Solve 7! (Factorials) please help I suck at math :(

Answer:

I think it's x=3 I think that's it

I think the answer is 3 because 4÷2=2. Hence, 6÷2=3

The type of sampling method in which a sample frame is divided into groups, which are highly similar to the other

According to the given question, we are asked to show the name which is given to the type of sampling method in which a sample frame is divided into groups, which are highly similar to the other.

As a result of  this, when a sample frame is divided into groups which are very similar to each other, then this is a simple random sampling.

In this method, we can see that there are different types of random sampling techniques which includes:

Therefore, the correct answer is Simple random sampling.

Read more here:

https://brainly.com/question/17019103

Answer:

true

Step-by-step explanation:

true

Answer:

the first one

10+n = 3n

Step-by-step explanation:

n is the number

and 3n means 3*n

Answer:  the answer the first one 10+n=3n

Step-by-step explanation:

n is the number

and 3n means 3*n

5. 4/9 probability

Explanation; You would do (4/13)/(9/13) and that = 4/9.

5b. I don't really get it, it sounds like its asking the same thing.

I gotta go so i will finish later hopefully

(f.g)(x) = (4x + 6)(-5x) = -20x^2 -30x

ok done. Thank to me :>

Answer:

i think the first question is yes and the second one is no

Step-by-step explanation:

Answer:

→ [tex]90°[/tex]

Step-by-step explanation:

Given that

PQRS is a rhombus

The diagonals PR and QS intersects at O

We know that

In a rhombus the diagonals bisects at each other at 90°

So,

In ∆ POQ,

∠ POQ + ∠OPQ + ∠OQP = 180°

➜ 90° + ∠OPQ + ∠OQP = 180°

➜ ∠OPQ + ∠OQP = 180° -90°

➜ ∠OPQ + ∠OQP = 90°

Therefore, the measure of ∠OPQ + ∠OQP is 90°.

Read more:

Similar Questions

In a rhombus ABCD, m∠A = 31°. Point O is a point of intersection of diagonals. Find the measures of the angles of triangle ΔBOC.

https://brainly.com/question/3124169?referrer

Answer:

Length of three sides=3(25)=75ft

Cost per metre=15.00

Total cost:-

[tex]\\ \sf\longmapsto 15(15)=225.00[/tex]

Answer:

a. f(0) = 4

b. f(6) = 8

Step-by-step explanation:

This is a piecewise function, so the actual equation is on the left, and the inequalities are on the right.

If x = 0, this would fall under the first part of the function because x < 5 is the requirement for the first part. Then, evaluating it: f(0) = 0 + 4 = 4.

If x = 6, this would fall under the second part of the function because 5 [tex]\leq[/tex] x < 7 is the requirement. 6 falls under this category, so that means the second part of the function is used. Because it is a constant, 8, this evaluates to f(6) = 8.

Step-by-step explanation:

what do you mean "what's the answer for this ?"

you only need to put 3 in place of x (that's what is meant by "x is 3" or x = 3) and then simply calculate.

you know what "squaring" ("something to the power of 2" or x²) means ? it means that you have to multiply that "something" by itself.

y = 3² + 11 = 3×3 + 11 = 9 + 11 = 20

that's all there is to this.

Step-by-step explanation:

[tex]\frac{rise}{run}[/tex]

Initially, as X increases, Y stays constant.

Then, between x = 3 and x = 5, the graph rises by 4 and runs by 2, or rises by 2 and runs by 1, so the slope is 2.

Between x = 5 and x = 9, the graph "rises" by -1 and runs by 1, so the slope is -1.

The greatest value of y is 4 at x = 5. (5, 4)

Answer:

Initially, as x increases, y remains constant.

Afterward, the slope of the graph of the function is equal to 2 for all x between x = 3 and x = 5.

The slope of the graph is equal to -1 between x = 5 and x = 9.

The greatest value of y = 4, and it occurs when x = 5.

Step-by-step explanation:

Slope = [tex]\frac{rise}{run}[/tex]

The rise is how much it increases by y (up or down), and the run is how much it increases by x (right or left).

From 3-5 the slope = [tex]\frac{4}{2}[/tex] =  2 → it goes up 2 units for every one unit right.

From 5-9 the slope = [tex]\frac{-4}{4}[/tex] = -1 → it goes down (-) 1 unit for every one unit right.

