Read the elapsed time on the stopwatch and answer the questions.
In which digit is there the least amount of confidence?
How many significant figures does this measurement have? I need help quick

Answer:

A conductor allows free charges to move about within it. The electrical forces around a conductor will cause free charges to move around inside the conductor until static equilibrium is reached. Any excess charge will collect along the surface of a conductor. Conductors with sharp corners or points will collect more charge at those points.

Explanation:

(b) negative charge

This is the answer

Answer:

acceleration is 8 m/s²

Explanation:

a = 36 - 12 / 3

a = 24 / 3

a = 8

hope this helps :)

Answer:

1

Explanation:

1

Answer:

053.

Explanation:

Given that the radius of curvature of the path, R = 75 m.

Speed of the car on that path , [tex]v_1 = 35 m/s[/tex]

The centripetal force,[tex]F_c[/tex] acting on the body having mass, m, when it moves with the velocity v  on curved path having radiusR

Ris[tex]F_c = mv^2/R[/tex]

Gravitational force, [tex]F_g[/tex] = mg.

Let tha angle of superelevation is [tex]\theta.[/tex]

As the car does not skid even with zero friction, so

[tex]mg\sin\theta = (mv_1^2)/2 \cos\theta[/tex]

[tex]\Rightarrow \tan\theta = v_1^2/2g=\cdots(i)[/tex]

On sunny day, let the minimun static friction coefficient between the wheels and the pavement is [tex]\mu.[/tex]  

As [tex]v_2[/tex] = 118 m/s is greater than   v_so the car tends to skid in upper direction and the frictional

force,f, will acts is downward direction.

As there is no skidding, so

[tex]f+ mg\sin\theta= (m(v_2)^2)/R\cos\theta[/tex]

[tex]\Rightarrow f=(m(v_2)^2)/R\cos\theta - mg\sin\theta[/tex]

where [tex]f= \mu N.[/tex]

[tex]So, \mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{N} \cdots(ii)[/tex]

Where N is the normal reaction can be determined by balancing the force in perpendicular direction of the plane.

[tex]N= mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta[/tex]

From equation (ii)

[tex]\mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]

[tex]=\frac{-g\tan\theta+v^2/R}{v_2^2\tan\theta+g}[/tex]

[tex]= \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]

[tex]=\frac{-g(v_1^2/2g)+v^2/R}{v_2^2(v_1^2/2g)+g}[/tex]

[tex]= \frac{v_2^2/R-v_1^2/R}{g+v_2^2/R\times v_1^2/Rg}[/tex]

[tex]=\frac{118^2/75-35^2/75}{9.81+118^2/75\times 35^2/(75\times 9.81)}[/tex]

=0.53

Hence, the minimum coefficient of friction is 0.53.

The correct answer is A physical change

Explanation:

Jorge's experiment shows water at different temperatures; in this experiment, it is expected at low temperatures such as -20°C water is in solid-state (ice), at medium temperatures such as 40°C water is in a liquid state (liquid water), and at high temperatures such as 120°C water is in gaseous state (water vapor). This implies during this experiment the changing factor is the physical state (solid, gas, or liquid), and this is a physical change because only the physical properties of water change but not its composition or identity. According to this, the correct answer is physical change.

Answer:

The components of the wind in the northern direction is approximately 35.36 km/hr

Similarly, the components of the wind in the western direction is approximately 35.36 km/hr

Explanation:

The given parameters are;

The magnitude of the speed of the wind, v = 50 km/hr

The direction of the wind = The northwest direction

Therefore;

Given that the angle between the northern and western direction = 90°

The angle in the northwestern direction, θ = 90°/2 = 45°

Therefore;

The components of the wind in the northern direction = [tex]v_y[/tex] = v × sin(θ)

Substituting the values, we have;

The components of the wind in the northern direction = [tex]v_y[/tex] = 50 × sin(45°) = 50/√2 ≈ 35.36 km/hr.

