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Answer:

it is kastle Meyer fasure

Answer:

i. 7.5 m

ii. 15000 N

Explanation:

Area under vt graph shows the displacement

so area of triangle ABE= 1/2×15×2

=7.5 m

ii) F=ma

here, m=1000kg

and a=v-u/t

=15-0/1

a=15

F=1000×15=15000N

Answer:

35.47 m/s

Explanation:

[tex]r = \sqrt{( - 23)^{2} + (27) ^{2} }[/tex]

=35.57

a) Answer:

Momentum = 6 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

Therefore, momentum = (0.02 × 300)kgm/s

Momentum = 6 kgm/s

b) Answer:

Momentum =80 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

Therefore, momentum = (40 × 2)kgm/s

Momentum = 80 kgm/s

c) Answer:

Momentum = 800 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

Therefore, momentum = (200 × 4)kgm/s

Momentum =800 kgm/s

Answer:

net force causing acceleration is 120N

Explanation:

Given parameters:

Mass of the object  = 10kg

Acceleration  = 12m/s²

Unknown:

Net force of this acceleration  = ?

Solution:

According to newtons second law of motion;

     Force  = mass x acceleration

Sine the unknown is the net force, input the parameters and solve for it;

   Force  = 10 x 12  = 120N

The net force causing acceleration is 120N

Answer:

A, B, and D.

Explanation:

I've answered this exact question on a quiz. Hope it's not too late!

Answer:

A

C

D

Is the right answers not A.B,D.

trust

Answer:

the umbra and penumbra

Explanation:

The two parts of a shadow are the umbra and penumbra.

A shadow is an expression formed when light from a source is cut blocked by an opaque body.

Most shadows are made up of two parts, umbra and penumbra.

The umbra is directly formed by light which impinges on an opaque body and it completely cut off.

Answer:

Explanation:

plasma, gas, liquid, solid

Answer:

66.6 or it could be 66.66 one of those

Explanation:

Answer:

1) t_total = 140 min ,  v = 126.7 m / min ,  2)  v = 0.628 m / s ,

3) v = 0.592 m / s ,  θ = -39.3 º

Explanation:

Here we have some short kinematics problems

1) d₁ = 4200 m at T1 = 25 min

    d₂ = 4.54 km at t2 = 1 h

    d₃ = 9000 m at t3 = 55 min

of the statement the direction of each route is the same

Let's reduce the distances to the SI system

     d₂ = 4.54 km (1000 m / 1 km) = 4540 m

     t₂ = 1 h (60 min / 1 h) = 60 min

Total time is

    t_total = t1 + t2 + t3

   t_total = 25 + 60 +55

   t_total = 140 min

the distance is

    d_total = 4200 + 4540 +9000

     d_total = 17740 m

with movement it is in one dimension and all displacement is in the same direction, distance equals displacement.

Speed ​​is

       v = 17740/140

       v = 126.7 m / min

in the direction of travel

Speed ​​is the modulus of speed

        | v | = 126.7 m / min

2) the angular velocity is

        w = θ / t

In this exercise

        t = 2 min (60 s / 1min) = 120 s

        θ = 30 rev (2π rad / 1 rev) = 60π rad

         w = 60π / 120

         w = 1.57 rad / s

linear velocity  is

        v = w r

        v = 1.57 0.40

        v = 0.628 m / s

velocity is the speed tangential to the  trajectory

3) the data for this exercise are

     distance = (number of steps) (distance of one step)

         d₁ = 500 0.40 m = 200 m West

         d₂ = 400 0.35 m = 140 m North

         d₃ = 300 0.30 m = 90 m East

in a total time of t = 2 min and 120 s

           t = 2  60 + 120 = 240 s

the distance traveled is

x axis we assume the direction towards + x (East) positive

           x_total = d₃ -d₁

           x_total = 90-200 = -110 m

y axis  

          y_total = d₂

          y_total = 140 m

we use the Pythagorean theorem to find the distance0

           D = √ (x_total² + y_total²)

           D = √ (110² + 90²)

           D = 142.13 m

The speed is

           v = D / t

            v = 142.13 / 240

           v = 0.592 m / s

speed is

           v = 0592 m / s

           tan θ = Y / X

           θ = tan -1 y / x

           θ = tan -1 (90 / (- 110))

           θ = -39.3 º

4) This angle is measured on the positive side of the x axis in a clockwise direction

          θ = 1.5 rev (2π rad / 1 rev) = 3π rad

           t = 90 s

the angular velocity is

           w = θ / t

           w = 3πi / 90

           w = 0.1047 rad / s

the speed is

            v = w R

            v = 0.14047 250

            v = 26.17 m / s

velocity is tangent to path

Answer:

The net force = 0

Explanation:

The given information includes;

The mass of the crate = 250 kg

The way the helicopter lifts the crate = Uniformly (constant rate (speed), no acceleration)

In order to pull the crate upwards, the helicopter has to provide a force equivalent to the weight of the crate keeping the helicopter on the ground.

