Read the following code:


n = 3

while(n <= 5):

print(n)

n = n + 1


What output would be produced for the given values of n?


A. 0 1 2 3 4

B. 1 2 3 4 5

C. 2 3 4

D. 3 4 5

Answer:

4

Explanation:

Input/output, datapath, control, and memory

There wrong its C bold it.

:)))))

Answer:

Written in C

#include <stdio.h>

int main() {

   float salary;

   printf("Salary: ");

   scanf("%f", &salary);

   float HRA, DA;

   if(salary <= 10000){

       HRA = 0.20; DA = 0.80;

   }

   else if(salary >= 10000 && salary <= 20000){

       HRA = 0.25; DA = 0.90;

   }

   else{

       HRA = 0.30; DA = 0.95;

   }

   salary = salary + salary * HRA + salary * DA;

     printf("Gross Salary: %.2f\n", salary);

   return 0;

}

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer:

The answer to this question is given below in the explanation section

Explanation:

The correct option for this question is Animation tab.

Animation tab in PowerPoint ribbon is a unique tab that is not found in other office applications such as in word, excel, outlook, publisher etc.

Because in PowerPoint you can use animation to make your slides animated and all animation can be managed and animation-related settings, you can find in the animation tab.

However, other tabs such as Home, Insert, and View are common in all office applications.

Answer:

Modify

If scores[index] > highest then highest = scores[index]

End Of highest

Name = students[index]

End For Display

to

If scores[index] > highest then highest = scores[index]

Name = students[index]

End Of highest

End For Display

Explanation:

In the code, you posted the code segment that gets the name of the student with the highest score is outside the if condition that determines the highest.

To make correction, we only need to bring this code segment into the loop.

See Answer

Answer:

I hope the above picture may help you.

Answer:

using a limited access public computer to watch movies

Explanation:

Cause it doesn't involve you performing any illegal actions.

Answer:

C. using a limited access public computer to watch movies

Explanation:

IM A DIFFERENT BREEED!!

PLUS NOTHING ELSE MAKES SENSE LOL!

Answer:

7. true

8.B

Hopefully those are correct!

Explanation:

Answer:

a. I think the Aluminum will conduct heat better.

b. I think the Fiberglass will insulate heat better.

Fiberglass is used to insulate most everyday items, so I can be sure that fiberglass can be the best insulator, as for aluminum it conducts heat like you wouldn't believe.

Note: Your answer doesn't have to be right, they just want you to make a prediction about your answer, that means it's alright to guess, also know I didn't guess I am just telling you that you didn't have to ask this question. <3

Answer:

Written in Python

numVal = int(input("Input: "))

for i in range(numVal,0,-1):

    print(i)

print("Ready!")

Explanation:

This line prompts user for numVal

numVal = int(input("Input: "))

This line iterates from numVal to 1

for i in range(numVal,0,-1):

This line prints digits in descending order

    print(i)

This line prints the string "Ready!"

print("Ready!")

Answer:

Here is the C program:

#include <stdio.h>  //to use input output functions

//functions prototype

unsigned int mod(unsigned int a, unsigned int b);  

unsigned int mul(unsigned int a, unsigned int b);  

unsigned int sub( unsigned int a,unsigned int b);

float divide(unsigned int a,unsigned int b);  

unsigned int add( unsigned int a,unsigned int b);  

int main()  {  //start of main method

unsigned int a, b;   //declare variables to store the operands

char d;  //declare variable to store the operator

printf("Enter an operator:  ");   //prompts user to enter an operator

scanf("%c",&d);  //reads the operator from use

getchar();  //gets a character

while (d!='q')   { //keeps iterating until user enters q to quit

printf("Enter 1st operand: ");   //prompts user to enter first operand

scanf("%d",&a);   //reads first operand from user

getchar();  //reads character

printf("Enter 2nd operand: ");   //prompts user to enter second operand

scanf("%d",&b);   //reads second operand from user

getchar();  

if (d=='%')  {   //if the character of operator is a mod

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

mod(a,b);  }  //displays computed modulo of two input operands

if (d=='*')   //if the input character is for multiplication operator

{printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

mul(a,b); }  //displays computed multiplication

if (d=='+')  {  //if the input character is for addition operator

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = "); // displays =

add(a,b);  }   //displays computed addition

if (d=='/')  {  //if the input character is for division operator

printf("%d",a); // prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

divide(a,b);  }   //displays computed division

if (d=='-')  {  //if the input character is for subtraction operator

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b); // displays operand 2

printf(" = ");  //displays =

sub(a,b);  }  //displays computed subtraction

printf("Enter an operator: ");   //asks again to enter an operator

scanf("%c",&d);  //reads operator from user

getchar();  }  }   //gets character

unsigned int mod( unsigned int a, unsigned int b){  //function to compute modulo of two integers with no sign

     int c = a%b;  //computes mod

    printf("%d",c);  }  //displays mod result

unsigned int add(unsigned int a, unsigned int b){     // function to compute addition of two integers

    int c = a+b; //computes addition

    printf("%d\n",c);  } //displays result of addition

unsigned int mul(unsigned int a, unsigned int b){       //function to compute multiplication of two integers

    int c = a*b;  //multiplies two integers

   printf("%d\n",c); }  //displays result of multiplication

float divide(unsigned int a, unsigned int b){   //function to compute division of two integers

    float c = a/b;  //divides two integers and stores result in floating point variable c

    printf("%f\n",c);  } //displays result of division

unsigned int sub(unsigned int a, unsigned int b){       //function to compute subtraction of two integers

    int c = a-b;  //subtracts two integers

    printf("%d\n",c);  }  //displays result of subtraction

Explanation:

The program is well explained in the comments mentioned with each line of the program. The program uses while loop that keeps asking user to select an operator and two operands to perform arithmetic calculations. The if conditions are used to check what arithmetic calculation is to be performed based on user choice of operand and calls the relevant function to perform calculation. There are five functions that perform addition, modulo, subtraction, division and multiplication and display the result of computation. The screenshot of output is attached.

Answer:

B

Explanation:

Answer:

b  def drawT():

Explanation:

Answer: not sentence [3:6]

I hope this helps

Explanation:

Answer:

no

Explanation:

mabey yes

Answer:

4096 VLANs

Explanation:

A VLAN (virtual LAN) is a group of devices on one or more LAN connected to each other without physical connections. VLANs help reduce collisions.

An 802.1Q Ethernet frame header has VLAN ID of 12 bit VLAN field. Hence the maximum number of possible VLAN ID is 4096 (2¹²).  This means that a switch supporting the 802.1Q protocol can have a maximum of 4096 VLANs

A lot of VLANs ID are supported by a switch. The maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol is 4,094 VLANS.

But that of 0x000 and 0xFFF are set apart. This therefore makes or leaves it as 4,094 possible VLANS limits. Under IEEE 802.1Q, the maximum number of VLANs that is found on an Ethernet network is 4,094.

Learn more about VLANs from

https://brainly.com/question/25867685

Answer:

See Explanation

Explanation:

Your program is correct and doesn't need an attachment.

However, there's a mismatch in placement of curly braces in your program

{

}

I've made corrections to that and I've added the corrected program as an attachment.

Aside that, there's no other thing to be corrected in your program.

Use another compiler to compile your program is you are not getting the required output.

Answer:

B. The process will be terminated by the operating system.

Explanation:

When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.

So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.

Based on the information given regarding CPU scheduling, the correct option is C. The process's state will be changed from running to blocked.

It should be noted that in a system where Round Robin is used for CPU scheduling, when a process cannot finish its computation during its current time quantum, the process's state will be changed from running to blocked.

It should be noted that a prices transition to a blocked state occurs when it's waiting for some events like a particular resource becoming available.

Learn more about CPU scheduling on:

https://brainly.com/question/19999569

Answer: D

Explanation: Because if he took the battery out it would not have short circuited.

Answer:  

Here is the C++ program:  

#include <iostream>   //to use input output functions    

using namespace std;   //to identify objects cin cout    

int main() {   //start of main method    

int red,green,blue,smallest;   //declare variables to store integer values of red,green, blue and to store the smallest value    

cout<<"Enter value for red: ";  //prompts user to enter value for red    

cin>>red;  //reads value for red from user    

cout<<"Enter value for green: ";  //prompts user to enter value for green  

cin>>green; //reads value for green from user    

cout<<"Enter value for blue: "; //prompts user to enter value for blue    

cin>>blue;   //reads value for blue from user    

//computes the smallest value  

if(red<green && red<blue) //if red value is less than green and blue values    

smallest=red;   //red is the smallest so assign value of red to smallest    

else if(green<blue)   //if green value is less than blue value    

smallest=green; //green is the smallest so assign value of green to smallest  

else //this means blue is the smallest    

smallest=blue;  //assign value of blue to smallest    

//removes gray part by subtracting smallest from rgb  

red=red-smallest; //subtract smallest from red    

green=green-smallest; //subtract smallest from green    

blue=blue-smallest; //subtract smallest from blue    

cout<<"red after removing gray part: "<<red<<endl;  //displays amount of red after removing gray    

cout<<"green after removing gray part: "<<green<<endl; //displays amount of green after removing gray  

cout<<"blue after removing gray part: "<<blue<<endl;  } //displays amount of blue after removing gray  

Explanation:  

I will explain the program using an example.    

Lets say user enter 130 as value for red, 50 for green and 130 for blue. So  

red = 130    

green = 50

blue = 130  

First if condition if(red<green && red<blue)   checks if value of red is less than green and blue. Since red=130 so this condition evaluate to false and the program moves to the else if part else if(green<blue) which checks if green is less than blue. This condition evaluates to true as green=50 and blue = 130 so green is less than blue. Hence the body of this else if executes which has the statement: smallest=green;  so the smallest it set to green value.    

smallest = 50    

Now the statement: red=red-smallest; becomes:    

red = 130 - 50    

red = 80    

the statement: green=green-smallest;  becomes:    

green = 50 - 50    

green = 0    

the statement: blue=blue-smallest; becomes:    

blue = 130 - 50    

blue = 80    

So the output of the entire program is:    

red after removing gray part: 80                                                                                                 green after removing gray part: 0                                                                                                blue after removing gray part: 80    

The screenshot of the program along with its output is attached.

Answer:

it's business

Explanation:

business you started with small and work for it grow up.

Answer:

The equivalent if statements is:

ranforce = randi([0, 12]);

if (ranforce == 0)

     disp('There is no wind')

else  if(ranforce>0 && ranforce <7)

     disp('There is a breeze')

else  if(ranforce>6 && ranforce <10)

     disp('This is a gale')

else  if(ranforce>9 && ranforce <12)

     disp('It is a storm')

else  if(ranforce==12)

     disp('Hello, Hurricane!')

end

Explanation:

The solution is straight forward.

All you need to do is to replace the case statements with corresponding if or else if statements as shown in the answer section

Answer:

The program equivalent in C++ is:

#include <cstdio>

#include <cstdlib>

#define SIZE 5

using namespace std;

int main(int argc, char *argv[]) {

int numerator = 25;

int denominator = 10;

FILE * inPut = fopen(argv[1], "r");

FILE * outPut = fopen(argv[2], "w");

float result = (float)numerator/denominator;

fprintf(outPut,"Result is %.2f\n", result);

float arr[SIZE];

for(int i = 0; i < SIZE; i++) {

fscanf(inPut, "%f", &arr[i]);

fprintf(outPut, "%7.4f\n", arr[i]);

}

return 0;

}

Explanation:

See attachment for explanation.

Each line were numbered with equivalent line number in the C program

Answer:

Data bar

Explanation:

The answer to this question is data bar. Through the use of a day bar we are able to see trends in our data. They are very useful when it comes to visualization of values that are In a range of cells. Now if the bar is longer then the value we are visualizing is definitely higher. And if it is shorterr the value is lower. Several applications like excel has programmes that makes use of data bars especially for statistical purposes.

Explanation:

:*):*):*)*)*:)*:)*:*)*:**:*)*:)*:)*:*):*)*P:)*:*):*)

:*

):*

)*:

)*:*

):*):*)*:*):*)*:*):*):*):)*:*):*):*):*)

:*):*)

This is python code.

In python, you are supposed to put a colon at the end of while loops. This code does not have a colon after the while loop, therefore, you need to add a colon to the end of the statement.

The error to be fixed in the while loop is to add a colon at the end of the while statements.

x = 1

while (x<26)

     print(x)

     x = x + 1

This is the right code;

x = 1

while(x < 26):

   print(x)

   x = x + 1

The actual code , the while statement is missing a colon at the end of it.

