Se midió el pH de una muestra del agua de lluvia en la ciudad de México, y se obtuvo un valor de 3.5 Calcula la [H+] en dicha muestra.

The percent by mass of the solution made from 17 g sodium chloride, NaCl (the solute) and 59 g water is 22.4%

First, we shall obtain the mass of the solution. Details below:

Mass of solution = Mass of NaCl + mass of water

Mass of solution = 17 + 59

Mass of solution = 76 grams

Finally, we shall determine the percent by mass of the solution. Details below:

Percent by mass = (mass of NaCl / mass of solution) × 100

= (17 / 76) × 100

= 22.4%

Thus, the percent by mass of the solution is 22.4%

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Answer:

The variable Q

Explanation:

i just took the test and got it right.... i hope this helps :)

The variable Q represents thermal energy in the equation Q = mcΔT. Hence, option B is correct.

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Q =  mcΔT

Q = heat energy

m = mass

c = specific heat capacity

ΔT = change in temperature

Hence, option B is correct.

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Answer: False

Explanation: just took on edge

The value of Qc for the given solution is approximately 3.67425e⁻⁶.

To find the value of Qc (the reaction quotient) for the given solution, we need to determine the concentrations of the respective ions and use them to calculate Qc.

The balanced equation for the dissolution of lead(II) chloride (PbCl₂) in water is:

PbCl₂(s) ⇌ Pb²⁺(aq) + 2Cl⁻(aq)

From this equation, we can see that one mole of PbCl₂ dissociates to yield one mole of Pb²⁺ ions and two moles of Cl⁻ ions.

Given that the concentration of lead(II) nitrate (Pb(NO₃)₂) is 1.82e⁻⁴ M and the concentration of sodium chloride (NaCl) is 2.25e⁻² M, we can use the stoichiometry of the balanced equation to determine the concentrations of Pb²⁺ and Cl⁻ ions.

Since lead(II) nitrate dissociates completely, the concentration of Pb²⁺ ions is equal to the concentration of lead(II) nitrate:

[Pb²⁺] = 1.82e⁻⁴ M

Sodium chloride dissociates into one mole of Na⁺ ions and one mole of Cl⁻ ions. Since we're interested in the concentration of Cl⁻ ions, we'll use the given concentration of NaCl to calculate it:

[Cl⁻] = 2 * 2.25e⁻² M

      = 4.5e⁻² M

Now, we can write the expression for Qc using the concentrations of the respective ions:

Qc = [Pb²⁺][Cl⁻]²

Putting in the values we obtained:

Qc = (1.82e⁻⁴ M)(4.5e⁻² M)²

   = 1.82e⁻⁴ (20.25e⁻⁴)

   = 36.7425e⁻⁸  

Simplifying the expression:

Qc = 3.67425e⁻⁶

Therefore, the value of Qc for the given solution is approximately 3.67425e⁻⁶.

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Given, the balanced chemical equation is:

2 NH₃(g) → N₂(g) + 3 H₂(g)

The absolute magnitude of the rate of change for [NH₃] is 4.35 m/s.

Therefore, option A is the correct answer.

Given, the balanced chemical equation is:

2 NH₃(g) → N₂(g) + 3 H₂(g)

The rate of change for H2 is 8.70 m/s.

To find the absolute magnitude of the rate of change for [NH₃], we have to use the stoichiometric coefficient in the balanced chemical equation. From the balanced chemical equation, 2 mol NH₃ reacts with 3 mol H₂

We can write,

Rate of change of NH₃ (in m/s) = -1/2 * rate of change of H₂ (in m/s)

So,Rate of change of NH₃ = -1/2 * 8.70 m/s= -4.35 m/s

The absolute magnitude of the rate of change for [NH₃] is 4.35 m/s.

Therefore, option A is the correct answer.

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The best statement that describes the reflection of a wave is: When a wave reflects off a surface, it retains its characteristics and changes direction.

A wave is defined as a disturbance that moves through space and matter with the transfer of energy from one place to another. When the wave moves from one medium to another, it reflects off the surface. Reflection of a wave is described as the change in the direction of the wave when it bounces back from the surface on which it strikes.

When a wave reflects off a surface, the angle of incidence is equal to the angle of reflection, which is known as the law of reflection. The normal line, which is perpendicular to the surface, splits the incident and reflected waves at the point of incidence. The angle between the normal line and the incident wave is the angle of incidence, and the angle between the normal line and the reflected wave is the angle of reflection.

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Given :

A compound is found to be made up of 3.21 g Carbon and 1.02 g Oxygen.

To Find :

The percent composition from this data.

Solution :

We know, percentage composition is given by :

[tex]\%mass = \dfrac{mass}{mass of compound}\times 100[/tex]

So, percentage composition of Carbon is :

[tex]\%Carbon = \dfrac{3.21}{3.21+1.02}\times 100\\\\\%Carbon = \dfrac{3.21}{4.23}\times 100\\\\\%Carbon = 75.89 \%[/tex]

Since, compound is made up of Carbon and Oxygen.

