Question 1
Describe a procedure you could follow to determine the specific heat of a 45-g piece of metal.
Instructions

Question 1Describe A Procedure You Could Follow To Determine The Specific Heat Of A 45-g Piece Of Metal.Instructions

Answers

Answer 1

Answer:

2.1 × 10^-8 J/°c

Explanation:

Is this the answer if yes I would explain if not , that's all I know .

Answer 2

When a 58.8-g piece of hot alloy is placed in 125 g of cold water in a calorimeter, the temperature of the alloy decreases by 106.1°C, while the temperature of the water increases by 10.5°C. The specific heat of the alloy is 0.087 J/(g °C).

Step 1: We know that the heat gained by the water is equal to the heat lost by the alloy. This is based on the law of conservation of energy, which states that energy cannot be created or destroyed, only transferred.

Step 2: We can calculate the heat gained by the water using the formula:

q = mcΔT

where:

q = heat energy

m = mass

c = specific heat

ΔT = change in temperature

For water, the specific heat (c) is 4.18 J/(g °C). So, the heat gained by the water is:

q = (125 g)(4.18 J/(g °C))(10.5 °C) = 5497.5 J

Step 3: The heat lost by the alloy is equal to the heat gained by the water. So, the heat lost by the alloy is also 5497.5 J.

Step 4: We can calculate the specific heat of the alloy using the formula:

c = q/(mΔT)

where:

c = specific heat

q = heat energy

m = mass

ΔT = change in temperature

So, the specific heat of the alloy is:

c = 5497.5 J / (58.8 g)(106.1 °C) = 0.087 J/(g °C)

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Related Questions

How much energy is required to vaporize 1.5 kg of aluminum? (Refer to table
of latent heat values.)
A. 733 kJ
B. 1650 kJ
C. 7095 kJ
D. 600 kJ

Answers

Answer:

B 1650

Explanation:

Please help me l don’t understand please !!!!!!

Answers

Answer: C

Explanation:

he never had evidence in the first place that was nearly enough.

Approximately 1 mL of two clear, colorless solutions, 0.1 M Ba(NO3)2 and 0.1 M Na2SO4, were combined. Upon mixing, a thick milky white precipitate formed. After centrifugation, the solution above the precipitate was found to be clear and colorless. Based on the these observations, determine if a reaction occurred. If so, what is the net ionic equation for the reaction.

Answers

Answer:

Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)

Explanation:

Let's consider the molecular equation for the reaction between Ba(NO₃)₂ and Na₂SO₄. This is a double displacement reaction in which BaSO₄ forms a white precipitate.

Ba(NO₃)₂(aq) + Na₂SO₄(aq) ⇒ BaSO₄(s) + 2 NaNO₃(aq)

The complete ionic equation includes all the ions and insoluble species.

Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Na⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and insoluble species.

Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)

Plzzz help me plz I am timed!!

Answers

Answer:

Explanation:

pretty sure its gaillieo

Answer:

Galileo

Explanation:

he was the first one to use a telescope

Determine the mass of hydrogen contained in 9.06 x 1024 H2O molecules.

Answers

Answer:

15.2 g H2

Explanation:

2H2O -> 2H2 + O2

9.06 x 10^24 molecules x (1 mol/6.022 x 10^23 molecules) x (2 mol H2/2 mol H2O) x (1.008 g/1 mol) = 15.2 g H2

How many moles are in 272 grams of hydrogen peroxide (H2O2) ?

Answers

Answer:

8 moles

Explanation:

When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.

Meaning that for this problem, we'll use the molar mass of hydrogen peroxide (H₂O₂), as follows:

272 g ÷ 34 g/mol = 8 mol

There are 8 moles in 272 grams of hydrogen peroxide.

Plz help me I am timed!!!!!

Answers

Answer:

i think its the gibbous phase

Explanation:

The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calculate the Kspvalue, take the negative log and enter the (pKsp) value with 2 decimal places.

Answers

Answer: [tex]K_{sp}=1.25\times 10^{-14}[/tex]

[tex]pK_{sp}=13.90[/tex]

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as [tex]K_{sp}[/tex]  

The equation for the ionization of magnesium phosphate is given as:

[tex]Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}[/tex]

 When the solubility of [tex]Mg_3(PO_4)_2[/tex] is S moles/liter, then the solubility of [tex]Mg^{2+}[/tex] will be 3S moles\liter and solubility of [tex]PO_4^{3-}[/tex] will be 2S moles/liter.

