Sum and Product of Two Numbers Find two numbers whose sum is 20 and whose product is the maximum possible value. (Hint: Let x be one number. Then 20 - x is the other number. Form a quadratic function by multiplying them, and then find the maximum value of the function.)

Answer:

y = 2.5

Step-by-step explanation:

To double check this, you can do 5 times (2.5), then do 16.7 minus that answer so you do, 16.7- 12.5 which does indeed equal 4.2

Answer:

y = 2.5

Step-by-step explanation:

[tex]4.2 =16.7-5y[/tex]

Subtract 16.7 from both sides of the equation you get:

[tex]-12.5=-5y[/tex]

Divide by -5:

[tex]2.5=y[/tex]

Hope this answers your question :)

The number of signatures that Sadie and Cora have is 40 signatures.

Sadie has 10 and she is collecting signatures at an average rate of 3 per day. This will be:

10 + 3d

Cora has 20 and is averaging 2 signatures every day. This will be:

= 20 + 2d

The equation will be:

10 + 3d = 20 + 2d

Collect like terms

3d - 2d = 20 - 10

d = 10

Therefore, the number of signature will be:

= 10 + 3d

= 10 + 3(10)

= 10 + 30

= 40

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The Length of the line segment RS is 9 units

In geometry, the line that is bounded by two distinct points is known as a Line segment. In simple words, we can say that a line segment is part of a straight line that connects two distinct points.

To find the length of the line segment we can use the distance formula

Where (x₁, y₁) and (x₂, y₂) are endpoints of Line segments  

Here we have

R ( 6,5) and S (6,-4)    

And we need to find the length of the line segment RS

Length of Line segment RS = distance between two points

= √ [ (6 - 6)² + (-4 - 5)²]  

= √ [ (-9)²]  

= 9 units

The Length of the line segment RS is 9 units

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Answer:

Step-by-step explanation:

1(x1)+ (-4)x2+ (-10)x3 = -40                               Eq 1

0   +    (1)x2 +   3(x3)   = 14                               Eq 2

0  +   (-2)x2 + (-5)x3  =  -23                             Eq 3

from the 2nd equations we get

x2 + 3*x3 = 14

x2 = 14 - 3*x3

plug this into equation 3

(-2)*(14-3*x3) + (-5)x3 = -23

now solve for x3  :)

-28+6*x3-5*x3 = -23

-28 +x3 = -23

x3 = 5

nice !

now find x2

x2 = 14-3*(5)

x2 = -1

now find x1

x1 + (-4)*(-1) + (-10)*5 = -40

x1 +4 -50=-40

x1 = 6

X = [ 6 ; (-1) ; 5 ]

Answer:

B 3/32

Step-by-step explanation:

3/8 divided by 4

do the keep change flip method and solve

3/8 x 1/4

Step-by-step explanation:

The y intercept is the y value when x=0,

So plug in x=0,

[tex]5(0) - 2y = 20[/tex]

[tex] - 2y = 20[/tex]

[tex]y = - 10[/tex]

The dimensions of the window: Length = 9ft , width = 4ft

What are dimensions?

In mathematics, a dimension is the length or width of an area, region, or space in one direction.

The homes we live in and the items we use on a daily basis all have three dimensions: height, length, and width.

Here, we have

l = w + 5

Area = length × width

The linear equation of the given dimension is:

36 = (w + 5)w

w² + 5w - 36 = 0

(w + 9)(w - 4) = 0

w + 9 = 0

w = -9

We only measure positive numbers so, we disregard this value.

we take,

w - 4 = 0

w = 4

l = 4 + 5

l = 9

The length of the window is 9 ft and the width of the window is 4 ft.

Hence, the dimensions of the window: Length = 9ft , width = 4ft

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Check the picture below.

[tex]\textit{Sum and Difference Identities} \\\\ cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta) \\\\[-0.35em] ~\dotfill\\\\ cos(105^o)\implies cos(60^o+45^o)\implies cos(60^o)\cdot cos(45^o)-sin(60^o)\cdot sin(45^o) \\\\\\ \cfrac{1}{2}\cdot \cfrac{\sqrt{2}}{2}~~ - ~~\cfrac{\sqrt{3}}{2}\cdot \cfrac{\sqrt{2}}{2}\implies \cfrac{\sqrt{2}}{4}~~ - ~~\cfrac{\sqrt{6}}{4}\implies {\Large \begin{array}{llll} \cfrac{\sqrt{2}-\sqrt{6}}{4} \end{array}}[/tex]

It is proven that the value of x in the given expression 2x-9 -5 = 1 is 7.