So, %Oxygen is ( 100 - 75.89 )% = 24.11%

Hence, this is the required solution.

Answer: it is an importtant resource because it is what keeps most things alive in earth.

Explanation:

The structure of compound X is likely 2-Methyl-1-butene (CH3CH=C(CH3)CH2CH3) to yield a product without chirality centers during hydroboration-oxidation.

a. Suggesting three possible structures for compound X (C5H10) can involve considering different isomers of pentane and pentene. Here are three possibilities:

Pentane: CH3CH2CH2CH2CH3

2-Methylbutane: CH3CH(CH3)CH2CH3

2-Methyl-1-butene: CH3CH=C(CH3)CH2CH3

These structures satisfy the molecular formula C5H10 and represent different isomeric possibilities for compound X.

b. Hydroboration-oxidation of compound X yields a product with no chirality centers. This suggests that compound X must be an alkene with a symmetric or non-chiral structure. Among the three possible structures suggested above, the alkene 2-Methyl-1-butene (CH3CH=C(CH3)CH2CH3) would result in a product with no chirality centers when subjected to hydroboration-oxidation.

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The reaction between CdSO₄ and K₂S is a precipitation reaction where cadmium sulfide precipitates as a solid, while potassium sulfate remains in the aqueous form.

a) The "(s)" in the chemical equation CdS(s) represents that cadmium sulfide is a solid precipitate. It indicates that the product formed in the reaction is solid.

b) The chemical equation for the dissolution of cadmium sulfate (CdSO₄) in water is:

CdSO₄(s) → Cd²⁺(aq) + SO₄²⁻(aq)

The chemical equation for the dissolution of potassium sulfide (K₂S) in water is:

K₂S(s) → 2K⁺(aq) + S²⁻(aq)

c) The difference between potassium sulfate being aqueous (K₂SO₄(aq)) and cadmium sulfide being a solid (CdS(s)) lies in their solubility in water. Potassium sulfate is soluble in water, meaning it dissolves and dissociates into its respective ions (K⁺ and SO₄²⁻) in the solution. On the other hand, cadmium sulfide is insoluble in water and forms a solid precipitate, indicating that it does not dissolve but instead forms solid particles.

In the lab, the difference can be observed by visual inspection. When the reaction between CdSO₄ and K₂S takes place, a yellow precipitate of cadmium sulfide will form, indicating the presence of the solid. The potassium sulfate, being in an aqueous form, will remain dissolved and not form any visible solid.

d) The name for this type of reaction is a precipitation reaction or double displacement reaction. In this reaction, the ions from two compounds exchange to form an insoluble solid (precipitate) and a soluble compound.

In the given reaction between CdSO₄ and K₂S, cadmium sulfide (CdS) is the insoluble solid (precipitate), and potassium sulfate (K₂SO₄) is the soluble compound formed in solution.

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Answer:

algae

Explanation:

fish and herons arent herbivores

Herbivores are typically tagged as animals that feeds directly on the plants in a food chain.

In the given food chain, Fish is the herbivore

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The standard enthalpy change for the given reaction is approximately -156.87 kJ.

To calculate the standard enthalpy change (ΔH°) for the given reaction using standard heats of formation, the balanced equation for the reaction is:

Fe(s) + 2HCl(aq) → [tex]FeCl_2[/tex](s) + [tex]H_2[/tex](g)

The standard heats of formation (ΔH°f) for the compounds involved are as follows:

Fe(s): 0 kJ/mol

HCl(aq): -92.31 kJ/mol (source: NIST Chemistry WebBook)

[tex]FeCl_2[/tex](s): -341.49 kJ/mol (source: NIST Chemistry WebBook)

[tex]H_2[/tex](g): 0 kJ/mol

Now, let's calculate the standard enthalpy change (ΔH°):

ΔH° = Σ(ΔH°f products) - Σ(ΔH°f reactants)

ΔH° = [ΔH°f([tex]FeCl_2[/tex]) + ΔH°f([tex]H_2[/tex])] - [ΔH°f(Fe) + 2ΔH°f(HCl)]

ΔH° = [-341.49 kJ/mol + 0 kJ/mol] - [0 kJ/mol + 2(-92.31 kJ/mol)]

ΔH° = -341.49 kJ/mol + 2(92.31 kJ/mol)

ΔH° = -341.49 kJ/mol + 184.62 kJ/mol

ΔH° = -156.87 kJ/mol

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The formula of the coordination compound lithium pentacyanocobaltate(II) is [LiCo(CN)₅]²⁻.

What is lithium pentacyanocobaltate(II) ?

