The amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is 8350 J.
Amount of heat requiredThe amount of heat required to change 25 g of −30°C ice into 0°C liquid water is calculated as follows;
Q = mLf
where;
m is mass of the iceLf is latent heat of fusionQ = 25 x 334
Q = 8350
Thus, the amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is 8350 J.
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Answer:
The amount of energy needed to change 25 g of −30°C ice into 0°C liquid water is 9,887.5 J.
What is the difference between molecules and
compounds?
Answer:
All compounds can be classified as molecules, but not all molecules can be called compounds. Molecules are formed by two or more atoms that are bonded by chemical bonding's. Compounds are constructed by two or more elements where the elements are mixed in fixed ratios.
Answer:
Molecules are formed by two or more atoms that are bonded by chemical bondings.
Compounds are constructed by two or more elements where the elements are mixed in fixed ratios
*All compounds can be classified as molecules, but not all molecules can be called compounds.
Explanation:
pls brainliest if you don't mind
anyway i hope this helped have an awesome day bye byee
What does acid rain look like so that anyone can recognize it?
3. A wooden block is at rest on a wooden inclined
plane. As the angle the plane makes with the
horizontal is increased, the magnitude of the
force of static friction between the block and
the plane
(1) decreases
(2) increases
(3) remains the same
As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases
Static frictional forceSince the static frictional force between the block and the plane is given by F = μN where
μ = coefficient of static friction and N = normal force on plane = component of weight of block perpendicular to the plane = Wcosθ where W = weight of block and θ = angle of inclined planeNow, F = μN
F = μWcosθ
Since μ and W are constant, we see that
F ∝ cosθ and cosθ ∝ θ
So, F ∝ θ
Since the static frictional force is directly proportional to the angle the plane makes with the horizontal, when the angle the plane makes with the horizontal is increased, the static friction between the block and the plane increases.
So, As the angle the plane makes with the horizontal is increased, the magnitude of the force of static friction between the block and the plane (2) increases
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3) A square coil of sides 0.40 m carries a current of 3.0 A in a uniform magnetic field of 5.0 mT. the plane of the coil is parallel to the magnetic field as shown in figure below.
a) Calculate the force on each side of the coil.
b) What is the resultant effect of the force on the coil?
c) What happen to the coil?
Really need help! ;(
Could you please explain it? :)
GIVING 10 POINTS
Answer:b
Explanation: If you look at the line on the graph, you can see that it is going downward, meaning it has a negative slope, and choice b is the only one that has a negative slope
Which statement describes the density of the inner planets?
All the inner planets are dense.
The inner planets are less dense than the outer planets.
Earth is dense, while the other inner planets are not.
Mercury and Venus are dense, while Earth and Mars are no
Answer:
The inner planets are less dense than the outer planets
Please brainliest my answer iam begging you for god sake
Answer:
The inner planets are less dense than the outer planets .
Explanation:
Please Mark Me As a brainliestpysics question can anyone answer me this question
Answer:
Im pretty sure they're equal, i could be wrong though. Hope i helped have an amazing day :D
Explanation:
Answer:
B: equal
Explanation:
A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.
d. At what angle do the cars move after the collision? (2 points)
Given :-
A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.To Find :-
At what angle do the cars move after the collision?Solution :-
Here it's given that a car of mass 1000kg moving with velocity of 25m/s North . Another car of mass 1200kg is moving with velocity 30m/s East.
So that ,
[tex]v_{1}= 25m/s \ E= 25 \hat{i} m/s [/tex]
And ,
[tex]v_{2}= 30m/s \ N = 30 \hat{j} m/s [/tex]
See attachment .
From Triangle law of vector addition , the resultant of both vectors will be given by third side of the triangle taken in opposite direction.
So , if the resultant velocity makes an angle [tex]\theta[/tex] . Then ,
[tex] tan\theta = \dfrac{v_2}{v_1} [/tex]
Substituting the respective values,
[tex]tan\theta =\dfrac{30m/s}{25m/s} [/tex]
Simplify ,
[tex]tan\theta =\dfrac{6}{5}[/tex]
Take arctan both sides ,
[tex]\theta = tan^{-1}\bigg(\dfrac{6}{5}\bigg)[/tex]
Hence the cars move at an angle of tan-¹(6/5) NE after the collision .
If each pull-up requires 300 J and Ben does a pull-up in 2 seconds, what is his power? 150 watts 300 watts 600 watts 750 watts
Answer:
150 watts
Explanation:
300/2 = 150 watts
Answer:
150 watts
Explanation:
The explanation is in the picture
PLEASE MARK BRAINLIEST
according to Newton's second law of motion. what is force product
Answer:
Force can be defined as the product of mass and acceleration.
