Solve the equation.
–2x – 18 = 6
A. -12
B. -3
C. -2
D. 6

Using a calculator, it is found that the correlation coefficient between weight and value is of -0.15.

Inserting these values in a calculator, it is found that the correlation coefficient between weight and value is of -0.15.

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Answer:

A.32

Step-by-step explanation:

Answer:

32

Step-by-step explanation:

the formula for circumference is 2πr. Using math we get r as 32

Answer:

y=1/4x+9

Step-by-step explanation:

x-4y=-36

add 4y to both sides to find x

x=4y−36

To find y=

add -x to both sides

−4y=−x−36

divide both sides by -4

y=mx+b

y=1/4x+9

Answer:

3.643 X 10 -1

Step-by-step explanation:

Answer:

3.643 × 10 ^− 1

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the  

10 . If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

3.643 × 10 ^− 1

Answer: $1.35 is the answer

Answer:

5 quarters is equal it 1$ and 25¢, 2 nickles is equal to 10¢, put these together and you get 1$ and 35¢ or 1.35$

Step-by-step explanation:

Let n be the number of caterpillars.

Since each catepillar eats 7 leaves,

Wesley have 7n number of leaves.

In this case 7n = 42, so n = 6.

Answer: 7n = 42, n = 6.

Explanation:

Every caterpillar eats 7 milkweed leaves. That means [tex]n[/tex] is the number of caterpillars Wesley feeds every day. Since we know 7n is equal to 42, n = 6 because 42 ÷ 7 = 6.

Answer:

To catch your friend you have to paddle for 1.25 hours

Step-by-step explanation:

Your friend is 0.5 mile in front of you and paddling 3 miles per hour. You are paddling 3.4 miles per hour.

Since the speed is the relationship between the space traveled by an object and the time used for it, then the distance is defined as:

distance= speed*time

Being x the time it takes to reach your friend, then your friend's position will be:

while your position is:

When you reach your friend the position of both should be the same. So:

3*x + 0.5= 3.4*x

Solving:

0.5= 3.4*x - 3*x

0.5= 0.4*x

0.5 ÷0.4= x

1.25= x

This means that to catch your friend you have to paddle for 1.25 hours

Answer:

-21

Step-by-step explanation:

-13 +(-2) = -15

-15+(-2) = -17

-17+(-2 )=- 19

-19+ (-2)= -21

Answer:

y=2-4x

y=2-4*1

y=2

y=2-4*2

y=2-6

y=-4

y=2-4*3

y=2-12

y=-10

The x values are the 1,2,3. The y values are the 2, -4,-10

y=2-4x

x=-1 , y=__

substitute x value with -1

y=2-4*-1

y=2-(-4)

y=2+4

y=6

x=-1, y=6

Answer:

b = 1

Step-by-step explanation:

8 = b - 1 + 8b

combine like terms

8 = 9b - 1

add 1 to both sides of the equation

8 + 1 = 9b - 1 + 1

8 + 1 = 9b

9 = 9b

divide both sides of the equation by 9

9/9 = 9b/9

1 = b

Answer:

b = 1

Step-by-step explanation:

Given

8 = b - 1 + 8b, that is

8 = 9b - 1 ( add 1 to both sides )

9 = 9b ( divide both sides by 9 )

1 = b

Answer:

B is your answer

Step-by-step explanation:

Answer:

The answer is D) (X,Y) ---(-y-x)

Answer:

option c

Step-by-step explanation:

The zeros of 3x+1

3x=-1

x=-⅓

plug in -⅓ into the trinomial. if it gives an answer of 0 then it's a factor

3(-⅓)²+16(-⅓)+5

=0

Answer:

20

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

:P

Answer:

Step-by-step explanation:

∵ ABCD is a rhombus

∴ AC is ⊥ on BD

∴ ΔAEB is right angled triangle

Answer:

C, or the third one

Step-by-step explanation:

Answer:

Y = 40

Step-by-step explanation:

44 - 66y + 65y + 5 = 9

49 - y = 9

-y = -40

y = 40

Answer:

y = 40

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define

11(4 - 6y) + 5(13y + 1) = 9

Step 2: Solve for y

Step 3: Check

Plug in y into the original equation to verify it's a solution.

Here we see that 9 does indeed equal 9.

∴ y = 40 is the solution to the equation.

Answer:

Velocity = 0

Speed = 0.84

Step-by-step explanation:

Khan Academy

Luis's average velocity over the 95 sec period is 0 m/s.

Given that, Luis walks 40 m toward his truck. He notices he forgot his keys, so he returns back to his house.

Magnitude of average velocity is always less than or equal to the average speed because displacement is always smaller than or equal to distance.

Average Velocity = Total time / Total Displacement

​It is a vector quantity and has units of m/s.

