Suppose there is a gaseous mixture of nitrogen and oxygen. If the total pressure of the mixture is 480 mmHg, and the partial pressure of nitrogen is 290 mmHg, calculate the partial pressure of oxygen in the mixture using Dalton's law.

Answers

Answer 1

Answer:

Partial pressure of oxygen = 190 mmHg

Explanation:

From the question;

Mixture contains only nitrogen and oxygen

Total pressure of the mixture = 480 mmHg

Partial pressure of nitrogen = 290 mmHg

Dalton's law states that the pressure of a system is as a result of the sum of the partial pressures of the individual components of the mixture. This means that in this mixture;

Pressure of mixture = Partial Pressure of Nitrogen + Partial Pressure of Oxygen

480 = 290 + Partial pressure of oxygen

Partial pressure of oxygen = 480 - 290

Partial pressure of oxygen = 190 mmHg


Related Questions

Ammonia's unusually high melting point is the result of:__________

a. dipole-dipole forces.
b. London dispersion forces.
c. hydrogen bonding.
d. covalent bonding.
e. ionic bonding.

Answers

Answer:

c. hydrogen bonding.

Explanation:

Hydrogen bonding occurs when hydrogen is covalently bonded to a highly electronegative atom such as oxygen, flourine, nitrogen etc.

Hydrogen bonds are quite strong and are known to lead to elevated boiling points. As a result of hydrogen bonding, ammonia is known to have a high melting and boiling point compared to its relative molecular mass.

Which statement describes how phase changes can be diagrammed as a substance is heated?

The phase is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the phase is on the x-axis.

The time is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the time is on the x-axis.

Answers

Answer:

The temperature is on the y-axis and the time is on the x-axis.

Explanation:

Which statement describes how phase changes can be diagrammed as a substance is heated? (D is the answer)

The phase is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the phase is on the x-axis.

The time is on the y-axis and the temperature is on the x-axis.

The temperature is on the y-axis and the time is on the x-axis.

Which statement describes the appearance of a temperature-vs.-time graph? (C is the answer)

A horizontal line shows that the temperature increases at a constant rate over time.

A vertical line shows that the temperature decreases at a constant rate over time.

Horizontal lines where the temperature is constant during phase changes connect upward-sloping lines where the temperature increases.

Horizontal lines where the temperature increases are connected by upward-sloping lines where the temperature is constant for each phase.

write a short paragraph about your daily activities nowadays​

Answers

Ones day my include eating, resting, exercising. Unfortunately mine included not eating, not sleeping, and not exercising. I lay wife awake on my bed wishing for deaths door to find me sooner than later. I do my chores because if I don’t then my parents may take away the few things I love most. In conclusion, my daily activities include thoughts of “ why am I still alive” and actions of crying, punching ext.

My daily activities consists of barely anything productive. i wake up do school work then i take a nap and once i wake up again i am on my phone for multiple hours then i eat stay up till 6 on my phone and repeat

what is the mass of 16.6 x 10^23 molecules of barium nitrate

Answers

It is fact that
6.023
×
10
23
formula units of barium nitrate have a mass of
16.6*10^23

g
. This is what we specify when we say molar mass. And thus the mass of
5.30
×
10
22
formula units of barium nitrate is the quotient multiplied by the molar mass:
5.30
×
10
22
6.023
×
10
23
m
o
l
×
16.6*10^23

g

m
o
l

1

The mass of 16.6 × 10²³ molecules of barium nitrate is 718.7g

The number of moles of a substance can be calculated by dividing the mass by its molar mass. That is;

no. of moles = mass(g) ÷ molar mass (g/mol)

no. of moles of Ba(NO3)2 = 16.6 × 10²³ ÷ 6.02 × 10²³

no. of moles = 2.75 × 10⁰

no. of moles = 2.75moles.

Molar mass of Ba(NO3)2 = 261.34g/mol

mass of Ba(NO3)2 = 261.34 × 2.75

Mass of Ba(NO3)2 = 718.7g

Therefore, the mass of 16.6 × 10²³ molecules of barium nitrate is 718.7g.

