The simplex matrix using the linear programming problem gives optimal solution x = 12.5, y = 0, with objective function value f = 9(12.5) + 3(0) = 112.5
To set up the simplex matrix for the given linear programming problem, we need to introduce slack variables for each inequality constraint and form the initial tableau as follows:
Basic Variables x y s1 s2 RHS
s1 2 3 1 0 300
s2 1 4 0 1 200
z -9 -3 0 0 0
In this tableau, x and y are the decision variables, s1 and s2 are the slack variables, and z is the objective function.
We start with the coefficients of the decision variables in the objective function, which are -9 and -3. We choose the variable with the most negative coefficient to enter the basis, which is y in this case.
To determine which variable to exit the basis, we calculate the ratio of the right-hand side (RHS) value to the coefficient of the entering variable for each constraint. The smallest nonnegative ratio corresponds to the variable that will exit the basis.
For the y variable, we have the following ratios:
s1: 300/3 = 100
s2: 200/4 = 50
Since the ratio for s2 is smaller, we choose s2 to exit the basis. To pivot, we divide the second row by 4 and perform row operations to eliminate the y variable from the other rows:
Basic Variables x y s1 s2 RHS
s1 2 0 1 -3/4 50
y 1/4 1 0 1/4 50
z -9/4 0 0 9/4 225
The new entering variable is x, with coefficient -9/4 in the objective function. The ratios for x are:
s1: 50/2 = 25
y: 50/(1/4) = 200
Therefore, y exits the basis and we pivot on the (2,1) element:
Basic Variables x y s1 s2 RHS
s1 1/2 0 1/2 -3/8 25
x 1/8 1 -1/8 1/8 12.5
z -9/8 0 9/8 9/8 237.5
The optimal solution is x = 12.5, y = 0, with objective function value f = 9(12.5) + 3(0) = 112.5
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Determine the intercepts of the line.
Do not round your answers.
y+5=2(x+1)
4:14=14:?
What does ? equal to
How tall, in cm, is the stack of 8 cups?
cm
2
How tall, in cm, is 1 cup? Explain how you determined the height of 1 cup.
Your teacher thinks that instead of having to figure out these stacks each time, it would be useful to understand the general relationship.
Write an equation expressing the relationship between the height of the stack and the number of cups in the stack.
Let h represent the height of the stack, in cm, and n the number of cups in the stack.
The equation shows that the height of the stack is directly proportional to the number of cups in the stack, with a proportionality constant of 2 cm.
The stack of 8 cups is 16 cm tall.
To determine the height of 1 cup, we can divide the height of the stack (16 cm) by the number of cups (8):
1 cup = 16 cm ÷ 8 cups = 2 cm
The general relationship between the height of the stack (h) and the number of cups in the stack (n) can be expressed as:
h = n × 2 cm
Thus, this equation shows that the height of the stack is directly proportional to the number of cups in the stack, with a proportionality constant of 2 cm.
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GEOMETRY PLEASE HELP!!
A point is chosen at random in the large square shown below. Find the. probability that the point is in the smaller, shaded square. Each side of the large square is 17 cm, and each side of the shaded square is 6 cm.
Round your answer to the nearest hundredth.
Answer:
To find the probability that the point is in the smaller shaded square, we need to compare the area of the shaded square to the area of the large square.
The area of the large square is 17 cm x 17 cm = 289 cm^2.
The area of the shaded square is 6 cm x 6 cm = 36 cm^2.
Therefore, the probability that a randomly chosen point is in the shaded square is:
Probability = Area of shaded square / Area of large square
Probability = 36 cm^2 / 289 cm^2
Probability = 0.1241 (rounded to four decimal places)
Rounding to the nearest hundredth, the probability is approximately 0.12.
Therefore, the probability that the point is in the smaller, shaded square is 0.12.
REALLY NEEDS HELP IF YOU HAVE THE WHOLE QUIZ ANSWERES ID LOVE YOU FOR IT!!!!!!!
the table includes results from polygraph experiments in each case it was known if the subject lied or did not lie, so the table indicates when the polygraph test was correct find the test statistic needed to test the claim that whether a subject lies or does not lie is independent of poly graph test indication
Okay, let's break this down step-by-step:
We have data on whether a subject lied (L) or told the truth (T), and whether the polygraph test indicated they lied (L) or told the truth (T).
