Answer:
i don't know how to explain it but I think it's just the way you do it by yourself
The period of a .75 m pendulum is _s
Hi there!
We can use the following equation for the period of a pendulum:
[tex]\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}[/tex]
T = Period (s)
L = length of simple pendulum (.75 m)
g = acceleration due to gravity (9.8 m/s²)
Plug in the values:
[tex]T = 2\pi \sqrt{\frac{.75}{9.8}} = \boxed{1.738 s}[/tex]
What is the acceleration of the object?
At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by
−0.50t, in m/s2 for t in seconds. It stops at t =
A. 64 s
B. 32 s
C. 16 s
D. 8.0s
E. 4.0s
A car is moving at 16 m/s at a time t = 0. With an acceleration of 0.50t, in m/s², for t, in seconds, it slows down. At t = 8 seconds, it stops. Option D is correct.
What is velocity?The change of displacement with respect to time is defined as the velocity. velocity is a vector quantity.
Given data;
t = 0 ,u=16 m/s
acceleration = −0.50t m/s²
v=0,t=?
The acceleration is found as;
[tex]\rm a= \frac{dv}{dt} \\\\\ dv=adt \\\\ dv=-0.50 \ t dt[/tex]
Intregating both sides we get;
[tex]\rm [v]_0^{16}=-0.50\frac{t^2}{2} \\\\ 16=0.25 t^2\\\\\ t^2=\frac{16}{0.25} \\\\\ t= 8 \ sec[/tex]
Hence, the car stops at t=8sec. Option D is correct.
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Two dwarf galaxies revolve in circles around a normal large galaxy. Dwarf Galaxy A is 70,000 light years away from the large galaxy, and Dwarf Galaxy B is 500,000 ly away from the large galaxy. Which of the two galaxies, A or B, takes the longest time to orbit the large galaxy and what law tell us so
Answer:
B
Explanation:
From Kepler's Third Law, T^2 is proportional to r^3.
Now r of B is larger than r of A,
so T of B is larger than T of A.
Then B takes the longest time.
Dwarf Galaxy B takes the longest time to orbit the large galaxy. This can be explained using Kepler's Third Law of Planetary Motion, also known as the Law of Periods.
Kepler's Third Law states that the square of the orbital period (T) of a celestial body is directly proportional to the cube of the semi-major axis (a) of its elliptical orbit. Mathematically, it can be expressed as:
[tex]\[ T^2 \propto a^3 \][/tex]
Where:
T is the orbital period (time taken for one complete orbit), and
a is the semi-major axis of the elliptical orbit.
In the case of dwarf galaxies A and B revolving around the large galaxy, we can use the distances from the large galaxy to each of the dwarf galaxies as the semi-major axes (a) of their orbits.
Let's compare the values of [tex]\( a^3 \)[/tex] for the two dwarf galaxies:
For Dwarf Galaxy A:
[tex]\( a_{\text{A}} = 70,000 \)[/tex] light years
For Dwarf Galaxy B:
[tex]\( a_{\text{B}} = 500,000 \)[/tex] light years
Now, let's calculate [tex]\( a^3 \)[/tex] for each galaxy:
For Dwarf Galaxy A:
[tex]\( a_{\text{A}}^3 = (70,000)^3 = 343,000,000,000 \)[/tex] cubic light years
For Dwarf Galaxy B:
[tex]\( a_{\text{B}}^3 = (500,000)^3 = 125,000,000,000,000,000 \)[/tex] cubic light years
Since [tex]\( a_{\text{B}}^3 \)[/tex] is significantly larger than [tex]\( a_{\text{A}}^3 \)[/tex], it means that Dwarf Galaxy B has a larger a value and therefore a longer orbital period according to Kepler's Third Law. In other words, Dwarf Galaxy B takes the longest time to orbit the large galaxy.
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What is the effect of clouds on the "output" of a Solar PV module?
Answer:
What is the effect of clouds on the "output" of a Solar PV module?
Clouds do impact photovoltaic panels. The quantity of power your photovoltaic panels can produce is directly dependent on the level of light they receive. ... They will see complete direct sunlight “plus” reflected light from the clouds! They will drink in more energy than they could on a cloudless day!
Explanation:
I hope it will help you...
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Can you please help me with this one
oh ok where is it bring it
Explain why friction becomes desirable and undesirable
Answer:
A friction is very much desirable to stop the body from its moving condition. ... If the friction is more between the block and inclined surface then a large force is required to push the block on the plane.
Explanation:
hope it will help you have a great day bye and Mark brainlist if the answer is correct
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3. An airplane travels at a speed of 600 km/h. How much time will it take to fly a distance of 3180 km to California
Answer:
5.3 hours
Explanation:
(3180 km) / (600 km/h) = 5.3 hours
According to newton second law of motion what is force equal to
Answer:
According to Newton, "Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration."
