PrOblem 1: Find the slope of the line containing the points: (3,-5) and (-1, -2)
Problem 2: Find the x and y intercepts of the line: 2x – 3y = 12
Problem 3: Graph the line x-4y=8

Answer:

Step-by-step explanation:

total of 15(36) = 540 person•hours was used

540 / 30 = 18 people

18 - 15 = 3 people need to be added

[tex]\huge \bf༆ Answer ༄[/tex]

For converting radians to degree, we multiply the value in radian by [tex] \dfrac{180}{π}[/tex]

That is ~

Answer:

The gradient is negative.

Step-by-step explanation:

The gradient represents the rise/run ratio. Always read the line's path left to right, and if it goes up, then it is positive, down means negative gradient, and if it doesnt move then it 0. It is undefined if the line is vertical.

Answer:

three hours every 1 book

Step-by-step explanation:

36-12

6-2

3-1

Using it's formula, it is found that the slope of the line formed from the two given places is of [tex]\mathbf{\frac{6}{7}}[/tex]

Given two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex], the slope is given by change in y divided by change in x, that is:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

In this problem:

Hence, applying the formula for the slope, considering [tex](x_1, y_1) = (-1, -4)[/tex] and [tex](x_2,y_2) = (6,2)[/tex]:

[tex]m = \frac{2 - (-4)}{6 - (-1)} = \frac{6}{7}[/tex]

The slope is of [tex]\mathbf{\frac{6}{7}}[/tex]

A similar problem is given at https://brainly.com/question/5427529

From the given diagram, the following statements are true:

AB = BC

3y = 5y - 22

3y - 5y = -22

-2y = -22

y = 11

Similarly, m<DBE = 50 degrees

m<BED = 90 - m<DBE

m<BED = 90 - 50

m<BED = 40 degrees

Since BE = BC = 3y

BE = BC = 3(11) = 33

Also, 7x  - 2 = 40

7x = 40 + 2

7x = 42

x = 6

Get the measure of m<BEA

m<BEA = 7x - 2

m<BEA = 7(6) - 2

m<BEA = 40 degrees

Learn more on angles here: https://brainly.com/question/16281260

he must buy 24 jackets to get atheist 260 dollars

Answer:

Yes, this is a function

Step-by-step explanation:

You know this because it passes the vertical line test.

I hope this helps!

Answer:

Function

Step-by-step explanation:

Answer:

Step-by-step explanation:

=> 3x + 4y + 6z = 15

=> 3x + 4y + 6z - 4y = 15 - 4y

=> 3x + 6z = 15 - 4y

=> 3x + 6z - 6z = 15 - 4y - 6z

=> 3x = 15 - 4y - 6z

[tex] = > \frac{3x}{3} = \frac{15 - 4y - 6z}{3} [/tex]

[tex] = > x = 5 - \frac{4}{3} y - 2z \: (ans)[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{QUESTIONS:}[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{ANSWER:}[/tex]

[tex]x = 5 - \frac{4}{3} y - 2z[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{SOLUTION:}[/tex]

[tex]3 \orange{+ 4y + 6z = 15}[/tex]

Move the variables to the right-hand side and change their signs.

[tex]3x = 15 \orange{ - 4 - 6z}[/tex]

Divide both sides of the equation by 3

[tex]\orange{3x = 15 - 4 - 6z}[/tex]

[tex]↓[/tex]

[tex]\orange{x = 5 - \frac{4}{3} y - 2z}[/tex]

The x-intercepts of 3x+4y+6z=15 is

[tex]x = 5 - \frac{4}{3} y - 2z[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

#CarryOnlearning

Answer:

It's A bar graph but I got to see the question to be for sure but its a bar graph and it helps you  measure rates of things from numbers , months , years etc .

