Answer: c. incident ray
Explanation:
A car’s brakes decelerate it at a rate of -2.40 m/s2. If the car is originally travelling at 13 m/s and comes to a stop, then how far, in meters, will the car travel during that time?
Answer:
Approximately [tex]35.2\; \rm m[/tex].
Explanation:
Given:
Initial velocity: [tex]u = 13\; \rm m \cdot s^{-1}[/tex].
Acceleration: [tex]a = -2.40\; \rm m \cdot s^{-2}[/tex] (negative because the car is slowing down.)
Implied:
Final velocity: [tex]v = 0\; \rm m \cdot s^{-1}[/tex] (because the car would come to a stop.)
Required:
Displacement, [tex]x[/tex].
Not required:
Time taken, [tex]t[/tex].
Because the time taken for this car to come to a full stop is not required, apply the SUVAT equation that does not involve time:
[tex]\begin{aligned} x &= \frac{v^2 - u^2}{2\, a} \\ &= \frac{{\left(0\; \rm m \cdot s^{-1}\right)}^2 - {\left(13\; \rm m \cdot s^{-1}\right)}^2}{2\times \left(-2.40\; \rm m\cdot s^{-2}\right)} \approx 35.2\; \rm m \end{aligned}[/tex].
In other words, this car would travel approximately [tex]35.2\; \rm m[/tex] before coming to a stop.
The cardinal, central, and secondary traits are all part of __________ categorized traits. A. Gordon Allport’s B. Robert McCrae’s C. Paul Costa’s D. Hans Eysenck’s
Answer:
Gordon Allport’s
Explanation:
edge2o2o
The cardinal, central, and secondary traits are all part of Gordon Allport’s categorized traits. The Correct option is A
Who was Gordon Allport ?
Gordon Willard Allport was born on 11 November 1897 and died 9 October 1967. He was an American psychologist. Allport was first psychologists who studied on personality. he has developed theory of personality. which was one of the greatest finding in the study of personality psychology. He was Appointed as a social science instructor at Harvard University in 1924,
Gordon Allport was a great trait theorist who categorized personality traits into three categories cardinal, central, and secondary.
Hence option A is Correct.
To know more about traits, click :
https://brainly.com/question/1463051
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An object in FREE-FALL on the MOON would experience which of the following
FORCES?
O a. Weight
O b. Normal
O c. Air Resistance
d. a and c
O e. None of these
Answer:
e. none of these
Explanation:
An object in FREE-FALL on the MOON would experience only acceleration
A 0.200 H inductor is connected in series with a 88.0 Ω resistor and an ac source. The voltage across the inductor is vL=−(12.0V)sin[(487rad/s)t].
Required:
a. Derive an expression for the voltage vR across the resistor. Express your answer in terms of the variables L, R, VL (amplitude of the voltage across the inductor), ω, and t .
b. What is vR at 2.00 ms? Express your answer with the appropriate units.
Answer:
a. (VL)R/ωL[1 - cos[ωt]] = (10.84 V)[1 - cos[(487rad/s)t]]
b. 1.084 mV
Explanation:
a. Since it is a series circuit, the current in the inductor is the same as the current in the resistor.
Now, the voltage across the inductor vL = -Ldi/dt.
So, the current, i = -1/L∫vLdt.
Now, vL = −(12.0V)sin[(487rad/s)t] and L = 0.200 H
Substituting these into i, we have
i = -1/L∫vLdt
= -1/0.200H∫[−(12.0V)sin[(487rad/s)t]]dt.
= -[−(12.0V)]/0.200H∫[sin[(487rad/s)t]]dt.