So we have 4 possible outcomes:
LL: Subject lied, test indicated lied
LT: Subject lied, test indicated truth
TL: Subject told truth, test indicated lied
TT: Subject told truth, test indicated truth
We want to test the null hypothesis that a subject's truthfulness is independent of the polygraph test result.
So we need to calculate a test statistic that would allow us to determine if the observed frequencies of the 4 outcomes deviate significantly from what we would expect if the null hypothesis is true.
A good test for this is the chi-square test of independence. Here are the steps:
1) Calculate the expected frequency for each cell, assuming independence. This is (row total * column total) / total sample size.
2) Calculate the observed frequency for each cell from the data.
3) Square the difference between observed and expected for each cell.
4) Sum the squared differences across all cells. This gives you the chi-square statistic.
5) Compare the chi-square statistic to the critical value for 3 degrees of freedom at your desired alpha level (typically 0.05).
If the chi-square statistic exceeds the critical value, we reject the null hypothesis of independence. Otherwise, we fail to reject it.
Does this make sense? Let me know if you have any other questions! I can also walk you through an example if this would be helpful.
Let x1, x2, x3, be i.i.d. with exponential distribution exp(1). Find the joint pdf of y1 = x1/x2, y2 = x3/(x1 x2), and y3=x1 x2. are they mutually independent?
The joint pdf of y1, y2, and y3 is f(y1, y2, y3) = 2[tex]e^(^-^y^1^-^y^3^)[/tex](y1y3)⁻². They are not mutually independent, as their joint pdf cannot be factored into individual pdfs of y1, y2, and y3.
To find the joint pdf, first note the transformations: x1 = y3/y1, x2 = y3/y2, and x3 = y1y2y3. The Jacobian of this transformation is |J| = |(∂(x1, x2, x3)/∂(y1, y2, y3))| = |2y1y2y3²|.
Next, find the joint pdf of x1, x2, and x3: f(x1, x2, x3) = [tex]e^-^x^1e^-^x^2e^-^x^3[/tex] , since they are i.i.d. with exp(1) distribution. Now, apply the transformation and Jacobian: f(y1, y2, y3) = f(x1, x2, x3)|J| = [tex]e^-^x^1e^-^x^2e^-^x^3[/tex] (2y1y2y3²) = 2[tex]e^(^-^y^1^-^y^3^)[/tex](y1y3)⁻². As the joint pdf cannot be factored into individual pdfs of y1, y2, and y3, they are not mutually independent.
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Find the amount of money required for fencing (outfield, foul area, and back stop), dirt (batters box, pitcher’s mound, infield, and warning track), and grass sod (infield, outfield, foul areas, and backstop). Need answers for each area.
The amount of fencing, dirt and sod for the baseball field are: length of Fencing & 1410.5 ft. Area of the sod ≈ 118017.13ft² Area of the field covered with distance ≈ 7049.6ft²
How did we determine the values?Area of a circle = πr²
Circumference of a circle = 2πr
where r is the radius of the circle
The area of a Quarter of a circle is therefore;
Area of a circle/ 4
The perimeter of a Quarter of a Circle is;
The perimeter of a circle/4
Fencing = ¼ x 2 x π x 380 + 2 x 15 +2 x 380 + ¼ x 2 x π x 15
Fencing = 197.5π + 190π = 1410.5 feet.
Grass =
π/4 x (380 - 6)² + 87 ² - π/4 × (87 + 30)² + 2 x 380 x 15 + π/4 x 15² - (3/4) x π x 10² - 25π
= 31528π + 18969 = 118017.13
The area Covered by the sod is about 118017.13Sq ft.
Dirt = π/4 x 380 ² - π/4 x (380 - 6)² + π/4 (87 + 30)² - 87² + π100 = (18613π - 30276)/4
= 7049.6
Therefore, the area occupied by the dirt is about 7049.6 Sq ft.
