The closest distance or the number of miles Teri ran is equal to 5 miles.
What is the unitary method ?
The unitary method is a method in which you find the value of one unit and then the value of required no. of units.
It is given that Teri ran 8 kilometers.
It is also given that , 1 mile is approximately equal to 1.6 kilometers.
This is a question of unitary method. We know that value of one unit is given as 1 mile is equal to 1.6 kilometers approximately. We know have to calculate the no. of miles Teri ran , by converting 8 kilometers to miles.
So ,
1 miles = 1.6 kilometers
This implies :
8 kilometers = 8 / 1.6 miles
or
8 kilometers = 5 miles
or
8 kilometers is approximately equal to 5 miles.
Therefore , the closest distance or the number of miles Teri ran is equal to 5 miles.
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AlgebraName1. If f(x) = 2x - 4, find each valdea)(3)b) f(x) = 9
Answer:
Step-by-step explanation:
Comment
The question is since f(x) really means y, then when y = 9 what's x?
Solution
y = 2x - 4
y = 9
9 = 2x - 4 Add 4 to both sides
9+4 = 2x Combine
13 = 2x Divide both sides by 2
13/2 = 2x/2
6.5 = x
Do you mean what is f(X) when x is 3. f(3) = 2x - 4. So what is y when x = 3
y = 2x - 4 Substitute 3 for x
y = 2*3 - 4 Combine
y = 6 - 4
y = 2
E Homework: HW 9.3Question 7, 9.3.17HWотFind the area of the shaded regionInside the square and between thetwo circles. Use x 3.1410 m10 mThe area of the shaded region is approximatelym?(Type an integer or decimal)
Area of shaded region = 168.56 [tex]m^2[/tex]
What is area of square and semicircle?
Area of square is the total space taken by the square.
If the side of square is a units, then area of square is calculated by
Area of square = [tex]a \times a[/tex] sq units
Area of semicircle is the total space taken by the semicircle
If the radius of semicircle is r units, then area of semicircle is calculated by
Area of semicircle = [tex]\frac{1}{2}\times \pi \times r^2[/tex] sq units
Here,
Side of square = 28 m
Area of square = [tex]28 \times 28 = 784 m^2[/tex]
Radius of circle = [tex]\frac{28}{2} = 14 m[/tex]
Area of two semicircles =
[tex]2 \times \pi \times r^2 \times \frac{1}{2}\\3.14 \times 14 \times 14\\615.44 m^2[/tex]
Area of shaded region = [tex](784 - 615.44) m^2[/tex]
= 168.56 [tex]m^2[/tex]
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Complete Question
The figure has been attached here.
Complete the following statement.a0
ANSWER
x = 10
EXPLANATION
We want to find the missing box in the statement given.
Let the box be represented by x:
[tex]x\text{ + (-7) = 3}[/tex]To solve this, move (-7) to the other side, the sign changes:
[tex]\begin{gathered} x\text{ = 3 + (+7)} \\ x\text{ = 3 + 7} \\ x\text{ = 10} \end{gathered}[/tex]The box is 10.
r-s for r=63 and s=9
54
Explanation
to figure out this, just replace the given values and evaluate
Step 1
[tex]r-s[/tex]let
r=63
s=9
now, replace
[tex]\begin{gathered} r-s \\ 63-9 \\ 54 \end{gathered}[/tex]so, the answer is 54
What is the answer to this or is the answer right
Answer:
(c) corresponding angles
Step-by-step explanation:
You want to know the description of the marked angles in the given diagram.
Interior anglesInterior angles are between the "parallel" lines. Angle 5 is interior, but angle 1 is not, so they cannot be described as interior angles.
Exterior anglesExterior angles are both outside the "parallel" lines. Angle 1 is exterior, but angle 5 is not, so they cannot be described as exterior angles.
Corresponding anglesCorresponding angles are both in the same direction from the point of intersection of the "parallel" lines with the transversal. Here, both angles 1 and 5 are "northwest" of the intersection point, so are corresponding angles.
Alternate anglesAlternate angles are on opposite sides of the transversal. Consecutive, or same-side, angles are on the same side of the transversal. Angles 1 and 5 are not alternate angles, as they are both on the same side of the transversal.
Determine the values of m and n in the polynomial 2x* + mx -x + n such that the binomial (x - 1) is a factor and that the remainder when divided by (x + 2) is -18.
The remainder theorem of polynomials states: if a polynomial p(x) is divided by a binomial (x - a), the remainder obtained is p(a).