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do seeds need energy to germinate

Answers

Answer:

Seeds need oxygen so that they can produce energy for germination and growth. The embryo gets energy by breaking down its food stores. Like all organisms, this is done through a process known as aerobic respiration. —a series of reactions where energy is released from glucose, using oxygen.

1. A baseball pitcher won 75% of the games he pitched. If he pitched 43 ballgames, how many games

did he win?

Answers

Answer:

He won 32 games.

Explanation:

Another way of expressing 75% is 75/100.

To calculate how many games the baseball pitcher won, we multiply the total of games played (43, in this case) by the percent won:

43 * 75/100 = 32.25 ≅ 32

So the baseball pitcher won 32 games.

The chemical reaction between iron (Fe) and oxygen (O) results in the loss of electrons from iron. This reaction is an example of _____.
A) respiration
B) sublimation
C) oxidation
D) combustion

Answers

Answer:

d combustion because iron and oxegen need eachother

Answer:

The Correct answer would be Oxidation.

Explanation:

which have
different numbers of electrons?

Answers

Answer:

These are called isotopes. They have the same number of protons (and electrons), but different numbers of neutrons. Different isotopes of the same element have different masses. Mass is the word for how much substance (or matter) something has.

Every element in group one has ______________ electron in its outer shell. Every element in group two has _______________ electrons in its outer shell.

need help

Answers

Every element in group one has 1 electron in its outer shell. Every element in group 2 has 2 electrons in its outer shell

2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3H2(g)a. Determine the volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of aluminum to produce aluminum sulfate.b. Determine the % yield if 112 g of aluminum sulfate is produced under the above conditions.

Answers

Answer:

a. 167 mL.

b. 39.3 %.

Explanation:

Hello!

In this case, for the undergoing chemical reaction, since 45.0 g of aluminum react, based on the 2:3 mole ratio with sulfuric acid, we can compute the required moles  as shown below:

[tex]n_{H_2SO_4}=45.0gAl*\frac{1molAl}{27.0gAl} *\frac{3molH_2SO_4}{2molAl} =2.50molH_2SO_4[/tex]

Next, since the molarity of a solution is computed based on the moles and volume (M=n/V), we can compute the required volume of sulfuric acid as shown below:

[tex]V=\frac{n}{M}=\frac{2.50mol}{15.0mol/L}=0.167L[/tex]

That in mL is 167 mL.

Moreover, for the percent yield, we compute the grams of aluminum sulfate that are produced based on the required 2.50 moles of sulfuric acid:

[tex]m_{Al_2(SO_4)_3}=2.50molH_2SO_4*\frac{1molAl_2(SO_4)_3}{3molH_2SO_4}*\frac{342.15gAl_2(SO_4)_3}{1molAl_2(SO_4)_3} \\\\m_{Al_2(SO_4)_3}=285.13gAl_2(SO_4)_3[/tex]

Therefore the percent yield is:

[tex]Y=\frac{112g}{285.13g}*100\%\\\\Y=39.3\%[/tex]

Best regards!

if there is no mass # and n # how do you find the mass # and n #​

Answers

If you know the number of protons and neutrons, you can find the mass by adding them. I’m not sure what you mean by n #.

Use what you’ve learned about Lewis structures and formal charges to predict which of the following sulfur-containing molecule(s) would be least likely to exist.

SO2

H2S2

SCl2

HS

HSOH

Answers

Answer:

its DDDDDDDDDDDDDDDDDD

The structure that is least likely to exist is HS.

Sulfur is an element in group 16. Sulfur is a divalent element that has two lone pairs of electrons. This means that sulfur forms compounds in which it is bonded to two atoms or groups.

All the molecules listed can exist because they consists of structures in which sulfur is bonded to two atoms or groups. The only structure that can not exist is HS because it does not satisfy the valency of sulfur.

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A 13.8 g of zinc is heated to 98.8 c in boiling water and then dropped onto a beaker containing 45.0 g of water at 25.o °C .when the water and metal come to thermal equilibrium the temperature is 27.1°C .what is the specific heat capacity

Answers

Answer:

[tex]C_{zinc}=0.400\frac{J}{g\°C}[/tex]

Explanation:

Hello!

In this case, by considering thermodynamics and the temperature of zinc, we can infer it is hot while water is cold, it means that the heat lost by the zinc is gained by the water and we can write:

[tex]Q_{Zn}=-Q_{water}[/tex]

In terms of mass, specific heat and temperatures we can write:

[tex]m_{Zn}C_{Zn}(T_{eq}-T_{Zn})=-m_{water}C_{water}(T_{eq}-T_{water})[/tex]

In such a way, by solving for the specific heat capacity of the zinc we write:

[tex]C_{zinc}=\frac{-m_{water}C_{water}(T_{eq}-T_{water})}{m_{Zn}(T_{eq}-T_{Zn})}[/tex]

Thus, by plugging in the given values we obtain:

[tex]C_{zinc}=\frac{-45.0g*4.184\frac{J}{g\°C}* (27.1\°C-98.8\°C)}{13.8g*(27.1\°C-98.8\°C)}\\\\C_{zinc}=0.400\frac{J}{g\°C}[/tex]

Best regards!

In order to make 159 ml of a 0.135 M benzoic acid solution, what mass of benzoic acid (C7H6O2) is required?

Answers

Answer:

Explanation:

159 mL of .135 M benzoic acid will contain

.159 x .135 = .021465 moles of benzoic acid.

Molecular weight of benzoic acid = 122 gm

grams of .021465 moles = 122 x .021465 = 2.6 grams .

So 2.6 grams of benzoic acid will be required .

Identify the place which has the highest boiling point of water. Identify the place which has the highest boiling point of water. Denver, Colorado, 5280 feet Death Valley, 282 feet below sea level New Orleans, sea level Mt. Everest, 29035 feet A pressurized passenger jet, 35,000 feet

Answers

Answer:

B. because if it was to change so would the amount of wieght that gravity puts on us.

Explanation:

A. might seem right but it's not 35,000 under seal level is the OPPOSITE of 35,000 above sea level.

C. water pressure can change where you are at because of the speed or the type of body of water.

D. it does not make any sense.

hope this helps!!!

A patient provides a urine sample. The density of the patient's urine is 1.0192 g/mL. What is the specific gravity of the urine?

Answers

Answer:

1.092

Explanation:

Density = 1.0192 g/mL

oecific gravity = ?

Specific gravity is the ratio of a material's density with that of water.

The density of water at 4 degrees Celsius =  1 g/mL

Specific gravity = 1.0192 / 1 = 1.0192

Because specific gravity is a ratio, it has no dimension.

A Rolaids tablet contains calcium for neutralizing stomach acid. if a Rolaids tablet neutralizes 24.65ml of 0.547m hydrochloric acid, how many milligrams of calcium carbonate are in a Rolaids tablet?​

Answers

There are 674 mg of calcium carbonate in a Rolaids tablet

Further explanation

Reaction

CaCO₃ + 2HCl ⇒ CaCl₂ + CO₂ +H₂O

V HCl = 24.65 ml

M HCl = 0.547

mol HCl :

[tex]\tt 24.65\times 0.547=13.48~mlmol[/tex]

ratio mol CaCO₃ : HCl = 1 : 2, so mol CaCO₃ :

[tex]\tt \dfrac{1}{2}\times 13.48=6.74~mlmol=6.74\times 10^{-3}~mol[/tex]

mass of CaCO₃ (MW=100~g/mol) :

[tex]\tt 6.74\times 10^{-3}\times 100=0.674~g=674~mg[/tex]

Why does determining volume work only for a regular shaped object

Answers

Answer:

Because only regular-shaped objects have a consistent length, width, height, and shape.

Explanation:

Because only regular-shaped objects have a consistent length, width, height, and shape. When dealing with an object composed of differing shapes, your must calculate each portion separately and then add them.

HELP

1. A student determines that the number of grams in a sample of Al2O3 is 18.3 grams. How many moles are in the sample?


2. A chemist needs 35 grams of CaO for a chemical reaction. How many moles of CaO are needed for the chemical reaction?

3. For an acid-base titration, 126 grams of H2SO4 were needed. How many moles of H2SO4 were needed for the Laboratory Activity?

4. A student needs 100 g of vinegar (CH3COOH) for a lab activity. How many moles does the student need?

Answers

Answer:

Explanation:

1)

Given data:

Mass of Al₂O₃ = 18.3 g

Number of moles = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 18.3 g/ 101.96 g/mol

Number of moles =0.18 mol

2)

Given data:

Mass of CaO needed = 35 g

Number of moles = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 35 g/ 56 g/mol

Number of moles =0.625 mol

3)

Given data:

Mass of H₂SO₄  needed = 126 g

Number of moles = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 126 g/ 98.1 g/mol

Number of moles = 1.28 mol

4)

Given data:

Mass of vinegar = 100 g

Number of moles = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 100 g/ 60.1 g/mol

Number of moles = 1.66 mol

empirical formula for
Ca 40.078 22.3%
As 74.9216 41.6%
O 15.9994 35.6%
H 1.00794 0.560%

Answers

The empirical formula : CaAsO₄H

Further explanation  

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

Determine the mass ratio of the constituent elements of the compound.   Determine the mole ratio by by dividing the percentage by the atomic mass

Ca

[tex]\tt \dfrac{22.3}{40.078}=0.556[/tex]

As

[tex]\tt \dfrac{41.6}{74.9246}=0.555[/tex]

O

[tex]\tt \dfrac{35.6}{15.9994}=2.225[/tex]

H

[tex]\tt \dfrac{0.56}{1.00794}=0.556[/tex]

Divide by the smallest ratio(0.555) :

Ca : As : O : H ⇒

[tex]\tt \dfrac{0.556}{0.555}\div \dfrac{0.555}{0.555}\div \dfrac{2.225}{0.555}\div \dfrac{0.556}{0.555}=1\div 1\div 4\div 1[/tex]

How does the density and distribution of your “stars” change as the balloon expands?

Answers

Answer:

The Universe is constantly expanding and as it expands the stars and objects in space move farther apart, just like the points on the balloon when air is blown into it. Density and distribution of "stars" as the balloon expands because when volume increases the density will increase.

Hope this Helps

What are the starting substances (molecules) in a chemical equation called?

Answers

Answer:

A chemical reaction is the process in which atoms present in the starting substances rearrange to give new chemical combinations present in the substances formed by the reaction. These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.

Which chemical equation is balanced? OCH4 + O2 + H2O + CO2 OCH4 + O2 + 2H2O + CO2 O 6 CH4 + O2 + 2H2O + 2 CO2 OCH4 + 202 + 2H2O + CO2​

Answers

Answer:

CH₄ + 2O₂   →    2H₂O + CO₂

Explanation:

Chemical equation:

CH₄ + O₂   →    H₂O + CO₂

Balanced chemical equation:

CH₄ + 2O₂   →    2H₂O + CO₂

Option d is correct option.

1st step:

CH₄ + O₂   →    H₂O + CO₂

Left hand side                    Right hand side

C = 1                                       C = 1

H = 4                                      H = 2  

O =  2                                     O = 3

Step 2:

CH₄ + O₂   →    2H₂O + CO₂

Left hand side                    Right hand side

C = 1                                       C = 1

H = 4                                      H = 4  

O =  2                                     O = 4

Step 3:

CH₄ + 2O₂   →    2H₂O + CO₂

Left hand side                    Right hand side

C = 1                                       C = 1

H = 4                                      H = 4  

O =  4                                     O = 4

defferent between crysttiline solid and amerphus solid​

Answers

Answer:

Crystalline solids have well-defined edges and faces, diffract x-rays, and tend to have sharp melting points. In contrast, amorphous solids have irregular or curved surfaces, do not give well-resolved x-ray diffraction patterns, and melt over a wide range of temperatures.

Explanation:

Hope this helped!

A student must prepare 7.00 L of 0.100 M Na2CO3 (106 g/mol). Which is the best procedure for preparing this solution

Answers

Answer:

Measure 74.2 g Na2CO3 and add H20 until the final homogeneous solution has a volume of 7.00 L

Explanation:

The best procedure is

Mole of

[tex]Na_2CO_3 = Volume \times molarity\\\\= 7.00 L \times 0.100 mol\\\\[/tex]

= 0.700 mol

The mass of

[tex]Na_2Co_3 = Moles \times molar\ mass \\\\= 0.700 mol \times 106 g/mol[/tex]

= 74.2 g

So as per the above calculation, the option 3 is correct as the solution volume is 7.00 L so the same is to be considered

hence, all other options are wrong

Consider two solutions separated by a semipermeable membrane, as shown in the illustration to the right. The membrane allows the passage of small molecules and ions, but not large molecules like polysaccharides or proteins. Solution A contains a 10% solution composed
of glucose and the protein albumin dissolved in water.
Solution B contains a 5% solution of NaCl in water. Indicate whether each substance in the system would flow into Solution A, Solution B, or neither.

1. Water
2. NaCl
3. glucose
4. Albumin
5. Glucose

Answers

Answer:

The correct movement would be -

1. Water  - into solution A.

2. NaCl  - into solution A.

3. glucose  - into Solution B.

4. Albumin  - neither.

Explanation:

All the substances are separated by the semipermeable membrane and the semipermeable membrane allows the only small molecule to pass through it. So the movement of the given substance would be -

1. Water  - into solution A.

Water molecules are small and can easily pass through the semipermeable membrane as it is given that the solution b has low solute concentration and solution A has high solute concentration. It is known that the movement of the solvent always takes place from low solute concentration to high so the movement of water will be into solution A.

2. NaCl  - into solution A.

The movement of small ionic molecule NaCl is always from high to low concentration as it is given that solution B has high concentration than solution A so movement will take place into solution A.

3. glucose  - into Solution B.

It is also a small molecule and moves from the high glucose region to the low glucose concentration region, in solution A the concentration of glucose is high than solution B so movement would be into solution B.

4. Albumin  - neither.

Albumin is a protein which is macromolecule and large in size to pass through the semipermeable membrane so, albumin move neither solution A nor solution B.

When 10 Joules of heat are transferred into 30 g of Copper at 18.20oC, the final temperature is 19.07oC. What is the specific heat of copper?

Answers

Answer:

c = 0.38 j/g.°C

Explanation:

Given data:

Heat absorbed by copper = 10 j

Mass of copper = 30 g

Initial temperature = 18.20°C

Final temperature = 19.07°C

Specific heat capacity of copper = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 19.07°C -18.20°C

ΔT = 0.87 °C

10 J = 30 g×c×0.87 °C

10 J = 26.1 g.°C×c

c = 10 J /26.1 g.°C

c = 0.38 j/g.°C

2.If a liquid has a volume of 5800 mL and you need the volume in Liters, will the number appear to

become smaller or larger?

Answers

Answer:

The number becomes smaller

Explanation:

Volume = 5800mL

To be converted to L

The relationship between mL and Liters is given as;

1 L = 1000 mL

This means that;

1 L = 1000 mL

x L = 5800 mL

x = 5800 / 1000 = 5.8 L

Comparing 5.8 with 5800, the number becomes smaller.

How do you know your cell's are working

Answers

are you alive? then your cells are working

Now consider a sample of the gas at 33 deg C, 744 mm Hg, and 450 mL. If the pressure is decreased to 725 mm Hg and the temperature raised to 66C. What is the new volume of the gas? New volume =​

Answers

Answer:

V₂ =  511.59mL

Explanation:

Given data:

Initial volume = 450 mL

Initial pressure = 744 mmHg

Initial temperature = 33°C (33 +273 = 306 K)

Final temperature = 66°C (66+273 = 339 K)

Final pressure = 725 mmHg

Final volume =?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 744 mmHg × 450 mL × 339 K / 306 K ×725 mmHg

V₂ = 113497200 mmHg .mL. K / 221850 K.mmHg

V₂ =  511.59mL

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