Thus S = 0.173 g/L or [tex]\frac{0.173g/L}{262.8g/mol}=0.00065mol/L[/tex]

[tex]K_{sp}=(3S)^3\times (2S)^2[/tex]

[tex]K_{sp}=108S^5[/tex]

[tex]K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}[/tex]

[tex]pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90[/tex]

The value of Ksp and pKsp for the given reaction is 1.25 × 10⁻¹⁴ and 13.90 respectively.

How we calculate the Ksp?

Solubility product constant (Ksp) is define as the product of the solubilities of the products, present in any chemical reaction.

Given chemical reaction will be represented as:

Mg₃(PO₄)₂ → 3Mg²⁺ + 2PO₄³⁻

Solubility of Mg₃(PO₄)₂ = 0.173 g/L or 0.173g/L / 262.8g/mole = 0.00065mol/L
Now for the given reaction let we consider that solubility of Mg₃(PO₄)₂ be x, solubility of Mg²⁺ be 3x and solubility of PO₄³⁻ will be 2x and equation for Ksp will be written as:
Ksp = [Mg²⁺]³[PO₄³⁻]²

Ksp = [3x]³[2x]²

Ksp = 108[x]⁵

Now we pot the solubility value of x as the solubility of Mg₃(PO₄)₂ & we get,

Ksp = 108(0.00065)⁵

Ksp = 1.25 × 10⁻¹⁴

Now we calculate the value of pKsp as:
pKsp = -log(Ksp)

pKsp = -log(1.25 × 10⁻¹⁴)

pKsp = -(-13.90) = 13.90

Hence value of pKsp is 13.90.

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A low pitch sound is associated with which of the following?
а. high frequency
b. low frequency
с. fundamental tone
d. low intensity

No links plz

Answers

(D) I think not sure

1. What do producers do, and what is another name for them?

Answers

Producers are the foundation of every food web in every ecosystem—they occupy what is called the first tropic level of the food web. The second trophic level consists of primary consumers—the herbivores, or animals that eat plants. At the top level are secondary consumers—the carnivores and omnivores who eat the primary consumers. Ultimately, decomposers break down dead organisms, returning vital nutrients to the soil, and restarting the cycle. Another name for producers is autotrophs, which means “self-nourishers.” There are two kinds of autotrophs. The most common are photoautotrophs—producers that carry out photosynthesis. Trees, grasses, and shrubs are the most important terrestrial photoautotrophs.  In most aquatic ecosystems, including lakes and oceans, algae are the most important photoautotrophs.

Which has more mass, 1 mole of magnesium or 1 mole of calcium?

Answers

Calcium is the answer

Answer:

calcium has more mass

Explanation:

1 mole calcium mass= 40.078 g

1 mole magnesium mass= 24.305 g

Of the following waves, which kind of wave does NOT require a medium?
a. light
b. water
с. ultrasound
d. sound

Answers

A. Both C and D need water as a medium and sound needs air to vibrate in order to travel. light, on the other hand, does not need a medium

Anyone know the answer

Answers

Answer:

b

Explanation:

i know

A flask contains 1.45 moles of N2, 0.659 moles of He. If the total pressure is 775 torr, what is the partial pressure of O2 ?

Answers

Answer:

533.2 torr.

Explanation:

The following data were obtained from the question:

Mole of N₂ = 1.45 moles

Moles the He = 0.659 mole

Total pressure = 775 torr

Partial pressure of N₂ =?

Next, we shall determine the mole fraction of N₂. This can be obtained as follow:

Mole of N₂ = 1.45 moles

Moles the He = 0.659 mole

Total mole = 1.45 + 0.659 = 2.109 moles

Mole fraction of N₂ = Mole of N₂ / total mole

Mole fraction of N₂ = 1.45 / 2.109

Mole fraction of N₂ = 0.688

Gina, we shall determine the partial pressure of N₂. This can be obtained as follow:

Total pressure = 775 torr

Mole fraction of N₂ = 0.688

Partial pressure of N₂ =?

Partial pressure of N₂ = total pressure × mole fraction of N₂

Partial pressure of N₂ = 775 × 0.688

Partial pressure of N₂ = 533.2 torr.

Therefore, the partial pressure of N₂ is 533.2 torr.

Paul swam 7 5/8 miles. His sister swam five times as many miles. How many miles did Paul's sister swim?

