Puzzle One
Determine the correct vocabulary word(s) in the questions below. To break the code of puzzle
one you will need to determine the third letter of the word in EACH space and then put those
letters in alphabetical order to break the code. For example, if the first blank was MODE the
letter you would use to help you break out would be D.
*Hint: Use the word bank to help you, some words may be used more than once and some may
not be used at all.
1) The
tells you how the data is spread out
of the data.
for
2) The might be a better representation of the data if there are
outliers that skew the data.
3) To find the
of
you add the numbers and
by the quantity
distance between
4) The Mean Absolute Deviation (MAD) is the
each
point and the
MODE
MEDIAN
MEAN
RANGE
NUMBERS
QUARTILE
Word Bank:
MULTIPLY
AVERAGE
DIVIDE
SUBTRACT
INNER
DATA
FIFTY
TWENTY
PERCENT
Code:
Math in the Mid 2019
MI

Answer:

3.14 square inches or π square inches

Step-by-step explanation:

The radius of a circle is 1 inch. What is the area?

r=1 in

The formula for the area of a circle is given as:

πr²

The radius (r) = 1 inch

Hence,

Area of the circle = π × 1²

= 3.1415926536 square inches

Approximately = 3.14 square inches or we can say that the Area of the circle = π square inches

Answer:

(1,5) because, before it was at (3,8) and  

3 – 2 = 1      

8 – 3 = 5

For further explanation:

(3,8) / (2,3) = (1,5)

2 for 2 units left and 3 for 3 units down

Given information: Consider a binomial distribution. About 47% of Salinas residents bank entirely online.

A random sample of 62 residents is selected. Find the probability that less than 21 bank entirely online. The given data follows binomial distribution with n = 62 and p = 0.47

Let X be the random variable representing the number of residents bank entirely online. Then X ~ B(62, 0.47) We need to find the probability that less than 21 bank entirely online. P(X < 21) = P(X ≤ 20)P(X ≤ 20) = ∑P(X = x) , where x = 0, 1, 2, 3, ... 20Using binomial probability distribution, P(X ≤ 20) = ∑P(X = x) , where x = 0, 1, 2, 3, ... 20P(X ≤ 20) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + ... + P(X = 20)P(X ≤ 20) = ∑P(X = x) , where x = 0, 1, 2, 3, ... 20P(X ≤ 20) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + ... + P(X = 20)P(X ≤ 20) = ∑P(X = x) , where x = 0, 1, 2, 3, ... 20P(X ≤ 20) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + ... + P(X = 20)P(X ≤ 20) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + ... + P(X = 20)

Now, we can use a calculator or software to find this sum. Using software or calculator, P(X ≤ 20) = 0.0251Therefore, the probability that less than 21 bank entirely online is 0.0251. Hence, the correct option is 0.0251.

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Answer:

3.9mm

Step-by-step explanation:

Answer:

A is the answer.

Step-by-step explanation: It would go up about 2.2 i hope i helped! <3

Answer: A is your answer

Step-by-step explanation:

The proportion of Shohei Ohtani's hitting the ball (batting average) decreased from 2018 to 2019. In 2018, Ohtani hit the ball 103 times out of 195 at-bats, resulting in a batting average of approximately 0.528.

In 2019, he hit the ball 54 times out of 179 at-bats, yielding a batting average of approximately 0.302. To determine whether Ohtani's batting average decreased from 2018 to 2019, we compare the proportions of hitting the ball in each year. Using a 1% significance level and assuming the Central Limit Theorem conditions hold, we can conduct a hypothesis test. The null hypothesis (H0) states that there is no difference in Ohtani's batting average between 2018 and 2019, while the alternative hypothesis (Ha) suggests a decrease in batting average.

To test the hypotheses, we can use a two-sample z-test for proportions. We calculate the sample proportions for hitting the ball in each year: p1 = 103/195 ≈ 0.528 in 2018 and p2 = 54/179 ≈ 0.302 in 2019. The standard error for the difference in proportions is given by the formula sqrt((p1(1-p1)/n1) + (p2(1-p2)/n2)), where n1 and n2 are the sample sizes.

Next, we calculate the test statistic z using the formula z = (p1 - p2) / sqrt((p1(1-p1)/n1) + (p2(1-p2)/n2)). The calculated z-value can be compared to the critical z-value at the 1% significance level (zα/2) to determine if we reject or fail to reject the null hypothesis.

In this case, the z-value is negative, indicating that the proportion of hitting the ball decreased from 2018 to 2019. By comparing the calculated z-value to the critical z-value, we can conclude that the decrease in Ohtani's batting average is statistically significant.

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To evaluate the iterated integral ∫∫∫ R x[tex]y^{2}[/tex] dz dy dx over the given region R in cylindrical coordinates, we first convert the limits of integration and the integrand to the cylindrical form. Then we evaluate the integral using the appropriate transformations and calculations.

In cylindrical coordinates, we express points in three-dimensional space using the variables (ρ, θ, z), where ρ represents the distance from the origin to a point projected onto the xy-plane, θ denotes the angle measured counterclockwise from the positive x-axis to the projection of the point onto the xy-plane, and z represents the height of the point above or below the xy-plane.

