Plzzzz help mee plzzzz help meeee

Answer:

15J

Explanation:

Let's assume force and motion have the same direction, so the dot product between the two reduces to the product of magnitudes.

If you studied calculus:  [tex]w= \int \limits^3_0 6x-4dx[/tex], by definition. Some "easy" math, that's [tex](3x^2-4x)\limits^3_0=27-12 - 0 = 15 J[/tex]

Else. we have to take the long way.  if the force was constant, and you plotted magnitude of the force vs position in a graph, you would get an horizontal line, and your work would be the area between the line and the x axis. And there is no reason why it shouldn't be the same for a variable force - if you think about it, it's the same way they justify the position formula for an accelerated motion. Let's graph it and start debating - sorry for my paint skills. We can easily say that in the green triangle the force is opposing the motion, so its work is negative, while in the blue area force and displacement go in the same direction, thus work is positive. Now it's just to calculate the area of two triangles

For the green one, it's a right triangle with side lengths 4 and 2/3, whose area is [tex]\frac12(4)(\frac23) = \frac43[/tex].

For the blue triangle, it's again a right triangle with side lengths 14 and 3-2/3= 7/3, whose area is [tex]\frac12(14)(\frac73) = \frac{49}3[/tex]

Our total work is the difference between the two, or [tex]w= \frac{49}3-\frac43 = \frac{45}3 = 15[/tex]

Answer:

the ground when the ball hits it

Explanation:

A ball falls freely towards the Earth. If the action force is the Earth pulling down on the ball, then identify which of the following best describe the reaction force:

Answer:

Explanation:

Ax= 20*sin37

Ay =20*cos37

Bx=15*cos40

By =  -15*sin40

Cx = -6*cos60

Cy = -6*sin60

Answer:

Ax = 12 cos 53

Ay = 12 sin 53

Bx = 15 cos 320 = 15 cos 40

By = 15 sin 320 = -15 sin 40

Cx = 6 cos 240 = -6 cos 60

Cy = 6 sin 240 = -6 sin 60

Answer:

Fetus

Explanation:

the outsiders I got nuggets out of the elder and I get to make it in and I got I got

Answer:

A hydrometer is an instrument used to determine specific gravity

Answer:

it is used determine specific gravity

Explanation:

and u can see them in use by measuring proof of moonshine

Answer:

scientists often prefer to measure mass rather than weight because weight is affected by gravity while mass is not. Mass is always the same.

Explanation:

Weight is a force rather than a measure of the amount of matter something contains. The same amount of matter can have different weights depending on where it is. Mass directly measures the amount of matter present and remains the same no matter where it's measured.

39°C=1.28L

8°C=? Less

=8°C/39°C×1.28L

=8/39×1.28L

=10.24/39

=512/195

=2.6L

Explanation:

c) aceleración

Answer:

blah blah blahblah

Explanation:

because math is math and  nobody understands it

Answer:

Explanation:

The energy equation is E=hv

Answer:

draw the picture / (.) (.) \ Patrick star

Answer:

Sample answer: The mass of the car and the speed of the car (determined by the height of the hill) determine whether the car will break the egg.

안녕하세요

answer is 355 meters ...

Answer:

0.355m

Explanation:

To convert from cm to m, divide by 100

35.5÷100=0.355m

Answer:

.1 A1 = a1      A1 is amount at .1 %

.01 A2 = a2    A2 is the amount at .01%

a1 + a2 = 454     total of a1 and a2

A = 454 / .03  =  15133.33    tot amount needed

454 = .1 A1 + .01 A2    

A2 = 15133.33 - A1    

454 = .1 A1 + .01 (15133.33 - A1)

454 = .09 A1 + 151.33

A1 = 302.67 / .09 = 3363

A2 = 15133.3 - 3363 = 11770.3

Check:

.1 * A1 = 336.3

.01 * A2 = 117.7

total = 336.3 + 117.7 = 454

Answer:

One of Canada's best-known poems, “In Flanders Fields” was written on May 2, 1915, when Canadian serviceman John McCrae was stationed at an army hospital in Flanders, Belgium, during World War I.

Explanation:

Answer:

C. Mechanical Energy

Explanation:

The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

Answer:

A

Explanation:if the things have the same charge they will repel makeing the ball move away form its positively charged guy = that the coil gun works.

Answer:

Cretacious-Tertiary

Explanation:

I hope this helps!

Explanation:

Uhhhh here is an example

a=vt. =27 m/s10 s. =2.7 m/s2.