In this case, the polynomial is:
[tex]p(x)=2x^4+mx^3-x^2+n[/tex]Applying the remainder theorem p(-2) = -18, that is:
[tex]\begin{gathered} p(-2)=2\cdot(-2)^4+m\cdot(-2)^3-(-2)^2+n \\ -18=2\cdot16+m\cdot(-8)-4+n \\ -18=32-8m-4+n \\ -18-32+4=-8m+n \\ -46=-8m+n\text{ (eq. 1)} \end{gathered}[/tex]Given that (x - 1) is a factor, then p(1) = 0, that is:
[tex]\begin{gathered} p(1)=2\cdot1^4+m\cdot1^3-1^2+n \\ 0=2+m-1+n \\ -2+1=m+n \\ -1=m+n\text{ (eq. 2)} \end{gathered}[/tex]Now, we have a system of 2 equations and 2 variables: m and n. Subtracting equation 2 to equation 1, we get:
-8m + n = -46
-
m + n = -1
------------------------
-9m = -45
m = (-45)/(-9)
m = 5
Substituting this result into equation 2, we get:
5 + n = -1
n = -1 - 5
n = -6
In this figure, lines a and B are intersected by Line T. Which of these statements proves that lines A and B are parallel
Correct answer is C, For the given figure, ∠2 = ∠3, as they are corresponding angles of parallel lines.
What are corresponding angles?The angles created when a transversal intersects two parallel lines are known as corresponding angles.
Typical examples of equivalent angles include opening and closing a lunchbox, resolving a Rubik's cube, and endless parallel railroad tracks.
Two congruent or identical triangles' corresponding angles are those of a congruent pair of their sides in a triangle. As a result, these angles are equivalent or have the same value.
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Complete Question -
In the figure, lines a and b are intersected by line t. Which of these statements proves that lines a and
b are parallel?
∠1 and ∠2 are supplementary∠1 and ∠3 are supplementary∠2 = ∠3∠1 = ∠2Determine whether the relation defines a function, and give the domain and range.{(-8, 7),(4.7).(-9, 1);
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Define when a relation defines a function
A function is a relation which describes that there should be only one output for each input (or) we can say that a special kind of relation (a set of ordered pairs), which follows a rule i.e., every X-value should be associated with only one y-value is called a function.
The domain is the set of all first elements of the ordered pairs. The range on the other hand is the set of all second elements of the ordered pairs.
Since every x-values of the given relation is associated with only one y-value, therefore it defines a function.
The domain is given as:
[tex]\lbrace-8,4,-9\rbrace[/tex]The range is given as:
[tex]\lbrace7,7,1\rbrace[/tex]An error has been made in subtracting the polynomials as shown in the student work. What error has the student made, (Ignore the response I wrote and write a new one).
In carrying out the subtraction:
[tex](6x^2-4x-5)-(3x^2-7x+2)[/tex]We observe that:
[tex]\begin{gathered} 6x^2-3x^2=3x^2 \\ -4x-(-7x)=3x\text{ and }-4x+(-7x)=-11x \\ -5-(2)=-7\text{ and }-5+(2)=-3 \\ \end{gathered}[/tex]We observe that the student added two of the terms instead of subtracting. This was the error in the students' work.
Help plssssssssssssssssssssssssssssssss
Answer: [tex]y=-2x+3[/tex]
Step-by-step explanation:
Perpendicular lines have slopes that are negative reciprocal slopes, so the slope of the line we want to find is -2.
The y-intercept is given to be 3, so the equation is [tex]y=-2x+3[/tex].
Let g(x)=x^2-64 and h(x)=root(8x+512). Find each combination and state its domain. 1. (h/g)(x)(Number one has a fraction) 2. (h・g)(x)3. (g・h)(x)Show work please!
Given the functions:
[tex]\begin{gathered} g(x)=x^2-64 \\ h(x)=\sqrt[]{8x+512} \end{gathered}[/tex]1. (h/g)(x)
[tex](\frac{h}{g})(x)=\frac{h(x)}{g(x)},\text{ g(x)}\ne0[/tex]We substitute the functions and solve:
[tex](\frac{h}{g})(x)=\frac{\sqrt[]{8x+512}}{x^2-64}[/tex]Factor the common term 8:
[tex]=\frac{\sqrt[]{8(x+64)}}{x^2-64}[/tex]And we have:
[tex]\begin{gathered} x^2-64\ne0 \\ x^2-64+64\ne0+64 \\ x^2\ne64 \\ x\ne8\text{ and x}\ne-8 \end{gathered}[/tex]13. Nick is five years older than Will. The sum of their ages is 21. How old is Nick? Solve algebraically.