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write an equation of the ellipse centered at (4, 1) if its minor axis is 8 units long and its major axis is 10 units long and parallel to the x-axis.
The equation of the ellipse centered at (4, 1) with a minor axis of 8 units and a major axis of 10 units parallel to the x-axis is: (x - 4)²/25 + (y - 1)²/16 = 1
To write the equation of the ellipse centered at (4, 1) with a minor axis of 8 units, a major axis of 10 units, and parallel to the x-axis.
We will use the standard equation of an ellipse in the form:
(x - h)²/a² + (y - k)²/b² = 1
Here, (h, k) represents the center of the ellipse, a is the semi-major axis, and b is the semi-minor axis.
Given that the ellipse is centered at (4, 1), we have h = 4 and k = 1.
Since the major axis is 10 units long and parallel to the x-axis, the semi-major axis a is half of that, which is 5 units.
Similarly, the minor axis is 8 units long, so the semi-minor axis b is half of that, which is 4 units.
Now, we can plug these values into the standard equation of an ellipse:
(x - 4)²/5² + (y - 1)²/4² = 1
Simplify the equation to:
(x - 4)²/25 + (y - 1)²/16 = 1
The equation of the ellipse centered at (4, 1) with a minor axis of 8 units and a major axis of 10 units parallel to the x-axis is:
(x - 4)²/25 + (y - 1)²/16 = 1
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Help! I DONT GET THIS AT ALL?!
Whoever answers I give points.
Solving Two step inequalities
Which inequality statement below is false? Explain.
(1). 6>6 (3). -4 < 15
(2). 10<10 (4). 3 < 7/2
Please help! And if you do thank you!
Answer:
Number 3 and 4 are correct, but I have no clue about 1 or 2.
Step-by-step explanation:
I'm just gonna start with number 4
if you put 7/2 into decimals you get 3.5 7/2 is greater than 3
number 3. -4 is in the negative zone, so it is less than 15 which is positive
if I were you, I would guess that number 1 is false. but i cant be sure
Find the general solution to the homogeneous differential equation:
(d2y/dt2)−18(dy/dt)+97y=0
The general solution to the homogeneous differential equation (d²y/dt²)−18(dy/dt)+97y=0 is y(t) = C₁ [tex]e^3^t[/tex] cos(8t) + C₂ [tex]e^3^t[/tex]sin(8t).
To solve the given differential equation, first, we need to find the characteristic equation by replacing d²y/dt² with r², dy/dt with r, and y with 1. This gives us the quadratic equation r² - 18r + 97 = 0.
Next, find the roots of the characteristic equation using the quadratic formula, which yields r = 3 ± 8i.
Since the roots are complex conjugates, the general solution to the homogeneous differential equation takes the form y(t) = [tex]e^\alpha^t[/tex](C₁cos(βt) + C₂sin(βt)), where α and β are the real and imaginary parts of the complex roots, respectively. In this case, α = 3 and β = 8. Substituting these values, we obtain the general solution y(t) = C₁ [tex]e^3^t[/tex]cos(8t) + C₂ [tex]e^3^t[/tex]sin(8t).
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Question Progress
Homework Progress
Find the exact values of the following, giving your answers as fractions
a) 4¹
b) 2³
c) 3
The exact values using law of negative exponents and reciprocals are:
a) 4⁻¹ = 1/4
b) 2⁻³ = 1/8
c) 3⁻⁴ = 1/81
How to find the reciprocal of numbers?The law of negative exponents and reciprocals states that:
Any non-zero number that is raised to a negative power will be equal to its reciprocal raised to the opposite positive power. This means that, an expression raised to a negative exponent will be equal to 1 divided by the expression with the sign of the exponent changed.
a) The number is given as: 4⁻¹
Applying the law of negative exponents and reciprocals, we have:
4⁻¹ = 1/4¹
= 1/4
b) The number is given as: 2⁻³
Applying the law of negative exponents and reciprocals, we have:
2⁻³ = 1/2³
= 1/8
c) The number is given as: 3⁻⁴
Applying the law of negative exponents and reciprocals, we have:
3⁻⁴ = 1/3⁴
= 1/81
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Correct question is:
Find the exact values of the following, giving your answers as fractions
a) 4⁻¹
b) 2⁻³
c) 3⁻⁴
Calculate the dimensions of the room on the blueprint.For a painting, the ratio of the length to the width is 5:3. The painting is 45 cm wide.