Answers

Answer:

Distance cover by Paul's sister by swim = 38.125 miles

Explanation:

Given:

Distance cover by Paul by swim = [tex]7\frac{5}{8}[/tex] = 61/8 miles

Distance cover by Paul's sister by swim = 5 times Distance cover by Paul

Find:

Distance cover by Paul's sister by swim

Computation:

Distance cover by Paul's sister by swim = 5 times Distance cover by Paul

Distance cover by Paul's sister by swim = 5 x [61 / 8 miles]

Distance cover by Paul's sister by swim = 305 / 8 miles

Distance cover by Paul's sister by swim = 38.125 miles

What type of energy is being represented in the image

Answers

Answer:

Its Kinetic  energy

Explanation:

You are giving the bow potential energy. "When you let the bow go, it returns to its original shape. The energy is transformed to kinetic energy and transferred to the arrow"

Answer:

potential

Explanation:

the energy is potential lol

how many moles of ammonia can be formed from 4.0 mol H2

how many moles of hydrogen are required to form 8.0 mol NH3

how many moles of nitrogen are required to react with 6.0 mol H2

Answers

Answer: 1. 2.7 moles  of ammonia are formed

2. 12.0 moles  of hydrogen are required

3. 2.0 moles of nitrogen are required

Explanation:

The balanced chemical equation is:

[tex]N_2+3H_2\rightarrow 2NH_3[/tex]

According to stoichiometry:

3 moles of hydrogen form = 2 moles of ammonia

Thus 4.0 moles of hydrogen form =[tex]\frac{2}{3}\times 4.0=2.7moles[/tex] of ammonia

According to stoichiometry:

2 moles of ammonia are formed by = 3 moles of hydrogen

Thus 8.0 moles of ammonia are formed by  =[tex]\frac{3}{2}\times 8.0=12.0moles[/tex] of hydrogen

According to stoichiometry:

3 moles of hydrogen react with = 1 mole of nitrogen

Thus 6.0 moles of hydrogen react with =[tex]\frac{1}{3}\times 6.0=2.0moles[/tex] of nitrogen

If the colour of a solution turns pink on adding few drops of phenolphthalein indicator, it means solution is acidic. Select one :
True
False​

Answers

Answer:

False, it becomes colourless in acidic solutions and turns pink in basic solutions

Scientists have developed a new way to extract natural gas, called hydraulic fracturing, or fracking. Which of these is a positive impact of this method?

A. Decreased habitat
B. Decreased earthquakes
C. Increased supply
D. Increased demand​

Answers

Answer:

The answer is C if its wrong you can report my answer I'm 100% sure its C

What is the coefficient for hydrogen in the balanced equation for the reaction of solid tungsten(VI) oxide with gaseous hydrogen to form solid tungsten and liquid water?

Answers

Answer:

2

Explanation:

WO2(s) + 2H2(g) -> W(s) + 2H2O(l)

The tablets were crushed, and 4.9993 g of the powder was transferred to a beaker and reacted with HCl. After filtration, the filtrate was transferred to a 100-mL volumetric flask and diluted with water. 20.00 mL of this stock solution were combined with 0.2 M Na3PO4. The resulting precipitate weighed 0.3451 g after drying. Calculate the moles of BiPO4 precipitated, the moles of Bi3 in the stock solution, and the mass of BSS per tablet.

Answers

Answer:

Explanation:

From the information given:

Mass of BiPO₄ = 0.3451 g

Number of moles of BiPO₄ = [tex]0.3451 \ g \ BiPO_4 \times \dfrac{1 \ mol \ BiPO_4}{303.95 \ g \ BiPO_4}[/tex]

[tex]= 0.001135 \ mol[/tex]

The number of moles of Bi³⁺ in 20.00 mL is:[tex]= 0.001135 \ mol \ BiPO_4 \times \dfrac{1 \ mol \ of \ Bi^{3+}}{1 \ mol \ BiPO_4}[/tex]

=  0.001135 mol of Bi³⁺

The number of moles of Bi³⁺ in 100 mL stock solution

[tex]= 0.001135 \ mol \ Bi^{3+} \times \dfrac{100 \ mL}{20.0 \ mL}[/tex]

[tex]= 0.005675 \ mol[/tex]

Mass of BSS in 4.9993 g tablets

[tex]m = 0.005675 \ mol \ Bi^{3+} \times \dfrac{1 \ mol \ BSS}{1 \ mol \Bi^{3+}} \times \dfrac{362.1 \ g \ BSS}{1 \ mol \ BSS}[/tex]

m = 2.055 g BSS

Mass of BSS in 5.0103 g (5 tables)

[tex]m = 2.055 g \ BSS \times \dfrac{5.0103 \ g}{4.9993 \ g}[/tex]

= 2.06 g

The mass of BSS per tablet is [tex]=\dfrac{2.06 \ g}{5 \ tablet}[/tex]

= 0.412 g BSS/ tablet

1.Why do you think the agricultural revolution led to more population growth?

