19 × 17 = 323

19 + 19 + 17 + 17 = 72

h = 6m

B = 323m

P = 72m

Total Surface Area = 2(323m) + (72m × 6m) = 1078m²

Answer:

q=0

Step-by-step explanation:

Hope this helped!!

the answer is 192

Step-by-step explanation:

q/32 = 6

q = 192

Step-by-step explanation:

6/5(4)=24/20

1/2(5)=5/10

3/9(7)=21/63

3/8(5)=15/40

4/3(9)=36/27

2/4(8)=16/32

9/6(2)=18/12

7/5(6)=42/30

4/7(3)=12/21

Answer:

who do pow en odd an odd an 9 all 9 FM

Answer:

if mi stands for miles then 8 miles = 14080 yards

Step-by-step explanation:

8 x 1760

Answer:

14080

Step-by-step explanation:

8 * 1760 = 14080

The Intersection of events A and B (A ∩ B) in this particular scenario has no outcomes, as there are no combinations that satisfy both the conditions of having an even sum and being divisible by 3.

The outcomes in the intersection of events A and B, we first need to identify the possible outcomes for each event.

Event A represents the sum of the dice being even. For a pair of dice, there are a total of 36 possible outcomes (6 sides on the first die multiplied by 6 sides on the second die). Out of these outcomes, half will result in an even sum. This is because if one die shows an odd number, the other die must show an even number to achieve an even sum. Therefore, Event A consists of 18 outcomes.

Event B represents the sum of the dice being divisible by 3. To determine the outcomes for Event B, we need to identify the combinations of numbers on the dice that add up to a multiple of 3. There are four such combinations: (1, 2), (2, 1), (2, 4), and (4, 2). These four combinations result in a sum that is divisible by 3. Hence, Event B consists of four outcome.

The outcomes in the intersection of A and B (A ∩ B), we need to identify the outcomes that satisfy both conditions, i.e., the outcomes that are both even and divisible by 3. From the information above, we know that Event A has 18 outcomes and Event B has four outcomes. However, none of the outcomes satisfy both conditions simultaneously. Therefore, the intersection of A and B (A ∩ B) has no outcomes.

It is important to maintain academic integrity by avoiding plagiarism. Plagiarism involves using someone else's work or ideas without proper attribution. To ensure originality, it is essential to express the information in your own words and provide accurate explanations based on the given data.

In conclusion, the intersection of events A and B (A ∩ B) in this particular scenario has no outcomes, as there are no combinations that satisfy both the conditions of having an even sum and being divisible by 3.

To know more about Intersection .

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Answer:

circumference = 8 x 3.14 = 25.12 m

area = 3.14(4²) = 50.24 m²

Step-by-step explanation:

Answer:

C= about 25.13

A= about 50.27

Step-by-step explanation:

The formula for circumference is 2* pi* r

The formula for area is pi *r^2

Answer:

6) .000000947

7) 244000000

8) .076

Solution :

Given :

p = 12% = 0.12

n = 15..

Mean is defined as the product of a sample size n and the probability p such that :

[tex]$\mu_X = np = 1500 \times 0.12$[/tex]

             = 180

Standard deviation may be defined as the square of a product of the sample size n, the probability p and the probability 1-p :

[tex]$\sigma_X = \sqrt{np(1-p)}$[/tex]

[tex]$\sigma_X = \sqrt{1500 \times 0.12 \times (1-0.12)}$[/tex]

     ≈  12.5857

The z-score is given by :

[tex]$z=\frac {x- \mu}{\sigma } $[/tex]

[tex]$z=\frac {165-180} {12.5857 }$[/tex]

 ≈  -1.19  

[tex]$z=\frac {x- \mu}{\sigma } $[/tex]

[tex]$z=\frac{195-180} {12.5857 }$[/tex]

 ≈  1.19  

Now determining the corresponding probability using table  :

P (165 ≤ X ≤ 195 ) = P (-1.19 ≤ Z ≤ 1.19 )