The reflection of the triangle JKL across the line x = 4 is equivalent to

equivalent to flipping the preimage across the line x = 4.

The correct coordinates are;

[tex]\underline{J'(7, \, -1)}[/tex]

[tex]\underline{K'(6, \, 3)}[/tex]

[tex]\underline{L'(5, -2)}[/tex]

Reasons:

The given transformation is a reflection about the line x = 4

The points of triangle JKL are J(1, -1), K(2, 3), and L(3, -2), in the line x = 4

Distance between x-coordinate of the point J and the line x = 4 is 4 - 1 = 3

Which gives;

Distance between x-coordinate of the point J' and the line x = 4 is 4 + 3 = 7

Therefore, the coordinate of the point J' is [tex]\underline{J'(7, \, -1)}[/tex]

Similarly, we have;

Distance between x-coordinate of the point K and the line x = 4 is 4 - 2 = 2

Distance between x-coordinate of the point K' and the line x = 4 is 4 + 2 = 6

The coordinate of the point K' is [tex]\underline{K'(6, \, 3)}[/tex]

Distance between x-coordinate of the point L and the line x = 4 is 4 - 2 = 2

Distance between x-coordinate of the point L' and the line x = 4 is 4 + 2 = 6

The coordinate of the point L' is  [tex]\underline{L'(5, -2)}[/tex]

Learn more here:

https://brainly.com/question/24758871

The answer is 7

Step-by-step explanation:

subtract 4 from 25 which is 21 than divide by 3 getting x =7

Answer:

x=7

Step-by-step explanation:

3x+4=25

3x=25–4

3x=21

X=21÷3

X=7

Answer:

100 meters is 8.6 meters longer than 100 yards.

Step-by-step explanation:

Conversion of yards to meters.

Each yard has 0.914 meters.

So 100 yards is 100*0.9144 = 91.4 meters.

How many meters longer to the nearest tenth is 100 meters than 100 yards?

100 yards = 91.4 meters

100 - 91.4 = 8.6

So 100 meters is 8.6 meters longer than 100 yards.

Answer:

x = -2

Step-by-step explanation:

5x + 2(x - 4) = 5x + x - 10

→ Expand the brackets

5x + 2x - 8 = 5x + x - 10

→ Collect the x terms

7x - 8 = 6x - 10

→ Minus 6x from both sides

x - 8 = -10

→ Add -8 to both sides

x = -2

Number of marbles with Mallika = x

Number of marbles with Kishore = x (same number of marbles)

To get 100 marbles = x + x + 30

=》x + x + 30 = 100

2x + 30 = 100

2x = 100 - 30

2x = 70

x = 70/2

x = 35

■ Final answer =》Mallika & Kishore both have 35 marbles each.

■ Equation =》2x + 30 = 100

■ Equation type =》Linear equation in 1 variable

______

Hope it helps ⚜

The equation for the given situation will be;

⇒ 2x + 30 = 100

Where, 'x' is represent the number of marbles.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Mallika and Kishore have the same number of marbles.

And, To have 100 marbles they must pool their marbles together and then get 30 more.

Now,

Since, Mallika and Kishore have the same number of marbles.

Hence, Let the number of marbles = x

So, We can formulate;

⇒ x + x + 30 = 100

⇒ 2x + 30 = 100

⇒ 2x = 100 - 30

⇒ 2x = 70

⇒ x = 35

Thus, Number of marbles each have = 35

And, The equation for the given situation will be;

⇒ 2x + 30 = 100

Where, 'x' is represent the number of marbles.

Learn more about the mathematical expression visit:

brainly.com/question/1859113

#SPJ2

Answer:

f(x)= 40x

Step-by-step explanation:

Hope this helps, have a nice day/night! :D

Answer:

D Option is the correct one.

Step-by-step explanation:

As,

Distance covered = 40km = 40000m(1k=1000m)

time = 10:15-9:00 = 1:15hours = 75mins

We need to find the rates of the bicyclist in one hour so, for this first we need to calculate the total distance which covered in one hour.

For calculating distance for one hour,

40000/75 = 533.33m/min (means they covered 533.33m distance in one min)

for one hour:

533.33*60= 32000m = 32km

They covered 32km distance in one hour.

Now from the given options D is the correct one because according to give condition north bicyclist covered 4km more that south one. And other reason is we also need to check the sum of distance covered by the both cyclist which must be equal to 32km.