Step-by-step explanation:

Answer:

hello

Step-by-step explanation:

say hell-o

Answer:

7½ cups of sugar

Step-by-step explanation:

2 cups of flour needs 3 cups of sugar

1 cups of flour needs 3/2=1.5 cups of sugar

1×5 cups of flour needs 1.5×5=7.5 cups of sugar=7½ cups of sugar ANS

Answer:

Diagonal and horizontal lines

Step-by-step explanation:

To answer this question it is first important to know what a function is. A function is a relationship that has a singular y value for each x-value. This means that x-values will never repeat.

Linear functions are functions that increase in a constant way. Meaning that the slope of the line is constant and there is a common difference between the points. Because the change is constant, there is no change in direction. Thus, the function will be one straight line.

This line can obviously be diagonal because a diagonal line has unique x and y values. However, the line can also be horizontal. Horizontal lines many have repeating y-values but because the x-values don't repeat it is still a function. This reason is also why vertical lines are the only straight line to not be a liner function. In vertical lines, the x-values repeat. So, it does not work as a function.

Answer:

gradient M = 4

Step-by-step explanation:

pick any two pairs

M= change in Y / change in X

considering the last pairs

3--1/0--1=4✓

considering first pair

-1--5/-1--2 is also 4✓

I hope it helps

[tex]1)3k - 2k \\ = k(3 - 2) \\ = k(1) \\ = k[/tex]

[tex]2) {5x}^{2} - 10x - {8x}^{2} + x \\ = {5x}^{2} - {8x}^{2} - 10x + x \\ = - 3 {x}^{2} - 9x \\ = - 3x(x - 3)[/tex]

[tex]3) - (m + n) + 2(m - 3n) \\ = - m - n + 3m - 6n \\ = - m + 2m - n - 6n \\ = m - 7n [/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

7 hours

Step-by-step explanation:

Answer:

she could park there for 7 hours

Step-by-step explanation:

13-4=9 9/1.50=6

1/27

Explanation:

You would multiply to get to the answer.                                                                                    

I'll do the first two parts to get you started.

=====================================================

Part (i)

We can show that the operation [tex]\nabla[/tex] is not commutative by picking two random and different real numbers for a,b. In other words, I'm using a counter-example.

Let's say we go for a = 1 and b = 2

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\1 \nabla 2 = \frac{3*1+2}{5} - 1\\\\1 \nabla 2 = \frac{5}{5} - 1\\\\1 \nabla 2 = 1 - 1\\\\1 \nabla 2 = 0\\\\[/tex]

Now let's swap the values. We'll try a = 2 and b = 1

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\2 \nabla 1 = \frac{3*2+1}{5} - 1\\\\2 \nabla 1 = \frac{7}{5} - 1\\\\2 \nabla 1 = 1.4 - 1\\\\2 \nabla 1 = 0.4\\\\[/tex]

We can see that [tex]1 \nabla 2[/tex] and [tex]2 \nabla 1[/tex] are not the same value. In general, [tex]a \nabla b \ne b \nabla a[/tex] Therefore, the operation [tex]\nabla[/tex] is not commutative.

The only time [tex]a \nabla b = b \nabla a\\\\[/tex] is true is when [tex]a = b[/tex], since,

[tex]\frac{3a+b}{5}-1 = \frac{3b+a}{5}-1\\\\\frac{3a+a}{5}-1 = \frac{3a+a}{5}-1\\\\\frac{4a}{5}-1 = \frac{4a}{5}-1\\\\[/tex]

It's when [tex]a \ne b[/tex] is where the operation becomes noncommutative.

Another way to arrive at the [tex]a = b[/tex] condition is to solve the original equation for either 'a' or b.

=====================================================

Part (ii)

Using the previous part as inspiration, we'll do a counter-example to show that the operation is not associative. Pick 3 random values for a,b,c. Here are the values I'll pick.