                            = 1-2 x P(Z < -1.19)

                            = 1-2 x 0.1170

                            = 1-0.2340

                            = 0.7660

                             = 76.60%

Given values,

           = 0.12

The mean will be

→ [tex]\mu x = np[/tex]

By putting the values,

       [tex]= 1500\times 0.12[/tex]

       [tex]= 180[/tex]

The standard deviation will be:

→ [tex]\sigma x = \sqrt{np(1-p)}[/tex]

       [tex]= \sqrt{1500\times 0.12\times (1-0.12)}[/tex]

       [tex]= 12.5857[/tex]

The z-score will be:

→ [tex]z = \frac{x- \mu}{\sigma}[/tex]

     [tex]= \frac{165-180}{12.5857}[/tex]

     [tex]= -1.19[/tex]

and,

→ [tex]z = \frac{195-180}{12.5857}[/tex]

     [tex]= 1.19[/tex]

hence,

The probability will be:

→ [tex]P(165 \leq X \leq 195) = P(-1.19 \leq Z \leq 1.19)[/tex]

                                [tex]= 1-2\times P(Z < -1.19)[/tex]

                                [tex]= 1-2\times 0.1170[/tex]

                                [tex]= 1-0.2340[/tex]

                                [tex]= 0.7660[/tex]

                                [tex]= 76.60[/tex] (%)

Thus the answer above is right.  

Learn more about probability here:

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Answer:

Yes, result is significant ; PVALUE < α

Step-by-step explanation:

Given :

x = 536

n = sample size = 1012

Phat = x / n = 536 / 1012 = 0.5296 = 0.53

H0 : P0 = 0.5

H1 : P0 > 0.5

Test statistic :

(Phat - P0) ÷ sqrt[(P0(1 - P0)) / n]

1-P0 = 1 - 0.5 = 0.5

(0.53 - 0.5) ÷ sqrt[(0.5*0.5)/1012]

0.03 ÷ 0.0157173

= 1.9087

Pvalue :

Using the Pvalue from test statistic :

Pvalue = 0.02815

To test if result is significant :

α = 0.05

0.02815 < 0.05

Pvalue < α ; Hence, result is significant at α=0.05; Hence, we reject H0.

Answer:

1

2

DNE

Step-by-step explanation:

Answer:

I got an answer

Step-by-step explanation:

1 is inference

2 is biased question as individuals are lead towards an answer that aligns with what the one who made the question wants

3 is statistics

4 is random

5 is survey

Answer: 53.79

Step-by-step explanation:

The area of a circle with a radius of r is [tex]pi r^2[/tex]

Answer:

No

Step-by-step explanation:

No, absolutely not. I don't think we'd have the same sample average number. The randomising of values is quite high, very high, for one to think that we'd end up having the same average. Walking out there, talking to random people who don't even know each other at all means they will definitely give different numbers. Again, when you look at it, there are 21 of us, 21 is also a high number as well.

I believe with all these factors involved and actively militating, 21 people can't have the same sample average. No!

Answer:

The awnser is d i think

Answer:

D

Step-by-step explanation:

because 1 is a factor of every number and also three is a factor of 27

Answer:

300:15 = 100:5 = 20:1

Answer = 20:1

Answer:

the answer is 12

Step-by-step explanation:

A(t)=P(e^(rt))

Insert the values as follows:

The equation for "continual" growth (or decay) is A = Pe^(rt), where "A", is the ending amount, "P" is the beginning amount (principal, in the case of money), "r" is the growth or decay rate (expressed as a decimal), and "t" is the time (in whatever unit was used on the growth/decay rate).

34820=P(e^((.78)(5)))

34830=P(49.4024)

704.82335

Hope that helps :)

Answer:

Mean: 14

Median: 15

Mode: All values appear just once

Range: 7

Answer:

The chances of landing on blue are 1 in 4, or one fourth. The chances of landing on red are 1 in 4, or one fourth. This problem asked us to find some probabilities involving a spinner.