How long is the painting?
can you teach me how to solve it?
The painting is 75 cm long, if the painting is 45 cm wide.
From the question, we have the following parameters that can be used in our computation:
Ratio of the length to the width is 5:3. T
This means that
Length : Width = 5 : 3
The painting is 45 cm wide.
So, we have
Length : 45 = 5 : 3
Express as a fraction
So, we have
Length/45 = 5/3
Evaluate the above expression
so, we have the following representation
Length = 75
Hence, the length is 75
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A company's profit increased linearly from $6 million at the end of 1 year to $14 million at the end of year 3. (a) Use the two (year, profit) data points (1, 6) and (3, 14) to find the linear relationship y = mx + b between × = year and y = profit. (b) Find the company's profit at the end of 2 years. (c) Predict the company's profit at the end of 5 years.
The linear relationship between x = year and y = profit is y = 4x + 2.
The company's profit at the end of 2 years is $10 million.
The company's profit at the end of 5 years is $22 million.
How to determine an equation of this line?In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical expression:
y - y₁ = m(x - x₁)
Where:
x and y represent the data points.m represent the slope.First of all, we would determine the slope of this line;
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = (14 - 6)/(3 - 1)
Slope (m) = 8/2
Slope (m) = 4
At data point (1, 6) and a slope of 4, a linear equation for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - 6 = 4(x - 1)
y = 4x - 4 + 6
y = 4x + 2
When x = 2 years, the profit is given by;
y = 4(2) + 2 = $10 million
When x = 5 years, the profit is given by;
y = 4(5) + 2 = $22 million.
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Given the differential equation x^2y??+5xy?+4y=0 , determine the general solution that is valid in any interval not including the singular point and specify the singular point. The given equation looks like an Euler equation to me, but I'm not sure what to do with it or how to find the singular point.
The given differential equation is an Euler equation, the general solution is y = c1 + c2/[tex]x^4[/tex] and the singular point of the differential equation is x = 0
How to find the general solution and singular point?You are correct, this is an Euler equation. To solve it, we can make the substitution y = [tex]x^r[/tex]. Then we have:
y? = r[tex]x^(^r^-^1^)[/tex]y?? = r(r-1)[tex]x^(^r^-^2^)[/tex]Substituting these into the original equation, we get:
x²(r(r-1)[tex]x^(^r^-^2^)[/tex]) + 5x(r[tex]x^(^r^-^2^)[/tex]) + 4[tex]x^r[/tex]= 0
Simplifying, we have:
r(r+4)[tex]x^r[/tex] = 0
Since [tex]x^r[/tex] is never zero, we must have r(r+4) = 0. This gives us two possible values for r: r = 0 and r = -4.
For r = 0, we have y = c1, where c1 is an arbitrary constant.For r = -4, we have y = c2/[tex]x^4[/tex], where c2 is another arbitrary constant.Thus, the general solution is:
y = c1 + c2/[tex]x^4[/tex]
This solution is valid in any interval not including the singular point x = 0, which is the singular point of the differential equation.
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Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter.
x = e^sqrt(t)
y = t - ln t2
t = 1
y(x) =
Answer:
y(x) = -(2/e)x +3
Step-by-step explanation:
You want the equation of the line tangent to the parametric curve at t=1.
(x, y) = (e^(√t), t -2·ln(t))
PointAt t=1, the point of tangency is ...
