The inicial number of jobs is 63.1 thousand, and each year this number will decrease by 1.7 thousand.
So the change from 2008 to 2018, that is, 10 years, will be:
[tex]10\cdot(-1.7)=-17[/tex]To find the change in percentage, we need to divide the change (-17) by the inicial amount of jobs (63.1), then we have that:
[tex]\frac{-17}{63.1}=-0.27=-27\text{\%}[/tex]So the change in this period is -27%, therefore the answer is B.
8. Find the slope between (-5, 4) & (0,3). * O m = 1/5 O O m = -5 m = 5 O m = -1/5
We can determine the slope using the following expression:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Now, using the two points given, we have:
[tex]m=\frac{3-4}{0-(-5)}\Rightarrow m=-\frac{1}{5}[/tex]From this, we have that the slope(m) equals -1/5.
Use the ALEKS calculator to write as a percentage.
31
32
Round your answer to the nearest tenth of a percent.
0%
X 5
?
Divide 31 into 32 and then multiply the result by 100 to get the percent:
[tex]\begin{gathered} \frac{31}{32}=0.96875 \\ \\ 0.96875*100=96.875 \end{gathered}[/tex]Then, to the nearest tenth of a percent the given fraction is 96.9%What is the slope of a line that passes the points (-1,4 ) and ( 3,9 ) ?
Answer:
slope = 5/4
Step-by-step explanation:
What is the slope of a line that passes the points (-1,4 ) and ( 3,9 ) ?
slope = change in y ÷ change in x
slope = (9-4) ÷ (3 - (-1))
slope = 5/4
The figure shows a quarter circle and an equilateral triangle. What is thearea of the shaded part? Give your answer to 3 significant figures. (Take it= 3.14.)7 cm
Since the triangle is equilateral, all of its interior angles have a measure of 60º.
Substract the area of the triangle from the area of a circular sector with radius 7cm enclosed by an angle of 60º to find the area of the shaded region.
The area of an equilateral triangle with side length L is:
[tex]A=\frac{\sqrt[]{3}}{4}L^2[/tex]The area of a circular sector of radius r enclosed by an angle of θ degrees is:
[tex]A=\frac{\theta}{360}\times\pi r^2[/tex]Replace θ=60 and r=7cm to find the area of the circular sector:
[tex]A_c=\frac{60}{360}\times3.14\times(7\operatorname{cm})^2=25.643\ldots cm^2[/tex]Replace L=7cm to find the area of the triangle:
[tex]A_T=\frac{\sqrt[]{3}}{4}\times(7\operatorname{cm})^2=21.2176\ldots cm^2[/tex]Then, the area of the shaded region is:
[tex]\begin{gathered} A_C-A_T=25.6433\ldots cm^2-21.2176\ldots cm^2 \\ =4.4257\ldots cm^2 \\ \approx4.43\operatorname{cm}^2 \end{gathered}[/tex]Therefore, the area of the shaded region to 3 significant figures, is:
[tex]4.43\operatorname{cm}^2[/tex]i need help with this problem
Answer:
whats the problme?
Step-by-step explanation:
Evaluate. 5[83–(8-1)²]
5 [ 83- (8-1)²]
we will first work on the inner parenthesis
5 [ 83 - (7)²]
5[ 83 - 49]
5[34]
=170
use the two given points and calculate the slope.(6,4),(4,-1)
EXPLANATION:
Given;
We are given two points which are shown below;
[tex]\begin{gathered} (6,4) \\ (4,-1) \end{gathered}[/tex]Required;
We are required to calculate the slope.
Step-by-step solution;
To calculate the slope given two points, we shall use the following formula;
[tex]\begin{gathered} Slope: \\ m=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]Where the variables are;
[tex]\begin{gathered} (x_1,y_1)=(6,4) \\ (x_2,y_2)=(4,-1) \end{gathered}[/tex]We can now substitute these values and solve;
[tex]m=\frac{-1-4}{4-6}[/tex][tex]m=\frac{-5}{-2}[/tex][tex]m=\frac{5}{2}[/tex]Therefore.
ANSWER:
[tex]m=\frac{5}{2}[/tex]What’s the correct answer answer asap for brainlist
Answer:
A. a chorus
Step-by-step explanation:
A shop repairs 4 types of electronic devices. The number of repairs of each device last week is shown in the bar graph below. Use this bar graph to answer the questions.
Answer:
a) Telephone; 2 repairs
b) 3 more repairs
c) computer, radio , and television = 3 types
Explanation:
From the bar graph we see that the least amount of repairs done to the telephones. How many r
I'll send a picture! please answer fast!
Given data:
The given expression for the points is,
[tex]10w-3t+5[/tex]Thus, the expression or
Jamar finds some nickels and quarters in his change purse. How much money (in cents) does he have if he has 4 nickels and 11 quarters? How much money (in cents) does he have if he has n nickels and q quarters?