Pentacyanocobaltate attracted attention as an early example of a metal complex that reacts with hydrogen. It contains low-spin cobalt(II) with a doublet ground state.

Let's break down the formula to understand its components:

The central metal ion is cobalt (Co) in the +2 oxidation state, denoted as Co(II).

The ligands are pentacyanocobaltate, which means there are five cyanide ligands (CN⁻) bonded to the cobalt ion.

The coordination complex is negatively charged, with a charge of 2-, so it requires two lithium ions (Li⁺) as counter ions to balance the charge.

Therefore, the complete formula is [LiCo(CN)₅]²⁻, where the square brackets indicate the coordination complex and the superscript 2- indicates the charge.

The formula of the coordination compound pentaamminechlorocobalt(III) nitrate is [Co(NH₃)₅Cl]NO₃.

Breaking down the formula:

The central metal ion is cobalt (Co) in the +3 oxidation state, denoted as Co(III).

The ligands are pentaamminechlorocobalt, indicating there are five ammonia ligands (NH₃) and one chloride ligand (Cl⁻) bonded to the cobalt ion.

There is no need for any counter ions to balance the charge in this compound.

Thus, the complete formula is [Co(NH₃)₅Cl]NO₃, where the square brackets denote the coordination complex, and NO₃ indicates the presence of nitrate ions as the counter ions.

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Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 40.51 g is the mass of 2.31x10²³ formula units of SrF[tex]_2[/tex].

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. It measure the number of elementary entities of a given substance that are present in a given sample.

Given number of atoms= 2.31x10²³atoms

we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number

mole =given number of atoms ÷ 6.022×10²³(Avogadro number)

Substituting the values

mole= 2.31x10²³÷ 6.022×10²³

mole = 0.38 moles of SrF[tex]_2[/tex]

mass of SrF[tex]_2[/tex]= moles of SrF[tex]_2[/tex] × Molar mass of SrF[tex]_2[/tex]

mass of SrF[tex]_2[/tex]= 0.38  × 106.6184

mass of SrF[tex]_2[/tex] = 40.51 g

Therefore, 40.51 g is the mass of 2.31x10²³ formula units of SrF[tex]_2[/tex].

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The one that cannot be metabolised to make molecules that can enter the citric acid cycle is d. metal ions.

Carbohydrates, lipids, and proteins can all be metabolized to produce molecules that can enter the citric acid cycle (also known as the Krebs cycle or TCA cycle). These molecules can be converted into acetyl-CoA, a key intermediate in the citric acid cycle, through various metabolic pathways.

Carbohydrates can be broken down into glucose, which can then undergo glycolysis to produce pyruvate. Pyruvate can be further converted into acetyl-CoA, which enters the citric acid cycle.

Lipids (fats) can be hydrolyzed to release fatty acids and glycerol. Fatty acids are broken down through beta-oxidation, resulting in the production of acetyl-CoA. Glycerol can also be converted into glyceraldehyde-3-phosphate, an intermediate in glycolysis that can generate pyruvate and subsequently acetyl-CoA.

Proteins can be broken down into amino acids through protein digestion and cellular processes such as proteolysis. Amino acids can enter various metabolic pathways, some of which lead to the production of intermediates that can feed into the citric acid cycle.

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Answer:

0.642 g

Explanation:

La ecuación balanceada es:

Primero convertimos 1.89 g de Cu₂O en moles, usando su masa molar:

Después convertimos moles de Cu₂O en moles de Mg, usando los coeficientes estequiométricos:

Finalmente convertimos moles de Mg en gramos, usando la masa molar de Mg:

The oxidation number of bromine in the HBrO molecule is +1. Bromine usually has multiple oxidation states, and in HBrO, it has an oxidation state of +1, the correct answer is b.

This can be determined by assigning oxidation numbers to the other atoms in the molecule and applying the rules for assigning oxidation numbers. In HBrO, hydrogen (H) has an oxidation state of +1, and oxygen (O) typically has an oxidation state of -2. Since the sum of oxidation numbers in a neutral molecule is zero, the oxidation number of bromine (Br) is determined to be +1.

To further explain, oxidation numbers represent the hypothetical charge an atom would have if all the bonds were purely ionic. In HBrO, hydrogen (H) is typically assigned an oxidation state of +1, as it usually donates its one valence electron to form a single bond. Oxygen (O) is generally assigned an oxidation state of -2, as it commonly accepts two electrons to complete its valence shell. The sum of the oxidation numbers in HBrO is then +1 for hydrogen and -2 for oxygen, resulting in a net oxidation number of -1. Since the molecule is neutral, the oxidation number of bromine (Br) must be +1 to balance the charges and achieve a total oxidation number of zero. Therefore, the correct answer is b. +1.