(x, y) = (e^(√1), 1 -2·ln(1)) = (e, 1)
SlopeThe derivatives with respect to t are found using the chain rule:
dx = d(e^u)du = d(e^√t)(1/(2√t))dt
dx = (e^√t)/(2√t))·dt
dy = (1 -2/t)·dt
Then the slope of the tangent line is ...
m = dy/dx = (1 -2/t)(2√t)/e^√t
For t=1, this is ...
m = (1 -2/1)(2√1)/(e^1) = -2/e
Point-slope equationThe equation for a line with slope m through point (h, k) is ...
y = m(x -h) +k
The equation for a line with slope -2/e through point (e, 1) is ...
y = (-2/e)(x -e) +1
y = (-2/e)x +3
Answer:
y(x) = -(2/e)x +3
Step-by-step explanation:
You want the equation of the line tangent to the parametric curve at t=1.
(x, y) = (e^(√t), t -2·ln(t))
PointAt t=1, the point of tangency is ...
(x, y) = (e^(√1), 1 -2·ln(1)) = (e, 1)
SlopeThe derivatives with respect to t are found using the chain rule:
dx = d(e^u)du = d(e^√t)(1/(2√t))dt
dx = (e^√t)/(2√t))·dt
dy = (1 -2/t)·dt
Then the slope of the tangent line is ...
m = dy/dx = (1 -2/t)(2√t)/e^√t
For t=1, this is ...
m = (1 -2/1)(2√1)/(e^1) = -2/e
Point-slope equationThe equation for a line with slope m through point (h, k) is ...
y = m(x -h) +k
The equation for a line with slope -2/e through point (e, 1) is ...
y = (-2/e)(x -e) +1
y = (-2/e)x +3
Find the open interval(s) wher the followign function is increasing, decreasing, or constant. Express your answer in interval notation.
The open interval where the function is increasing at (-∞, ∞), decreasing at 0, or constant at 3.
Here we have the graph and through the graph we have to find the open interval(s) where the following function is increasing, decreasing, or constant.
While we looking into the give graph we have identified that the function of the graph is determined as.
=> y = 3x + 2
To determine whether the function y = 3x + 2 is increasing, decreasing, or constant, we can analyze its first derivative.
The first derivative of y = 3x + 2 is y' = 3.
As the first derivative is a constant (y' = 3), the original function is continuously increasing for all values of x, and there are no intervals in which it is decreasing or constant.
Thus, the open interval where y = 3x + 2 is increasing is (-∞, ∞).
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Find the value of x.
X
7 feet
43.2°
(triangle)
The calculated value of x in the triangle is 4.79 feet
Finding the value of x in the triangleFrom the question, we have the following parameters that can be used in our computation:
X
7 feet
43.2°
The value of x in the triangle can be calcuated using the following sine rule
sin(43.2) = x/7
Make x the subject of the above equation
So, we have
x = 7 * sin(43.2)
Evaluate the products
x = 4.79
Hence, the value of x is 4.79 feet
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express the number as a ratio of integers. 0.19 = 0.19191919
We can express 0.19 as the ratio of integers 1919/10000 and the repeating decimal 0.19191919... as the ratio of integers 1919/1000000.
To express the number 0.19 as a ratio of integers, we can use a technique called repeating decimals. We can see that 0.19191919... has a repeating block of two digits, which is 19. To express this as a ratio of integers, we can assign a variable to the repeating block, say x. We can then write:For more such question on integers
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Find the solution of the given initial value problem.
y'' + 4y = sint - u2π(t)sin(t - 2π) where y(0) = 3 and y'(0) = 6.
I've gotten to that point, what I'm having troubles with isbreaking them up. Like the partial fractional decompositon ofeach part. So far for 1/(s^2+4)(s^2+1) I have gotten theLaplace to be -(1/6)sint but I don't know if that's right. I'm not sure how to apply the partial fraction to e^-2(pi)s. And for (3s+6)/(s^2+4) do I have to do the 3s and 6separately?
For the term 1/(s²+4)(s²+1), the partial fraction decomposition would be A/(s²+4) + B/(s²+1), where A and B are constants that can be solved using algebraic equations.
The Laplace transform of e^(-2πs)sin(t-2π) is (s/(s²+1)² + 4π/(s²+1)). For the term (3s+6)/(s²+4), you can separate it into 3s/(s²+4) and 6/(s²+4), and their Laplace transforms would be (3/2)cos(2t) and (3/2)sin(2t), respectively. Once you have the Laplace transforms for each term, you can use linearity of Laplace transforms to get the solution of the given initial value problem.