1 nickel is worth 5 cents and 1 quarter is worth 25 cents.
So, if he has 4 nickels, this is worth 4 times 5 cents and if he has 11 quarters, this is worth 11 times 25 cents.
Both are worth the sum of these, so:
[tex]4\cdot5+11\cdot25=20+275=295[/tex]So, he has 295 cents.
If he has n nickels and q quarters, he has 5 times n plus 25 times q worth, so he has:
[tex]5n+25q[/tex]For each relation, decide whether or not it is a function.
Relation 1: Yes, each input corresponds to only one output.
Relation 2: No, the input of -1 corresponds to two outputs: sun and moon.
Relation 3: Yes, each input corresponds to only one output.
Relation 4: Yes, each input corresponds to only one output.
Select the correct answer. What is the solution to the equation? (x - 2)^1/2 + 4 = x A. -3 and -6 B. 3 and 6 C. -3 D. 6
Answer:
D. x = 6
Step-by-step explanation:
Given equation:
[tex](x-2)^{\frac{1}{2}}+4=x[/tex]
Subtract 4 from both sides:
[tex]\implies (x-2)^{\frac{1}{2}}+4-4=x-4[/tex]
[tex]\implies (x-2)^{\frac{1}{2}}=x-4[/tex]
Square both sides:
[tex]\implies \left( (x-2)^{\frac{1}{2}}\right)^2=(x-4)^2[/tex]
[tex]\implies x-2=(x-4)^2[/tex]
Expand the brackets on the right side:
[tex]\implies x-2=(x-4)(x-4)[/tex]
[tex]\implies x-2=x^2-8x+16[/tex]
Subtract x from both sides:
[tex]\implies x-2-x=x^2-8x+16-x[/tex]
[tex]\implies -2=x^2-9x+16[/tex]
Add 2 to both sides:
[tex]\implies -2+2=x^2-9x+16+2[/tex]
[tex]\implies 0=x^2-9x+18[/tex]
[tex]\implies x^2-9x+18=0[/tex]
Factor the left side of the equation:
[tex]\implies x^2-6x-3x+18=0[/tex]
[tex]\implies x(x-6)-3(x-6)=0[/tex]
[tex]\implies (x-3)(x-6)=0[/tex]
Apply the zero-product property:
[tex]\implies x-3=0 \implies x=3[/tex]
[tex]\implies x-6=0\implies x=6[/tex]
Therefore, the solutions of the quadratic equation are:
[tex]x=3, \quad x=6[/tex]
Input both solutions into the original equation to check their validity:
[tex]\begin{aligned}x=3 \implies (3-2)^{\frac{1}{2}}+4&=3\\(1)^{\frac{1}{2}}+4&=3\\1+4&=3\\5&=3\end{aligned}[/tex]
[tex]\begin{aligned}x=6 \implies (6-2)^{\frac{1}{2}}+4&=6\\(4)^{\frac{1}{2}}+4&=6\\2+4&=6\\6&=6\end{aligned}[/tex]
Therefore, the only valid solution to the given equation is x = 6.
Answer:
The answer is D. 6
Step-by-step explanation:
Add both sides:
(x - 2)^1/2 + 4 + (-4) = x + (-4)
(x - 2)^1/2 = -4
Solve exponent:
(x - 2)^1/2 = x - 4
((x - 2)^1/2)^2 = (x - 4)^2
x − 2 = x^2 − 8x + 16
x − 2 − (x^2 − 8x + 16) = x^2 − 8x + 16 − (x^2 − 8x + 16)
−x^2 + 9x − 18 = 0
(−x + 3)(x − 6) = 0
−x + 3 = 0 or x − 6 = 0
x = 3 or x = 6
Check the answers: (Plug them in to see what will work.)
x = 3 (won't work)
x = 6 (does work)
Therefore,
x = 6
I need help with this practice,I will send you an additional pic that goes along with this problem Freya went to her local park to find 5 organisms/species She found 5 and wrote down the name of these organisms and the quantity of each she seen:Eastern gray squirrels/14 individualsWolf spiders/2 individualsPaper wasps/9 individualsBlack vulture/1 individualNorthern cardinals/7 individuals
ANSWER :
The answer is 5/33 or 0.15
EXPLANATION :
From the problem, we have a total of 5 number of species.