Given: 2x-9 -5 = 1

We need to prove that x = 7

2x - 9 - 5 = 1

2x - 13 = 1

2x = 14

x = 7

Therefore, it is proven that the value of x in the given expression  2x-9 -5 = 1 is 7.

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A formula for the sequence 2.3, 2.8, 3.3, 3.8, ... is a_n = 1.8 + 0.5 n.

First, let us understand the arithmetic progression:

Arithmetic Progression (AP) is a number sequence in which the difference between any two consecutive numbers is a constant value.

We can find the common difference (d) by subtracting any two consecutive terms of arithmetic progression.

The nth term of an arithmetic progression is given by:

a_n = a + (n - 1)d

where

a = first term of an arithmetic progression

n = nth term of an arithmetic progression

d = common difference

We are given the following sequence;

2.3, 2.8, 3.3, 3.8, ...

We need to write a formula for the given sequence.

Let us find the common difference;

d = 2.8 - 2.3 = 0.5

a = 2.3

substitute the values in the above formula;

a_n = 2.3 + (n - 1) * 0.5

a_n = 2.3 + 0.5 n - 0.5

a_n = 1.8 + 0.5 n

So, the formula for the given sequence is a_n = 1.8 + 0.5 n.

Thus, a formula for the sequence 2.3, 2.8, 3.3, 3.8, ... is a_n = 1.8 + 0.5 n.

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Answer: 4,300 gallons of water

215 x 4 = 860 gallons of water using the dishwasher

215 x 6 x 4 = 5,160 gallons of water by hand

5,160 - 860 = 4,300 gallons of water saved by using the dishwasher.

- Your welcome, keep it up champ.

Answer:

D. Normality of the estimator (e.g., sample mean)

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The question was incomplete. Check below the complete question.

Which of the following is the necessary condition for creating confidence intervals for the population mean? A. Known population parameter B. Normality of the population C. Known standard deviation of the estimator D. Normality of the estimator (e.g., sample mean)

The factored form of n2 + n is:  n(n+1).

Given data:

n²+n

Now let find the factored form of n²+n

n²+n

Rewrite in factored form

n(n+1)

Hence,

n²+n = n(n+1)

Therefore n(n+1) is the factored form.

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Answer:

43.2km/h

Step-by-step explanation:

1km = 1000m

1h = 3600s

1km/h to m/s

= 1 × 1000/3600

= 1000/3600

1m/s to km/h

= 1 ÷ 1000/3600

= 1 × 3600/1000

Hence, 12m/s = 12 × 3600/1000

= 43.2km/h

According to the concept of difference, the amount of time spend on answering the phone call is 50 minutes.

Difference:

Difference means the result of one of the important mathematical operations, which is obtained by subtracting two numbers and it tells us by how much a number differs from the other.

Given,

On Saturday mornings, Eddie volunteers at the hospital where his mother works. One Saturday, he answers phone calls at the information desk while the receptionist is away. The he spends 40 minutes delivering flowers to patients' rooms. In all, Eddie volunteers at the hospital for 90 minutes that day.

Here we need to find the amount of time spend on answering the phone calls.

While we looking into the given question, we have identified the following things,

Total amount of time spend by Eddie = 90 minutes

Time spend in delivering flowers = 40 minutes

So, the time spend by answering the phone calls is calculated as the difference between the total time and the flower delivering time

=> 90 - 40

=> 50

Therefore, he spent 50 minutes on answering the phone calls.

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The birth weight of elephants at the 99% confidence level is 3820 pounds

What is the standard deviation?

Standard deviation is defined as the amount of variation or the deviation of the numbers from each other.