Force = mass x acceleration
Answer: According to Newton’s Second Law of physics, the force is equal to the mass of the object times the acceleration. The force acting on an object would be equal to the mass of an object times its acceleration... This means the more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration
What do you mean by escape speed at a place?
In celestial mechanics, escape velocity or escape speed is the minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a primary body, thus reaching an infinite distance from it.
PLEASE MARK AS BRAINLIEST
what is the kinetic energy of a sky diver with a mass of 60.0 kg falling at a terminal velocity of 40.0 ms?
Answer:
48,000 J
Explanation:
m = 60.0 kg
v = 40.0 m/s
kinetic energy = mv^2/2 = 60*40^2/2 = 48,000 J
using my friend account again
HELP ME PLIS
On the periodic table, the elements known as noble gases are found in
Answer:
The noble gases are located in the 18th group of the periodic table.
What is the speed of the plane wave defined by sin(ωt−kx) with ω=3376.7 Thz and k=11.79μm−1?
The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s
Speed of a wavethe speed of the plane wave defined by sin(ωt−kx) is v = ω/k where
ω = angular frequency of wave and k = wave number of waveNow ω = 3376.7 Thz = 3376.7 × 10¹² Hz and k = 11.79μm⁻¹ = 11.79 × 10⁶ m⁻¹
So, substituting the values of the variables into v, we have
v = ω/k
v = 3376.7 × 10¹² Hz/11.79 × 10⁶ m⁻¹
v = 286.4 × 10⁶ m/s
v = 2.864 × 10⁸ m/s
The speed of the plane wave defined by sin(ωt−kx) is 2.864 × 10⁸ m/s
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The lightbulb of a flashlight creates light and heat, both of which are forms of
energy. What is the source of the energy?
A. Elastic potential energy stored in the molecules of the flashlight
B. Chemical potential energy stored in the ions of the battery
C. Kinetic energy of the electrons flowing through the lightbulb
O D. Gravitational potential energy stored in Earth's gravitational field
Answer:
B
Explanation:
how can i plot a graph?
Answer:
so you have your boxes go by tens on the x-axis okay which is the one going straight up then the second number goes by 5's is your y-axis. 30,6 so 30 is your x and 6 is your y. start at 0,0 which is the little corner piece. find 30 on x and then go over 6 and that's it!
Explanation:
A new company is making security cameras. These security cameras will be different than other security cameras because instead of detecting motion, they will detect body heat.
What type of electromagnetic wave will the camera detect?
A
gamma ray
B
infrared
C
microwave
D
radio wave
Answer:
b
Explanation:
Car 1 brakes to a stop on a dry road. Car 2 does the same thing, at the same speed, on a road where it has been raining. Explain how the following will be different for car 2: a) braking distance, b) thinking distance and c) stopping distance.
Answer: car 1 is going how fast
Explanation: no need to answer without speed I won't know distance.
Physics Unit 5 CA - Conservation of
1. A student is pushing a car toward a gas station. They exert a constant force of 100 N
on the car for 40 m bring the car from rest to 5 m/s. What is the mass of the car?
Answer:
160 kg
Explanation:
f = ma
100 = m * a
a = v/t
v = distanc/time
dist = 40m
time = 8 sec
v = 40/8
a = 40/(64)= 5/8
m = 100*8/5= 160 kg
A car engine burns gas at 495 K and exhausts to the air at 293 K if it ran at the highest possible efficiency and use 10,000 J of input heat how much he would it be rejected into the air? WILL GIVE BRAINLIEST
Answer:
5,920 J
Explanation:
Lowest temperature T₂ = 293 K
Highest temperature T₁ = 495 K
Highest possible efficiency e = 1 - T₂/T₁ = 1 - 293/495 = 0.408
Input heat Q₁ = 10,000 J
Find output heat Q₂
e = 1 - Q₂/Q₁
0.408 = 1 - Q₂/10,000
Q₂/10,000 = 1 - 0.408 = 0.592
so
Q₂ = 10,000 x 0.592 = 5,920 J
If each pull-up requires 300 J and Ben does a pull-up in 2 seconds, what is his power? 150 watts 300 watts 600 watts 750 watts
Answer:
150 watts
Explanation:
300/2 = 150 watts
Answer:
150 watts
Explanation:
The explanation is in the picture
PLEASE MARK BRAINLIEST
If you increase your speed from 10 mph to 30 mph, how much will your stopping distance increase?
When you double the speed of your car, your braking distance quadruples. every time you double your speed, you multiply your braking distance by four.
The stopping distance of a vehicle is the sum of breaking distance and thinking distance. The stopping distance of a vehicle when we increase the velocity from 10mph to 30 mph, increases from30 feet to 90 feet.