Using the given Biodiversity Index formula :
[tex]\frac{\text{ total number of species}}{\text{ total number of individuals}}=\frac{5}{14+2+9+1+7}=\frac{5}{33}\quad or\quad0.1515[/tex]The tables of ordered pairs represent some points on the graphs of lines q and v. Line 9 Line v Х -9 -3 2. Х 0 10 у 0 18 33 у 10 8 3 Which system of equations is represented by lines q and v? F 21x - y = 9 5x + 6y = 40 G 3x - y = -27 x + 2y = 16 H 21x - y = 9 5x - 6y = 20 3 9x - y = -27 x + 2y = 8
One of the forms we can write the equation of a line is like this:
y - y1 = m(x - x1)
Where (x1, y1) is a point where the line passes through, and the value of m, the slope of a line is given by the following formula:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]Then, for the first line (line q), we can take the points (-9, 0) and (-3, 18), then we get:
[tex]mq=\frac{18-0}{-3-(-9)}=\frac{18}{-3+9}=\frac{18}{6}=3[/tex]By replacing the value of the slope and the coordinates of the point (-9, 0), we get:
y - 0 = 3(x - (-9))
y = 3(x + 9)
y = 3x + 27
y - y = 3x + 27 - y
0 = 3x + 27 - y
-27 = 3x + 27 - 27 - y
-27 = 3x - y
For line v, we can take the points (-4, 10) and (0, 8), then we get:
[tex]mv=\frac{8-10}{0-(-4)}=\frac{-2}{4}=-\frac{1}{2}[/tex]By taking -1/2 for the slope and the coordinates of the point (0,8), we gat:
y - 0 = -1/2(x - 8)
y = -1/2x + 4, multiplying both sides by 2:
2y = -x + 16
2y + x = -x + x + 16
2y + x = 16
Then, the system represented by the lines q and v is option G
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match the following scenarios with the correct inequality.
A phone company charges $15 per
month, and $2.50 for each gigabyte
of data used. Jaime cannot spend
more than $30 a month.
arrowBoth
A chess club has only $50 to make
t-shirts. It costs $15 for the design
and $3 per t-shirt.
arrowBoth
Sarah has $40 in a piggy bank. She
wants to keep at least $20 in the
piggy bank, and takes out half of
a dollar each week for a soda.
arrowBoth
The linear inequalities in this problem are given as follows:
Jaime/phone company: 15 + 2.5x ≤ 30.Chess club/t-shirt: 15 + 3x ≤ 50.Sarah/bank: 40 - 0.5x ≥ 20. What is a linear function?A linear function, in slope-intercept format, is modeled according to the rule presented as follows:
y = mx + b
In which the parameters of the function are described as follows:
The coefficient m is the slope of the function, representing the rate of change of the function, that is, the change in y divided by the change in x.The coefficient b is the y-intercept of the function, which is the value of y when the function crosses the y-axis(x = 0).For cost/monetary functions, the slope and the intercept are given as follows:
Slope: variable amount, such as cost per item.Intercept: fixed amount = one-time amount, such as flat fees.Then the inequalities are given as follows:
Jaime/phone company: 15 + 2.5x ≤ 30. (slope of 2.5 and intercept of 15).Chess club/t-shirt: 15 + 3x ≤ 50. (slope of 3 and intercept of 15).Sarah/bank: 40 - 0.5x ≥ 20. (slope of -0.5, negative as the amount is removed from the bank account, and intercept of 40).More can be learned about linear functions at https://brainly.com/question/24808124
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4x-7 (2-x)=3x+2/ need help
First, apply distributive property to solve the parenthesis:
[tex]4x-7(2)-7(-x)=3x+2[/tex][tex]4x-14+7x=3x+2[/tex]Combine like terms:
[tex]-14+11x=3x+2[/tex][tex]11x-3x=2+14[/tex][tex]8x=16[/tex]Divide both sides by 8:
[tex]\frac{8x}{8}=\frac{16}{8}[/tex][tex]x=\text{ 2}[/tex]Cuantas veses cabe el 13 en 47
Hay 3 veces 13 en 47.
La respuesta la divides 47 por 13 lo que te daría 3.6153846153846.
Six friends went out for dinner. The total cost of their dinner was $92,82. If they divide the bill equally, how much should
each friend pay?