Laplace transforms are a mathematical tool used to transform a function of time into a function of complex frequency. This transformation allows for the solving of differential equations, particularly those with initial conditions, by converting them into algebraic equations that can be easily solved.
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Need help with this…
The ratio of their areas is (3:8)² which simplifies to 9:64.
Area of smaller circle is 256/9 π.
The ratio of their perimeters is 5:3 since they are regular polygons with proportional side lengths.
How to calculate the ratioThe ratio of the areas of two similar polygons is equal to the square of the ratio of their corresponding sides. Since the scale factor of the polygons is 3:8, the ratio of their corresponding sides is 3:8. Therefore, the ratio of their areas is (3:8)^2, which simplifies to 9:64.
The area of a circle is proportional to the square of its radius. Let r be the radius of the smaller circle, then the radius of the larger circle is 3/2 times r. The area of the larger circle is given as 64π, so (3/2)^2 times the area of the smaller circle must also equal 64π. Solving for the area of the smaller circle, we get:
(9/4)πr^2 = 64π
r^2 = (64/9) * (4/π)
r^2 = 256/9π
Area of smaller circle = πr^2 = π * (256/9π) = 256/9 π.
The ratio of the areas of two regular polygons is equal to the square of the ratio of their side lengths. Let s1 and s2 be the side lengths of the first and second pentagons, respectively. Then we have:
Area of first pentagon / Area of second pentagon = (s1^2 / s2^2)
We are given the areas of the two pentagons, so we can plug them in and simplify:
150√3 / 54√3 = (s1² / s2²)
25 / 9 = (s1^2 / s2^2)
s1 / s2 = √(25/9) = 5/3
Therefore, the ratio of their perimeters is 5:3 since they are regular polygons with proportional side lengths.
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Calculate the standard score of the given X value, X = 77.4 where µ = 79.2 and σ = 74.4 and indicate on the curve where z will be located. Round the standard score to two decimal places.
Rounding to two decimal places, the standard score is -0.02 when the mean µ = 79.2 and standard deviation σ = 74.4
What is the standard score?The standard score, also known as the z-score, is a measure of how many standard deviations a given data point is away from the mean of a distribution. It is calculated by subtracting the mean from the data point and then dividing the difference by the standard deviation:
z = (X - µ) / σ
where X is the data point, µ is the mean of the distribution, and σ is the standard deviation.
What is the standard deviation?The standard deviation is a statistical measure that represents the amount of variation or dispersion in a set of data. It is the square root of the variance, which is the average of the squared deviations of each data point from the mean.
The formula for calculating the standard deviation is:
σ = sqrt [ Σ ( Xi - µ )² / N ]
where σ is the standard deviation, Xi is each data point, µ is the mean of the data, and N is the number of data points.
According to the given informationThe formula for calculating the standard score (z-score) is:
z = (X - µ) / σ
where X is the given value, µ is the mean, and σ is the standard deviation.
Substituting the given values, we get:
z = (77.4 - 79.2) / 74.4
z = -0.024
Rounding to two decimal places, the standard score is -0.02.
To indicate the location of z on the curve, we can use a graph of the standard normal distribution to locate z. A z-score of -0.02 corresponds to a point on the curve that is slight to the left of the mean, but still very close to it. This can be seen on a graph of the standard normal distribution, where the mean is located at the center of the curve.
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2074-Set B Q.No. 20 Following information are provided related to wages: Monthly working days Hourly output..... Required: Total wage amount of the worker 26 days 4 units following particulars are given Working hour per day Wage rate per unit 8 hours .Rs. 10 [2] Ans: Rs. 8,320
Complete compensation= 832 individual items x Rs10/unit coming out to be: Rs. 8320
How to solveTo determine the aggregate salary of a laborer, we will begin by computing the whole quantity of units manufactured per calendar month and then increase it by the wage rate for each unit.