Then,

[tex]d = b \nabla c = \frac{3b+c}{5}-1 = \frac{3*2+3}{5}-1 = 0.8\\\\a \nabla (b \nabla c) = a \nabla d = \frac{3a+d}{5}-1 = \frac{3*1+0.8}{5}-1 = -0.24\\[/tex]

Next, we can say:

[tex]d = a \nabla b = \frac{3a+b}{5}-1 = \frac{3*1+2}{5}-1 = 0\\\\(a \nabla b) \nabla c = d \ \nabla c = \frac{3d+c}{5}-1 = \frac{3*0+3}{5}-1 = -0.4[/tex]

Let's compare the two outputs:

[tex]a \nabla (b \nabla c) = -0.24\\\\(a \nabla b) \nabla c = -0.4[/tex]

They don't match up, so [tex]a \nabla (b \nabla c) \ne (a \nabla b) \nabla c[/tex] when (a,b,c) = (1,2,3).

In general, the operation is not associative in R.

Answer:

[tex]x=98.13^\circ,135^\circ,278.13^\circ,315^\circ[/tex]

Step-by-step explanation:

[tex]tan^2x+7tanx+8=0,[0^{\circ},360^\circ)[/tex]

[tex]tan^2x+7tanx+8=0[/tex]

[tex]u=tanx[/tex] <-- U-substitution

[tex]u^2+7u+8=0[/tex]

[tex](u+7)(u+1)=0[/tex]

[tex](tanx+7)(tanx+1)=0[/tex] <-- Replace u with tanx

[tex]tanx+7=0[/tex]

[tex]tanx=-7[/tex]

[tex]x=98.13^\circ,278.13^\circ[/tex]

[tex]tanx+1=0[/tex]

[tex]tanx=-1[/tex]

[tex]x=135^\circ,315^\circ[/tex]

Therefore, [tex]x=98.13^\circ,135^\circ,278.13^\circ,315^\circ[/tex]

Answer:

a

Step-by-step explanation:

(x-2)(x-11) less than or equal to 0

which means x is between 2 and 11 when it is less than 0

Answer: B

Step-by-step explanation: Jacob doesn't know either colleges' actual price. Bayside could still be equal to or more expensive than Lakeshore.

Answer:

D!!!

Step-by-step explanation:

you have to make a table to see that randy has run 3 miles.!!!

Answer: D is the correct answer!

Step-by-step explanation: Like the one above me!

Answer:

Step-by-step explanation:

(y + 3) = (1/8)(x - 2)

Answer:

n=22.23

Step-by-step explanation:

21+n=43.23

-21 to both sides

0+n=22.23

n=22.23

Answer:

the answer is A)5+0.5n=11

Step-by-step explanation:

5 is increased by half a number, so half of. a number(n) is added to 5

Answer:

D is correct

Step-by-step explanation:

I hope this helps

5 increased by half a number is 11.

5 increased by half a number is 11. 5 + 1/2n = 11 where n is the unknown number. 1/2n = 11 - 5 = 6 n = 6 * 2 = 12 The number is 12.

Answer: [tex]f(x) = 5(x+1)^{2} - 13[/tex]

Vertex = (-1, -13)

Step-by-step explanation:

[tex]f(x) = 5x^{2} + 10x - 8\\f(x) = 5(x^{2}+2x)-8\\f(x) = 5(x^{2}+2x+1-1)-8\\f(x) = 5((x+1)^{2}-1)-8\\f(x) = 5(x+1)^{2}-5-8\\f(x) = 5(x+1)^{2}-13[/tex]

Vertex = (h, k) = (-1, -13)

Answer:

66

Step-by-step explanation:

66 is the only number between 63 and 68 that is divisible by both 2 and 11.

66/2=33   66/11=6

Answer:

1,200

Step-by-step explanation

Multiply 720 and 100 = 72,000

Divide by 60 = 1,200

Answer:

The answer is 1,200

Step-by-step explanation:

First Multiply 720 and 100 which = 72,000

Then Divide 72,000 by 60 = 1,200