Provide your answer below:
Answer:$15.47 per person
Step-by-step explanation:
The total cost of the bill, divided into 6 groups:
92.82/6=15.47
While solving an equation 2x^2+32=0 the answer calculated is x=+-4i I understand the +- means the answer can be positive or negative but what does the i mean
Answer:
Explanation:
Given:
[tex]\begin{gathered} 2x^2+32=0 \\ \text{The answer is x=}+-4i \end{gathered}[/tex]To fully understand how we get the given answer, we simplify the equation first:
[tex]\begin{gathered} 2x^2+32=0 \\ \text{Simplify and rearrange} \\ 2x^2=-32 \\ x^2=-\frac{32}{2} \\ x^2=-16 \\ \end{gathered}[/tex]Next, we apply the rule:
[tex]\begin{gathered} \text{For x}^2=f(a),\text{ the solutions are } \\ x=\sqrt[]{f(a)} \\ x=-\sqrt[]{f(a)} \end{gathered}[/tex]So,
[tex]\begin{gathered} x^2=-16 \\ x=\sqrt[]{-16},x=-\sqrt[]{-16} \end{gathered}[/tex]Then, we also apply the radical rule:
[tex]\begin{gathered} \sqrt[]{-a}=\sqrt[]{-1}\sqrt[]{a} \\ So, \\ x=\sqrt[]{-16} \\ =\sqrt[]{-1}\sqrt[]{16} \\ \text{Then, apply the imaginary number rule:} \\ \sqrt[]{-1}=i \\ \text{Hence,} \\ x=4i \end{gathered}[/tex]For
[tex]\begin{gathered} x=-\sqrt[]{-16} \\ Use\text{ the same steps} \\ x=-4i \end{gathered}[/tex]Therefore the x-values are: x=4i, x=-4i. The i on the answer means imaginary number. It is a number that, when squared, has a negative result.
The total cost, in dollars of a membership in a fitness center is given by the function c(m) = 40m +10, where m is the number of months a person is a member. In dollars, how much is the cost of a membership for 1 year?
The cost of a membership for 1 year is 490
How to determine the cost of a membership for 1 year?The equation of the membership is given as
c(m) = 40m + 10
From the question, we understand that:
m represents the number of months
For the cost of a membership for 1 year, the number of months is 12
i.e. m = 12
Substitute the known values in the above equation
So, we have
c(12) = 40 * 12 + 10
Evaluate
c(12) = 490
Hence, the cost is 490
Read more about linear equation at
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1)EF=JHFEG = HJGXProve FEG = HJGStatement1) EF = JHReason1) given2)2) given3) Vertical angles are conguent3)4)4)Theorem
2.
[tex]\angle FEG\cong\angle HJG[/tex]3.
[tex]\angle HGJ\cong\angle EGF[/tex]after how many hours will the two trucks be 558 miles apart?
Given:
a.) A truck travels due west at an average speed of 48 miles per hour.
b.) The other truck travels due east at an average speed of 45 miles per hour.
Let's determine how many hours will the two trucks be 558 miles apart.
We will be using the following equation:
Let the two trucks be named Truck A and Truck B.
Let x = the time the two trucks will be 558 miles apart
[tex]\text{ (Speed of Truck A)(x) + (Speed of Truck B)(x) = 558 miles}[/tex]We get,
[tex]\text{ 48x + 45x = 558}[/tex]Let's find x,
[tex]\text{ 48x + 45x = 558}[/tex][tex]\text{ 93x = 558}[/tex][tex]\text{ }\frac{\text{93x}}{93}\text{ = }\frac{\text{558}}{93}[/tex][tex]\text{ x = }6[/tex]Therefore, the two trucks will be 558 miles apart after 6 hours.
Graph the line that has an z-intercept of (-3,0) and a y-intercept of (0, - 5). What is the slope of this line?
Answer:
the slope is -5/3
Step-by-step explanation:
it is that because to find slope u do y2-y1/x2-x1
What is the scale factor of Figure B to Figure A?48.6B2510A1021.5A. O 6.25B.O 2.5C.0.16D. 0.4
As per given by the question,
There are given that two traingle, figure A and figure B.
Now,
The ratio of a dimension on figure B to the corresponding dimension on figure A is,
[tex]4\colon10=8.6\colon21.5=10\colon25[/tex]So,
The scale factor is,
[tex]\begin{gathered} k=\frac{10}{4}=\frac{25}{10}=\frac{21.5}{8.6}=2.5 \\ \end{gathered}[/tex]The scale factor of figure B on the figure A is 2.5.
Hence, the option B is correct.
while digging in his garden , will pushes a shovel into the ground at an 80 degree angle with 585 newtons of force . show the resolution of the force into its retangular components
Solution
Part a
Part b
For this case we can do this:
Fx= 585 N* cos 80= 101.58 N
Fy= 585N * sin 80= 576.11 N
Then the best answer is:
B. (102, 576) N
can somebody please help me with this question
Answer:
I don't really understand this but I think will be a great way to solve this so 123.00
Step-by-step explanation:
.
What is Qualitative Data and what is the discreate and Continuous in qualitative data?
Answer:
Qualitative data is the data that is not represented by numbers, for example, favorite food or country.
On the other hand, the quantitative data is represented by numbers and it is classified as discrete and continuous. The discrete data is the data that only can take specific values, for example, the number of people is always a whole number, there can't be 5.5 people. The continuous data is the data that can take decimal values, for example, the mass of an object can be 4.06 kg.
What is the value of (–3 + 3i) + (–2 + 3i)?
Answer: -5+6i
Step-by-step explanation:
26 is 50% of what number?