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Acceleration of the car is ~

[tex] \boxed{1.5 \: \: m/s}[/tex]

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

We know that,

Acceleration = rate of change in velocity ~

that is ~

where,

now, let's solve ~

Hi there!

We can begin by using the derived kinematic equation:

[tex]t = \sqrt{\frac{2h}{g}[/tex]

Plug in the given values and let g = 9.8 m/s²:

[tex]t = \sqrt{\frac{2(20)}{g}} = \boxed{2.02 s}[/tex]

Now, we can solve for its final velocity using the equation:

[tex]v_f = v_i + at[/tex]

It is dropped from rest, so vi = 0 m/s.

[tex]v_f = at[/tex]

[tex]v_f = 9.8(2.02) = \boxed{19.796 m/s}[/tex]

Answer:

a. The ball would reach the ground in approximately [tex]2.02\; \rm s[/tex].

b. The velocity of the ball right before landing would be approximately [tex]19.8\; \rm m\cdot s^{-1}[/tex].

(Assumptions: the ball was dropped with no initial velocity; air resistance on the ball is negligible; [tex]g = 9.81\; \rm m\cdot s^{-2}[/tex].)

Explanation:

Under these assumptions, the acceleration of this ball would be constantly [tex]a = g = 9.81\; \rm m\cdot s^{-2}[/tex] (same as the gravitational field strength) during the descent.

Displacement of the ball: [tex]x = 20.0\; \rm m[/tex].

Initial velocity of the ball: [tex]v_{0} = 0\; \rm m\cdot s^{-1}[/tex].

Let [tex]t[/tex] denote the duration of this descent.

The SUVAT equation [tex]x = (1/2)\, a\, t^{2} + v_{0}\, t[/tex] relates the known quantities [tex]a[/tex], [tex]x[/tex], and [tex]v_{0}[/tex] to the unknown [tex]t[/tex].

Substitute the known quantities into this equation and solve to find the value of [tex]t\![/tex]:

[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2} + 0\; {\rm m \cdot s^{-1}} \times t[/tex].

[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2}[/tex].

[tex]\displaystyle t^{2} = \frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}[/tex].

Since [tex]t > 0[/tex]:

[tex]\begin{aligned}t &= \sqrt{\frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}} \\ &\approx 2.01928\; \rm s\\ &\approx 2.02\; \rm s \\ & (\text{Rounded to 2 sig. fig.})\end{aligned}[/tex].

Since the acceleration of this ball is constant, the velocity of the ball right before landing would be:

[tex]\begin{aligned}v_{1} &= a\, t \\ &\approx 9.81\; \rm m\cdot s^{-2} \times 2.01928\; \rm s \\ &\approx 19.8\; \rm m \cdot s^{-1} \end{aligned}[/tex].

Answer:

The energy of motion is known as kinetic energy.

Explanation:

Let the ball at the ground be A and that at the top be B.

Assume that you see the motion of A while sitting at B.

You(B) are obviously at rest w.r.t. yourselves. However you(B) and A have the same acceleration in the same direction. Thus acceleration of A w.r.t. you(B) is 0.

Thus, to you, it will appear as if A is travelling towards you with an uniform speed of 20m/s.

Dividing the distance 20m with that speed, we get that A reaches you(B) in 1s.

Now, you have considered these motions and time by assuming you were stationed at B. However, the time taken for A to meet B shouldn't be dependent on which reference frame you assume. Thus, time taken for A and B to collide is 1s.

Since B falls freely, he covers a distance of  1/2(g)(1²)=5  (assuming g = 10m/s²)

Thus, they meet at a height of (20–5)m = 15m from the ground.

Answer:

c. postive

Explanation:

All physical objects are made up of atoms. Inside an atom are protons, electrons and neutrons. The protons are positively charged, the electrons are negatively charged, and the neutrons are neutral.

Therefore, all things are made up of charges. Opposite charges attract each other (negative to positive). Like charges repel each other (positive to positive or negative to negative). Most of the time positive and negative charges are balanced in an object, which makes that object neutral.

Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged. One way to discharge them is through a circuit.

Hope this helps, have a nice day/night! :D

Answer:

C

Explanation:

C because if you build anything up it remains the same.

Answer:

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

GPE = 25 × 10 × 4 = 1000

We have the final answer as

Hope this helps you

From Rutherford  and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.

Rutherford proposed Planetary model atom, which visualized an atom to consists of a positively charged heavy core called the nucleus around which negatively charged electrons circle in orbits much as planets move round the sun

Thus, from Rutherford  and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.

Learn more here:https://brainly.com/question/24263685

the answer is reflected or u can say repelled