The weight of the crate = The mass of the crate × The acceleration due gravity acting on the crate

The weight of the crate, [tex]F_w[/tex]↓ = 250 kg × 9.81 m/s² = 2,452.5 N

The force the helicopter should provide to just lift the crate, [tex]F_{(helicopter)}[/tex]↑ = The weight of the crate = 2,452.5 N

The net force, [tex]F_{(net)}[/tex] = [tex]F_{(helicopter)}[/tex]↑ - [tex]F_w[/tex]↓ = 2,452.5 N - 2,452.5 N = 0

The net force = 0.

Answer:

The answer is D.

Explanation:

Answer:

you would do multiplication, d=rt. (distance=d rate=r time=t).

Explanation:

You already have all the variables figure out so just plug in the numbers.

For an easier equation you would just do .6*45=27, the 27 is the total kilometers in 45 minutes.

Answer:

s=10

Explanation:

4(s+5)=60

4s+20=60

4s=40

s=10

Answer:

a_AV - 15 m/s – 36 m/s =-70 m/s2. At. 3.0 s.

Explanation:

The average acceleration of the car as it slows down is  -5 m/s².

Given is a race car that slows down from 36 m/s to 15 m/s in 3 seconds.

initial velocity [u] = 36 m/s

final velocity [v] = 15 m/s

time taken [Δt] = 3 s

We can calculate the acceleration as follows -

a = Δv/Δt

a = (v - u) / Δt

a = (15 - 30)/3

a = -15/3

a = -5 m/s²

Therefore, the average acceleration of the car as it slows down is

-5 m/s².

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Answer:

c

Explanation:

An object's speed is the characteristic which is related to kinetic energy but not the potential energy. Thus, the correct option is C.

The kinetic energy of an object is the energy which it possesses due to the motion of the object. Kinetic energy is defined as the work which is needed to accelerate an object of a given mass from rest position to its stated velocity. Having gained this amount of energy during the acceleration of the object, the object maintains this kinetic energy unless its speed changes or it experiences acceleration.

Kinetic energy is directly proportional to the mass of the object and to the square of the velocity of the object, the expression is:

K.E. = 1/2 m × v²

where, KE = Kinetic energy,

m = mass of the object,

v = velocity of the object.

Therefore, the correct option is C.

Learn more about Kinetic energy here:

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Answer: A chemical formula is a way of showing and representing information about a chemical proportion of atoms that constitute a particular chemical compound or molecule

Answer:

2 minutes or 120 seconds

Explanation:

The answer is 2 minutes or 120 seconds because 36 km is 36000 m and 36000 divided by 300 is 120, so the answer is 120 seconds, and converted to 2 minutes. Hope it helps!

Answer:

Gravitation is the attractive force existing between any two objects that have mass. The force of gravitation pulls objects together. Gravity is the gravitational force that occurs between the earth and other bodies. Gravity is the force acting to pull objects toward the earth.

Answer:

B, 4π^2r/T^2

Explanation:

Im on the same quiz, and I'm pretty sure this is the right answer cause I found it on 4 other websites. Good luck

Answer:

thank you very much for giving me points.

Explanation:

I really appreciate it so muchhhhh so muchhhh thanks again

Answer:

synthesis and combustion

double replacement

single replacement

decomposition only

in that exact order edge 2020

The presented reactions are:

S + O₂ ⇒ SO₂    Synthesis or combination

CaCl₂ + AgNO₃ = Ca(NO₃)₂ + 2 AgCl   Double displacement

Zn + CuSO₄ = Cu + ZnSO₄   Single displacement

2 Na₂O = 4 Na + O₂   Decomposition

Let's consider and classify the following reactions.

S + O₂ ⇒ SO₂

This is a synthesis or combination reaction. 2 compounds combine to form another.

