Yes, the force that will stretch is rights to the breaking point equal to 5000 N. Because the longer wire will аlso breаk аt 5000 N. The force per unit аreа is the sаme in both cаses.
What happens to stretch wire to breaking point?When а stress is аpplied to а piece of mаteriаl, the mаteriаl undergoes а corresponding deformаtion or strаin. Under а tensile stress, the mаteriаl stretches. Initiаlly, the аmount by which it stretches is proportionаl to the аpplied force. Thаt is, the mаteriаl obeys Hooke’s Lаw, which is expressed by the equаtion F = -kx, where k is а constаnt аnd x is the chаnge in the length of the mаteriаl.
Your question is incomplete, but most probably your full question was
A wire is stretched right to the breaking point by a 5000 N force. A longer wire made of the same material has the same diameter. Is the force that will stretch it right to the breaking point larger than, smaller than, or equal to 5000 N?
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A boat with a mass of 1000 kg drifts with the current down a straight section of river parallel to the +x axis with a speed of 2.0 m/s. At t 0 the boat engages its engines, and accelerates at 2.7 m/s7. If the boat is oriented with its nose 45 from the +x axis, which of the following is a possible value for the boat's momentum at t- 3.0 s after the engine had started?
8100 kgm/s is a possible value for the boat's momentum at t- 3.0 s after the engine had started
m=1000kg
a=2.7 m/s^2
t=3
I=F/t
I=2700/2
I=900
F×t=P
P = momentum
t=time
f= force
F×t=P
P=2700×3
P=8100 kgm/s
Momentum is the result of a particle's mass and velocity combined. A vector quantity with both magnitude and direction is momentum. A particle's force is equal to its rate of change in momentum over time, which is stated in Isaac Newton's second equation of motion.
Any grouping of particles has a momentum equal to the vector sum of its momenta. The third law of Newton asserts that forces between particles are equal and opposite, and that any change in one particle's momentum is totally counterbalanced by a similar change in another particle's momentum.
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a perfectly elastic collision is a collision: a perfectly elastic collision is a collision: between two springs. that conserves thermal energy. that conserves kinetic energy. that conserves potential energy. that conserves mechanical energy. submitrequest answer
perfect elastic collusion is a collision that conserves kinetic energy.
in physics, an elastic collision is an encounter between two bodies where the total kinetic energy of the two bodies remains the same. In an ideal, perfectly elastic collision, no kinetic energy is converted into other forms such as heat, noise, or potential energy
The main reason why there is no loss of energy is because of the lack of collusion. it can be either one-dimensional or two dimensional
The linear momentum of the system as a whole does not change, but the individual momentums of the components involved change, being equal and opposite in magnitude, canceling each other out, and conserving the initial energy
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a paper airplane gliding down towards the ground will experience the force of air resistance pushing up. the weight of the paper airplane is 16 N down and the force of air resistance is 9 N up. find the net force
The net force acting on the airplane is 25N.
Forces acting on the paper airplane when it is in the air:
The forward force generated by the engine, propeller, or rotor is called thrust. It resists or defeats the drag force. It operates generally perpendicular to the longitudinal axis. However, as will be discussed later, this is not always the case.Drag is an airflow disruption generated by the wing, rotor, fuselage, and other projecting surfaces that causes a backward, decelerating force. Drag acts backward and perpendicular to the relative wind, opposing thrust.Weight is the total load carried by airplane, including the weight of the crew, fuel, and any cargo or baggage. Due to the influence of gravity, weight pulls the airplane downward.Lift—acts perpendicular to the flight path through the center of lift and opposes the weight's downward force. It is produced by the air's dynamic influence on the airfoil.Given.
Weight of the paper airplane, F1 = 16N
The force of air resistance, F2 = 9N
Net force = F1 + F2
Net force = 25N
Thus, the net force acting on the airplane is 25N.
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✓
Sarah is building an electric motor whilst listening to the radio. She notices
that when she switches the motor on, the radio makes clicking noises. Using
knowledge about how radio waves are produced, describe why the radio
makes clicking noises.
Type your answer here....
The reason for the sound is the fact that there are other channels that are interfering with the particular channel that she was looking for.
Why does the radio make clicking noises?We know that radio waves are part of the electromagnetic waves. These are waves that do not require any material medium for them to become propagated thus they are able to move from one place to another even in a vacuum. Radio waves are known to have a long wavelength thus they can travel a far distance.
