Solve for x in the equation x2 - 8x+41 - 0

X=-41 371

x= -4 + 5i 0 X-4+ 371

x = 4 + 5/​

Answers

Answer 1

Answer:

x= 4+5i

Step-by-step explanation:

Answer 2

The values of x in the given quadratic equation, x²-8x+41 = 0 are x = 4+5i or x = 4-5i

What is quadratic equation?

A quadratic equation is any equation that can be rearranged in standard form as where x represents an unknown value, and a, b, and c represent known numbers, where a ≠ 0.

Given is a quadratic equation, x²-8x+41 = 0, we need to find the values of x,

Since, 41 is a prime number, which can not be factorized so, we will use quadratic formula,

x = [-b ± √(b²-4ac)] / 2a

Here, a = 1, b = -8, c = 41

Therefore,

x = [8 ± √(8²-4(41))] / 2

= [8 ± √(64-164)] / 2

= [8 ± √(-100)] / 2

= [8 ± 10i] / 2

= [4 ± 5i]

Therefore, x = 4+5i or x = 4-5i

Hence, the values of x in the given quadratic equation, x²-8x+41 = 0 are x = 4+5i or x = 4-5i

Learn more about quadratic equation, click;

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

according to the question

(x+2)(x-2)=96

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Step-by-step explanation:

As we know that the area of a rectangle is defined by multiplying the length by the width.

[tex]A=l\times w[/tex]

Given

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[tex]A=l\times w[/tex]

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width = w = x-2 = -10-2 = -12 units

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[tex]y = - \frac{1}{6} x - 1 \\ [/tex]

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Step-by-step explanation:

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