Answer:
4x^2 - 8x +16
Step-by-step explanation:
(2x - 4)^2 can be looked at like this (2x - 4)(2x - 4) which can then be foiled
4x^2 -8x + 16, I presume that there is no equals zero so I don't think I can use the quadratic formula.
Thus it is 4x^2 - 8x + 16.
Which value of x would make the following matrix singular?
5 x
3 6
Answer: 10
Explanation:
(30)-(30)= 0
Singular matrices must equal 0
(Correct on my quiz)
The value of x would make the following matrix singular is 10
Matrices of a functionFor a matrix to be singular, the determinant of the matrix must be zero.
For the given 2 by 2 matrix, for the matrix to be a singular matrix then, its determinant must be zero as shown;
(5* 6) - (3 * x) = 0
30 - 3x = 0
3x = 30
x = 10
Hence the value of x would make the following matrix singular is 10
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find the sum of all the odd numbers between 51 and 99 inclusive
Answer:
1875
Step-by-step explanation:
Please Help Me With this question.
Answer:
Y=76x
Step-by-step explanation:
if you divide 3 and 228 it is 76. if you divide 5 and 380 it is 76.if you divide 532 and 7 it is 76. and if you divide 11 and 836 it is 76.
Answer:
Step-by-step explanation:
The trick is to get rid of b in y = mx + b. The way to do that is to take 2 values and subtract them
(380 - 228) / (5 - 3) = 152/2 = 76
Not all problems work out this nicely.
The answer is
y = 76x
In this case you can be a little more direct. m = 380 ÷ 5 = 76, but not all equations are this well behaved and doing it the long way is the best way.
Suppose that u⃗ =⟨8,−2⟩ and v⃗ =⟨5,−5⟩. What is the angle between u⃗ and v⃗ , rounded to the nearest degree?
9514 1404 393
Answer:
31°
Step-by-step explanation:
One way to find the difference angle is to look at the angle of the quotient. We can use complex numbers to represent the vectors for the purpose of that math. The magnitude is not important in this problem, so we do not have to finish the division.
(8 -2i)/(5 -5i) = (8 -2i)(5 +5i)/((5 -5i)(5 +5i)) = (40 -10i +40i +10)/( )
The numerator is 50 +30i, which has an angle of ...
arctan(30/50) ≈ 30.96° ≈ 31°
_____
Additional comment
Effectively, we have found the angle as the angle of the product of one vector with the conjugate of the other, when written as complex numbers. In vector terms, you might use the definition of the dot product. That seems to take a lot more math.
u·v = |u|×|v|×cos(θ)
θ = arccos(u·v/(|u|×|v|))
θ = arccos((8·5 +(-2)(-5))/√((8² +(-2)²)(5² +(-5)²))) = arccos(50/√3400)
The graph below shows a distance versus time graph. What is the average speed
between 2 p.m. and 4 p.m.?
Answer Choices and Graph in the picture.
Answer:
option B is correct answer.
Step-by-step explanation:
(200-75)/2 = 62.5 miles per hour.
paki sagot po kailangan na kasi..
thank you in advance ☺
1. 5
2.2
3.2,5
4.2,5
5.2
HOPE IT HELPS:)
PLS FOLLOW:)
#BRAINLIEST:)
What is the value of w?
Answer:
w= -2. Solve for w: (w-5) (w+2) = w^2-4. Expand out terms of the left hand side: w^2-3 w-10 = w^2-4. Subtract w^2-4 from both sides
Step-by-step explanation:
evans uncle bought 2 1/4 pounds of hamburger meat and used 1/3 of it to make lunch. How much hamburger meat did evans uncle use to make lunch?
Answer/Step-by-step explanation:
To find the answer subtract 2 1/4 by 1/3
how can you tell if data is continuous or discrete
For me, it helps to ask this question: Does it make sense to apply the midpoint? If it doesn't make sense, then the data is discrete. Otherwise, the data is continuous.
Here's an example:
Let's say we are counting the number of people buying a movie ticket. So the numbers we care about are positive whole numbers 1,2,3,... It doesn't make sense to apply the midpoint to the values 1 and 2 to get 1.5; you can't sell half a ticket. Therefore the variable "number of movie tickets sold" is a discrete variable. There are gaps in the data.
On the other hand, if we were measuring the weight of various coins, then this variable is continuous. It's possible to have any positive number decimal number weight (eg: 2.275 grams perhaps). It makes sense to apply the midpoint to any two weights and get some other weight. We don't have to worry about sticking to whole numbers only. Unlike before, there aren't any gaps and we consider this number set to be dense.
One way you could remember the two is to keep this in mind: If you count it, then it's likely discrete. If you can measure it, then it's continuous.
There are probably exceptions to that rule, but for the most part it holds up I think.
Complete the statement based on the following information.
9514 1404 393
Answer:
(c) ΔTRS
Step-by-step explanation:
Perhaps the easiest way to find corresponding vertices is to look at the angle markings:
1 mark: angles J and T
2 marks: angles K and R
3 marks: angles I and S
Then, in order of corresponding angles, we have ...
ΔJKI ≅ ΔTRS
you have to estimate
Answer:
75,388
Step-by-step explanation:
Long Multiplication form
[tex]\mathrm{Mutliply\:the\:bold\:numbers}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&0&\textbf{2}\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&8\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&\textbf{0}&2\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply}\\\\8\cdot \:4=32[/tex]
[tex]\mathrm{Carry\:}3\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}3\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply\:the\:top\:number\:by\:the\:bolded\:digit\:of\:the\:bottom\:number}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{8}&\textbf{0}&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:2\cdot \:9=18[/tex]
[tex]\mathrm{Carry\:}1\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}8\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&1&\space\space\\ \space\space&\space\space&8&0&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&\space\space&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:number\:to\:the\:multiplication}:\quad \:1+0\cdot \:9=1[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{1}&\space\space\\ \space\space&\space\space&8&\textbf{0}&2\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:8\cdot \:9=72[/tex]
[tex]\mathrm{Carry\:}7\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}7\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ 7&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:rows\:to\:get\:the\:answer.\:\:\:Fill\:in\:trailing\:zeros\:\:(not\:required)}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&8&0&2\\ \space\space&\times \:&\space\space&9&4\end{matrix}}{\begin{matrix}0&3&2&0&8\\ 7&2&1&8&0\end{matrix}}[/tex] [tex]=75,388[/tex]
See Image for the addition:
last month adhem ate 5 apples , 8 bananas , 7 Peaches , 10 oranges what the ratio of apples to the total of the fruit
Answer: 5:30
Step-by-step explanation: there are 5 apples and 30 total fruits.
Answer:
5:30 or simplified 1:6
Step-by-step explanation:
There are 30 fruits including the apples, and the apples only make up 5 of the fruits.
Item 4 Evaluate. [(1 1/4−3/4)⋅(−2/3)3]÷(−4) What is the value of the expression? Enter your answer as a simplified fraction in the box.
Answer:
1/27
Step-by-step explanation: I took the quiz and the right answer is 1/27
The value of the given expression would be 0.25 which is simplified by using the PEMDAS rule in the expression.
What is PEMDAS rule?The Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction rule is abbreviated as PEMDAS. This rule is used to answer the problem correctly and properly.
The given expression would be below as:
⇒ [(1 1/4−3/4)⋅(−2/3)3]÷(−4)
Using the PEMDAS rule in the above expression,
⇒ [(5/4−3/4)⋅(−2/3)3]÷(−4)
Apply the subtraction operation,
⇒ [(2/4)⋅(−6/3)]÷(−4)
Reduce the fractions, and we get
⇒ [(1/2)⋅(−2)]÷(−4)
Cancel out the terms of 2 to each other
⇒ (−1)÷(−4)
Cancel out the negative sign to each other
⇒ 1 / 4
Apply the division operation to get
⇒ 0.25
Therefore, the value of the given expression would be 0.25 which is evaluated.