= 60V/H∫[sin[(487rad/s)t]]dt
Integrating i, we have
i = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)t]] + C
at t = 0, i(0) = 0
0 = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)× 0]] + C
0 = 60V/H ÷ [(487rad/s)[-cos[0]] + C
0 = 60V/H ÷ [(487rad/s)[-1]+ C
C = 60V/H ÷ [(487rad/s)
So, i = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)t]] + 60V/H ÷ [(487rad/s)
i = 60V/H ÷ [(487rad/s)[1 - cos[(487rad/s)t]]
i = (0.123A)[1 - cos[(487rad/s)t]] = VL/ωL[1 - cos[ωt]] where ω = 487rad/s and VL = 12.0 V and L = 0.200 H
So, the voltage across the resistor vR = iR where R = resistance of resistor = 88.0 Ω
So, vR = iR = VL/ωL[1 - cos[ωt]] × R = (VL)R/ωL[1 - cos[ωt]]
= (0.123A)[1 - cos[(487rad/s)t]] × 88.0 Ω
= (10.84 V)[1 - cos[(487rad/s)t]]
b. vR at t = 2.00 ms = 0.002 s
So, vR = (10.84 V)[1 - cos[(487rad/s)(0.002)]]
= (10.84 V)[1 - cos[0.974]]
= (10.84 V)[1 - 0.9999]
= (10.84 V)(0.0001)
= 0.001084
= 1.084 mV
REEEEEEEEEEEEEEEEEE
Answer:
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In the pictire ,can we separate hydrogen (H) from oxygen (O)?
Paanswer nga po.....
A.)
Water is the name of the pure substance H₂O
B.)
Hydrogen and Oxygen are the compound of water
C.)
Yes, we can
D.)
This process known as Electrolysis
A car accelerates at a rate of 5.0 m/s2 when the engine supplies a net force of 5500 N. What is the mass of the car?
1100 kg
550 kg
2200 kg
27500 kg
Answer:
1100 kgExplanation:
The mass of the car can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{5500}{5} \\ [/tex]
We have the final answer as
1100 kgHope this helps you
Do you think there is a temperature at which sound cannot be heard?
Answer:
The definition would be defined in the clarification section downwards and according to the given question.
Explanation:
This would be considered a lapse of temperature. The rate of acceleration sometimes gradually decreases, because as the temperature is lowered through height. The latter suggests that perhaps the layer of water nearest to either the surface moves the quickest, as well as the layer of water and the furthest just above the surface, travels the fastest pace, with shock energy passing underground.The waves move and curve vertically as a consequence. This will create an area of the "shadow zone" where the sound couldn’t reach into. Although it could be possible to have seen the origin, a guy standing throughout the loss impairment may not remember the sound. The charged particles are refracted vertically and it's never going to reach the listener.If a 4N weight is hung on a spring, and it extends by 0.2m, what is the spring constant (k)?
Answer: 200 N/m
Explanation:
The Gravitational spring energy(Us) is equal to 1/2kx^2. So we have x as .2 m and Us as 4 N. So 4 N = 1/2 * k * .2^2. So now we solve for K and get 200 N/m.
Answer:
20 N/m
Explanation:
4/0.2 = 20 N/m
/ = divide
student measures the weight of a bag of bananas with a spring balance.
Describe what is inside a spring balance and explain how it works.
A spring balance measures the weight of an object by opposing the force of gravity acting with force of an extending spring. May be used to determine mass as well as weight by recalibrating the scale. Some spring balances are available in gram or kilogram markings and are used to measure the mass of an object. Spring balances consist of a cylindrical tube with a spring inside. One end (at the top) is fixed to an adjuster which can be used to calibrate the device. The other end is attached to a hook on which you can hang masses etc.
What is Hydroelectric energy used for? Use in your own words.
How much is the velocity of a body when it travels 600m in 5 minutes?
There are 60 minutes in an hour. Whatever distance a person crosses in 5 mins, he/she can cross 12 times that distance in 1 hour. So, in one hour the person could have crossed 12 X 600 = 7200 meters.
But, 1000 meters equal one kilometer. So, 7200m = 7.2 km. Thus, this person travels 7.2 km in one hour, and hence has a speed of 7.2 km/hr
Answer:
2m/s
Explanation:
V=S/t
v=distance ÷ time
v=600m. × 5mins
v=600/5 ×60
600/300
2m/s
If a dog has a mass of 2.5 kg, what is its weight and what is the normal force that it feels.