The code is written in python. In python while or for loops statements always ends with a colon.

In the error code, there was no colon at the end of the while loop.

The right codes which I have written will print the value 1 to 25.

learn more on python loop here: https://brainly.com/question/19129298?referrer=searchResults

Answer:

I've implemented this program using python

userinput = int(input("Length: "))

mylist = []

mylist.append(userinput)

for i in range(1,userinput+1):

   userinp = int(input("Input: "))

   mylist.append(userinp)

smallval = mylist[1]

for i in range(1,len(mylist)):

   if smallval > mylist[i]:

       smallval = mylist[i]

for i in range(1,len(mylist)):

   mylist[i] = mylist[i] - smallval

for i in range(1,len(mylist)):

   print(mylist[i],end=' ')

Explanation:

I've added the full source program as an attachment where I used comments to explain difficult lines

The program written in python 3 deducts the least from a list of user given integers and prints the output. The program goes thus :

len_input = int(input())

#the number of inputs the user wishes to supply

vals = []

#initialize an empty list to accept the inputs

for i in range(1, len_input +1):

#use a loop to accept the user inputs

num = int(input())

#allow users to take in the inputs

vals.append(num)

#append each value to the list

least =min(vals)

#using the min function, obtain the lowest value from the list

output_vals = []

#initialize an empty list to hold the normalized values

for i in range(len_input):

#loop using a for loop

diff = vals[i] - least

#deduct the minimum value from each element in the list

output_vals.append(diff)

#append the values to the new list.

print(output_vals)

#display the output

A sample run of the program and the script is attached.

Learn more :https://brainly.com/question/14276852

Answer:

laptops

Explanation:

B

You can buy new applications at a retail store on DVD for laptops. Thus, option A (laptops) is correct.

A website is an accumulation of internet pages and related items that is posted on at least one server and given an unique domain name. Most blogs focus on a single subject or objective, such as reporting, education, industry, entertaining, or photo sharing.

A raster-based photograph designed for the web and publishing is stored as a JPG file. The JPG format is the default file format for image sensors and is the most widely used picture format on the web because of its universal compatibility and decompression. Portraits in both colour and black and white work brilliantly with them.

Therefore, option A (laptops) is the correct option.

Learn more about DVD, here:

https://brainly.com/question/13664390

#SPJ6

Answer:

Follows are the method to this question:

class Invoicing  //defining a class Invoicing  

{

  public static final double Tax = 8.0; //defining static variable Tax that holds a value

  public static double Total;//defining a double variable Total

  public void computeInvoice(double p1)//defining method computeInvoice that take double parameter

  {

      Total = p1 + p1 * (Tax / 100);//defining double variable Total that holds Price value

      System.out.printf("Price $%.2f\n" , Total);//print calculated value

  }

  public void computeInvoice(double p2, int q)//defining method computeInvoice that takes integer and double parameter

  {

      Total = p2 * q;//use Total variable that calculate Price with Tax

      Total = Total + (Total * (Tax/ 100));//calculate taxes on Total

      System.out.printf("Price $%.2f\n" , Total);//print calculated value

  }  

  public void computeInvoice(double p3, int q, double c)//defining method computeInvoice that takes one integer and two-double parameter  

  {

      Total = p3 * q;//use Total to calculate Total price

      Total = Total - c;//remove coupon amount from Total amount

      Total = Total + (Total * (Tax/ 100));//calculate taxes on Total

      System.out.printf("Price $%.2f\n" , Total);//print calculated value

  }

}

public class TestInvoice  //defining Main class TestInvoice  

{

  public static void main(String[] ar)//defining main method  

  {

      Invoicing  obm = new Invoicing ();//creating Invoicing class object obm

      obm.computeInvoice(24.95);//calling method computeInvoice

      obm.computeInvoice(17.5, 4);//calling method computeInvoice

      obm.computeInvoice(10, 6, 20);//calling method computeInvoice

  }

}

Output:

please find attached file.

Explanation:

In the above-given code, a class "Invoicing" is defined, inside the class two static double variable "Total and Tax" is defined, in which the Tax variable holds a value that is "8.0".

In class three same method, "computeInvoice" is used that accepts a different parameter for providing method overloading, which can be defined as follows:

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}