Solve for r.
–
17r+6r+16r+17r–19r=12
r=

Answer:

5

Step-by-step explanation:

set up point slope form

y + 8 = 2(x-1)

set y to zero

0+8=2(x-1)

8=2x-2

10= 2x

x = 5

Answer:

8

Step-by-step explanation:

yw :)

9514 1404 393

Answer:

  a.  h(t) = -20t +400

  b.  θ(t) = arctan(2 -2/15t); dθ/dt = -30/(1125 -120t +4t^2)

  c.  15 seconds; 100 ft

Step-by-step explanation:

a. The initial height of the elevator is 400 ft. The rate of change of height is -20 ft/s, so the height equation can be ...

  h(t) = -20t +400

__

b. The tangent of the angle above the line of sight is "opposite"/"adjacent":

  tan(θ) = (h(t) -100)/(150) = -2/15t +2

  θ(t) = arctan(2 -2/15t) . . . . radians

The derivative of the angle function is ...

  dθ/dt = 1/(1+(2 -2/15t)^2)(-2/15)

  dθ/dt = -30/(1125 -120t +4t^2)

__

c. The value of dθ/dt will have a peak where the denominator has a minimum, at t = -(-120)/2(4)) = 15. (The quadratic vertex coordinate is t=-b/(2a).)

The elevator appears to be moving fastest at t=15 seconds.

The height at that time is ...

  h(15) = 400 -20(15) = 100

The elevator appears to be moving fastest when it is at eye level, 100 ft above the ground.

Answer:

B.

Step-by-step explanation:

im not sure to my answer(●'◡'●)

Answer: The both involve writing a rate

I hope this helps i would appreciate brainliest if possible :)

I think any of these would work

10;18

15;28

20;35

Answer:

5:9

Step-by-step explanation:

To Find:

ratio of yellow paint to blue paint to make a particular shade of green.

Solution:

The ratio can be written as 5 to 9, or 5:9

We know that if we mix 5 gallons of blue paint with 9 gallons of yellow paint we get the particular shade of green that we want.

Then the ratio of gallons of blue paint to gallons of yellow paint is 5 to 9, or 5:9

Meaning that for every 5 gallons of blue paint we need 9 of yellow paint.

Answer:

that have no answer so sorry

Answer: 12

2 + 10

12

:)

Answer: 12

Step-by-step explanation: just add 2 to 10

Answer:

[tex]11[/tex]

Step-by-step explanation:

[tex]\sf{Use\: the\: distance\: formula\: to\: determine\: the\: distance\: between\: two\: points.[/tex]

[tex]\sf{Distance=\sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}[/tex]

[tex]\mathrm{Plug\:the\:points}[/tex]

[tex]\sqrt{\left(4-\left(-7\right)\right)^2+\left(5-5\right)^2}[/tex]

[tex](4+7)^2=11^2\\(5-5)^2=0[/tex]

[tex]\sqrt{11^2+0}[/tex]

[tex]11^2+0=11^2\\\sqrt{11^2}[/tex]

[tex]\mathrm{Apply\:radical\:rule:\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\:\mathrm{is\ greater\ than \:or\ equal\: to \:0}[/tex]

[tex]=11[/tex]

Answer:

Point slope form: y − 7 = 3 4 ( x − 3 ) Slope intercept form: y = 3 4 x + 19 4 or y = 3 4 x + 4 3 4

Step-by-step explanation:

hope this helps, have a nice day/night! :D

if it helped, please mark this as brainliest!

Answer:

Slope = 1

Step-by-step explanation:

Slope = change in y / change in x

Slope = 6 - (-4)/7 - (-3)

Slope = 10/10

Slope = 1

-Chetan K

[tex]y = 2x -2 ~~~~.....(i) \\\\y = x^2 -4 x +3 ~~~~ .....(ii) \\\\\\x^2-4x +3 = 2x -2\\\\\implies x^2 -4x -2x +3 +2 =0\\\\\implies x^2 -6x +5 =0\\\\\implies x^2 -5x -x +5 =0\\\\\implies x(x-5) -(x-5) =0\\\\\implies(x-5)(x-1) =0\\\\\implies x = 5 ~~ \text{or}~~ x = 1 \\\\\\\text{Substitute x = 1 in equation (i):}\\\\y = 2 -2 =0\\\\ \text{Substitute x = 5 in equation (i):}\\\\\\y = 2(5) -2 = 10 -2 =8 \\\\\text{Hence,}~~ (x,y) = (1,0) ~ \text{and} ~ (x,y) = (5,8)[/tex]

Answer:

The graph moved down 5 units

Step-by-step explanation:

Answer:

Step-by-step explanation:

The best way to get an answer to this question is to study the graph you get when you study the result from Desmos, which is a free  graphing program.