Answers

Answer:

The agricultural revolution increased agricultural production and technological advancements. I think this led to population growth because the increase in labor and the increase in technologies increased human deveolpment. The revolution also allowed farmers to grow and produce more food and transport it to where it was needed.

Explanation:

When planning a simple experiment, what does it mean to “test one variable”?

a During the experiment, the scientist keeps the control the same but changes many other elements he or she is testing.

b During the experiment, the scientist has only one element, or variable, that is changed to test the hypothesis.

c The scientist can only use simple language and materials when planning the one variable to be tested.

d The scientist plans and performs just one science experiment a day to test one variable.

Answers

Answer:

I believe the answer is "b". "During the experiment, the scientist has only one element, or variable, that is changed to test the hypothesis."

Explanation:

I remember from last year but I'm not totally sure. Good luck!

The experimental setup has been the design that includes the experimental and the control group. during the experiment, only one variable is changed to test the hypothesis. Thus, option b is correct.

What is experimental design?

The experiment design includes the testing of the hypothesis to solve the problem and reach the solution through the analysis of the observations. It has been the setup that includes the test and the control group that involves the dependent, independent, and controlled variables.

Testing one variable in the experimental designs means changing one of the elements of the experience to prove the reliability of the hypothesis. This variable is the factor that alters and affects the other factors of the experiment and leads to a cause and effect.

The result of the effect of the hypothesis proves the testability of the experiment and provides solutions to the research question. This further leads to the formulation of the law and theory.

Therefore, option A. testing one variable involves proving the hypothesis.

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The reaction for the formation of ammonia is given a
N2(g) + 3H2(g) = 21H3(g)
write the vate reaction for :
a) the formation of NH₃.
6) the disappearance of N and H₂​

Answers

Answer:

a.

[tex]rate_{NH_3}=\frac{2d[NH_3]}{dt}[/tex]

b.

[tex]rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}[/tex]

Explanation:

Hello there!

In this case, according to the law of rate proportions, it is possible to write the the rates of reaction for the formation of NH3 and the disappearance of the N2 and H2, by considering that the coefficient in the reaction for NH3 is +2 and those of N2 and H2, -1 and -3 respectively. Moreover, we set up these equations as derivatives as shown below:

a.

[tex]rate_{NH_3}=\frac{2d[NH_3]}{dt}[/tex]

b.

[tex]rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}[/tex]

Best regards!

As a future educator how will you handle a pupil who could possibly be a gifted child

Answers

Answer:

Learn how gifted students think. ...

Created tiered assignments for students. ...

Include a variety of levels in your classroom library. ...

Utilize their talents and interests. ...

Explore real-word application.

Tam a highly reactive alkali metal in period 3 with only one valence electron
O Sodium (Na)
Beryllium (Be)
Magnesium (Mg)

Answers

Answer:

Sodium (Na)

Helium

Magnesium (Mg).

Explanation:

From the periodic table, we will understand that the group 1 metals are the alkali metal. However, the period runs from left to right on the periodic table while the group runs from up to down in the periodic table. In period 3, the alkali metal present there with one valence electron in its outermost shell is sodium (Na).

The only noble gas exists in the last group, group zero of the periodic table. However, the only noble gas with two electrons in its outermost shell is called Helium

The ALkaline earth metals are group 2 metals. They are usually shiny metals and the ability to lose 2 electrons in their outermost electron shell. The alkaline earth metal located in period 3 is Magnesium (Mg).

What is another name for heat?
A
light energy
B.
infrared energy
C
Thermal energy
D
electromagnetic energy

Answers

Answer:

C

Explanation:

thermal energy is the another name for heat

Which statement describes a homogeneous catalyst?
do
It is in a gaseous phase only. It is in the same phase as the reactants.
It is completely consumed by reactants.
It forms different products than the uncatalyzed reaction forms.

Answers

A homogeneous catalyst is in the same phase as the reactants.

The statement which is  given below describe a homogeneous catalyst.

"It is in the same phase as the reactants"

What is homogeneous catalyst?

The catalyst which have similar phase to the reactant of the reaction is called homogeneous catalyst.

Mostly in  homogeneous catalyst, catalyst present in liquid form.

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Calculate the pH of each solution:

0.030 M HBr

3.0 M HF

0.50 M HNO3

O.0010 M NaOH

0.150 M KOH

Answers

تسمضحسحسىحشخشوثوسهعسحضجثوض

In the balanced equation-aPb(NO3)2(s)heatb PbO(s)+ c NO2(g)+ dO2(g); the values of a,b,c, d are respectively

Answers

Answer:

The balance reaction is

2Pb(NO3)2 ----》4NO2+2PbO+O2

hence the value of a,b,c,d are 2,4,2,1 respectively!

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