Given what we have said, we know that a radio is a device that have been built so as to be able to receive the radio waves. However, there are a number of frequencies that we are looking at that could be received by the radio at the same time. This could be referred to by the use of the word co channel interference.
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Claify each planet a an inner planet or an outer planet. Planet A ha 67 moon, and
major part of it atmophere
are hydrogen and helium. Planet B ha ring but
not much atmophere. Planet C ha no moon but
ha high volcanic activity
Known a the red planet, planet
D ha high amount of carbon
dioxide in it atmophere and
ha two moon. Planet E ha a thin layer of
atmophere but no moon due
to the effect of the Sun’ gravity. Planet F ha 27 moon, and it
atmophere i motly compoed
of hydrogen, helium, and methane
The inner planets are Planets C , D and E.
The outer planets are Planets A. B and F.
How many types of planets are there in our Solar System?
Astronomers frequently divide our Solar System's planets into two groups: the inner planets and the outer planets.
Inner Planets
Due to their position, nearer to the Sun, the inner planets are smaller and more rocky. Mercury, Venus, Earth, and Mars are the inner planets, which are listed in order of proximity to the sun from closest to farthest. The four inner planets are referred to as "terrestrial planets" because they have solid surfaces and, as suggested by their names, are fairly similar to Earth. However, the term can be deceptive because the conditions on each of the four worlds vary greatly. They have either no moons or few moons, are primarily composed of heavy metals like iron and nickel, and are small in size.Outer Planets
The outer planets are much larger in size, farther distant, and mostly composed of gas.Jupiter, Saturn, Uranus, and Neptune are the outer planets that appear after an asteroid belt.The outer planets are large, gas-encased planets that are also referred to as gas giants or Jovian planets. Each has a large number of moons and each has rings. Even though they are large, only Jupiter and Saturn are visible without telescopes. Astronomers learned the solar system was larger than previously believed when Uranus and Neptune, the first planets identified since antiquity, were discovered.On the basis of the above comparison the planets in the question are classified as-
Planet A - Outer Planet as has 67 moon, and major part of it atmophere are hydrogen and helium.
Planet B - Outer Planet as has ring but not much atmophere.
Planet C - Inner Planet as has no moon but has high volcanic activity
Planet D - Inner Planet as has high amount of carbon dioxide in it atmophere and has two moon
Planet E - Inner Planet as has a thin layer of atmophere but no moon due to the effect of the Sun’ gravity
Planet F - Outer Planet as it has 27 moon, and it has atmophere mostly composed of hydrogen, helium, and methane
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How does the angle at which a ray of light strikes a pane of window glass compare with the angle at which it passes out the other side?.
The angle at which a ray of light leaves the other side of a window pane is the same as the angle at which it strikes the glass.
What is refraction of light?Refraction is the change in direction of a wave when it passes from one medium to another or from a gradual to a sudden change in the medium.
When a wave of light passes from one medium to another, its direction is changed. This phenomenon is called refraction. It occurs because the speed of light is different in different media.
The amount of refraction that occurs depends on the difference in the speed of light in the two media, and the angle at which the light wave is incident on the boundary between the two media. The greater the difference in the speed of light, the greater the amount of refraction. The angle of incidence also affects the amount of refraction; the greater the angle, the greater the refraction.
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Imagine that you jump out of an airplane and wait 3.8 seconds before pulling the parachute.
a. How fast are you going when you pull the chute?
b. How far have you fallen before you pull the chute?
While pulling the speed is 37.24 m/s and distance before 70.76 m
Acceleration due to gravity
a = 9.8 m/s2
a. by the equation of motion
V = U + at
= 0 + (9.8 m/s2) ×(3.8 s)
= 37.24 m/s
b. distance fallen
S = ut + (1/2)at
= 0 + (1/2)×9.8×3.82
= 70.76 m
A parachute acts like a wing on an airplane though it acts with the same force as a human when falling. The T-11's main canopy uses a unique deployment sequence to reduce shock and canopy vibration when opening. The T-11 is designed for an average descent velocity of 19 feet per second for the 95th percentile service member, compared to 24 feet per second for the T-10C.