CaCl₂ + AgNO₃ = Ca(NO₃)₂ + 2 AgCl

This is a double displacement reaction. Both compounds exchange their cations and anions.

Zn + CuSO₄ = Cu + ZnSO₄

This is a single displacement reaction. A metal displaces other metal from its salt.

2 Na₂O = 4 Na + O₂

This is a decomposition reaction. A compound decomposes into 2 other compounds.

The presented reactions are:

S + O₂ ⇒ SO₂    Synthesis or combination

CaCl₂ + AgNO₃ = Ca(NO₃)₂ + 2 AgCl   Double displacement

Zn + CuSO₄ = Cu + ZnSO₄   Single displacement

2 Na₂O = 4 Na + O₂   Decomposition

Learn more: https://brainly.com/question/21392527

Answer: 3.75 m/s

Explanation:

Here's what you know: The car has mass 1500 kg, and initial velocity 15.0 m/s.  The truck has mass 4500 kg and initial velocity 0 m/s.  The final mass is 6000 kg (4500 kg plus 1500 kg, because they stick together) and we are looking for the final velocity.  Using the formula p = mv, and the concept that p before equals p after, the p of the car plus p of the truck equals the p of them together. So, 1500 x 15 + 4500 x 0 = 6000 x v final.  22500 = 6000 v, and v = 3.75 m/s.  The velocity is positive, and the initial velocity of the car was positive, so the two vehicles together are traveling to the south just like the car was initially.

Answer:

Explanation:

Kinetic energy can be stored. For example, it takes work to lift a weight and place it on a shelf or to compress a spring. ... Kinetic energy can also be transferred from one body to another in a collision, which can be elastic or inelastic. One example of an elastic collision would be one billiard ball striking another.

Explanation:

Kinetic energy can be stored. For example, it takes work to lift a weight and place it on a shelf or to compress a spring. ... Kinetic energy can also be transferred from one body to another in a collision, which can be elastic or inelastic. One example of an elastic collision would be one billiard ball striking another.

Answer:

Explanation:

To find the mass given the force and acceleration we use the formula

[tex]m = \frac{f}{a} \\ [/tex]

where

f is the force

a is the acceleration

We have

f = 18 N

a = 2 m/s²

We have

[tex]m = \frac{18}{2} \\ [/tex]

We have the final answer as

Hope this helps you

The best image of galaxy is second option.

Galaxies are vast systems of gravity-bound gas, dust, dark matter, and anything from a million to a trillion stars. Supermassive black holes are expected to be present at the centers of almost all big galaxies. The sun is merely one of 100 to 400 billion rotating stars in our own galaxy, the Milky Way.

There are more galaxies visible as we gaze farther into space. According to a 2016 study, there are two trillion, or two million million, galaxies in the observable universe. While some of those far-off systems resemble our own Milky Way galaxy, others are very dissimilar,

There are three general types of galaxies elliptical, spiral, and irregular.

So the best shape is second option elliptical with boundary.

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Answer:

2.75 s

Explanation:

From the question given above,

Total time (T) spent by the ball in air = 5.5 s

Time taken (t) to reach the greatest height =...?

Thus, we can obtain the time taken (t) for the ball to reach the greatest height as follow:

T = 2t

Where:

T is the total time spent by the ball in air.

t is the time taken to reach the greatest height

Total time (T) spent by the ball in air = 5.5 s

Time taken (t) to reach the greatest height =...?

T = 2t

5.5 = 2 × t

Divide both side by 2

t = 5.5/2

t = 2.75 s

Therefore, the time taken (t) to reach the greatest height is 2.75 s.

Answer:

System management

Explanation:

Answer:

The horizontal component of the velocity is approximately 13.22 m/s

Explanation:

The velocity of the kick which the football player gives the ball = 21 m/s

The angle of the path taken by the ball = 51°

The velocity can be represented vectorially, showing the vertical and horizontal components as follows;

v = 21 × cos(51°)·[tex]\hat i[/tex] + 21 × sin(51°)·[tex]\hat j[/tex]

Where we have;

The horizontal component of the velocity = 21 × cos(51°)

The vertical component of the velocity = 21 × sin(51°)

Therefore;

The horizontal component of the velocity = 21 × cos(51°) ≈ 13.22 m/s

The horizontal component of the velocity ≈ 13.22 m/s.