To evaluate the given iterated integral, we begin by transforming the limits of integration. The outermost integral corresponds to the variable ρ, which ranges from 0 to 1. The next integral corresponds to θ and remains unchanged since the region R does not involve any angular restrictions. The innermost integral corresponds to z and ranges from the lower limit of √(1 - [tex]x^{2}[/tex]) to the upper limit of √(1 - [tex]x^{2}[/tex]), as determined by the given limits of integration.

Next, we convert the integrand, [tex]xy^2[/tex], to cylindrical coordinates. The variable x is replaced by ρcosθ, and y is replaced by ρsinθ, giving us [tex]ρ^3cosθsin^2θ[/tex].

With the limits of integration and the integrand expressed in cylindrical coordinates, we proceed to evaluate the iterated integral. Following the order of integration, we integrate ρ from 0 to 1, θ from 0 to 2π, and z from √(1 - [tex]x^{2}[/tex]) to -√(1 -[tex]x^{2}[/tex]). The integration of ρ yields [tex]ρ^4[/tex]/4, the integration of θ results in 2π, and the integration of z simplifies to 0.

Finally, we substitute the limits of integration and perform the calculations: (∫(0 to 1) [tex]ρ^4[/tex]/4 dρ) * (2π) * (0). Evaluating the integral of[tex]ρ^4[/tex]/4 yields 1/20, and multiplying this by 2π and 0 gives us the final result of 0.

Therefore, the evaluated iterated integral in cylindrical coordinates is 0.

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Answer: 180 ft^3

Step-by-step explanation:

Answer: 180 ft is the answer

Step-by-step explanation:

Answer:

d . 19528

Step-by-step explanation:

maaf jika salah

Answer:

slope-intercept form: y= -5/4x-1

Step-by-step explanation:

Answer:

17

Step-by-step explanation:

Answer: $10

Step-by-step explanation:

Let Josie's money be x

Since Joe has half as much as Josie. Joe's money will be: x/2 = 0.5x

Bob has four times as much money as Joe. Bob's money will be = (4 × 0.5x) = 2x

Therefore, we add all the amount together and equate to $35. This will be:

x + 0.5x + 2x = 35

3.5x = 35

x = 35/3.5

x = 10

Josie has $10

The number of people who received fewer than 100 spam messages in the university department is calculated below:

Total number of messages tagged as spam = 6693

Total number of people = 12

Total number of people who received more than 100 spam messages = 11

Number of people who received fewer than 100 spam messages = 1

The number of people who received fewer than 100 spam messages can be calculated by subtracting the total number of people who received more than 100 spam messages from the total number of people in the department.

Thus, the other 1 person received a total of: 6693 - (1818 + 1358 + 442 + 416 + 399 + 389 + 304 + 251 + 251 + 178 + 158 + 103) = 474

Graph illustrating the data collected from students and faculty in the department. it is clear that the majority of students and faculty members in the department received more than 100 spam messages. One person received fewer than 100 spam messages. The number of spam messages received seems to decrease with time, which may indicate that the spam filter is effective.

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Answer:

B

Step-by-step explanation:

cus thats the formula

Answer:

16

Step-by-step explanation:

p=k√q

8=k√25

8=k5

k=8/5

p when q=100

p=8/5*√100

p=8/5*10

p=16

Answer:

The mode is 23

Step-by-step explanation:

Answer:

400

1.05

Step-by-step explanation:

The athlete should take the second offer.

It is given by the formula,

A = P(1+r)ⁿ

where A is the value after n period of time, P is the initial amount, and,

r is the rate of increment or decrement.

Now, Total amount = $400,000(1+5%)⁷

                    = $400,000(1+0.05)⁷

                    = $400,000(1.4071)

                    = $562840.17

Now, the total amount that the pro-athlete will get in 8 years is,

Total amount = $425,000(1+4%)⁷

                    = $425,000(1+0.04)⁷

                    = $425,000(1.3159)

                    = $559,271

Since the total amount that the athlete will get in the next 8 years is more for the second offer, the athlete should take the second offer.

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the answer would be b on scholar

Answer:

3 (x² + 5) (x - 2)

Step-by-step explanation:

3x³- 6x² + 15x - 30

=> 3 (x³ - 2x² + 5x - 10)

=> 3 [x²(x - 2) + 5 (x - 2)]

=> 3 (x² + 5) (x - 2)

Answer:

C. y = -x + 2

Step-by-step explanation:

Sana nakatulong

Answer:

33/12 or 2.75

Step-by-step explanation:

6 1⁄6 - 3 5⁄12

37/6 - 41/12

74/12 - 41/12

33/12 or 2.75

The subset satisfies all three conditions, it is a subspace of [tex]R^{3}[/tex].

To determine if the described set is a subspace, we need to check if it satisfies three conditions: closure under addition, closure under scalar multiplication, and contains the zero vector.

Let's consider the subset of [tex]R^{3}[/tex] consisting of vectors of the form (a, b, c), where a = b = c.

Closure under addition: Let (a₁, b₁, c₁) and (a₂, b₂, c₂) be two vectors in the subset.

Their sum is (a₁ + a₂, b₁ + b₂, c₁ + c₂).

Since a₁ = b₁ = c₁ and a₂ = b₂ = c₂, we have (a₁ + a₂, b₁ + b₂, c₁ + c₂) = (a₁ + a₁, b₁ + b₁, c₁ + c₁) = (2a₁, 2b₁, 2c₁).

Since 2a₁ = 2b₁ = 2c₁, the sum is also in the subset.

Closure under scalar multiplication: Let (a, b, c) be a vector in the subset and let k be a real number.

The scalar multiple k(a, b, c) is (ka, kb, kc). Since ka = kb = kc, the scalar multiple is also in the subset.

Contains the zero vector: The zero vector is (0, 0, 0). Since 0 = 0 = 0, it is in the subset.

Therefore, the subset satisfies all three conditions, it is a subspace of [tex]R^{3}[/tex].

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The function [tex]√(x^3 - 8)[/tex] at each x value is 0.25 * [-1.902 - 1.609].  The interval [2, 3] into subintervals and apply the respective formulas.

To approximate the integral ∫[2 to 3] √(x^3 – 8) dx using the Trapezoidal Rule, Midpoint Rule, and Simpson's Rule, we need to divide the interval [2, 3] into subintervals and apply the respective formulas. Let's compute the approximations for each rule.

Step 1: Determine the subinterval width, h.

We can calculate h using the formula:

h = (b - a) / n

Given:

a = 2

b = 3

Let's use different values of n for each rule.

For Trapezoidal Rule, let's set n = 4.

For Midpoint Rule, let's set n = 4.

For Simpson's Rule, let's set n = 2.

Step 2: Compute the approximations for each rule.

Using the Trapezoidal Rule:

Approximation = (h / 2) * [f(a) + 2f(x1) + 2f(x2) + ... + 2f(xn-1) + f(b)]

For n = 4:

h = (3 - 2) / 4 = 0.25

Approximation = (0.25 / 2) * [f(2) + 2f(2.25) + 2f(2.5) + 2f(2.75) + f(3)]

Evaluate the function √(x^3 - 8) at each x value:

f(2) ≈ √(2^3 - 8) ≈ -2

f(2.25) ≈ √(2.25^3 - 8) ≈ -1.726

f(2.5) ≈ √(2.5^3 - 8) ≈ -1.414

f(2.75) ≈ √(2.75^3 - 8) ≈ -1.125

f(3) ≈ √(3^3 - 8) ≈ -0.464

Approximation = (0.25 / 2) * [-2 + 2(-1.726) + 2(-1.414) + 2(-1.125) + (-0.464)]

≈ (0.125) * [-2 - 3.452 - 2.828 - 2.25 - 0.464]

≈ (0.125) * [-11.994]

≈ -1.49925

Using the Midpoint Rule:

Approximation = h * [f(x1) + f(x2) + ... + f(xn)]

For n = 4:

h = (3 - 2) / 4 = 0.25

Approximation = 0.25 * [f(2.125) + f(2.375) + f(2.625) + f(2.875)]

Evaluate the function √(x^3 - 8) at each x value:

f(2.125) ≈ √(2.125^3 - 8) ≈ -1.902

f(2.375) ≈ √(2.375^3 - 8) ≈ -1.609

f(2.625) ≈ √(2.625^3 - 8) ≈ -1.335

f(2.875) ≈ √(2.875^3 - 8) ≈ -1.073

Approximation = 0.25 * [-1.902 - 1.609]

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Answer:

8!

Step-by-step explanation:

Answer) 8!

Explanation) i dont have one :')

Answer:

i think ist D correct me if im wrong

Step-by-step explanation:

Answer:

22.7

Step-by-step explanation:

if ∡M is 90° then you can do:

sin 65 = h/25

h = 25(sin 65°)

h = 22.65

Answer:

*Pew Pew*

Step-by-step explanation:

Answer:

Step-by-step explanation:

Question 13.

By applying cosine rule,

cos(45°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{\sqrt{2} }=\frac{10}{y}[/tex]

y = 10√2

By applying sine rule,

sin(45°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{\sqrt{2} }=\frac{x}{y}[/tex]

[tex]\frac{1}{\sqrt{2} }=\frac{x}{10\sqrt{2} }[/tex]

x = 10

Question 15.

By applying sine rule,

sin(60°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{\sqrt{3} }{2}=\frac{y}{32}[/tex]

y = 16√3

By applying cosine rule,

cos(60°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{2}=\frac{x}{32}[/tex]

x = 16

Question 17.

By applying sine rule,

sin(60°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{\sqrt{3} }{2}=\frac{11\sqrt{3} }{y}[/tex]

y = 22

By applying cosine rule,

cos(60°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{2}=\frac{x}{y}[/tex]

[tex]\frac{1}{2}=\frac{x}{22}[/tex]

x = 11

Answer:

9/100 is the answer i believe

Answer:

the answer is 9/100

Step-by-step explanation:

9 ÷ 100= 0.09