Even if the main parachute fails he can use his backup parachute to land. There are even tactics you can use to increase your chances of surviving a free fall to Earth if your reserves also fail. So if you have two parachutes of the same size and shape but different materials and one is heavier than the other the heavier parachute will fall faster.
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which answer best describes the second law of thermodynamics as it is used in engineering thermodynamics?
A control volume's time rate of entropy change is equal to the rate of entropy generated inside the control volume plus the rate of entropy entering or leaving the control volume through mass transfer.
A state of disorder, randomness, or uncertainty is most frequently associated with the scientific concept of entropy, which is also a quantifiable physical property. In other words, entropy is the increase in disorganization within a system. It is defined as the measurement of degree of randomness. A physical principle based on observed interactions between heat and energy, the second law of thermodynamics is applicable to all situations. A straightforward explanation of the law is that, without an energy source to change the direction of heat flow, heat always travels from hotter to cooler objects. The overall entropy of a system never decreases; according to the second law of thermodynamics, it always either rises or stays the same.
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The larger the frequency of a photon of light, the _______ the energy of the photon.
The larger the frequency of a photon of light, the increase the energy of the photon.
As frequency increases, the energy of emitted photons will increase. The opposite is also actual. as the frequency of radiation decreases, there may be a corresponding lower in the power of emitted photons.
The higher the frequency, the more energy the photon has. Of path, a beam of mild has many photons. This means that absolutely intense purple light can bring more electricity to a given area than less severe blue light.
The quantity of energy is directly proportional to the photon's electromagnetic frequency and consequently, equivalently, is inversely proportional to the wavelength. The better the photon's frequency, the better its energy. Equivalently, the longer the photon's wavelength, the decrease its power.
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In lab we applied the conservation of energy to a system to allow us to equate the initial energy to the final energy. How does the initial energy become stored in the system?.
The initial energy becomes stored in the system by the tension in the string.
What is energy in physic?Energy is the capacity to do work. Energy cаn exists in mаny different forms. Аll forms of energy аre either kinetic or potentiаl. The energy аssociаted with motion is cаlled kinetic energy. The energy аssociаted with position is cаlled potentiаl energy. Potentiаl energy is not "stored energy". Energy cаn be stored in motion just аs well аs it cаn be stored in position.
А tension force is а force developed in а rope, string, or cаble when stretched under аn аpplied force. It is the force generаted when а loаd is аpplied аt the ends of аn object, normаlly to the cross-section of it. It cаn аlso be cаlled the pulling force, stress, or tension. This type of force is only exerted when there is contаct between а cаble аnd аn object. Tension аlso аllows force to be trаnsferred аcross relаtively lаrge distаnces.
Your question is incomplete, but most probably your full options were
a. The energy is supplied by the tension in the string.
b. The energy is part of the mass.
c. The force of Gravity does work on the mass when it is displaced some height when the pendulum is displaced by some angle theta.
d. I did work on the mass by dispacing it some height when I displaced the pendulum by some angle theta.
Thus, the correct option is A.
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The fastest recorded pitch in Major League Baseball, thrown by Aroldis Chapman in 2010, was clocked at 169.14 km/h (105.1 mi/h). If a pitch were thrown horizontally with this velocity, what would the ball's vertical displacement be by the time it reached home plate, 18.3 m (60.0 ft) away?
Answer:
The ball would fall vertically for 112.45m
Explanation:
The vertical height of a horizontal throw is affected only by the speed of the throw and the acceleration due to gravity.
At this point, we may use this formula to determine the vertical height of the throw
vertical height =
The initial throwing speed has to be converted to m/s to ensure uniformity during the calculations. To do this we multiply by 1000 and divide by 3600
169.1km/hr = 46.972m/s
Maximum height = m
The pitch would make the ball fall vertically for 112.45m by the time it reached the home plate 18.2 m away
Answer:
The ball's vertical displacement 5.7 cm
Explanation:
Given:
V₀ = 169.14 m
D = 18.3 m
g = 9,81 m/s²
____________
Δh - ?
Ball flight time:
t = D / V₀ = 18.3 / 169.14 ≈ 0.108 s
The ball's vertical displacement:
Δh = g·t² / 2
Δh = 9.81·0.108² / 2 ≈ 0,057 m or 5.7 cm
Explain the difference between music and noise.
What is the net force in this image?
Answer:
D
Explanation:
If we ignore certain factors, then the net force is 0N, because we have two equal but opposite forces (10N-10N).
A metal sphere with a mass of 0.020 kg rolls along a friction-less surface at 3.2 m/s and strikes a stationary sphere having a mass of 0.041 kg. The first sphere stops completely. The spheres are in contact for 0.005 s before the second sphere is shot off down the track. What is the force applied to the second ball?
Answer:
Kinetic energy
Explanation:
Kinetic = movement or something
the ball moved, sounds like kinetic.
Drag each description into the type of weathering that ur describes
Note: Can you please add a screenshot? So I can help you out.
a movie camera with a single lens (has a converging lens) of focal length 75 mm takes a picture of a 180 cm high person standing 2.7 m away. what is the position of the image of the person? (write the value in cm and use only one decimal place).
The position of the image of the person is 0.5 cm.
What is meant by focal length?An optical system's focal length is the inverse of its optical power; it indicates how strongly the system converges or diverges light. A positive focal length system converges light, while a negative focal length system diverges light.
The rays are bent more sharply in a system with a shorter focal length, bringing them closer to focus or diverging them faster. For the special case of a thin lens in air, a positive focal length is the distance over which initially collimated (parallel) rays are brought to a focus.
Given,
Focal length=75mm
Height of the person=2.7m
f=((1/f)-(1/p))⁻¹
f=fp/p-f
Thus, the height of the image is
[tex]h_{i}[/tex]=m[tex]h_{p}[/tex]
[tex]h_{i}[/tex]=(i/p)[tex]h_{p}[/tex]
[tex]h_{i}[/tex]=f[tex]h_{p}[/tex]/p-f
[tex]h_{i}[/tex]=(75mm)(1.80m)/(27m-0.075m)
[tex]h_{i}[/tex]=5mm
[tex]h_{i}[/tex]=0.5 cm
The position of the image of the person is 0.5 cm
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From the information given in the diagram below, find the coefficient of friction between
the 43 kg box and the surface on which it is pulled. Note that the box is accelerating at
0.79 m/s2.
Answer:
μ = 0.55
Explanation:
Given:
m = 43 kg
a = 0.79 m/s²
F pull = 265 N
_____________
μ - ? Friction coefficient
2 Newton's law:
m·a = Fpull - μ·m·g
μ·m·g = Fpull - m·a
Friction coefficient:
μ = (Fpull - m·a) / (m·g)
μ = (265 - 43·0.79) / (43·9.8) ≈ 0.55
Read the question, and write your response in the space provided.
20. A force of 6.2 x 10' N is needed to blast off a 5.0 x 10³ kg rocket from rest.
What is the rocket's average acceleration?
Answer: 124m/s2
Explanation: I'm pretty sure this is correct, if it is not I'm sorry, and have a good day!
why is ""friction"" (also called viscosity when it pertains to a gas) crucial for accretion disks?
Because Friction between gas orbiting at different speeds transfers angular momentum, also generating heat.
Friction is nothing but the opposing force acting on the device. In this case when accretion disks moves, it transfers angular momentum and and due to friction it also generates heat.
And as we know from conservations of energy that whatever heat is generated and angular momentum gets transferred, both will act as a negative parameter for a accretion disks.
That is the reason it is vey important to know and take care of the friction during designing or using of accretion disks.
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3. below is a 4-bit up-counter. what is the largest number of the counter if the initial state q3q2q1q0
The largest number is 1111. Option A.
The initial state in a state or activity diagram. Represents the state of an object before the events contained in the diagram act on it. Transitions from initial states are usually unlabeled and represent transitions to enclosing states. A final state marks the end of the execution flow of a state machine or region.
Can have multiple incoming transitions but no outgoing transitions. Each region can have at most one final state. For orthogonal regions, execution flow stops when all region end conditions are reached. In quantum state terms, colliding particles form an initial state. In a collision, particles can be annihilated and/or exchanged resulting in a different set of particles in the final state.
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Consider a box resting on a horizontal surface. The box has a mass of 2.13 kg and the coefficient of static friction between the box and the surface is 0.151. Determine the force that must be applied down at a 37.8º angle to the horizontal to make the box start moving.
The force that must be applied down at an angle of 37.8° to the horizontal to make the box start moving is 3.99 N.
What is force?Force is obtained by multiplying the mass of a body by its acceleration.
To calculate the force that must be applied to make the box start moving, we use the formula below.
Formula:
F = mgμ/cos∅......... Equation 1Where:
F = Force applied to the boxm = Mass of the boxg = Acceleration due to gravityμ = Cofficient of static friction∅ = AngleFrom the question,
Given:
m = 2.13 kgg = 9.8 m/sμ = 0.151∅ = 37.8°Substitute these values into equation 1
F = (2.13×9.8×0.151)/(cos37.8°)F = 3.99 NHence, the force that must be applied to the box is 3.99 N.
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the left end of a spring is attached to a wall. when bob pulls on the right end with a 200 nn force, he stretches the spring by 20 cmcm. the same spring is then used for a tug-of-war between bob and carlos. each pulls on his end of the spring with a 200 nn force.
When a spring is only pulled by Bob with 200 N force, the spring stretches 20 cm. If the same spring is pulled by Bob and Carlos with 200 N forces each, the string will stretch 40 cm.
The elasticity is followed the Hooke's Law:
F = kx
Where:
F = force applied
k = spring constant
x = length of extension / compression
From the Hooke's Law, we know that the applied force is directly proportional to the change of length, or
F2 : F1 = x2 : x1
Parameters given in the problem:
F1 = 200 N (Force applied by Bob)
x1 = 20 cm
F2 = 200 + 200 = 400 N (Forces applied aby Bob and Carlos)
Therefore,
400 : 200 = x2 : 20
x2 = 400 x 20 / 200 = 40 cm
Thus, when both Bob and Carlos pulls the spring, the spring will stretch 40 cm
Complete question:
The left end of a spring is attached to a wall. When Bob pulls on the right end with a 200 N force, he stretches the spring by 20 cm . The same spring is then used for a tug-of-war between Bob and Carlos. Each pulls on his end of the spring with a 200 N force.
How far does the spring stretch?
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the truck suffers less damage because it is made of stronger metal. but what about the two drivers? do they experience the same forces? to answer this question, suppose that each vehicle is initially moving at 8.00 m/s and that they undergo a perfectly inelas- tic head-on collision. each driver has mass 80.0 kg. including the masses of the drivers, the total masses of the
The force experienced by the truck driver is lesser than the force experienced by a car driver in a perfectly inelastic collision.
According to law of conservation of momentum,
m1 u1 + m2 u2 = m1 v1 + m2 v2
After perfect inelastic collision,
v1 = v2
m1 u1 + m2 u2 = ( m1 + m2 ) v
u1 = 8 m / s
u2 = - 8 m / s
m1 = 3800 kg
m2 = 830 kg
Substituting the known values,
( 3800 * 8 ) - ( 830 * 8 ) = ( 3800 + 830 ) v
30400 - 6640 = 4630 v
v = 6.43 m / s
Since final velocity is positive, the vehicles will move the direction of truck after collision.
For the truck,
a = ( 6.43 - 8 ) / 0.15
a = - 10.48 m / s²
F = 3800 * - 10.48
F = - 39.83 KN
For the car,
a = ( 6.43 - ( - 8 ) ) / 0.15
a = 96.2 m / s²
F = 830 * 96.2
F = 79.85 KN
I Ft I < I Fc I
Therefore, the force experienced by the truck driver is lesser than the force experienced by a car driver.
The given question is incomplete. The complete question is:
Most of us know intuitively that in a head-on collision between a large dump truck and a subcompact car, you are better off being in the truck than in the car. Why is this? Many people imagine that the collision force exerted on the car is much greater than that experienced by the truck. To substantiate this view, they point out that the car is crushed, whereas the truck is only dented. This idea of unequal forces, of course, is false. Newton's third law tells us that both objects experience forces of the same magnitude. The truck suffers less damage because it is made of stronger metal. But what about the two drivers? Do they experience the same forces? Suppose that each vehicle is initially moving at 6.40 m/s and that they undergo a perfectly inelastic head-on collision. Each driver has mass 81.0 kg. Including the drivers, the total vehicle masses are 830 kg for the car and 3800 kg for the truck. The collision time is 0.150 s.
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Choose the picture of how the Earth would move if you "turned off the gravity forces
Answer:
I think the answer is d; as the object is revolving around the earth in a circular motion due to centripetal force provided by gravity and if you "turned off" the gravity then it would tend to continue away from the planet but in the same direction.
a 4-kg mass of gas expands adiabatically and does 20 j of work. what is the change in the gas's internal energy?