Total units produced every month:
Monthly business days = 26
Productivity every hour = 4 individual items
Quantity of daily working hours = 8 hours
Units generated in one day = Productivity every hour multiplied by the Quantity of daily working hours
Units generated in one day are equal to 4 units/hour x 8 hours/day totalling= 32 individual items/day
Whole number units made each month = Units produced every day multiplied Monthly occupation days
Entire units produced each calendar month are equivalent to 32 individual items/day x 26 days which equals= 832 individual items/month.
The wage rate obtained receives Rs.10/individual item
Full pay gained is ascertained using Total units produced every month multiplied Wage rate Ruppees/Rs.10 for every unit.
Complete compensation= 832 individual items x Rs10/unit coming out to be: Rs. 8320
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given that z is a standard normal random variable, what is the probability that 1.20 ≤ z ≤ 1.85
4678 .
3849 .
8527 .
0829
the probability that 1.20 ≤ z ≤ 1.85 is approximately 0.0822.To find the probability that 1.20 ≤ z ≤ 1.85, we need to use the standard normal distribution table or calculator.
First, we find the area to the left of 1.85 in the standard normal distribution table, which is 0.9671. Then, we find the area to the left of 1.20 in the standard normal distribution table, which is 0.8849.
To find the probability that 1.20 ≤ z ≤ 1.85, we subtract the area to the left of 1.20 from the area to the left of 1.85:
0.9671 - 0.8849 = 0.0822
Therefore, the probability that 1.20 ≤ z ≤ 1.85 is approximately 0.0822.
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An implicit equation for the plane passing through the points (-5,0,5), (-5,-5,0) and (-8,-5,10) is ?
An implicit equation for the plane passing through the points (-5,0,5), (-5,-5,0), and (-8,-5,10) is x - 5y + 3z - 5 = 0.
To find the equation of a plane passing through three points, we can use the following formula:
(x - x1)(y2 - y1)(z3 - z1) + (y - y1)(z2 - z1)(x3 - x1) + (z - z1)(x2 - x1)(y3 - y1) = (x2 - x1)(y3 - y1)(z3 - z1) + (y2 - y1)(z3 - z1)(x3 - x1) + (z2 - z1)(x3 - x1)(y3 - y1)
where (x1, y1, z1), (x2, y2, z2), and (x3, y3, z3) are the given points.
Substituting the given values, we get:
(x + 5)(-5)(10) + (y - 0)(-5)(-8) + (z - 5)(-5)(0) = (y + 5)(-5)(10) + (z - 0)(-5)(-8) + (x + 5)(-5)(0)
Simplifying this equation, we get:
-50x + 50y - 50z + 250 = 0
Dividing both sides by -50, we get:
x - 5y + 3z - 5 = 0
Hence, the implicit equation for the plane passing through the points (-5,0,5), (-5,-5,0), and (-8,-5,10) is x - 5y + 3z - 5 = 0.
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Solve each exponential growth/decay word problem
A savings account balance is compounded
annually. If the interest rate is 2% per
year and the current balance is $1,557.00,
what will the balance be 5 years from
now?
Answer:
$1.720.34
Step-by-step explanation:
to do this problem we can use the exponential growth formula A=p(1+r)^t
substituting our values we get
A = 1,557.00(1+0.02)^5
after solving the equation for A we get that
A after 5 years will be $1,720.34
PROBLEM 4 A group of four friends goes to a restaurant for dinner. The restaurant offers 12 different main dishes. (i) Suppose that the group collectively orders four different dishes to share. The waiter just needs to place all four dishes in the center of the table. How many different possible orders are there for the group? (ii) Suppose that each individual orders a main course. The waiter must re- member who ordered which dish as part of the order. It's possible for more than one person to order the same dish. How many different possible orders are there for the group? How many different passwords are there that contain only digits and lower-case letters and satisfy the given restrictions? (i) Length is 7 and the password must contain at least one digit. (ii) Length is 7 and the password must contain at least one digit and at least one letter.
In Problem 4, there are (i) 495 different possible orders for the group when they collectively order four different dishes to share, and (ii) 20,736 different possible orders for the group when each individual orders a main course.
