Strontium metal and aqueous HCIreact to give hydrogen gas andaqueous strontium chloride. Writethe balanced chemical equation usingthe correct chemical formulas for thereactants and products and identifythe reaction type.

Answer:A

Explanation:because i did the test

Component Q is more powerful in explaining a scientific phenomenon because peer conformation and support are characteristics of a theory.

Scientific phenomena are events that can be witnessed in the natural and artificial worlds that make people wonder and pose questions. A theory is a logical interpretation or explanation of a phenomenon or set of occurrences. For instance, the theory of evolution through natural selection is a hypothesis because it explains the variety of life on earth.

In addition to offering accurate explanations or interpretations, theories also serve additional objectives. Here, we examine three additional goals of theories: the organizing of well-understood phenomena, the forecasting of outcomes in novel circumstances, and the development of fresh lines of inquiry.

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v/v Concentration is a type of concentration in which we use to determine what would be the percentage of a certain volume of solute (the one with the least volume) by a certain volume of solution (the one with the most volume). The formula for this will be:

%v/v = volume of solute/volume of solution

In this question, we have:

%v/v = 8.7%, which is 0.087

volume of solute = 34.2 mL

Now we add these values into the formula:

0.087 = 34.2/v

v * 0.087 = 34.2

v = 34.2/0.087

v = 393 mL of ethanol solution that contains 34.2 mL of ethanol

Answer:

dwn

Explanation:

Oxalic acid solution is a primary standard because it is highly pure, stable and does not change its concentration with environmental factors. > Coming to option B, Sodium thiosulphate, it is a secondary standard reagent. Sodium thiosulphate is also called hypo.

The 14 elements that make up the S-block are hydrogen (H), lithium (Li), helium (He), sodium (Na), beryllium (Be), potassium (K), magnesium (Mg), rubidium (Rb), calcium (Ca), cesium (Cs), strontium (Sr), francium (Fr), barium (Ba), and radium (Ra).

The Periodic Table's s-block elements are those in which the final electron enters the most outer s-orbital. Only two groups (1 & 2) are found in the s-block of the Periodic Table because the s-orbital can only hold two electrons.

S block elements' common outer electrical configuration is ns(1-2).

Given that it contains sodium, beryllium, magnesium, and lithium, I am rather certain that it contains alkaline metals.

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Acetyl group, oxaloacetic acid, coA, citric acid, and other elements are the substates and products required to initiate and finish the TCA cycle.

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The molarity of carbonic acid is 0.063M when titration is done between 47.00mL carbonic acid and 23.82mL of 0.1250M ammonium hydroxide.

Titration is a technique by which we know the concentration of unknown solution using titration of this solution with solution whose concentration is known. To know the end point we use phenolphthalein as indicator. End point is a point where completion of reaction happen

Mathematically

moles or carbonic acid =moles of ammonium hydroxide

[tex]M_{1} V_{1} =M_{2} V_{2} \\M_{1} =Molarity of carbonic acid\\V_{1} =Volume of carbonic acid\\M_{2} =Molarity of ammonium hydroxide\\V_{2} =Volume of ammonium hydroxide[/tex]

Substituting all values

[tex]M_{1}[/tex]=(0.1250×23.82)÷47.00

[tex]M_{1}[/tex]=0.063M

Thus the molarity of carbonic acid is 0.063M

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Answer: i also need help on the same question :(

Explanation:

Answer:

0.286 M

Explanation:

This is a great example of a practice problem that requires you to use the formula for dilution calculations.

To make it more interesting, let's assume that you're not familiar with that problem.

The most important thing to remember about a dilution is the the number of moles of solute must remain constant.

That is, the number of moles of solute present in the initial solution must be equal to the number of moles of solute present in the diluted solution.

Since molarity is defined as moles of solute per liter of solution, keeping the number of moles of solute constant allows you to decrease concentration by increasing the total volume of the solution.

195 ml of 0.355 ml NaCl is added to a 0.500 ml volumetric flask and the flask is filled with water. The [ Na⁺ ] concentration in the diluted solution is 138.45 M

Concentration is calculated by dividing a constituent's abundance by the mixture's total volume. Mass concentration, molar concentration, number concentration, and volume concentration are four different categories of mathematical description.

Molarity is the number of moles of solute per liter of solution and mole fraction is the proportion of solute moles to all other moles of substances present. Parts per thousand grams, mass percentage, the ratio of the solute's mass to the solution's mass multiplied by 100.

M₁ V₁ = M₂ V₂

0.355 × 195 = M₂ × 0.500

M₂ = 0.355 × 195 ÷ 0.500

138.45 M

Thus, The [ Na⁺ ] concentration in the diluted solution is 138.45 M

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The amount that could cause death in a 150 pound person is 675000 mg.

