Mathematics College

Sluiten
1.) Band A charges $800 to play for the evening and Band B charges $450 plus $1.25 per student.
a. Write a system of equations to represent the costs of the two bands. Use y for total cost and use x for
number of students.
Band A

Answers

Answer 1

Answer:

[tex]y = 800[/tex] ---- Band A

[tex]y = 450 + 1.25x[/tex] --- Band B

Step-by-step explanation:

Given

Band A:

[tex]Charges = \$800[/tex] per student

Band B:

[tex]Charges = \$450[/tex]

[tex]Rate = \$1.25[/tex] per student

Required

Write an equation for the system?

For band A, the given charges is irrespective of number of students.

So, the total cost y is:

[tex]y = 800[/tex]

For band B, the total y is calculated as thus:

y = Base Charges + Rate * Number of students (x)

[tex]y = 450 + 1.25 * x[/tex]

[tex]y = 450 + 1.25x[/tex]

So, the charges for the bands are:

[tex]y = 800[/tex] ---- Band A

[tex]y = 450 + 1.25x[/tex] --- Band B

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Chocolate total = $10.59
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Yehshshebsbsjsbbabanana

Subtract. Express your answer in simplest form.
5
ထ |
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O
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Answer:

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Answers

Answer:

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Step-by-step explanation:

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a. True or false?

Answers

Answer:

True

Step-by-step explanation:

44 x 10 = 440

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Answers

Step-by-step explanation:

−x

4

+(4×23)x

3

x+

x

10

−5

2 Simplify 4\times 234×23 to 9292.

-{x}^{4}+92{x}^{3}x+\frac{10}{x}-5−x

4

+92x

3

x+

x

10

−5

3 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

-{x}^{4}+92{x}^{3+1}+\frac{10}{x}-5−x

4

+92x

3+1

+

x

10

−5

4 Simplify 3+13+1 to 44.

-{x}^{4}+92{x}^{4}+\frac{10}{x}-5−x

4

+92x

4

+

x

10

−5

5 Collect like terms.

(-{x}^{4}+92{x}^{4})+\frac{10}{x}-5(−x

4

+92x

4

)+

x

10

−5

6 Simplify.

91{x}^{4}+\frac{10}{x}-591x

4

+

x

10

−5

Done

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Answers

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Answer:

Step-by-step explanation:

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Next subtract 1 from 1, which is 0.

Now add 4+4, which is 8.

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

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