Answer:
Nick = 13 years old.
Step-by-step explanation:
Define the variables:
Let n = the age of Nick (in years).Let w = the age of Will (in years).Given:
Nick is 5 years older than Will.The sum of their ages is 21.Create a system of equations with the given information and defined variables:
[tex]\begin{cases} w=n-5\\n+w=21\end{cases}[/tex]
Substitute the first equation into the second equation and solve for n:
[tex]\implies n+(n-5)=21[/tex]
[tex]\implies 2n-5=21[/tex]
[tex]\implies 2n-5+5=21+5[/tex]
[tex]\implies 2n=26[/tex]
[tex]\implies 2n \div 2=26 \div 2[/tex]
[tex]\implies n=13[/tex]
Therefore, Nick is 13 years old.
To find the age of Will, simply substitute the found value of n into the first equation and solve for w:
[tex]\implies w=13-5[/tex]
[tex]\implies w=8[/tex]
Therefore, Will is 8 years old.
I'll give brainliest!
The numbers written in correct scientific notation format are-
7 x 10⁻⁹
3 x 10⁻⁶
0.1 x 10⁻⁸
What is Scientific Notation?Scientific notation is a techniques of writing a large number or small number in a simple form. It involves expressing a number by the multiplication of 10 raise to the specific exponent.
Given are the set of numbers.
In order to classify the given numbers based on the correct syntax of scientific notation, it is necessary to understand the rules for writing the correct syntax.
The base to which exponent is raised should always be 10.The exponent should be a non-zero integer. (It can be both positive or negative integer)The absolute value of the coefficient is greater than or equal to 1 but it should be less than 10Based on the above rules, we can classify the correct scientific notation as -
7 x 10⁻⁹
3 x 10⁻⁶
0.1 x 10⁻⁸
Therefore, the numbers written in correct scientific notation format are-
7 x 10⁻⁹
3 x 10⁻⁶
0.1 x 10⁻⁸
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Suppose you deposit $10,000 in an account for 8 years at the annual interest rate 3%.
a. What would be the ending account balance if the interest is compounded by monthly?
b. What would be the ending account balance if the interest is compounded daily?
c. What would be the ending account balance if the interest is continuously compounded?
d. What are the graphs of (a), (b) and (c)?
e. Are these three answers similar? Why or not why?
For the ending account balances, these are the solution
a. The ending account if it is compounded monthly is $12,708.68
b. If it is compounded daily = $12712.374
c. If it is continuous = $12712.49
d. The graphs are in the attachment
e. The answers are not similar
How to solve for the ending account balancesThis is the data that we can use to solve the problem
Principal = $10000
Time = 8 years
Rate = 3 percent
The ending balance when compounded monthly
= number of months n
= 12
A = P (1 + r/n)^nt
= 10000 (1 + 0.03/12)⁸*¹²
= 10000 (1.0025)⁹⁶
= 100000 X 1.270868
= 12,708.68
The amount that would be the ending account if it is compounded monthly is $12,708.68
b. If it is compounded daily
total number of days in a year n = 365
10000 (1 + 0.03/365)⁸*³⁶⁵
10000 x 1.2712374
= $12712.374
c. The endind account if the interest is compounding continuously
[tex]A = Pe^r^t\\\\A = 10000 *e ^0^.^0^3^*^8[/tex]
= $12712.49
e. The answers are not similar here due to the fact that all of the accounting periods that we used are not the same for the problems that we have here.
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given the Venn diagram below what is the probability that both event A and B will occur
the probability of both is the one they share
[tex]0.2[/tex]Find the length of the side labeled x. Step by step.
Answer: 72.4
Step-by-step explanation:
soh-cah-toa
cos(25)= adjacent/hypotenuse
cos(25)= adjacent/48
adjacent= 48 * cos(25)
tan(59) = opposite/adjacent
tan(59) = x / 48 * cos(25)
x = 72.4
There is a mound of g pounds of gravel in a quarry. Throughout the
day, 400 pounds of gravel is added to the mound. Two orders of 600 pounds are sold and the gravel is removed from
the mound. At the end of the day, the mound has 1,200 pounds of gravel.