So for A,

Sum = 19 + 15 =34 (wrong not equal to 32)

For B,

Sum = 18 + 13 = 31 (wrong)

For C,

Sum = 16 + 10 = 26(wrong)

For D,

Sum = 18 + 14 = 32 (Right)

And second distance b/w both distance is 4km.

18-14 = 4(Right)

So, D option is the right one.

I hope it will help you.

Answer: 1.133333

Step-by-step explanation:

The value of the expression [tex]\frac{17}{15}[/tex] .

Simplification means simplifying processes involved in work towards consistency of efforts, costs and time. Fraction questions in mathematics frequently require lengthy calculations and complicated sums. Some pupils find it more challenging and require more time to solve. But don't worry—there is a solution for you in this article on math simplification. It will assist you in finding simple ways to simplify fractions. You'll discover what simplification is, how and where to simplify fractions, and the procedures involved in simplifying fractions in this article. Additionally, you'll learn the exact steps to take.

Here, do normal simplification using BODMAS rule.

Hence, the required value is [tex]\frac{17}{15}[/tex]

Learn more about simplification from given link

https://brainly.com/question/432678

#SPJ2

Answer:

1) 11c

2) 9m - 14

3) 4x - 5

-----

4) x = 4

5) x = 2

Step-by-step explanation:

1)

10c + c

11c

2)

5m + 2( 2m - 7 )

5m + 4m - 14

9m - 14

3)

6x - ( 2x + 5 )

6x - 2x - 5

4x - 5

-----

4)

3x + 7 = -5

3x = 12

x = 4

5)

18 = 4x + 10

8 = 4x

2 = x

Hopefully this helps!

Brainliest please?

Answer:

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

     [] Since is the line is going up from bottom-left to top-right, we know it will be positive

     [] Because this graph has distinctive coordinate-points, we can use rise over run

     () The other method is to use the change in y divided by the change in x

We start at (-2, 0), then count 2 up and 3 over to get to (2, 1) which gives us a slope of 2/3

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

[tex] \mathsf{ \frac{m + 21}{5} = n }[/tex]

Step-by-step explanation:

To make "n" the subject of the formula, rearrange the formula so it begins with " n = "

To isolate the variable "n", you need to inverse the other terms on that side of the equation where "n" really is.

=> m = 5n - 21

=> m + 21 = 5n - 21 + 21

=> m+ 21 = 5n

[tex] \mathsf{ \frac{m + 21}{5} = n }[/tex]

Answer:

5. w ≠ 8

Step-by-step explanation:

#1 is the expression for "The amount of water is greater than eight ounces."  This technically means it differs from eight ounces, but it's too specific for what the question is asking.

#2 is the expression for "The amount of water is greater than or equal to eight ounces." It doesn't necessarily differ from eight ounces.

#3 is the expression for "The amount of water is less than eight ounces."  Same issue as #1.

#4 is the expression for "The amount of water is greater than eight ounces."  Same issue as #2.

#5 is the expression for "The amount of water is not equal to eight ounces." This is the correct expression as the only information we know is that it's not eight ounces.

Answer:

48=2^4x3

Step-by-step explanation:

48=2x2x2x2x3

48=2^4x3

Hope this helps :)

Given:

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).

(a)If we translate  quadrilateral JKLM 3 units down and 3 units left:

(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)

Therefore, we match it with: A translation 3 units down and 3 units left

(b)If we translate  quadrilateral JKLM 2 units right and 3 units down:

(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)

Therefore, we match it with:A translation 2 units right and 3 units down

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:

A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)

(d)If we translate  quadrilateral JKLM 3 units left and 2 units up:

(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)

Therefore, we match it with: A translation 3 units left and 2 units up

(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

No suitable transformation is found from JKLM to STUV.

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).

(a)If we translate quadrilateral JKLM 3 units down and 3 units left:

(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)

Therefore, we match it with: A translation 3 units down and 3 units left

(b)If we translate quadrilateral JKLM 2 units right and 3 units down:

(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)

Therefore, we match it with:A translation 2 units right and 3 units down

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:

A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)

(d)If we translate quadrilateral JKLM 3 units left and 2 units up:

(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)

Therefore, we match it with: A translation 3 units left and 2 units up

(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

No suitable transformation is found from JKLM to STUV.

Answer:

-10u-10

Step-by-step explanation: