SHOW YOUR WORK FOR EACH ONE!


5. 10(x − 1)

6) −7(1 + 4x)

7) 7(−v − 7)

8) 7(2 − x)

9) 4(−7 − x)

10) 5(k − 5)

Answer:

The double shaded region

Answer:

1

Step-by-step explanation:

As you can see when you list out the factors of each number, 1 is the greatest number that 5, 6, and 15 divides into.

Answer:

0

Step-by-step explanation:

Zero is a rational number, and we know that the integer 0 can be written in any one of the following forms. ... Thus, 0 can be written as, where a/b = 0, where a = 0 and b is any non-zero integer. Hence, 0 is a rational number and not an integer.

Step-by-step explanation:

refer to the picture.. hope this helps :)

Answer:

10

Step-by-step explanation:

Firstly, AM=x+8

or, A=x+8-M......eqn (i)

MB=6x-2

or, B=6x-2-M......eqn (ii)

Now,

from eqn (i) and (ii)

x+8-M=6x-2-M

or, 8+2=6x-x-M+M

or, 10=5x

or, 10÷5=x

therefore, x=2

Again,

MB=6x-2

=6×2-2

=12-2

=10

is it correct

please mark me as BRAINLIEST

Answer:

plus ten points huh i only see five

Step-by-step explanation:

Answer:

|-x| + 3

Step-by-step explanation:

I say that because -x will be turned into positive x and then add the 3, and you will get the answer.

Answer:

5%

Step-by-step explanation:

To find the sales tax rate, you would divide the tax by the cost to see the percentage of the tax.

$750 / $37.50= 0.05

The answer is 5%

Hope this helps

Answer:

C

Step-by-step explanation:

SA of a cylinder formula:

A=2πrh+2πr^2

A=2π(3)(15)+2π(3)^2

A=339.29in^2

Hope that helps

Answer:

Step-by-step explanation:

Hi there!

From the given figure;

Radius(r) = 3 inch

Height (h) = 15 inch

Now;

Total surface area (TSA) = 2πr(r+h)

                              TSA = 2*([tex]\frac{22}{7}[/tex])*3(3+15)

                               TSA = [tex]\frac{132}{7}[/tex]*18

                               TSA = 339.42in².

Therefore,  the answer is option c (339.29in²).

Hope it helps!

Answer:

20?.... seems right to me.

Step-by-step explanation:

9514 1404 393

Answer:

  20 kg

Step-by-step explanation:

The mass of the chicken and pork for 1 week is (2 kg) +(3 kg) = 5 kg.

Normally, we think of a month as 4 weeks.

  (4 wk)(5 kg/wk) = 20 kg

If pork and chicken are consumed at the same rate for 4 weeks, the family will consume 20 kg of pork and chicken.

_____

If we consider a year to be 52 weeks (it is actually 1 or 2 days longer), then the number of weeks in an average month is ...

  52/12 = 4 1/3 weeks/month

Multiplying that value by 5 kg/week will give 21 2/3 kg per month.

__

The answer depends on the assumption you make about weeks in a month.

Answer:

23,208 is the final answer.

Hope this helps!

Answer:

23,208

Hopefully this is correct

Answer: scale to measure the weight

Step-by-step explanation:

Answer:

8 + 8 + 16 5 * 3 is 15 16 + 15 is 31 that is the answer to the question

Answer:

Δ ABD ≅ Δ CBD  SSS

Step-by-step explanation:

AB ≅ CB                  Given                                

AD ≅ DC                  Given                                

BD ≅ BD                  Reflexive property      

Δ ABD ≅ Δ CBD      SSS      

62 Miles per Hour =

90.933333 Feet per Second

(rounded to 8 digits)

Answer: 12

Plug 6 and 4 into the problem-

6(6 + 2)/4

6(8)/4

48/4 = 12

Hey there!

6(g + 2) / h

= 6(6 + 2) / 4

= 6(8) / 4

= 8(6) / 4

= 8 + 8 + 8 + 8 + 8 + 8 / 4

= 16 + 16 + 16 / 4

= 32 + 16 / 4

= 48 / 4

= 48 ÷ 4 / 4 ÷ 4

= 12 / 1

= 12 ÷ 1

= 12

Therefore, your answer is: 12

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Step-by-step explanation:

m1=-2

m1m2=-1

-2m2=-1

m2=1/2

y+5/x+4=1/2

so 2y+10=x+4

2y-x=-6

Answer:

[tex]y=\frac{1}{2}x-3[/tex]

Step-by-step explanation:

Hi there!