There is a mound of 2000 pounds of gravel in a quarry
Quantity of gravel added in the mound throughout the day = 400 pounds
Quantity of orders sold from the mound = 600*2 = 1200 pounds
Quantity of gravel left in the mound at the end of the day = 1200 pounds
Let g represent the pounds of gravel in the quarry
Formulating the equation we get the following:
Mounds of gravel in the quarry + Gravel added in the mound - Gravel sold from the mound = Gravel left at the end of the day
g + 400 - 600(2) = 1200
g + 400 - 1200 = 1200
g = 2000
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12. Sarah Steenburgh rented a car for seven days at $49.95 per day with unlimited mileage. In
Steenburgh's state, because she already has automobile insurance for her own car, she is
covered for the rental car. She drove 2,465 miles and paid $162.38 in gasoline. How much
did the rental car cost per mile to the nearest cent?
a. $0.19
b. $0.21
c. $0.23
d. $0.25
Answer:
b. $0.21
Step-by-step explanation:
(7·49.95 + 162.38)/2465 = 0.2077
Suppose that there are 150,000,000 people in Yourtown. And, suppose that Yourtown uses 310 × 109cubic meters of water per year. What is the amount of water (in cubic meters) used per person each year in Yourtown?
Given:
The number of people = 150,000,000.
The amount of water used in town = 310 × 109 cubic meters.
Required:
We need to find the amount of water (in cubic meters) used per person each year.
Explanation:
[tex]The\text{ amount of water used per person =}\frac{The\text{ amount of water used}}{The\text{ number of people}}[/tex]Substitute the number of people = 150,000,000 and the amount of water used in town = 310 × 109 cubic meters in the equation.
[tex]The\text{ amount of water used per person =}\frac{310\times109}{150000000}[/tex][tex]The\text{ amount of water used per person =}\frac{33790}{150000000}[/tex][tex]The\text{ amount of water used per person =}\frac{3379}{15000000}[/tex][tex]The\text{ amount of water used per person =}0.000225267\text{ cubic meters}[/tex]Final answer:
[tex]The\text{ amount of water used per person =}0.000225267\text{ cubic meters}[/tex]Use the drawing tools to form the correct answer on the graph.
Draw a point that belongs to the solution region of this system of inequalities.
y > 1.5x + 4
y < 2/3x + 4
A point that belongs to the solution region of this system of inequalities is (0, 4).
What is an inequality?An inequality can be defined as a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following arguments (symbols):
Greater than (>).Less than (<).Greater than or equal to (≥).Less than or equal to (≤).What is a graph?A graph refers a type of chart that's generally used to graphically represent data points on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.
In this scenario, a graph which represent the solution to the given system of inequalities is shown in the image attached below.
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what is a word problem for [tex]18 \div 6[/tex]
Given the expression:
[tex]18\div6[/tex]The answer = 3
The word problem for the given expression will be:
What is the 18 divided by 6?
What’s the correct answer answer asap for brainlist
Answer: Europe quit buying crops which left the united states with a surplus of crops
hope i helped
Step-by-step explanation:
Pythagorean Theorem
Find the length of the third side, write in simplest radical form if needed.
Using Pythagoras's theorem, the length of the third side of the right triangle is 3 units.
How to find the side of a right triangle using Pythagoras's theorem?The length of the third side of the right triangle can be found using Pythagoras's theorem.
The Pythagoras's theorem can be represented as follows:
c² = a² + b²
where
a and b are the legsc is the hypotenuse of the right triangleTherefore, the missing side of the right triangle is the other legs.
b² = (3√5)² - 6²
b² = 45 - 36
b = √9
b = 3
Therefore,
third side of the right triangle = 3 units
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By using Pythagoras' theorem the length of the third side is 3 units
What is Pythagoras's theorem?In a right-angled triangle, the sum of the squares of the smaller two sides of a right-angle triangle is equal to the square of the largest side.
Given, the hypotenuse is 3√5 units and one of the legs is 6 units and assuming the length is x units.
∴ x² = (3√5)² - 6².
x² = 9×5 - 36.
x² = 45 - 36.
x² = 9.
x = ± 3.
As length can not be negative the appropriate value for x is + 3.
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y = x ^ 2 + 2x - 24 i need to know the points at the x-intercept ( , ) and ( , ) points at the y intercept: ( , )and i’d it’s a min or max
Question : the function in the question is given below as
[tex]y=x^2+2x-24[/tex]Step 1: Calculate the x-intercept
The x-intercept for any curve is the value of the x coordinate of the point where the graph cuts the x-axis, or we can say that the x-intercept is the value of the x coordinate of a point where the value of the y coordinate is equal to zero.
Equating the equation above to zero (0)
[tex]\begin{gathered} y=x^2+2x-24 \\ x^2+2x-24=0 \end{gathered}[/tex]Solving using the quadratic formula below,
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]The general formula of a quadratic equation is given below
[tex]ax^2+bx+c=0[/tex]By comparing the coefficient, we will have the values to be
[tex]\begin{gathered} a=1 \\ b=2 \\ c=-24 \end{gathered}[/tex]Step 2: Substitute the values into the quadratic formula to get the values of x
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-2\pm\sqrt[]{2^2-(4\times1\times-24)}}{2\times1} \\ x=\frac{-2\pm\sqrt[]{4^{}+96}}{2} \\ x=\frac{-2\pm\sqrt[]{100}}{2} \\ x=\frac{-2\pm10}{2} \\ x=\frac{-2+10}{2}\text{ or }x=\frac{-2-10}{2} \\ x=\frac{8}{2}\text{ or x=}\frac{\text{-12}}{2} \\ x=4\text{ or x=-6} \end{gathered}[/tex]Hence,
The x-intercepts are
[tex](-6,0)\text{ and }(4,0)[/tex]x-intercepts are (-6,0) and (4,0)
Step 3: Calculate the coordinate of the y-intercept
The point where a line or curve crosses the y-axis of a graph.
In other words: find the value when x equals 0
[tex]\begin{gathered} y=x^2+2x-24 \\ y=(0)^2+2(0)-24 \\ y=0+0-24 \\ y=-24 \end{gathered}[/tex]Hence,
The y-intercept is
[tex](0,-24)[/tex]The y-intercept is (0,-24)
Below is the graph of the function on the question with its x-intercepts and y-intercepts
Step 4: Determine if the graph is minimum or maximum
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x^2 term. If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
The coefficient of the x^2 term is a positive 1
Hence,
The equation
[tex]y=x^2+2x-24\text{ }[/tex]is a minimum quadratic graph
Consider the following functions.f = {(-5, 2), (2, -5), (-1, -3)}and g = {(-1, 1), (-5,3)}Step 1 of 4: Find (f + g)(-1)
To calculate (f g)(-1), we use the definition:
[tex](f+g)(x)=f(x)+g(x)[/tex]This is true if x is defined for f and g. Now, for our problem:
[tex](f+g)(-1)=f(-1)+g(-1)=-3+1=-2[/tex][tex]undefined[/tex]three more than eight times a number is equal to 19. find the number.
Let that number be variable x
MATHEMATICALLY THE STATEMENT IS SAYING
[tex]8x + 3 = 19 \\ 8x = 19 - 3 \\ 8x = 16 \\ \frac{8x}{8} = \frac{16}{8} \\ x = 2 [/tex]
That number is 2ATTACHED IS THE SOLUTION
Tim needs to be at work at 8:00 A.M. It takes him 30 minutes to get ready in the morningand 15 minutes to drive to work. What is the latest time Tim can get up in the morningwithout being late for work?
The given information is:
- Tim needs to be at work at 8:00 A.M.
- He needs 30 minutes to get ready in the morning
- It takes him 15 minutes to drive to the work
The total time Tim needs to get ready and drive to work is:
[tex]30min+15min=45min[/tex]So, he needs at least 45 minutes to be on time at work. So, the latest time Tim can get up in the morning is 45 minutes earlier than 8:00 A.M., and it is equal to:
[tex]\begin{gathered} 8:00\text{ is equal to 7 hours and 60 min, so:} \\ 60min-45min=15min \\ \\ The\text{ latest time is: }7:15A.M. \end{gathered}[/tex]The answer is 7:15 A.M.
pls be quick or is do Friday
6 more than a number is the same as the
number times 4.
Answer:
2
Step-by-step explanation:
Use the order of operations to simplify - +4(4.50 – 1.50).O A. 122/2B. 24/1/2c. 23/1/D. 11/1/SUBMIT
SOLUTION
This becomes
[tex]\begin{gathered} -\frac{1}{2}+4(4.5-1.50) \\ opening\text{ the bracket we have } \\ -\frac{1}{2}+(4\times4.5)+(4\times(-1.50) \\ -\frac{1}{2}+18-6 \\ -\frac{1}{2}+12 \\ 12-\frac{1}{2} \\ =11\frac{1}{2} \end{gathered}[/tex]Hence the answer is option D