Explanation:
~Cornasha_Weeb
A copper wire has a diameter of 1.947 mm. What magnitude current flows when the drift velocity is 1.79 mm/s
Answer:
72.5 A
Explanation:
There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.
V = πr²h . . . . . volume of a cylinder
V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s
Then the charge flow rate is ...
(13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s
The magnitude of the current is about 72.5 amperes.
______
Additional comment
The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.
Peak expiratory flow readings are Higher in the morning; lower in the evening Lower when patients are well; higher when patient's airway is constricted Lower in the morning; higher in the evening Higher when patients are well; lower when patient's airway is constricted
Peak expiratory flow readings are higher when patients are well, but lower when a patient's airway is constricted.
What is the peak expiratory flow?This term is used in medicine to refer to the maximum rate of a person's exhalation or to how fast and how long can they exhale.
This rate is measured by using the peak expiratory flow test that requires you to deeply inhale and then exhale as fast as hard as possible.
What does the peak expiratory flow indicate?This rate is closely related to the amount of air flowing out of the lungs. This implies the peak expiratory flow is lower if there is a disease such as asthma that can constrict the airways.
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Acar accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is
meters/second?
To understand this question, you need to understand the concept of acceleration first. Have you ever been in a car and noticed that it was getting faster and faster? That "speeding up" of the car is known as acceleration! Acceleration is essentially the rate at which you speed up.
Okay, so we now know what acceleration is. What are its units? The unit of acceleration is the change in velocity over a period of time: [tex]\frac{∆v}{t}[/tex]
If you haven't learned about velocity yet, just think about it as speed for now. The funny-looking triangle, ∆, is a symbol for "the change of." For example, if I started walking at 3 [tex]\frac{feet}{second}[/tex] then sped up to 5 [tex]\frac{feet}{second}[/tex], then the change in my speed would be 2 [tex]\frac{feet}{second}[/tex], because I started walking 2 [tex]\frac{feet}{second}[/tex] faster!
Okay, enough with all the explanations. Hopefully, you understand the units now. Let's take a look at the question. A car accelerates from 4 [tex]\frac{meters}{second}[/tex] to 16 [tex]\frac{meters}{second}[/tex] in 4 seconds. What would the acceleration be? Let's set up an equation:
a = [tex]\frac{∆v}{t}[/tex]
a is the acceleration, ∆v is the change in velocity, and t is the time elapsed.
Now, let's plug in our values! ∆v is the change in velocity, and to find that we simply have to subtract 16 [tex]\frac{meters}{second}[/tex] by 4 [tex]\frac{meters}{second}[/tex]. That makes sense, right? Back to the equation.
a = [tex]\frac{∆v}{t}[/tex]
a = [tex]\frac{16-4}{4}[/tex]
(16 - 4 is the change in velocity, and 4 is the number of seconds the car was accelerating)
a = [tex]\frac{12}{4}[/tex]
a = 3 ([tex]\frac{meters}{second^{2}}[/tex])
We have our answer! The car's acceleration is 3 meters per second^{2}.
(You might be thinking: Wait. Meters per second squared? The reason for that is because acceleration is the rate at which the speed increases! That makes the unit [tex]\frac{\frac{meters}{second}}{second}[/tex], which can be simplified down to [tex]\frac{meters}{second^{2} }[/tex])
Let me know if you need clarification on anything I explained here!
- breezyツ
Why do charged particles interact with each other?(1 point)
because they are small
because they are small
because they are in the same molecule
because they are in the same molecule
because of their electric and magnetic fields
because of their electric and magnetic fields
because they have opposite charges
Answer:
because they have opposite charges
Explanation:
If you're talking about magnetism and electricity, the laws are that like charges attact and and unlike charges repel.
Charged particles interact with each other because they have opposite charges.
How charged particles interact with each other?When charged particles are close to each other, their electric fields interact. So particles with opposite charges attract each other whereas particles with similar charges repel each other.
So we can conclude that Charged particles interact with each other because they have opposite charges.
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Activity 5: My FB (Faulty Block)
Directions: Given the illustration of the fault blocks below, draw how it looks like
after acted upon by stress forces. Draw the direction of forces acting on each type
of stress force in the fault blocks and identify the type of stress acting on the
block.
7 principles of Exercise and Sports Training
Answer: individuality, specificity, progression, overload, adaptation, recovery, and reversibility.
Explanation:
individuality, specificity, progression, overload, adaptation, recovery, and reversibility.
Answer:
1. individuality
2. specificity
3. overload
4. adaptation
5. recovery
6. reversibility
7. progression
Explanation:
I learned this last year.
what is the relationship between distance, average speed and time
Answer:
average speed= total distance/total time
Explanation:
Related to the distance traveled by the object which means, it is only represented by the magnitude and direction of travel is not important. so average speed= total distance/total time
What is the speed of the plane wave defined by sin(ωt−kx) with ω=3376.7 Thz and k=11.79μm−1?