There is a change of -20 J in the gas's internal energy.
Adiabatic expansion is the method of volume expansion in which no heat is exchanged inside the system from the surrounding, or the heat exchange is zero. During extension, the exchange of energy takes put as work.Since we given with 4-kg mass of gas expands adiabatically and does 20 j of work.
According to the first law of thermodynamics
ΔQ = ΔU + W
where Q is the heat supply or received, U is the internal energy and W is the work done
since in case adiabatic process , ΔQ = 0
so, ΔU = -ΔW
wince a work done is done by the system, so the work done = +20 J
ΔU = -(+20) = -20 J
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8. assume pulleys and ropes are massless and frictionless. the surface with the 80 kg block has a coefficient of kinetic friction
The coefficient of kinetic friction ∝=9.81
Given that mass of block is 80kg .
Pulleys and ropes are massless and frictionless.
Coefficient of kinetic friction ∝ means the ratio of kinetic friction force of contacting surfaces to normal force .
Being a ratio parameter its unitless parameter.
[tex]F= mg\\\\F=\alpha N[/tex]
from these equations
[tex]mg=\alpha N[/tex]
Since there is no involvement of tension, g=∝
∝=9.81
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A rock climber carries his 15,000 g backpack to the top of the cliff.
What is the MASS, in kg, of the backpack?
Main answer- the mass of the backpack is 1.53kgs
Supporting answer- The mass of the body is the quantity of matter contained in it .
weight of a body is defined the amount of mass or heaviness of the body
Weight = mass x acceleration due to gravity
Body of the answer- Given ,
weight of backpack = 15000g = 15kgs
mass = weight of the body
acceleration due to gravity
mass of the bag = 15 kgs
9.8
= 1.53 kgs
Final answer- hence mass of the backpack is 1.53kgs
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the impulse one ball receives is equal to the blank force on it from the other ball multiplied by the time during which the force is applied. by newton's third law the force that the rubber ball exerts on the steel ball is blank the force t
The impulse one ball receives is equal to average force on it from the other ball multiplied by the time during which the force is applied
The impulse one ball receives is equal to average force on it from the other ball multiplied by the time during which the force is applied. By newton's third law the force that the rubber ball exerts on the steel ball is equal to the force that steel ball exerts on rubber ball. So the rubber ball receives the same amount of impulse , although the directions of impulse are opposite.
Jx = Fx Δt
Jx = Impulse acting on x
Fx = Average force acting on x ( Answer 1 )
Δt = Period of time
Jrubber = Frubber * Δt
Jsteel = Fsteel * Δt
According to Newton's third law,
Frubber = - F steel ( Answer 2 )
Jrubber = - Fsteel * Δt
Jrubber = - Jsteel ( Answer 3 and 4 )
Therefore, the answers are,
AverageEqual toThe sameOppositeThe given question is incomplete. The complete question is:
Suppose a rubber ball collides head-on with a more massive steel ball traveling in the opposite direction with equal speed. Which ball, if either, receives the larger impulse?
The impulse one ball receives is equal to the ___ force on it from the other ball multiplied by the time during which the force is applied. By Newton's third law the force that the rubber ball exerts on the steel ball is ___ the force the steel ball exerts on the rubber ball So the rubber ball receives ___ amount of impulse, although the directions of the impulses are ___
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assume mvp contains 410 story points of work. how long will it take to deliver mvp if velocity is 18 story points per sprint and each sprint is two weeks in duration?
To learn about the velocity and momentum.
What is velocity?
The direction of motion of a body or object is determined by its velocity. In most cases, speed is a scalar variable. In their most basic form, vector quantities are speeds. It measures how quickly a distance changes within an area. What counts is the change in displacement rate.
What is momentum?
Mass in motion is quantified by momentum, or how much mass is moving in how much space. It typically has the letter P.
find
how long would it take to complete the entire project Y each story point is two weeks long ?
The product story point is 410 story points and 18 story points per spirit.
so the number of spirits in the product is given as
the number of spirit = 410/18 = 23
23 spirits
the each spirits take a two weeks, so
the time to complete the entire project = so it take to complete entire project.
Therefore, 23 sprint and each sprint is two weeks in duration.
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HELP PLEASE!!! Match the correct term with the corresponding definition or description.
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