Notice the way the graph is laid out. If the graph was simply y = x^2 - 6x  then the y value for the minimum value would be x = 3 (just like the 2 values you do get) and y = -9

But y = x^2 - 6x + 3 has you moving up 3 units to y = - 6 and y = x^2 - 6x + 8 moves you to y = - 1. Which way are you going? The difference is 5 units and you are moving down because you start  at y = x^2 - 6x + 8 and move down to x^2 - 6x + 3.

Without finding minimums (which is a cumbersome process which needs to be done twice) there's no easy way to do this except graphing.

The answer is B.

Step-by-step explanation:

I am not sure, what is the level of math for you currently.

do you do differentiation and derivatives already ?

because that is how I find "extreme points" and "turning points" of a function right away.

the vertex is the turning point for a quadratic parabola.

that means the point where the slope (= the first derivative) of the function is 0.

and that is also where the axis of symmetry is.

8x - 8 = 0

8x = 8

x = 1 (axis of symmetry).

y = 4×1² - 8×1 = 4 - 8 = -4

so, the vertex is (1, -4)

in case you don't understand derivatives yet, there is a shortcut for this for quadratic equations (fyi - in fact, the generic result of the first derivative) :

y = ax² + bx + c

the x value for the axis is then

x = -b/(2a)

in our case

a = 4

b = -8

x = - -8/8 = 8/8 = 1

and then y is calculated as above.

Answer:

  0 and 1

Step-by-step explanation:

The scale of the graph is not marked, so we assume each grid line represents 1 unit. The leftmost crossing of the x-axis is between 0 and 1.

_____

Additional comment

The other real zero is between 2 and 3. If this is a polynomial function, it will have additional complex zeros.

Answer: A. True.

Step-by-step explanation:

A relationship is linear when the points on a scatterplot follow a somewhat straight line pattern. This is the relationship that we will examine. Linear relationships can be either positive or negative. Positive relationships have points that incline upwards to the right. As x values increase, y values increase.

Answer:

[tex]3\dfrac{1}{4} \ \ or \ \ 3,25[/tex]

Step-by-step explanation:

[tex]\displaystyle12 \frac{3}{8} -9\frac{1}{8} =12-9+\frac{3}{8} -\frac{1}{8} =3+\frac{2}{8} =3\frac{1}{4} \ \ or \ \ 3,25[/tex]

[tex]2x^2 -5x-8 =0\\\\\implies x = \dfrac{ -(-5) \pm \sqrt{(-5)^2 - 4\cdot 2 \cdot (-8)}}{2 \cdot 2}\\\\\\\implies x = \dfrac{5 \pm \sqrt{89}}{4}\\\\\\\text{Hence}~ x = \dfrac{5 + \sqrt{89}}{4},~~ x = \dfrac{5 - \sqrt{89}}{4}[/tex]

Answer:

[tex]\sf \boxed{\sf x=\frac{5+\sqrt{89}}{4}}[/tex]

[tex]\sf \boxed{\sf x=\frac{5-\sqrt{89}}{4}}[/tex]

[tex]\sf 2x^2-5x-8=0[/tex]

☁ We'll solve this equation using The Quadratic Formula:

[tex]\boxed{\sf \cfrac{-b\pm \sqrt{b^2-4ac}}{2a}}[/tex]

A= 2, b= -5, c= -8

[tex]\sf x=\cfrac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\times \:2\left(-8\right)}}{2\times \:2}[/tex]

[tex]\mapsto \sf \sqrt{\left(-5\right)^2-4\times \:2\left(-8\right)}[/tex]

[tex]**\sf \left(-5\right)^2=5^2[/tex]

[tex]\mapsto \sf \sqrt{5^2+4\times \:2\times \:8}[/tex]

[tex]\mapsto \sf \sqrt{5^2+64}[/tex]

[tex]\mapsto \sf \sqrt{89}[/tex]

______________

[tex]\sf x=\cfrac{-\left(-5\right)\pm \sqrt{89}}{2\times \:2}[/tex]

☁ Now, we'll Separate solutions, first, we'll solve the equation when ± is plus:

[tex]\mapsto \sf \cfrac{-\left(-5\right)+\sqrt{89}}{2\times \:2}[/tex]

☁ Multiply 2*2 =4

[tex]\boxed{\sf \cfrac{5+\sqrt{89}}{4}}[/tex]

_________________

☁ Now solve the equation when ± is minus:

[tex]\mapsto \sf \cfrac{-\left(-5\right)-\sqrt{89}}{2\times \:2}[/tex]

☁  Multiply 2*2 =4

[tex]\boxed{\sf \cfrac{5-\sqrt{89}}{4}}[/tex]

[tex]\sf Solution \:1:\boxed{\sf x=\frac{5+\sqrt{89}}{4}}[/tex]

[tex]\sf Solution \:2:\boxed{\sf x=\frac{5-\sqrt{89}}{4}}[/tex]

☁❅☁❅☁☁❅☁❅☁☁❅☁❅☁❅☁

Learn more: https://brainly.com/question/22286698

Answer:

1. B

2. A

Step-by-step explanation:

1.