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Answer:

A Liquid

Explanation:

structure with large distance (gas) than goes to a loosely ordered state (liquid)

I hope this helps

Answer:

200J

Explanation:

This is because 500J - 300J = 200J

I hope this helps!!!

Answer:

1700 Joules. I Took the test.

Explanation:

The number of hydrogen atoms required to convert all of the oxygen atoms into nitric acid is 6000.

One molecule of nitric acid has a formula of HNO3, containing one nitrogen atom, one hydrogen atom, and three oxygen atoms. Therefore, if there are 6000 nitrogen atoms and 6000 oxygen atoms present, this means that there are 6000/3 = 2000 nitric acid molecules. Each nitric acid molecule has one hydrogen atom. Therefore, to convert all 6000 oxygen atoms into nitric acid, we need 3 times as many hydrogen atoms, which is 3 x 2000 = 6000 hydrogen atoms. This is because each molecule of nitric acid requires three oxygen atoms and one hydrogen atom.So, the number of hydrogen atoms required to convert all of the oxygen atoms into nitric acid is 6000.

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Answer:

D

Explanation:

pressure is inversely proportional to gas volume

Answer:

Where is the chemical equations?

A balanced equation obeys the law of conservation of mass. The coefficient represent the number of molecules in a chemical equation.

An equation in which the number of reactants and products on the both sides of the reaction are equal can be defined as the balanced chemical equation. The coefficient are the numbers in front of the formula.

The coefficients are the numbers that must be added in front of the species involved in the reaction in order to balance it. It tells how many number of atoms or molecules are present in a reaction.

In the reaction N₂ + 3H₂ → 2NH₃ which is called Haber's process.

The coefficients are:

1 for Nitrogen molecule, 3 for Hydrogen molecule and 2 for the compound Ammonia.

Thus coefficients are numbers in front of each formula.

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13.1 g of KBr is required to produce 429.5 mL of a 0.256 M solution of KBr.

To calculate the mass of solute required to produce 429.5 mL of a 0.256 M solution of KBr, we can use the formula below;

Mass of solute = Molarity × Volume (liters) × Molecular weight of solute

We can also convert the volume of the solution from milliliters to liters by dividing by 1000.

Thus,429.5 mL = 429.5/1000 = 0.4295 Liters

Therefore,

Mass of KBr required = Molarity × Volume × Molecular weight of KBr= 0.256 mol/L × 0.4295 L × 119 g/mol= 13.1 g KBr

Thus, 13.1 g of KBr is required to produce 429.5 mL of a 0.256 M solution of KBr.

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The new pressure of the gas is [tex]45.906 torr.[/tex]

To calculate the new pressure:

[tex]P2 = P1 * (T2 / T1)[/tex]

where:

P1 is the initial pressure[tex](32.6 torr)[/tex]

T1 is the initial temperature [tex](735 K)[/tex]

P2 is the final pressure (unknown)

T2 is the final temperature [tex](1035 K)[/tex]

Substituting the values into the formula, we get:

[tex]P2 = 32.6 torr * (1035 K / 735 K)[/tex]

[tex]P2 = 45.906 torr[/tex]

Therefore, the new pressure of the gas is [tex]45.906 torr.[/tex]

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The Kb expression for the reaction of propylamine, C3H7NH2, with water is [C3H7NH2][C3H7NH+3][OH−] . Hence, option (c) is correct.

The Kb expression for the reaction of propylamine (C3H7NH2) with water can be determined by considering the equilibrium between the amine (C3H7NH2) and its conjugate acid (C3H7NH+3) with hydroxide ions (OH−) in water. The reaction can be represented as follows:

C3H7NH2 + H2O ⇌ C3H7NH+3 + OH−

The equilibrium constant expression for this reaction, Kb, is given by the product of the concentrations of the products (C3H7NH+3 and OH−) divided by the concentration of the reactant (C3H7NH2):

Kb = [C3H7NH+3][OH−] / [C3H7NH2]

Therefore, the correct Kb expression for the reaction is [C3H7NH2][C3H7NH+3][OH−] (option c).

The Kb expression for the reaction of propylamine, C3H7NH2, with water is [C3H7NH2][C3H7NH+3][OH−] (option c).

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Answer:

In a titration, you determine an unknown concentration of a sample by adding a second reactant of known concentration. In many titrations, you use a chemical called an indicator, which lets you know when the titration finishes.

Explanation:

Answer: I honestly think it might be C

Explanation: Collisions between objects are governed by laws of momentum and energy. When a collision occurs in an isolated system, the total momentum of the system of objects is conserved. ... In the collision between the two cars, total system momentum is conserved.

Answer: C. The total momentum after the collision is equal to the total momentum before the collision.

Hope this helps

Explanation: Collisions between objects are governed by laws of momentum and energy. When a collision occurs in an isolated system, the total momentum of the system of objects is conserved. ... In the collision between the two cars, total system momentum is conserved.