(i) To find the number of ways to order four different dishes out of 12, we use combinations. This is calculated as C(12,4) = 12! / (4! * (12-4)!), which equals 495 possible orders.
(ii) Since there are 12 dishes and each of the four friends can choose any dish, we use permutations. The number of possible orders is 12⁴, which equals 20,736 different orders.
For passwords, there are (i) 306,380,448 passwords of length 7 with at least one digit, and (ii) 282,475,249 passwords of length 7 with at least one digit and one letter.
(i) There are 10 digits and 26 lowercase letters. Total possibilities are (10+26)⁷. Subtract the number of all-letter passwords: 26^7. Result is (36⁷) - (26⁷) = 306,380,448.
(ii) Subtract the number of all-digit passwords from the previous result: 306,380,448 - (10⁷) = 282,475,249 different passwords.
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1. Find the net change in the value of the function between the given inputs.
f(x) = 6x − 5; from 1 to 6
2. Find the net change in the value of the function between the given inputs.
g(t) = 1 − t2; from −4 to 9
1)The net change in the value of the function f(x) = 6x - 5 between the given inputs 1 and 6 is 30.
2)The net change in the value of the function g(t) = 1 - t² between the given inputs -4 and 9 is -65.
1. To find the net change in the value of the function f(x) = 6x - 5 between the given inputs 1 and 6:
Follow these steps:
Step 1: Calculate f(1)
f(1) = 6(1) - 5 = 6 - 5 = 1
Step 2: Calculate f(6)
f(6) = 6(6) - 5 = 36 - 5 = 31
Step 3: Find the net change
Net change = f(6) - f(1) = 31 - 1 = 30
The net change in the value of the function f(x) = 6x - 5 between the given inputs 1 and 6 is 30.
2. To find the net change in the value of the function g(t) = 1 - t² between the given inputs -4 and 9:
Follow these steps:
Step 1: Calculate g(-4)
g(-4) = 1 - (-4)² = 1 - 16 = -15
Step 2: Calculate g(9)
g(9) = 1 - 9² = 1 - 81 = -80
Step 3: Find the net change
Net change = g(9) - g(-4) = -80 - (-15) = -80 + 15 = -65
The net change in the value of the function g(t) = 1 - t² between the given inputs -4 and 9 is -65.
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ind the values of k for which the system has a nontrivial solution. (Enter your answers as a comma-separated list.)
x1 + kx2 = 0
kx1 + 9x2 = 0
In linear algebra, the determinant is a scalar value that can be computed from a square matrix.
To find the values of k for which the system has a nontrivial solution, we need to first analyze the given system of linear equations:
x1 + kx2 = 0
kx1 + 9x2 = 0
A nontrivial solution means there exists a solution where x1 and x2 are not both equal to zero. We can find such solutions by finding the determinant of the coefficients matrix and setting it equal to zero:
| 1 k |
| k 9 |
The determinant is calculated as follows:
Determinant = (1 * 9) - (k * k) = 9 - k^2
For a nontrivial solution, the determinant must be equal to zero:
9 - k^2 = 0
Now, solve for k:
k^2 = 9
k = ±3
So the values of k for which the system has a nontrivial solution are k = -3 and k = 3. Your answer: -3, 3
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25. find the exact value of each expression. a. cos(-10pi/3)
The exact value of the expression cos(-10pi/3) is -1/2.
How to find the exact value of the expression?To find the exact value of cos(-10pi/3), follow these steps:
1. Determine the equivalent positive angle: Since the cosine function has a period of 2pi, we can add multiples of 2pi to the angle until we get a positive angle. In this case, we add 4pi (since 4pi = 12pi/3) to get the equivalent positive angle:
(-10pi/3) + (12pi/3) = 2pi/3.
2. Find the cosine value of the positive angle: Now, we find the cosine value of the positive angle 2pi/3. Using the unit circle, we can determine that cos(2pi/3) = -1/2.
So, the exact value of the expression cos(-10pi/3) is -1/2.
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I dont understand so an explanation would be amazing
Answer: 7≤x≤9
Step-by-step explanation:
Explanation is in image but i forgot to write final answer form. It's up top.