10^{-2} means that you move the decimal back two times

B is the only option that represents that correctly.

2.

5 * 10^{4} = 50000

2.5 * 10^{2} = 250

50000/250 = 200

Out of the options, A is the only option in which the equation also equals 200.

Answer:

Step-by-step explanation:

x + y = 18

y = 18 - x

xy = 72

x(18 - x) = 72

-x² + 18x = 72

0 = 72 - 18x + x²

x = (18 ± √(18² - 4(1)(72))) / (2(1))

x = (18 ± 6)/2

x = 12

x = 6

Answer:

The final velocity, V, of an object under constant acceleration can be found using the formula V2=v2+2as , where v is the initial velocity in meters per second, a is acceleration in meters per second, and s is the distance in meters.

Answer:

I and II

Step-by-step explanation:

All trapezoids have a midsegment. The base angles of isosceles trapezoids are always congruent. Because the top and bottom side are parallel, the same side interior angles are supplementary not complementary.

Answer:

Y=5 y=-3

Step-by-step explanation:

Two real solutions:

y =(2+√64)/2=1+4= 5.000

or:

y =(2-√64)/2=1-4= -3.000

Answer:

Factors are often given as pairs of numbers, which multiply together to give the original number. These are called factor pairs. A square number will have one factor pair consisting of one factor multiplied by itself. This factor is called the square root of the given number.

Answer:

Administer 14 ml, 350mg/125mg=2.8×5ml=14ml

a. We have GCD(34, 89) = 1; using the Euclidean algorithm,

89 = 2•34 + 21

34 = 1•21 + 13

21 = 1•13 + 8

13 = 1•8 + 5

8 = 1•5 + 3

5 = 1•3 + 2

3 = 1•2 + 1

b. Working backwards,

1 = 3 - 2

1 = 3 - (5 - 3) = 2•3 - 5

1 = 2•(8 - 5) - 5 = 2•8 - 3•5

1 = 2•8 - 3•(13 - 8) = 5•8 - 3•13

1 = 5•(21 - 13) - 3•13 = 5•21 - 8•13

1 = 5•21 - 8•(34 - 21) = 13•21 - 8•34

1 = 13•(89 - 2•34) - 8•34 = 13•89 - 34•34

c. Using the linear combination find in part b,

1 ≡ 13•89 - 34•34 (mod 89)

1 ≡ (-34)•34 (mod 89)

and

-34 ≡ -34 + 89 ≡ 55 (mod 89)

So, the inverse of 34 modulo 89 is 55.

d. Multiply both sides of the congruence by the inverse of 34:

55•34x ≡ 55•53 (mod 89)

x ≡ 2915 ≡ 32•89 + 67 ≡ 67 (mod 89)

Answer:

75 miles

Step-by-step explanation:

We know that she has driven 120 miles before the first stop.

Then she drives for 1/4 of the the distance she has already driven (120 miles). One fourth of 120 is 30.

So now, she's driven for 120 + 30 miles, or 150 miles.

She drives for another 2/3 of the distance she's traveled (150 miles). Two thirds of 150 is 100.

So now, she's driven for 150 + 100 miles, or 250 miles.

What we need to find out now is how much of the trip has she traveled.

We know that the entire distance she has driven is 55 miles more than 1 ⅔ of the remaining trip. So, in other words, the distance she has traveled minus 55 is equal to 1 2/3 of the trip.

To put this in an equation:

250 - 55 = 1 2/3t

t = the whole trip

Now, we solve for t.

250 - 55 = 195

1 2/3 = 5/3

so, 195 = 5/3t

t = 325

We subtract what she has already driven to the total to get the remaining distance.

325 - 250 = 75

Answer:

d .  37/12 unit^2.

Step-by-step explanation:

d) First find the points of intersection of the the 2 graphs, by solving them simultaneously:

x^3 = x^2 + 2x

x^3 - x^2 - 2x) = 0

x(x^2 - x - 2) = 0

x(x - 2)(x + 1) = 0

So they intersect at x = -1, x = 0 and x = 2.

Take the area from x = 0 to x = 2)

           2                        2

Area =  ∫ x^2 + 2x dx -   ∫  x^3 dx

            0                       0

   2

=  [ x^3/3 + x^2 ) - x^4/4]

   0

=   ((8/3 + 4) - 0) - (16/4 - 0) -

=   8/3 unit^2

Now calculate the area  from x = -1 to x = 0.

   0

=    (x^3/3 + x^2 ) - x^4/4 )

   -1

=   (( 0 +1/3 - 1) ) - (0 - 1/4)

=  5/12 unit^2

So the total area of the region =  8/3 + 5/12 = 37/12 unit^2.

Answer:

Step-by-step explanation:

here you go m = (y2-y1)/(x2-x1)

  = (11-(-9))/(3-(-1))

  = 20/4

  = 5