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You spin each spinner once. You get $39 if you spin a 2 and a vowel. You get $26 if you spin a 2 and a consonant. You get $9 if you spin a 1 and a vowel. Everything else earns $0. What is the expected value of this game? Round your answer to the second decimal if necessary
The expected value of the game is the mean value of the game
The expected value of the game is $9
For the first spinner;
The probability to spin 2 is 1/4The probability to spin 1 is 3/4For the second spinner;
The probability to spin a vowel is 1/4The probability to spin a consonant is 3/4So, the probability of spinning a 2 and a vowel is:
[tex]\mathbf{P(2\ and\ vowel) = \frac 14 \times \frac 14 = \frac{1}{16}}[/tex]
The earning for spinning a 2 and a vowel is $39.
So, the expected earning is:
[tex]\mathbf{Expected = 39 \times \frac{1}{16} = 2.4375}[/tex]
So, the probability of spinning a 2 and a consonant is:
[tex]\mathbf{P(2\ and\ consonant) = \frac 14 \times \frac 34 = \frac{3}{16}}[/tex]
The earning for spinning a 2 and a consonant is $26.
So, the expected earning is:
[tex]\mathbf{Expected = 26 \times \frac{3}{16} = 4.875}[/tex]
So, the probability of spinning a 1 and a vowel is:
[tex]\mathbf{P(1\ and\ vowel) = \frac 34 \times \frac 14 = \frac{3}{16}}[/tex]
The earning for spinning a 1 and a vowel is $9.
So, the expected earning is:
[tex]\mathbf{Expected = 9 \times \frac{3}{16} = 1.6875}[/tex]
So, the expected value of the game is:
[tex]\mathbf{Game =2.4375+ 4.875 + 1.6875}[/tex]
[tex]\mathbf{Game =9}[/tex]
Hence, the expected value of the game is $9
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What is the elapsed time from 11:34 A.M. to 12:06 P.M.?
Answer:
12hrs and 32 minutes
Step-by-step explanation:
because the same am time to pm time is exactly 12 hrs and 11:34am is 26 minutes away from 12am so you can 26 minutes to get to 12am then 12am is 12hrs away from 12pm so you add 12hrs and now you are at 12pm at 12pm you add 6 minutes to get to 12:06pm which is a total of 12hrs and 32 minutes
Can someone please help me I will mark u brilliant
Answer:
the whole number 5 goes to the left of the decimal
Step-by-step explanation:
so think about it this way...
I have 10 dots .......... that is 1.0 but if I only have 5 of the 10 I have 0.5. if you have anymore questions just ask and ill help
60% of students at a high school participate in club activities. Rewrite this percent as a fraction in simplest form
Step-by-step explanation:
............no.................
The circumference of a circle equals 2 r, where r is the radius. Find
the circumference of a compact disc that has a radius of 6.0 cm
Answer:
The answer is 37.68 or 37.7
Step-by-step explanation:
What you have to do first is find the diameter. So you have to multiply the radius (r) by 2 to get the diameter. 6 times 2 is 12. After that you, will multiply 12 by pi, or 3.14 to get 37.68
Heeeeelllllllppppppp
1.
[tex]y=\frac{5}{3} x-2[/tex]
2.
[tex]y=-2x+2[/tex]
3.
[tex]y=x+5[/tex]
4.
[tex]y=\frac{1}{4}x[/tex]
Which equations are true equations?
Select all correct answers.
150/5^2=30−4^2−12
8⋅7/2−12=22−2⋅3
48 ÷ 8 + 2³ = 5 + 3²
9^2−7^2=20÷(7−2)
Answer:
The second and third equations are the correct ones.
Step-by-step explanation:
You don't need one, if you want one, do the problem yourself.
Answer: B. 8⋅7/2−12=22−2⋅3 and C. 48 ÷ 8 + 2³ = 5 + 3²
There are 30 pens in a box.
12 of the pens are black.
7 of the pens are green.
The rest of the pens are red.
One of the pens is chosen at random.
Find the probability that the pen is red.