The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s
Speed of a wavethe speed of the plane wave defined by sin(ωt−kx) is v = ω/k where
ω = angular frequency of wave and k = wave number of waveNow ω = 3376.7 Thz = 3376.7 × 10¹² Hz and k = 11.79μm⁻¹ = 11.79 × 10⁶ m⁻¹
So, substituting the values of the variables into v, we have
v = ω/k
v = 3376.7 × 10¹² Hz/11.79 × 10⁶ m⁻¹
v = 286.4 × 10⁶ m/s
v = 2.864 × 10⁸ m/s
The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s
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3. An airplane travels at a speed of 600 km/h. How much time will it take to fly a distance of 3180 km to California
Answer:
5.3 hours
Explanation:
(3180 km) / (600 km/h) = 5.3 hours
the nuclues of an atom contains which subatomic particles
A 200g ball is accelerated from 5m/s to 25m/s in 0.3sec. What force was applied?
Answer:
30N
Explanation:
30N of force was applied
quizlet
i’m kinda stuck right now…
A football is kicked at ground level with a speed of 18.0 m/s at an angle of 31.0 to the horizontal. How much longer does it hit the ground?
HITLOW
SS
1/6
A5 kg body is having a Kinetic energy of 250 J. What is the velocity of the body?
15 m/s
20 m/s
40 m/s
10 m/s
ME
Answer:
10 m/s
Explanation:
KE = 1/2 • m • v^2
250 J = 1/2 • 5 kg • v^2
(2 • 250 J / 5 kg )^1/2 = v
(100)^1/2 = v
10 = v
Alkali Metals • Most ___________________ metals
Answer: They’re the most reactive metals
Explanation: They have larger ionic radii and low ionization energies
compare your previous result to the present hrf result are there any changes if yes explain your answer
Answer:
I don't know what are you saying but I don't have any results
Explanation:
[tex]kai6417[/tex]
A ball is placed at the top of a hill then released. After 5 seconds it has a speed of 20 m/s. What is the average acceleration of the ball
Answer:2
Explanation:When the ball is released from the top of the hill then it's initial velocity (u)=0 And it's final velocity will be after 5 second (v)=2.
Answer:
Explanation:
a ball is placed at the top of the hill and then released after five seconds and has a speed of 20 m/s. What is the average acceleration of the ball?
Two dwarf galaxies revolve in circles around a normal large galaxy. Dwarf Galaxy A is 70,000 light years away from the large galaxy, and Dwarf Galaxy B is 500,000 ly away from the large galaxy. Which of the two galaxies, A or B, takes the longest time to orbit the large galaxy and what law tell us so
Answer:
B
Explanation:
From Kepler's Third Law, T^2 is proportional to r^3.
Now r of B is larger than r of A,
so T of B is larger than T of A.
Then B takes the longest time.
Dwarf Galaxy B takes the longest time to orbit the large galaxy. This can be explained using Kepler's Third Law of Planetary Motion, also known as the Law of Periods.
Kepler's Third Law states that the square of the orbital period (T) of a celestial body is directly proportional to the cube of the semi-major axis (a) of its elliptical orbit. Mathematically, it can be expressed as:
[tex]\[ T^2 \propto a^3 \][/tex]
Where:
T is the orbital period (time taken for one complete orbit), and
a is the semi-major axis of the elliptical orbit.
In the case of dwarf galaxies A and B revolving around the large galaxy, we can use the distances from the large galaxy to each of the dwarf galaxies as the semi-major axes (a) of their orbits.
Let's compare the values of [tex]\( a^3 \)[/tex] for the two dwarf galaxies:
For Dwarf Galaxy A:
[tex]\( a_{\text{A}} = 70,000 \)[/tex] light years
For Dwarf Galaxy B:
[tex]\( a_{\text{B}} = 500,000 \)[/tex] light years
Now, let's calculate [tex]\( a^3 \)[/tex] for each galaxy:
For Dwarf Galaxy A:
[tex]\( a_{\text{A}}^3 = (70,000)^3 = 343,000,000,000 \)[/tex] cubic light years
For Dwarf Galaxy B:
[tex]\( a_{\text{B}}^3 = (500,000)^3 = 125,000,000,000,000,000 \)[/tex] cubic light years
Since [tex]\( a_{\text{B}}^3 \)[/tex] is significantly larger than [tex]\( a_{\text{A}}^3 \)[/tex], it means that Dwarf Galaxy B has a larger a value and therefore a longer orbital period according to Kepler's Third Law. In other words, Dwarf Galaxy B takes the longest time to orbit the large galaxy.
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Can you please help me with this one
oh ok where is it bring it
The net force on an object is
Answer:
Net Force. when all combinations of force acting on an object. Force. A push or pull
So it's the third answer
( the combination of all forces acting on it )