We define the LD 50 as the amount of the substance that could be used to cause mortality in about 50 percent of the population that is undergoing the test. In this case, we have been told that the  LD50 for Allura Red ingested for rats and rabbits is 10,000 mg/kg  an now we are asked for the LD 50 in a person that has a weight of 150-lb.

The first step in the work is to convert the mass of the person from pound to kilogram from here;

Given that

1 pound =  0.45 kilo gram

150 pounds = 150 pounds * 0.45 kilo gram/1 pound

= 67.5 Kg

Now, If

10,000 mg causes mortality in 1 Kg

x mg would cause mortality in 67.5 Kg

x = 675000 mg

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1) Check if the chemical reaction is balanced.

2) Moles of NaOH in the reaction.

3) Moles of neutralized acid.

4) Molarity of H2SO4

Answer:

Moles of Ca3(PO4)2 = 0.455 M * 0.125 L = 0.0569 mol

1 Mole of Ca3(PO4)2 = 3 moles of Ca2+ ions

Thus, moles of Ca2+ ion = 3 * 0.0569 = 0.1707 ~ 0.171 moles

The number of moles of ions in a solution can be calculated using the molarity and volume of the solution. The number of moles of Ca ²⁺ ions contained in 0.125 L of 0.455 M solution of Ca₃ (PO₄) ₂ is 0.0170 moles.

Molarity is a term used to represent the concentration of the solution. Mathematically it is the ratio of number of moles of solute to the volume of solution in liters.

The molarity of the calcium phosphate solution is given 0.455 M  and its volume is 0.125 L. Thus, the no.of moles of calcium phosphate in the solution is calculated as follows:

no.of moles of Ca₃ (PO₄) ₂  = molarity × volume

                                             = 0.455 M  × 0.125 L

                                             = 0.0568 moles.

It is clear from the formula that one mole of calcium phosphate contains 3 moles of Ca ²⁺ ions. Therefore,  the number of moles of calcium ions in 0.0568 moles of calcium phosphate is calculated as follows:

No. of moles of Ca ²⁺ ions  = 0.0568 × 3

                                            = 0.0170 moles.

Hence the number if moles of calcium ions in 0.125 L of 0.455 M calcium phosphate is 0.0170 moles.

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1) The solubility of the ions are;

lead II ions = 6.96 * 10^-4 M

iodide ions = 3.48 * 10^-4 M

2) The Ksp of silver chromate is 8.98 * 10^-22

We know that the Ksp has to do with the equilibrium constant that shows the extent to which a substance dissolves in water. We can see that the equation of the dissolution can be written for each of the reactants.

a) [tex]PbI2 (s) --- > Pb^{2+} (aq) + 2I^{-} (aq)[/tex]

Now we can see that the Ksp is obtained from;

Ksp = [[tex]Pb^{2+}[/tex]] [2[tex]I^{-}[/tex]]^2

Let the solubility be x

Ksp = 4x^3

x = ∛ 1.35 x 10^-9/4

x = 6.96 * 10^-4 M

Hence;

Concentration of lead II ions = 6.96 * 10^-4 M

Concentration of iodide ions =  6.96 * 10^-4 /2 = 3.48 * 10^-4 M

b) In order to obtain the solubility product of the silver chromate solution;

Let the solubility of each of the ions be x

We can see that;

Ksp = [3x]^3 [x]

Ksp = 3x^4

Ksp = 3(4.16 x 10^-6)^4

Ksp = 8.98 * 10^-22

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The sinking of the ocean crust back into the mantle when it meets continental crust is referred to as subduction , and this process occurs at the ocean trenches.

This is referred to as a geological process which occurs when there is collision between two tectonic plates in the earth in which one of the plate sinks into the mantle underneath the other plate.

During this process of subduction, the ocean crust sinks back into the mantle when it meets continental crust and it occurs mainly at the ocean trenches thereby making the options provided the correct choice.

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Answer:

Copper(I) bromide

Explanation:

Copper has oxidation numbers of +1 or +2

Bromide has a common charge of -1

This can be called Copper I bromide more precisely .or somewhat redudanately Copper mono bromide.

An older form of naming would be Cupous Bromide. Indicating a +1 charge on Copper. Cupric Bromide would be CuBr2 indicating a + 2 charge.