Step-by-step explanation:
30-(12-7)= red pens
30-19
11
Probability=
11/30
I just need the properties in order help plz
[tex] \: \: \: \: [/tex]
[tex]6x - 30 - 3x = - 12[/tex]
move the variable to the left hand side and change its sign, move the constant to the right hand side and change its sign[tex]6x - 30 = - 12[/tex]
collect like terms and calculate the sum[tex] 3x = - 18[/tex]
divide both sides of the equation by 3[tex]x = 3[/tex]
hope it helps[tex] \: \: \: \: \: [/tex]
[tex]\sf \longmapsto6(x−5)=3x−12[/tex]
Simplify both sides[tex]\sf \longmapsto(6)(x)+(6)(−5)=3x+−12[/tex]
[tex]\sf \longmapsto6x+−30=3x+−12[/tex]
[tex]\sf \longmapsto \: 6x - 30 = 3x - 12[/tex]
Subtract 3x from both sides[tex]\sf \longmapsto \: 6x−30−3x=3x−12−3x[/tex]
[tex]\sf \longmapsto3x−30=−12[/tex]
Add 30 to both sides[tex]\sf \longmapsto3x−30+30=−12+30[/tex]
[tex]\sf \longmapsto3x=18[/tex]
Divide both sides by 3[tex]\sf \longmapsto \: \dfrac{3x}{3} = \dfrac{18}{3} [/tex]
[tex]\sf \longmapsto \: x = 6[/tex]
[tex] \boxed{\sf \: x = 6 }[/tex]
Rick’s Rentals is a car rental company that uses the function f(x)=22+0.10x to determine the to
tal cost of a rental as a function of how many miles a person drives. Penny’s Pencils is another company that uses a similar function g(x)=22+0.10x to determine the total cost of an order of personalized pencils as a function of the number of pencils ordered. Determine the domain and range of the company whose function is continuous and justify your answer.
Answer:
Step-by-step explanation:
The number of miles driven is sometimes written as a mixed number, and thus is a continuous variable (whereas the number of pencils purchased is not continuous (it's a whole number).
The domain of the continuous function are [0, n), where n represents the number of miles driven and is rarely over about 500 miles per day; the range is [$22, r), where r is ($0.10/mile)(number of miles driven), or approximately $50. If the renter drove 600 miles the upper end of the range would be $60. And so on.
What is the answer to this question: 8V+3=105
Note: this is Vertical/Adjacent/Complementary Angles (Algebraic)
8V+3=105
clt
8v=105-3
=102
divide both sides by 8v
8v=102/8v
V=12.75
A long-sleeve shirt has 8 front buttons and 2 cuff buttons; a short-sleeve shirt has 6 front buttons and no cuff buttons. The factory which makes ‘Slimboy Shirts’ uses 10 times as many front buttons as cuff buttons. What is the ratio of long-sleeve shirts to short-sleeve shirts produced by the factory?
Leave your ratio in its simplest form.
Answer:
ratio of long-sleeved shirts to short-sleeved shirts is 1:2 this is my answer that I thought of if you don't feel comfortable believing me just wait for another person to answer and see what they say.
Step-by-step explanation:
use a calculator to find the square for 7.6
Answer:
Using a calcuator, [tex]7.6^{2} =57.76[/tex]
Answer:
Hey mate....
Step-by-step explanation:
This is ur answer....
Shows me 57.76 well....Hope it helps!
Brainliest pls!
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Jaya wants to make a vegetable garden in her backyard for 6 different vegetables. She makes 6 sections in the garden. The dimensions of the garden are 3 sections long by 2 sections wide. Each section is in the shape of a square. The area of the vegetable garden is 91.26 square feet. What is the length of the vegetable garden?
The length of the vegetable garden is 11.7 ft.
The dimension of the garden are 3 section long and 2 section wide.
let
each section length = x
Therefore,
length of garden = 3x
width of garden = 2x
Area of the vegetable garden = 91.26 ft²
3x(2x) = 91.26 ft²
6x² = 91.26
x² = 91.26 / 6
x² = 15.21
x = √15.21
x = 3.9
length of the vegetable garden = 3(3.9) = 11.7 ft
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please help with this
Answer:
2,4,6,
6,12,18
10,20,30
find thr value of a and b
Answer: a) 250
b) I don’t understand
Step-by-step explanation: I’m not sure if it’s correct or not
Step-by-step explanation:
a⟩. a = (5x²)/2 = {5(10)²}/2 = {5(10*10)}/2 = {5(100)}/2 = 500/2 = 250Ans.
b⟩. b = {2x²(x - 5)}/10x = [2(10)²{10²-5}]/10(10)² = [2(10*10){10*10 - 5}]/10(10*10) = [2(100){100 - 5}/10(100) = [200 {95}]/1000 = 19000/1000 = 19 Ans.