I
Answer:
Weight = normal force = 24.5 N
Explanation:
Given that,
Mass of a dog, m = 2.5 kg
We need to find its weight and the normal force that it feels.
The weight of an object is given by :
W = mg
Where g is the acceleration due to gravity
[tex]W=2.5\times 9.8\\\\=24.5\ N[/tex]
The normal force is balanced by the weight of an object. So,
Weight = normal force = 24.5 N
True or false. when objects collide , some momentum is lost
Answer:
It is neither false nor true. When they collide some of one of the objects goes to the other object.
Explanation:
Answer: True
Explanation:
A relaxed spring of length 0.15 m stands vertically on the floor; its stiffness is 1070 N/m. You release a block of mass 0.5 kg from rest, with the bottom of the block 0.6 m above the floor and straight above the spring. How long is the spring when the block comes momentarily to rest on the compressed spring?
Answer:
x' = 0.085 m = 8.5 cm
Explanation:
The law of conservation of energy says that:
Potential Energy Stored in Spring = Loss in Gravitational Potential Energy of Block
(1/2)kΔx² = mgh
where,
k = stiffness of spring = 1070 N/m
Δx = change in length of spring = ?
m = mass of block = 0.5 kg
g = 9.8 m/s²
h = height of block above spring = 0.6 m - 0.15 m = 0.45 m
Therefore,
(1/2)(1070 N/m)Δx² = (0.5 kg)(9.8 m/s²)(0.45 m)
Δx = √[2(2.205 Nm)/(1070 N/m)]
Δx = 0.064 m
but,
Δx = x - x' = 0.15 m - x' = 0.064 m
x' = 0.15 m - 0.064 m
x' = 0.085 m = 8.5 cm
A jogger runs north 6 km, 5 km east, and 4 km north again. Time is 1.9 hr. What is average velocity?
Answer:
Average velocity = 5.9 km/ hr (or 1.64 m/s).
Explanation:
Velocity = [tex]\frac{displacement}{time}[/tex]
It is a vector quantity and has an SI unit of m/s.
Displacement = [tex]\sqrt{x^{2} + y^{2} }[/tex]
x = 5 km east
y = 6 km north + 4 km north
= 10 km north
So that,
Displacement = [tex]\sqrt{5^{2} + 10^{2} }[/tex]
= [tex]\sqrt{25 + 100}[/tex]
= [tex]\sqrt{125}[/tex]
= 11.1803
Displacement = 11.18 km = 11180 m
Time = 1.9 hr = 6840 seconds
Average velocity = [tex]\frac{11.180}{1.9}[/tex]
= 5.8842
Average velocity = 5.9 km/ hr
The average velocity is 5.9 km/ hr (or 1.64 m/s).
a current of 200mA through a conductor converts 40 joules of electrical energy into heat in 30 seconds determine the potential drop across the conductor
Answer:
V = 6.65 [volt]
Explanation:
We must first find the power generated, power is defined as the amount of energy consumed or generated in a given time.
[tex]P=\frac{E}{t}[/tex]
where:
P = power [w]
E = energy = 40 [J]
t = time = 30 [s]
[tex]P =40/30\\P = 1.33[w][/tex]
Now we can calculate the voltage or potential drop by means of the power, the power is calculated by means of the product of the voltage by the current.
[tex]P =V*I[/tex]
where:
V = voltage [volts]
I = current = 200mA = 0.2 [A]
[tex]V = P/I\\V = 1.33/0.2\\V = 6.65 [Volt][/tex]
Two objects attract each other with a gravitational force of magnitude 1.01 10-8 N when separated by 19.9 cm. If the total mass of the two objects is 5.11 kg, what is the mass of each?
Answer:
m₂ = 1.17 kg
Explanation:
Given that,
Force between two objects, [tex]F=1.01\times 10^{-8}\ N[/tex]
Mass of object 1, [tex]m_1=5.11\ kg[/tex]
Distance between masses, r = 19.9 cm = 0.199 m
The gravitational force between two masses is given by :
[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex]
m₂ is the mass of object 2
[tex]m_2=\dfrac{Fr^2}{Gm_1}\\\\m_2=\dfrac{1.01\times 10^{-8}\times (0.199)^2}{6.67\times 10^{-11}\times 5.11}\\\\=1.17\ kg[/tex]
So, the mass of second object is 1.17 kg.
During the stretching routine who used the medicine ball for support.
The guy
The guy
The Girl
The Girl
Both people used a ball for support
Both people used a ball for support
No one used it
No one used it
3. If the bus stop is 0.68 km down the street from the museum and it takes
you 9.5 min to walk north from the bus stop to the museum entrance,
what is your average velocity?
Answer:
0.07km/minExplanation:
Step one:
given data
distance between museum and bus top= 0.68km
time taken to walk from the bus stop to the museum = 9.5min
Required
The average velocity is defined as the rate at which you are moving
The expression for the average velocity is
Average velocity = distance/time taken
Average velocity= 0.68km/9.5
Average velocity= 0.07km/min
Hence your average velocity is 0.07km/min
A ball is thrown vertically upward with an initial velocity of 23 m/s. What are its position and velocity after 2 s?
Answer:
The position of the ball after 2 s is 26.4 mThe velocity of the ball after 2 s is 3.4 m/sExplanation:
Given;
initial velocity of the ball, u = 23 m/s
time of motion, t = 2 s
The position of the ball after 2 s is given by;
h = ut - ¹/₂gt²
h = (23 x 2) - ¹/₂ x 9.8 x 2²
h = 46 - 19.6
h = 26.4 m
The velocity of the ball after 2 s is given by;
v² = u² + 2(-g)h
v² = u² - 2gh
v² = 23² - (2 x 9.8 x 26.4)
v² = 529 - 517.44
v² = 11.56
v = √11.56
v = 3.4 m/s
1. How far away must you be from a 675 kHz radio station with power 50.0 kW for there to be only one photon per second per square meter? Assume no reflections or absorption, as if you were in deep outer space. 2. Discuss the implications for detecting intelligent life in other solar systems by detecting their radio broadcasts.
a) 0.321 ly
b) 0.321 light years is not far in astronomical terms. Alien life would need to transmit at tremendous power in order for their radio transmissions to be detectable. Their radio signal also needs to be stronger than background noise in order to be distinguishable. Therefore it is unlikely that radio transmissions from alien life will ever be detected.
How does increasing the width of a wire affect a circuit?
A. It restricts the flow of electrons.
B. It reduces the voltage
C. It allows electrons to flow more easily
D. It increases the resistance
Whoever gets this right I’ll give brainliest. Be sure that the answer is right. I’d love a explanation too if you could include one.
Answer:
The resistance of a wire decreases with increasing thickness.
Explanation:
Hope this helped!
Answer: C it allows electrons to flow more easily
Explanation:i got it right i hope this helps you
Is Solar Energy renewable? Why or why not? Use in your own words.
Answer:
Solar energy is renewable.
Explanation:
If something is renewable, it is generated faster than it can be reasonably used or won't run out for longer than it would be used. Solar falls into the latter category. Using solar panels won't deplete the sun and the sun will likely be around for much longer than we will.
A small block of mass m1 = 0.4 kg is placed on a long slab of mass m2 = 2.8 kg. Initially, the slab is stationary and the block moves at a speed of vo = 3 m/s. The coefficient of kinetic friction between the block and the slab is 0.15 and there is no friction between the slab and the surface on which it moves.
Determine the speed v1.
Determine the distance traveled by the slab before it reaches the speed v1.
Answer:
v₁ = 0.375 m / s , x = 0.335 m
Explanation:
Let's analyze this interesting exercise, the block moves and has a friction force with the tile, we assume that the speed of the block is constant, so the friction force opposes the block movement. For the only force that acts (action and reaction) this friction force exerted by the block that is in the direction of movement of the tile.
We can also see that the isolated system formed by the block and the tile will reach a stable speed where friction cannot give the system more energy, this speed can be found by treating the system with the conservation of linear momentum.
initial moment. Right at the start of the movement
p₀ = m v₀ + 0
final moment. Just when it comes to equilibrium
[tex]p_{f}[/tex] = (m + M) v₁
how the forces are internal
p₀ =p_{f}
m v₀ = (m + M) v₁
v₁ = m /m+M v₀
let's calculate
v₁ = 0.4 /(0.4 + 2.8) 3
v₁ = 0.375 m / s
Let's apply Newton's second law to the Block, to find the friction force
Y axis
N - W = 0
N = W
N = m g
where m is the mass of the block
the friction force has the formula
fr = μ N
fr = μ m g
We apply Newton's second law to slab
X axis
fr = M a
where M is the mass of the slab
μ m g = M a
a = μ g m / M
let's calculate
a = 0.15 9.8 0.4 / 2.8
a = 0.21 m / s²
With kinematics we can find the position
v²= v₀²+2 a x
as the slab is initially at rest, its initial velocity is zero
v² = 2 a x
x = v2 / 2a
let's calculate
x = 0.375²/2 0.21
x = 0.335 m
Why are weathering, erosion and deposition a NECESSARY process in the rock cycle?
ANSWER THIS NOW PLEASE! AND YOU GET 225 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
YESS well it is partly nessary but it depends on the situation
Explanation:
Answer:
Weathering, erosion, and deposistion are necessary processes in the rock cycle because:
Explanation:
First, start with igneous rocks. magma erupts (Extrusive igneous rocks) or solidifies in the sub-surface of the earth (Intrusive igneous rock). when they are exposed Weathering and erosion occur which is a slow breakdown of rock through the wind, water, or other processes. The weathered pieces (sediments) move to other places by wind or water and get deposited someplace else. When there are enough sediments and there is overburden pressure on these sediments, they become a sedimentary rock. Due to overburden pressure, they become metamorphic rocks. now the thing to understand here is that when metamorphic rocks are exposed, they too undergo weathering and erosion and their pieces also become sedimentary rocks.
Lisa throws a stone horizontally from the roof edge of a 50 meter high dormitory. It hits the ground at a point 60 m from the building. Find the time of flight.
Answer:
Explanation:
Time of flight is the time of takes to hit the ground
Given
Height H = 50m
Acceleration due to gravity g = 9.8m/s³
Using the equation of motion;
S = ut+1/2gt²
u = 0m/s
Substitute and get time t
50 = 0(t)+1/2(9.8)t²
50 = 4.9t²
t² = 50/4.9
t² = 10.204
t = √10.204
t = 3.19secs
Hence the time of flight is 3.19secs
a 1000kg car uses a breaking force of 10,000N to stop in two second. What is the change in momentum of the car?
Answer:
ΔP = 20000 N s
Explanation:
To solve this problem we use the relation between momentum and moment
I = Δp
let's calculate the momentum
I = ∫F dt
if we use the average force
I = F t
I = 10000 2
I = 20000 N s
therefore with the first equation
ΔP = I = 20000 N s
An ant is crawling along a yardstick that is pointed with the O-inch mark to the east and the 36-Inch mark to the west. It starts at the 19-inch mark, crawls to the 27-inch
mark, then moves to the 7-inch mark. What was the total distance the ant traveled?
Answer:
33 Inches
Explanation:
The movement of the ant is sketched in the attached image. The ant moved from the 19-inch mark to 27-inch mark covering a distance of 13 Inches (27 - 19). Finally, it moved from the 27-inch mark to 7-inch mark covering a distance of 20 Inches (27 - 7).
Total Distance covered = 13 + 20 = 33 Inches.
Hence, the total distance the ant traveled is 33 Inches.
While traveling North along a highway a driver slows from 25 m/s to 15 m/s in 12 seconds. What is the
automobile's acceleration?
Answer:
- 0.8333 m/s^2
Explanation:
the equation for calculating acceleration that I have used is
(V2-V1)/t
where V2 is the final recorded velocity and V1 is the initial velocity and t is the duration of the acceleration.
which you plug the numbers in (15 - 25)/12 = 10/12 and because you are slowing down, it should be negative
I am in highschool honors physics so I am not college leveled, I might be wrong but I hope this is useful,