Here, total time = 95 sec and displacement = 0 meter

Now, average velocity = 95/0

= 0 m/s

Therefore, Luis's average velocity over the 95 sec period is 0 m/s.

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Answer:

radius r = 9.8 m

base circumference C = 61.575216 m

volume V = 1971.22792 m3

curved surface area A = 603.437117 m2

base surface area B = 301.718558 m2

total surface area K = 905.155675 m2

Answer: 3

Step-by-step explanation:

3x + 7 = y

3x + 7 = 16

*subtract 7 from both sides because inverse operations*

3x = 9

*divide both sides by 3 because inverse operations*

x = 3

Answer:A square and a rhombus both have sides equal in length. But square has all its angles equal to 90 degrees, but a rhombus only has its opposite angles equal.

Step-by-step explanation:

Answer:

A square has all its angles equal to 90 degrees a rhombus has no 90 degree angles

Answer:

[tex]Area = 129.5m^2[/tex]

[tex]Perimeter = 48m[/tex]

Step-by-step explanation:

Given

See attachment

Required

Determine the area and the perimeter of the garden

Calculating Area

First, we calculate the [tex]area\ of\ the\ rectangle[/tex]

[tex]A_1 = L * B[/tex]

Where:

[tex]L = 20-(3.5 +3.5)[/tex]

[tex]B = 7[/tex]

So:

[tex]A_1 = (20 - (3.5 + 3.5)) * 7[/tex]

[tex]A_1 = (20 - 7) * 7[/tex]

[tex]A_1 = 13 * 7[/tex]

[tex]A_1 = 91[/tex]

Next, we calculate the area of the two semi-circles.

Two semi-circles = One Circle

So:

[tex]A_2 = \pi r^2[/tex]

Where

[tex]r = \frac{7}{2}[/tex]

[tex]A_2 = \frac{22}{7} * (\frac{7}{2})^2[/tex]

[tex]A_2 = \frac{22}{7} * \frac{49}{4}[/tex]

[tex]A_2 = \frac{22}{1} * \frac{7}{4}[/tex]

[tex]A_2 = \frac{22*7}{4}[/tex]

[tex]A_2 = \frac{154}{4}[/tex]

[tex]A_2 = 38.5[/tex]

Area of the garden is

[tex]Area = A_1 + A_2[/tex]

[tex]Area = 91 + 38.5[/tex]

[tex]Area = 129.5m^2[/tex]

Calculating Perimeter

First, we calculate the perimeter of the rectangle

But in this case, we only consider the length because the widths have been covered by the semicircles

[tex]P_1 = 2 * L[/tex]

Where:

[tex]L = 20-(3.5 +3.5)[/tex]

So:

[tex]P_1 =2 * (20-(3.5 +3.5))[/tex]

[tex]P_1 =2 * (20-7)[/tex]

[tex]P_1 =2 * 13[/tex]

[tex]P_1 =26[/tex]

Next, we calculate the perimeter of the two semi-circles.

Two semi-circles = One Circle

So:

[tex]P_2 = 2\pi r[/tex]

Where

[tex]r = \frac{7}{2}[/tex]

[tex]P_2 = 2 * \frac{22}{7} * \frac{7}{2}[/tex]

[tex]P_2 = \frac{2 * 22 * 7}{7 * 2}[/tex]

[tex]P_2 = \frac{308}{14}[/tex]

[tex]P_2 = 22[/tex]

Perimeter of the garden is

[tex]Perimeter = P_1 + P_2[/tex]

[tex]Perimeter = 26 + 22[/tex]

[tex]Perimeter = 48m[/tex]

Note: Your expression sounds a little unclear, so I am assuming your expression is

[tex]\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3[/tex]

But, the procedure to solve the expressions involving exponents remains the same, so whatever the expression is, you may be able to get your concept clear.

In the end, I will solve both expressions.

Answer:

Please check the explanation

Step-by-step explanation:

Given the expression

[tex]\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3[/tex]

solving the expression

[tex]\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^b\times \:a^c=a^{b+c}[/tex]

[tex]\left(y+1\right)^5\left(y+1\right)^3=\left(y+1\right)^{5+3}[/tex]

                          [tex]=\left(y+1\right)^8[/tex]

Therefore, we conclude that:

[tex]\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3=\left(y+1\right)^8[/tex]

IF YOUR EXPRESSION IS THIS

                       ↓

[tex]\left(y\:+\:1\right)^{\left(5y+1\right)^3}[/tex]

solving the expression

as

[tex]\left(a+b\right)^3=a^3+3a^2b+3ab^2+b^3[/tex]

so

[tex]\left(5y+1\right)^3=125y^3+75y^2+15y+1[/tex]

               [tex]=125y^3+75y^2+15y+1[/tex]

Thus, the expression becomes

[tex]\left(y+1\right)^{\left(5y+1\right)^3}=\left(y+1\right)^{125y^3+75y^2+15y+1}[/tex]