Hope this helps!!
The position of an object at any time t is given by
s(t)=3t4−40t3+126t2−9
.
1 Determine the velocity of the object at any time t.
2 Does the object ever stop changing?
3 when is the object moving to the right and when is the object moving to the left
Answer:
Step-by-step explanation:
I will ASSUME that your equation is
s(t) = 3t⁴ - 40t³ + 126t² - 9
1) velocity is the derivative of position
v(t) = s'(t) = 12t³ - 120t² + 252t
2) changing what? position? velocity? acceleration? gender? color?
position No the plot is continuous
velocity Yes both magnitude and direction. Zeros at t = 0, 3, and 7 s
acceleration Yes, both magnitude and direction. Zeros at approx. t = 1.306 and 5.361 s
gender? who knows
color? probably.
3) velocity is positive (moving to the right on a standard number line) for
0 < t < 3 and t > 7
Moves to the left for
t < 0 and 3 < t < 7
1. the velocity of the object at any time "t" is v(t) = 12t³ - 120t² + 252t.
2. the object stops changing at t = 6 and t = 3.5.
3. the object is moving to the right in the interval 0 < t < 3.5 and moving to the left in the interval t > 6.
To determine the velocity of the object at any time "t," we need to find the derivative of the position function "s(t)" with respect to "t."
1. Velocity of the object at any time "t":
The velocity is the rate of change of position with respect to time, which is given by the derivative of the position function, s(t).
s(t) = 3t⁴ - 40t³ + 126t² - 9
To find the velocity function, we take the derivative of s(t) with respect to t:
v(t) = d/dt (3t⁴ - 40t³ + 126t²- 9)
v(t) = 12t³ - 120t² + 252t
So, the velocity of the object at any time "t" is v(t) = 12t³ - 120t² + 252t.
2. Does the object ever stop changing?
The object stops changing when its velocity becomes zero. To find when the velocity is zero, we need to solve the equation v(t) = 0.
12t³ - 120t² + 252t = 0
Now, we can factor out common terms:
t(12t² - 120t + 252) = 0
Now, set each factor equal to zero and solve for "t":
1st factor: t = 0
2nd factor: 12t² - 120t + 252 = 0
To solve the quadratic equation, we can either factor it further or use the quadratic formula. Factoring the quadratic equation gives us:
(t - 6)(12t - 42) = 0
Setting each factor to zero:
1. t - 6 = 0
t = 6
2. 12t - 42 = 0
12t = 42
t = 3.5
So, the object stops changing at t = 6 and t = 3.5.
3. When is the object moving to the right and when is the object moving to the left?
The object is moving to the right when its velocity (v(t)) is positive, and it is moving to the left when its velocity (v(t)) is negative.
Let's analyze the velocity function
v(t) = 12t³ - 120t² + 252t
To find the intervals where the object is moving to the right or left, we need to determine when v(t) is positive or negative.
1. Find critical points by setting v(t) = 0 and solving for "t":
12t³ - 120t² + 252t = 0
As we already found earlier, the critical points are t = 6 and t = 3.5.
2. Test each interval created by these critical points using test points to determine the sign of v(t) in those intervals.
Pick a value of "t" in each of these intervals:
- When t < 3.5 (e.g., t = 0),
- When 3.5 < t < 6 (e.g., t = 4),
- When t > 6 (e.g., t = 7).
Now, substitute these test values into the velocity function v(t):
- v(0) = 12(0)³ - 120(0)² + 252(0) = 0
- v(4) = 12(4)³ - 120(4)² + 252(4) = 192
- v(7) = 12(7)³ - 120(7)² + 252(7) = -588
Based on the test points, we can conclude:
- The object is moving to the right when 0 < t < 3.5 (positive velocity).
- The object is moving to the left when t > 6 (negative velocity).
Therefore, the object is moving to the right in the interval 0 < t < 3.5 and moving to the left in the interval t > 6.
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