Answer:

E, C, A, 90, 5, D, B, D, D, D and B, A C and E, A, E

Explanation:

1. is correct, it is E
2. is C, not D. D is when the liquid is freezing/when the solid is melting.
3. the answer is A. B is when the gas is condensing or when the liquid is boiling.
4. 90 temperature units. This is the boiling point. Technically the substance can still condense below this point until 5 temperature units, or D, but ignore that.
5. 5 temperature units.
6. D, this is where the solid and liquids exchange states (ie melting/freezing)
7. B, this is where boiling and condensing occurs
8. Crystallisation is a fancy word for freezing. The melting and freezing points are the same, so D
9. D. Fusion means freezing.
10. D and B.
11. A, C, and E
12. A has the highest temperature and the highest kinetic and potential energy
13. E has the lowest kinetic and potential energy

Answer:

Na2CO3 + 2HC2H3O2 → CO2 + H2O + 2NaC2H3O2

Explanation:

Label Each Compound With a VariableLabel each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.aNa2CO3 + bHC2H3O2 = cCO2 + dH2O + fNaC2H3O2Create a System of EquationsCreate an equation for each element (Na, C, O, H) where each term represents the number of atoms of the element in each reactant or product.Na: 2a + 0b = 0c + 0d + 1f

C: 1a + 2b = 1c + 0d + 2f

O: 3a + 2b = 2c + 1d + 2f

H: 0a + 4b = 0c + 2d + 3f

Solve For All VariablesUse substitution, gauss elimination, or a calculator to solve for each variable.

Simplify the result to get the lowest, whole integer values.

a = 1 (Na2CO3)

b = 2 (HC2H3O2)

c = 1 (CO2)

d = 1 (H2O)

f = 2 (NaC2H3O2)

Substitute Coefficients and Verify Result

Na2CO3 + 2HC2H3O2 = CO2 + H2O + 2NaC2H3O2

Reactants Products

Na 2 2 ✔️

C 5 5 ✔️

O 7 7 ✔️

H 8 8 ✔️

Since there is an equal number of each element in the reactants and products of Na2CO3 + 2HC2H3O2 = CO2 + H2O + 2NaC2H3O2, the equation is balanced.

The amount of gold that can be produced from 213.46g AuPO₄ is equal to 143.7g.

A mole is a standard unit that can be used to determine the huge number of quantities of ions,  atoms, molecules, or other particular particles. The mass of the 1 mole of any element is known as atomic mass (in grams) and the mass of one mole of any compound is called molar mass.

The number of units in one mole was found to be approximately 6.023 × 10 ²³  also called Avogadro’s constant.

Given, the mass of the AuPO₄  = 213.46 g

The molar mass of the AuPO₄ = 197 + 31 + 4(16) = 292 g/mol

The number of moles of the AuPO₄  = 213/292 = 0.729 mol

If the mole of AuPO₄  will produce one mole of the Au.

Then 0.729 mol of the AuPO₄ will produce Au = 0.729 mol

The mass of the Au (in grams) = 0.729 ×197 = 143.7 g/mol

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According to the stoichiometry, 0.4 ml of hydrogen gas  is produced from 0.2 moles of calcium .

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

In the given problem, 1 mole of calcium produces 1 mole of hydrogen gas.

Given 0.2 moles of calcium , so mass  of calcium  by number of moles formula,mass=number of moles×molar mass=0.2×40.07=8.014 g

As 40.07 g of calcium produces 2 g hydrogen

∴8.014 g calcium produces 8.014×2/40.07=0.4 ml.

Thus, the volume of hydrogen gas produced from 0.2 moles of calcium at standard temperature and pressure is 0.4 ml.

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Oxygen have 6 valence electrons. It needs only two electrons to get a full outer shell.

Thus, oxygen will gain two electrons.

Scientific notation is the way that scientists handle large numbers and small numbers. For example, instead of writing 0.000 000 0056, they write 5.6 × 10⁻⁹.

We can think of 5.6 × 10⁻⁹ as the product of two numbers: 5.6 (the digits) and 10⁻⁹ (the power of 10).

Here are some examples of scientific notation.

1000 = 1 × 10³; 7354 = 7.354 × 10³

100 = 1 × 10²; 482 = 4.82 × 10²

10 = 1 × 10¹; 89 = 8.9 × 10¹

1 = 1 × 10⁰; 6 = 6 × 10⁰

1/10 = 0.1 = 1 × 10⁻¹; 0.32 = 3.2 × 10⁻¹

1/100 = 0.01 = 1 × 10⁻²; 0.053 = 5.3 × 10⁻²

1/1000 = 0.001 = 1 × 10⁻³; 0.0078 = 7.8 × 10⁻³

The exponent of 10 is the number of places we must shift the decimal point to get the scientific notation.

Each place the decimal moves to the left increases the exponent by 1.

Each place the decimal point moves to the right decreases the exponent by 1.

EXAMPLE:

Write the following numbers in scientific notation: 1001;

6 926 300 000; -392; 0.000 000 13; -0.0038

Solution:

1.001 × 10³; 6.9263 × 10⁹; -3.92 × 10²; 1.3 × 10⁻⁷; -3.8 × 10⁻³

Hope this helps!

The equilibrium constant relates the concentrations of the products and reactants in the chemical equilibrium. To calculate it we can apply the following equation.

For the reaction: aA + bB ---> cC + dD

Equlibrium constant (Ke) will be:

The letters in square brackets refer to the concentration raised to the respective coefficient. Now we replace the known values:

So, the equilibrium constant (Ke) will be 3.2M

Answer:

a. Aluminum nitride

Explanation:

The compound AlN is a salt made up of Al and N.

Analyzing the oxidation states of each element, we can see that Aluminum acts with 3+ (because it has only one oxidation state), so Nitrogen need to interact with an oxidation state of 3-, for the molecule to be neutral.

Due to the nitrogen acts with 3- the name of the salt will be Aluminum nitride.

Answer:

6 N to the left, or -6 N
unbalanced

Explanation:

The forces are two 3 N forces. The forces are additive, so 3+3 = 6, so the answer is 6 N to the left.
Since the net force isn't 0, the forces are unbalanced (aka the block will move since there is a force pushing the block)

According to the chemical equation, the reaction absorbs 54.8 kJ per 2 moles of NH4Cl because that's the stoichiometry coefficient of this molecule.

Now, we need to find the number of moles in each mole of NH4Cl.

Then, we add them to find the molar mass.

This means that 1 mole of NH4Cl equals 53.49 grams.

At last, we multiply the mass of NH4Cl (27.1 g) by two ratios, the first ratio is about the molar mass, and the second ratio is about the amount of heat per moles.

Therefore, the amount of energy that would be absorbed is 13.88 kJ.

The change in enthalpy of the gas mixture during the reaction is - 95 kj.

The formula for the change in internal energy is given by:

ΔU = ΔH + W

ΔU = the change in inter energy = -181 kj ( decreased)

ΔH = the change in enthalpy

W = work done =  -86 kj

substituting the values in the formula we get :

ΔU = ΔH + W

- 181 kj = ΔH  - 86 kj

ΔH = -181 kj + 86  kj

ΔH = - 95 kj

Measurements show that the energy of a mixture of gaseous reactants decreases by 181.kj during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that -86.kj of work is done on the mixture during the reaction. The change in enthalpy of the gas mixture during the reaction is - 95 kj.

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Every substance has a specific temperature range at which it changes from one phase (solid, liquid, or gas) to another.

Measure the melting, boiling, and/or sublimation points of several substances using a realistic melting point device to see what these phase changes appear like on a tiny scale.

Make assumptions about the relative potency of the forces binding these compounds together based on the transition points.

By placing a small amount of an organic solid into a capillary tube, attaching it to the thermometer's stem in the centre of a heating bath, and gradually heating the bath, one can ascertain the temperature at which melting starts and ends.

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The relative atomic masses of the elements are:

Lead = 206.96 amu

Magnesium =  24.62 amu

Silicon = 28.08 amu

The relative atomic masses of the given elements from their isotopes is determined as follows:

1. Lead:

Relative atomic mass = (203.973 * 0.014) + (205.974 * 0.236) + (206.759 * 0.226) + (207.9766 * 0.523)

Relative atomic mass = 206.96 amu

2. Magnesium:

Relative atomic mass = (23.985 * 79.99) + (24.986 * 10%) + (25.983 * 11.01%)

Relative atomic mass = 24.62 amu

3. Silicon:

Relative atomic mass = (27.977 * 92.21%) + (28.976 * 4.70%) + (29.973 * 3.09%)

Relative atomic mass = 28.08 amu

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Answer

B.

Explanation

The diagram shown below correctly shades the S, P, D, F-block of the periodic table:

Comparing the above with the given options, the diagram which correctly shades the f-block of the periodic table in blue will be option B:

The strong base to be in equilibrium refers to shifting towards the left side of the reaction and far away from the right side i.e option 1

What do you understand by equilibrium?

A system is at an equilibrium when all of its external forces are in balance.

Generally, In any acid-base reaction, the equilibrium will favor that side of reaction which moves the proton towards the stronger base.

Let us consider the given reaction

HCl (acid)  +  NaOH (strong base)   NaCl  +  H20

As per the reaction, equilibrium will shift towards the left side as it involves the abstraction of the proton by the base.

Hence, the answer is option 1 first which means the position of equilibrium lies far to right.

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