Similarly, the components of the wind in the western direction = vₓ = 50 × cos(45°) = 50/√2 ≈ 35.36 km/hr

Answer:

Electricity produced via friction is a development of electric charges on articles. Energizes construct when negative electrons are moved starting with one article then onto the next. The article that surrenders electrons turns out to be decidedly charged, and the item that acknowledges the electrons turns out to be contrarily charged. This can occur in a few different ways.

Explanation:

[tex]\mathrm {All, done!}[/tex]

Answer:

c

Explanation:

impulse Is the product of force and distance so it's generally formula

The impulse should be equivalent to the option c.  a force applied to an object for a period of time.

Impulse of force represent the product of the resultant force ΣF and also the duration of the force Δt when the force should be constant. Also it should be lead to the changed to motion and changes to momentum

Therefore, The impulse should be equivalent to the option c.  a force applied to an object for a period of time.

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Explanation:

Please mark me as the brainliest answer

Answer:

The electrostatic force is larger by a factor of 8.988E9 / 6.674E-11 = 1.35E20

Explanation:

William gave you all the ingredients, but not the answer.  Being both 1/r^2 forces (resulting from massless mediators in QFT), and with unit charges in the problem (1 coulomb, 1 Kg), separated by unit distance (1m), the only nontrivial numerical values in the problem are the constants of proportionality: Coulomb's constant (k) and Newton's gravitational constant (G).  So to "compare and constrast": the ratio of the forces is simply the ratio of these constants.  The electromagnatic force is 1.35 X 10^20 times stronger than the gravitational force.  Assuming positive charge on both objects (the problem is ambiguous on this), they are repelled, whereas the much weaker gravitational force is attractive.  (Gravity only has one kind of "charge" - it's unsigned - and the force is always attractive).  

The problem doesn't say the objects are pointlike: if they have some extent and are either conductive or made of some dielectric, then things get messy because the charge distribution on the object won't be uniform then, but save that for grad school. :-)

Answer:

Hey baby, I love you. Yes i do play metal gear with snake

Explanation:

Answer:

Yes me too. I have played.

Explanation:

Answer:

B is your answer

Explanation:

C, D, and A are true and protons are located inside the nucleus and electrons are located outside the nucleus which means B is your answer.

Answer:

In these reactions the products are higher in energy than the reactants. ... This barrier is due to the fact that to make CO2 and H2O we have to break 4 carbon-hydrogen bonds and some ...

Explanation:

Answer: thermal energy

Explanation: hope this helps

Answer:833

Explanation:

Answer:

c

Explanation:

A spherical solid metal made up of Nickel, Iron and small amount of sulfur, silicon and oxygen.

you are welcome

Answer:

Physics

Explanation:

:):):)

b=36•3

momentum=mass×velocity

The total momentum of the given system is equal to zero. Therefore, option (C) is correct.

The linear momentum can be described as the product of the mass times the velocity of that object. Conservation of momentum is a property of an object as the total amount of momentum stays the same.

According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂v₂

where u₁ and u₂ are initial speed while v₁ & v₂ is final speed and m₁ and m₂ is the mass of the collided objects.

The first ball, m = 8.52 g and v = 2.13 m/s

The momentum of the first ball = 18.15 g.m/s

The second ball is moving in the opposite direction w.r.t. first ball,

The second ball, m = 8.52 g and v = - 2.13 m/s

The momentum of the first ball = - 18.15 g.m/s

The total momentum  of the system = 18.15 + (-18.15) = 0

Therefore, the total momentum of the given system is zero.

Learn more about the law of conservation of linear momentum, here:

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Answer:

See the explanation below

Explanation:

The pressure is defined as the product of the density of the liquid by the gravitational acceleration by the height, and can be easily calculated by means of the following equation.

[tex]P=Ro*g*h[/tex]

where:

Ro = density of the fluid [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation [m]

In this way we can understand that the greater pressure is achieved by means of the height of the liquid, that is, as long as the fluid has more height, greater pressure will be achieved at the bottom.

Therefore in order of decreasing will be

The largest pressure with the largest height of liquid, container B. The next is obtained with container D, the next with container A and the lowest pressure with container C.

The pressure decreases as we go from the container B - D - A - C

Answer:D

Explanation:AP3X

The statement describes the interaction between the permanent magnets and the electromagnet in an electric motor is option D.

A substance which is negative charged at one end and positive charged at another end creating the magnetic field around it.

A bar is a magnet which can attract the particle which are charged. It has two poles North and South.

The permanent magnet create magnetic field very strong. The electromagnet is find in the electric motor. In the motor, loop made up of conductor is rotated by the effect of magnetic field of permanent magnet.

Thus, the correct option is D.

Learn more about magnet.

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Answer: pluto

Explanation:

pluto is the smallest

The gravitational force between the asteroids is 2.7 × 10^-10 N.

Newton's universal law of gravitation states that the force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.

Given that:

Two asteroids with masses 3.45 x 10^3 kg and 6.06 x 10^4 kg are separated by a distance of 7,200 m.

Hence, the gravitational force between the asteroids:

F = GmM/r²

= ( 6.67 x 10^-11 × 3.45 x 10^3 × 6.06 x 10^4)/( 7,200)² N

= 2.7 × 10^-10 N.

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Answer:

B 2.69 x 10-10 N

Explanation:

test right yes yes

Answer:

The answer is C

Explanation:

Answer:

5.3 cm

Explanation:

This question is an illustration of real and apparent distance.

From the question, we have the following given parameters

Real Distance, R = 8.0cm

Refractive Index, μ = 1.5

Required

Determine the apparent distance (A)

The relationship between R, A and μ is:

μ = R/A

i.e.

Refractive Index = Real Distance ÷ Apparent Distance

Substitute values in the above formula

1.5 = 8/A

Multiply both sides by A

1.5 * A = A * 8/A

1.5A = 8

Divide both side by 1.5

1.5A/1.5 = 8/1.5

A = 8/1.5

A = 5.3cm

Hence, the letters would appear at a distance of 5.3cm

Answer:

26m/s²

Explanation:

Given parameters:

Mass of the student  = 60kg

Weight  = 1560N

Unknown:

Acceleration due to gravity  = ?

Solution:

Weight is a force on a body due to gravity;

  Weight  = mass x gravity

Insert the given parameters and solve;

    1560  = 60 x gravity

    Gravity  = [tex]\frac{1560}{60}[/tex]   = 26m/s²

Answer:

resultant force=16N→(TOWARDS THE DIRECTION OF 8N)

Explanation:

resultant force=8N+13N-5N

                        =16N→(TOWARDS THE DIRECTION OF 8N)

Answer:

a. 23.9 m/s b. 69.58°

Explanation:

a. Since the space vehicle is moving at a constant velocity of 22.4 m/s in the y direction relative to the space station, its initial vertical velocity v = 22.4 m/s.

Also, since the space vehicle moves in the y direction, its initial horizontal velocity u = 0 m/s.

Since its acceleration a = 0.206 m/s² for time, t = 40.5 s, we find the final horizontal velocity u' from u' = u + at.

Substituting the values of the variables into the equation, we have

u' = u + at

u' = 0 m/s  + 0.206 m/s² × 40.5 s

= 8.343 m/s

≅ 8.34 m/s

The resultant velocity relative to the space station V = √(v² + u'²)

= √[(22.4m/s)² + (8.34 m/s)²]

= √[501.76 m²/s² + (69.56 m²/s²]

= √[571.32 m²/s²]

= 23.9 m/s

b. The direction of the vehicle's velocity relative to the space station is thus θ = tan⁻¹(v/u')

= tan⁻¹(22.4 m/s/8.34 m/s)

= tan⁻¹(2.6959)

= 69.58°

Answer:

average speed = 0.5 m/s

Explanation:

average speed = (distance) / (elapsed time)

Given time elapsed = 30 seconds and distance = 15 meters

average speed = 15 meters / 30 seconds = 0.5 meters/second = 0.5 m/s