What is stopping distance?Stopping distance is the distance covered by a vehicle when we stops. Distance is the product of time and velocity. As the velocity increases then, the time taken to cover the distance will be lower.
Stopping distance mathematically is the sum of breaking distance and thinking distance .Thinking distance is simply the speed and it is in fact means how long it takes on average to think for a break.
Breaking distance is means how long the driver takes to break or stop in actual. In general, the breaking distance is speed multiplied by 2.
Thus, for 10 mph, the thinking distance is 10 feet and breaking distance is 10 × 2 = 20 feet and therefore, the stopping distance is 10 + 20 =30 feet.
Similarly for 30 mph, breaking distance is 60 feet and thinking distance is 30 feet thus, having 60 + 30 = 90 feet of stopping distance.
Therefore, when the speed increased from 10 mph to 30 mph, stopping distance increases from 30 feet to 90 feet.
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Light passes through a single slit of width 8.77 x 10-6 m. The second (m = 2 diffraction minimum occurs at an angle of 5.62º. What is the wavelength of the light IN NANOMETERS?
Answer:
429.424
Explanation:
Trust :)
The wavelength of the light passing through the single slit is approximately 429 nanometers.
To calculate the wavelength of the light passing through a single slit, we can use the formula for the diffraction of light:
w × sin(θ) = m ×λ
Where:
w is the width of the slit
θ is the angle of the diffraction minimum
m is the order of the diffraction minimum
λ is the wavelength of the light
Given:
Width of the slit (w) = 8.77 × 10^(-6) m
Angle of the diffraction minimum (θ) = 5.62º = 5.62° = 5.62 × π/180 radians
Order of the diffraction minimum (m) = 2
To solve for the wavelength (λ), rearrange the formula:
λ = (w × sin(θ)) / m
Substituting the given values:
λ = (8.77 × 10^(-6) m × sin(5.62° × π/180)) / 2
Calculating this expression:
λ ≈ (8.77 × [tex]10^{(-6)[/tex] m × sin(0.098)) / 2
λ ≈ (8.77 ×[tex]10^{(-6)[/tex] m × 0.098) / 2
λ ≈ 4.29 ×[tex]10^{(-7)[/tex] m
To convert the wavelength to nanometers, we multiply by[tex]10^9[/tex]:
λ = 4.29 × [tex]10^{(-7)[/tex] m × 10^9 nm/m
λ ≈ 429 nm
Therefore, the wavelength of the light passing through the single slit is approximately 429 nanometers.
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Why do charged particles interact with each other?(1 point)
because they are small
because they are small
because they are in the same molecule
because they are in the same molecule
because of their electric and magnetic fields
because of their electric and magnetic fields
because they have opposite charges
Answer:
because they have opposite charges
Explanation:
If you're talking about magnetism and electricity, the laws are that like charges attact and and unlike charges repel.
Charged particles interact with each other because they have opposite charges.
How charged particles interact with each other?When charged particles are close to each other, their electric fields interact. So particles with opposite charges attract each other whereas particles with similar charges repel each other.
So we can conclude that Charged particles interact with each other because they have opposite charges.
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If a green ball is rolled from an initial position of 2m and travels to a final
position of 10m - what distance does it travel? (just type the number, no
need for units).
Answer:
10m-2m = 8m
8
Hope this helps!
compare your previous result to the present hrf result are there any changes if yes explain your answer
Answer:
I don't know what are you saying but I don't have any results
Explanation:
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A football is kicked at ground level with a speed of 18.0 m/s at an angle of 31.0 to the horizontal. How much longer does it hit the ground?
How much work is done on a small car if 4250 N force is exerted to move it 83.5 m to the side of the road?
Answer:
354875 J
Explanation:
The equation for Work is:
[tex]Work=Force*Distance[/tex]
We can plug in the given values into the equation:
[tex]Work=4250N*83.5m=354875J[/tex]
Two spheres carry a charge of 1x10^-7 C. Their centers are separated by 0.7m. Calculate the magnitude of the force between the two charged objects.
Write your answer in scientific notation using one significant figure
PLEASE HELP ME
We have that the force between the two charged objects is mathematically given as
F=2.349N
Magnitude of the force between two charged objects.Question Parameters:
Two spheres carry a charge of 1x10^-7 C.
Their centers are separated by 0.7m.
Generally the equation for the Force is mathematically given as
[tex]F=\frac{q1q2}{4*\pi e*r}[/tex]
Therefore
[tex]F=\frac{(1e-7)^2}{9e9*0.7}[/tex]
F=2.349N
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Alkali Metals • Most ___________________ metals
Answer: They’re the most reactive metals
Explanation: They have larger ionic radii and low ionization energies