We are given the equation y=-2x+5 and we want to find the equation of the line that is perpendicular to that line, and pass through the point (-4, -5)

Perpendicular lines have slopes that multiply to get -1.

So to find the slope of the perpendicular line: use the formula [tex]m_1*m_2=-1[/tex], where [tex]m_1=-2[/tex]

Substitute:

-2m=-1

Divide both sides by -2

m=[tex]\frac{1}{2}[/tex]

Here's the equation of the line so far, as we know it, written in slope-intercept form (y=mx+b, where m is the slope and b is the y intercept):

[tex]y=\frac{1}{2}x+b[/tex]

We need to find b.

Because we know the line passes through the point (-4, -5), we can use it to help solve for b.

Substitute -4 as x and -5 as y

[tex]-5=\frac{1}{2}(-4)+b[/tex]

Multiply:

-5=-2+b

Add 2 to both sides

-3=b

Substitute -3 as b:

y=[tex]\frac{1}{2}x-3[/tex]

Hope this helps!

Answer:

They both have the same y intercept

Step-by-step explanation:

(1,0)(0,3)

(0,3)(1,-1)

Answer:

⁴/2

Step-by-step explanation:

because is I solveng to be a good

brainliest me

Answer:

Common ratio is - 4 / 2.

Step-by-step explanation:

Sequence = - 2, 4, - 8, 16, - 32, ....

Let the terms be " a ".

Here,

a1 = 2

a2 = 4

a3 = - 8

a4 = 16

a5 = - 32

Let the common ratio be " r ".

r1 = a2 / a1

= 4 / - 2

r1 = - 2

r2 = a3 / a2

= - 8 / 4

r2 = - 2

r3 = a4 / a3

= 16 / - 8

r3 = - 2

r4 = a5 / q4

= - 32 / 16

r4 = - 2

Since, the common ratios are same,

Therefore, r = - 2

- 4 / 2 = - 2

So, - 2 can also be written as - 4 / 2.

Hence,

r = - 4 / 2

Finally,

Common ratio ( r ) = - 4 / 2

Answer:

letter B.

Step-by-step explanation:

5.5ft

hope it helps you

The correct proof that proves that BE ≅ CF is the proof in option C. (see attachment).

Recall the following:

The isosceles triangle ABC given is shown in the image attached below.

To prove that, BE ≅ CF, establish the fact that △ABE ≅ △ACF by the AAS Congruence Theorem.

Since △ABE ≅ △ACF, therefore BE ≅ CF by the CPCTC Theorem.

Thus, the correct proof that proves that BE ≅ CF is the proof in option C. (see attachment).

Learn more about AAS Congruence Theorem on:

https://brainly.com/question/3168048

Answer: G is -1/3

Step-by-step explanation:

1. Given

2. Given

3. Alternate Interior Angles

4. Reflexive Property

5. SAS

Hope this helps!! :)

https://brainly.com/invite/3caaa23db4167cc1029ce1999a411bee?utm_source=invite&utm_medium=link&utm_campaign=bfp_parental_feed&utm_term=parent

Answer:

angle L = 100 degrees

angle M = 110 degrees

angle N = 70 degrees

angle P = 80 degrees

Step-by-step explanation:

find value of 'x' then substitute into each of the four angle expressions

to find 'x', add all expressions and set them equal to 360 (there are 360 degrees in any four-sided polygon)

2x + 20 + 3x - 10 + 2x - 10 + 2x = 360

combine 'like' terms to get:

9x = 360

x = 40

angle L = 2(40) + 20 = 100 degrees

angle M = 3(40) - 10 = 110 degrees

angle N = 2(40) - 10 = 70 degrees

angle P = 2(40) = 80 degrees

Check:

100 + 110 + 70 + 80 = 360

Answer:

jjjjnnuiuhjiihhiihb

Step-by-step explanation:

tyuijiojnoo.

yu8ijhiihj

Answer:

Step-by-step explanation:

Let the number of student tickets is s and general admission tickets - g.

Set equations and solve:

Double the first equation and subtract from the second to eliminate s:

Find s:

Let the student tickerts and general tickets be x and y respectively

From (1) put in (2)

And

Answer:

2.511 square kilometers

[tex] \green{\large\underline{\sf{Solution-}}}[/tex]

Given expression is

[tex]\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } [/tex]

can be rewritten as

[tex]\rm \:  =  \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} } [/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\ [/tex]

And

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\ [/tex]

So, using this identity, we

[tex]\rm \:  =  \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} } [/tex]

can be further rewritten as

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{25 - 1} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{24} [/tex]

[tex]\rm \:  =  \: \dfrac{1}{6} [/tex]

Hence,

[tex]\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}[/tex]