The average birth weight of elephants is 200 pounds     = 200

The deviation of 60 pounds.                                               = 1500

The birth weight of elephants is at the 85th percentile.      z = 99%= 1.645

Now from the formula of z-score:-

[tex]z=\sqrt{\frac{x-\mu}{\sigma} }[/tex]

[tex]1.64 =\sqrt{\frac{x-200}{1500} }\\[/tex]

[tex]1.645^{2} =\frac{x-200}{1500}[/tex]

2.68 = (x-200)/1500

2.68×1500=x-200

4020-200=x

3820=x

Hence the birth weight of elephants at the 99% level percentile is 3820 pounds

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Answer:

y = -12 + 4x

Step-by-step explanation:

1. Add 8x to both sides of the equation.

2y = -24 + 8x

2. Divide each term in 2y = -24 + 8x by 2, then simplify.

• Simplify left side: cancel the common factor of 2

y = -24/2 + 8x/2

• Simplify right side: 2y/2 = -24/2 + 8x

y = -12 + 4x

a) The hypothesis are given as follows:

b) The significance level is of α = 0.1.

c) The test statistic is of: t = -2.69.

d) The p-value is of: 0.018

e) The decision is to reject the null hypothesis.

At the null hypothesis, it is tested if there is not enough evidence that SUVs sustain less damage, that is, the mean is equal or greater than zero, hence:

[tex]H_0: \mu_d \geq 0[/tex]

At the alternative hypothesis, it is tested if there is enough evidence that the SUVs sustain less damage, that is, the mean if less than zero, hence:

[tex]H_1: \mu_d < 0[/tex]

The test statistic is given by the equation presented as follows:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

The sample of the differences is given as follows:

447, -893, -2373, 271, -1680, -1916, -1676.

Using a calculator from the above sample, the values of these parameters are given as follows:

[tex]\overline{x} = -1117, \mu = 0, s = 1100, n = 7[/tex]

Hence the test statistic is of:

t = (-1117 - 0)/(1100/sqrt(7))

t = -2.69.

Using a t-distribution calculator, considering a left-tailed test, as we are testing if the mean is less than a value, with 7 - 1 = 6 df and t = -2.69, the p-value is of 0.018.

Since this p-value is less than the significance level of 0.1, the decision is to reject the null hypothesis.

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Answer: -19x + 10

Step-by-step explanation:

1. Remove parenthesis

-10x + 2 - 9x + 8

2. Collect like terms

(-10x - 9x) + (2 + 8)

3. Simplify

-19x + 10

By using property of logarithms, We get the answer

In [tex](x^2 -1)[/tex] - In [tex]x^7[/tex] = In (x + 1) + In (x -1) - 7 In x

Given,

In the question:

The equation is :

In  [tex]\frac{x^{2} -1}{x^7}[/tex] , x > 1

To solve by using by using property of logarithms to expand the expression as a sum, difference, and / or constant multiple of logarithms.

Now, According to the question:

We know that:

The property of logarithms is:

[tex]log_{a}{\frac{m}{n} } = log_{a}m - log_{a}n[/tex]

The given equation is :

In  [tex]\frac{x^{2} -1}{x^7}[/tex] , x > 1

In  [tex]\frac{x^{2} -1}{x^7}[/tex] = In [tex](x^2 -1)[/tex] - In [tex]x^7[/tex]

Again, Using the another property of logarithms.

[tex]log_am^x = nlog_am[/tex] {x∈ R}

In [tex](x^2 -1)[/tex] - In [tex]x^7[/tex] = In [tex](x^2 -1)[/tex] - 7 In x

In [tex](x^2 -1)[/tex] - In [tex]x^7[/tex] = In [ (x + 1)(x - 1)] - 7In x

In [tex](x^2 -1)[/tex] - In [tex]x^7[/tex] = In (x + 1) + In (x -1) - 7 In x

{Log (mn) = [tex]log_{a}m - log_{a}n[/tex]}

Hence, By using property of logarithms, We get the answer

In [tex](x^2 -1)[/tex] - In [tex]x^7[/tex] = In (x + 1) + In (x -1) - 7 In x

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Answer:

32 cm²

Step-by-step explanation:

The value of tan W is 5/12

From the question, we have

tan W = 15/36

= 5/12 =0.41

Divide:

Divide, in its simplest form, means to divide into two or more equivalent portions, spaces, groups, or divisions. Divide, in plain English, means to provide the entire thing to a group in equal portions or to divide it into equal pieces. Let's say a square is divided into two triangles with equal areas by a diagonal. A division operation may or may not provide an integer as the outcome. The outcome may occasionally take the form of decimal numbers.

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Answer:

∴ The measure of the hypotenuse is 20cm (to the nearest tenth).

Step-by-step explanation:

Let the length of the hypotenuse be x cm.

 x² = 11² + 14²

∴ x = 20cm (to the nearest tenth)

The probability to take 5 classes is 0.1, while the probability to take at least one class is 0.6, the probability to take 2 or 3 classes is 0.23 and the expectation of the distribution is 1.37.

1.

We know that in a probability distribution,  the sum of all the probabilities is always equal to 1.

Let the probability of X = 5 be a

Hence,

0.4 + 0.25 + 0.15 + 0.08 + 0.02 + a = 1

or, 0.9 + a = 1

or, a = 1 - 0.9

or, a = 0.1

Hence the probability to take 5 classes is 0.1.

2.

We need to find P(X ≥ 1)

= 1 - P(X = 0)

we already know from the table that P(X = 0) is 0.4

Hence, P(X ≥ 1)

= 1 - 0.4

= 0.6

Hence, the probability to take at least one class is 0.6

3.

The probability to take 2 or 3 classes in a semester = P( X = 2)  +  P(X = 3)

= 0.15  +  0.08

= 0.23

4.

We know that the expectation of any distribution

= ∑xp(x)

where,

x is the random variable

p(x) is the probability of the random variable

Therefore,

E(X) = 0 X 0.4  +  1 X 0.25  +  2 X 0.15  +  3 X 0.08  +  4 X 0.02  +  5 X 0.1

= 0  +  0.25  +  0.30+  0.24  +  0.08  +  0.50

= 1.37

Therefore the expectation of the given distribution is 1.37

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keeping in mind that a line with an undefined slope is a vertical line, Check the picture below.

On solving the 3 variable equation you will get the answer x=6, y=1, and z=2. It is solved by elimination method.

What is elimination method?

The elimination method involves removing a variable from a system of linear equations by employing addition or subtraction along with multiplication or division of the variable coefficients.

Now, consider the first two equations.
-3x + 3y +2z = -11
3x + 5y - 5z = 13

Multiply the upper eqation with 5 and lower eqation with 2 to make coefficient of z equal.

-15x + 15y + 10z = -55
6x + 10y - 10z = 26

Add these two equations to eliminate z.

-9x + 25y = -29                   ... (1)

Now, consider second and third eqation from the the eqation given in the question.
3x + 5y - 5z = 13
5x - 6y - z = 22

Multiply the upper equation with 5 to make coefficient of z equal in both the equations.

3x + 5y - 5z = 13
25x - 30y - 5z = 110

Now, subtract the lower equation from the upper equation.
3x + 5y - 5z = 13
-25x + 30y + 5z = -110

To get the following equation:
-22x + 35y = -97                   ... (2)

Now, consider equation (1) and (2).
-9x + 25y = -29
-22x + 35y = -97

Multiply the upper equation with 35 and lower equation with 25.

-315x + 875y = -1015
-550x + 875y = -2425

Now, subtract these two equations to get the following equation:

235x = 1410
x = 6

Substitute the value of x in equation (1).

-9x + 25y = -29
-9 (6) + 25y = -29
25y = 25
y = 1

Now, substitute the value of x and y in following eqation:

-3x + 3y + 2z = -11
-3(6) + 3(1) + 2z = -11
-15 + 2z = -11
2z = 4
z =2

Hence, on solving the 3 variables equation, you will get the answer x=6, y=1, and z=2.

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The coefficients of the expression are 6, 1.

The constant of the expression is 9.

The error Jake might have made is that: D. Jake did not include the coefficient 1.

In Mathematics, a coefficient simply refers to a constant quantity or numerical value (number or numeral) that is typically placed before the variable in an algebraic expression.

Based on the algebraic expression provided, we can reasonably infer and logically deduce that there are two (2) coefficients and these include 6 as the coefficient of b and 1 as the coefficient of y.

This ultimately implies that, the error Jake made was not including the coefficient 1 for y.

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Complete Question:

On a math test a student, Jake, has to identify all the coefficients and constants of the expression 9 + 6b + y. Jake says that 6 is a coefficient and 9 is a constant. Identify all the coefficients and constants of the expression. What error might Jake have made?

The coefficient(s) of the expression is/are __

Use a comma to separate answers as needed.)

The constant(s) of the expression is/are __

(Use a comma to separate answers as needed.)

What error might Jake have made?

A. Jake said 9 is a coefficient. It is actually a constant.

OB. Jake said 6 is a constant. It is actually a coefficient.

OC. Jake did not include the constant 1.

OD. Jake did not include the coefficient 1.

Answer:14.1099

Step-by-step explanation: