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How you feel on days when you do exercise compared to days when you don't exercise

Answer:

See the answer below

Explanation:

To solve this problem we must use the definition of power and work in physics.

a)

The function of the conveyor belt is to carry the boxes from an initial point that is at low altitude to an end point that is at high altitude. In this way the conveyor belt prints a speed to the box to be able to raise it to the required vertical distance.

Since we have a velocity at the beginning and then we place the box at a high position, where then the box remains at rest, we can say that it converts kinetic energy to potential energy.

b)

Power is defined as the relationship of work over time. Therefore we have:

[tex]P=W/t[/tex]

where:

P = power = 3.8 [kW] = 3800 [W]

W = work [J]

t = time = 14 [s]

[tex]W=P*t\\W=3800*14\\W= 53200[J] = 53.2[kJ][/tex]

c)

Since the given time is equal to the given time at Point b, we can use the same work calculated.

We know that work is defined as the product of force by the distance traveled.

[tex]W =F*d[/tex]

So, the force is equal to:

[tex]F=W/d\\F=53200/5.3\\F=10037.73[N][/tex]

Now we know that force is defined as the product of mass by gravitation acceleration.

[tex]F =m*g[/tex]

where:

F = force or weight = 10037.73 [N]

g = gravity acceleration = 9.81 [m/s²]

m = mass [kg]

[tex]m=F/g\\m = 10037.73/9.81\\m = 1023.2 [kg][/tex]

d)

This part can be solved by means of the energy conservation theorem, where the potential energy is transformed into kinetic energy or vice versa.

[tex]E_{pot}=m*g*h = E_{kin}=0.5*m*v^{2}[/tex]

where:

h = elevation = 4.7 [m]

v = velocity [m/s]

[tex]m*g*h=0.5*m*v^{2}\\g*h=0.5*v^{2} \\v=\sqrt{\frac{g*h}{0.5} } \\v=\sqrt{\frac{9.81*4.7}{0.5} } \\v = 9.6 [m/s][/tex]

Complete question :

How much power is generated if a person applies 220 N of force to move a bicycle 5m in 10 s?

Answer:

Explanation:

Given that :

Force = 220N

Time = 10 seconds

Distance = 5 m

Power = Workdone / time

Answer: pointing back

Explanation:

Answer:

This question appear incomplete

Explanation:

This question appear incomplete. However, the density of water is generally known to be 997 kg/m³. The formula used to determine density is mass ÷ volume. In the case of the density of water, the mass is measured in kilograms (kg) while the volume is measured in cubic meter (m³).

Answer: 10

Explanation:

The mechanical advantage of that pulley is 10.

The force amplified by utilizing a tool, mechanical device, or machine system is known as mechanical advantage. To achieve the desired output force amplification, the gadget trades off input forces against movement. The law of the lever serves as a paradigm for this.

Mechanisms are machine parts made to control forces and motion in this way.

Given that: the weighs of the object: W = 100 Newton.

Applied force: F = 10 N.

For using a pulley, you have to apply a force of 10 Newtons to lift  an object that weighs 100 Newtons.

Hence, the mechanical advantage of the pulley is

= Weighs of the object/applied force

= 100 Newton / 10 Newton.

= 10.

The mechanical advantage of it is 10.

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Answer:

548.8 J

Explanation:

Answer:

i think its 8.2

Explanation:

Answer:

The car is considered to be speeding

Explanation:

The following data were obtained from the question:

Constant acceleration (a) = 7.4 m/s²

Time (t) = 2.4 s

Speed limit = 15.64 m/s

To know if the car speeding at any point, we shall determine the velocity of the car.

This can be obtained as follow:

Constant acceleration (a) = 7.4 m/s²

Time (t) = 2.4 s

Constant velocity (v) =?

a = v/t

7.4 = v / 2.4

Cross multiply

v = 7.4 × 2.4

v = 17.76 m/s

Thus, the velocity of the car is 17.76 m/s.

Comparing the velocity of the car (i.e 17.76 m/s) with the speed limit (i.e 15.64 m/s), we can see that the velocity of the car is higher than the speed limit. Therefore, the car is considered to be speeding.

[tex]\displaystyle v = 5.7735 \ m/s[/tex]

Math

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Physics

SI Units

Energy

Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2} mv^2[/tex]

Step 1: Define

Mass m = 30 kg

Kinetic Energy KE = 500 J

Step 2: Solve for v

Answer:

a) 37.70 m/s

b)710.6 m/s²

Explanation:

Given that ;

Mass of object = 2 kg

Radius of the motion = 2m

Frequency of motion = 3 rev/s

The formula to apply is;

v= 2πrf   where v is linear speed

v = 2×π×2×3 =12π = 37.70 m/s

Centripetal acceleration is given as;

a= 4×π²×r×f²  

a= 4×π²×2×3²

a=710.6 m/s²

Answer:

B. Yes, because they glow more brightly as they increase in

temperature

Explanation:

Did the test !!

The coils in an electric heater blackbody are not radiators. Because, they absorb no energy and emit no light. Thus, the correct option is C.

Electric heating is a process in which the electrical energy is converted directly into the heat energy at around about 100% efficiency, using rather the cheap devices. Common applications which are included are space heating, cooking, water heating and industrial processes.

A radiator is the key component of the engine's cooling system. Radiator has the main role to disperse a mix of antifreeze and water molecules throughout the fins, which releases some of the engine's heat energy while taking in the cool air before continuing to pass the rest of the electric engine.

Therefore, the correct option is C.

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Answer:

Radiation is used in monitoring the response of tumors to treatment and in distinguishing malignant tumors from benign ones. Bone and liver scans can detect cancers that have spread to these organs. Half of all people with cancer are treated with radiation, and the number of those who have been cured continues to rise.

Explanation:

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Answer:

6.45×10¯²⁶ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 97.3 MHz

Energy (E) =?

Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:

1 MHz = 1×10⁶ Hz

Therefore,

97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz

97.3 MHz = 9.73×10⁷ Hz

Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.

Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:

Frequency (f) = 9.73×10⁷ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 9.73×10⁷

E = 6.45×10¯²⁶ J

Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J

Answer:

 F_A = 8 F_B

Explanation:

The force exerted by the planet on each moon is given by the law of universal gravitation

        F = [tex]G \frac{m M}{r^{2} }[/tex]

where M is the mass of the planet, m the mass of the moon and r the distance between its centers

let's apply this equation to our case

Moon A

the distance between the planet and the moon A is r and the mass of the moon is 2m

        F_A = G \frac{2m M}{r^{2} }

Moon B

        F_B = G \frac{m M}{(2r)^{2} }

         F_B = G \frac{m M}{4 r^{2} }

the relationship between these forces is

         F_B / F_A = [tex]\frac{1}{2 \ 4 }[/tex] = 1/8

         F_A = 8 F_B

Answer:

F_A = 8 F_B

Explanation:

The force exerted by the planet on each moon is given by the law of universal gravitation

       F =

where M is the mass of the planet, m the mass of the moon and r the distance between its centers

let's apply this equation to our case

Moon A

the distance between the planet and the moon A is r and the mass of the moon is 2m

       F_A = G \frac{2m M}{r^{2} }

Moon B

       F_B = G \frac{m M}{(2r)^{2} }

        F_B = G \frac{m M}{4 r^{2} }

the relationship between these forces is

        F_B / F_A =  = 1/8

        F_A = 8 F_B

Answer:

10000N

Explanation:

Given parameters:

Mass of the car  = 1000kg

Acceleration = 3m/s²

g  = 10m/s²

Unknown:

Weight of the car  = ?

Solution:

To solve this problem we must understand that weight is the vertical gravitational force that acts on a body.

 Weight  = mass x acceleration due to gravity

So;

    Weight  = 1000 x 10  = 10000N

Answer:

85.77 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 41 m/s

Final velocity (v) = 0 m/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =?

The maximum height reached by the ball can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 41² – (2 × 9.8 × h)

0 = 1681 – 19.6h

Collect like terms

0 – 1681 = –19.6h

–1681 = –19.6h

Divide both side by –19.6

h = –1681 / –19.6

h = 85.77 m

Thus, the maximum height reached by the ball is 85.77 m

Answer:

The original analog sound waves are perfect but the copy is not because most analog waves have wavelengths that are too long to reproduce in copies

The original digital waves and the copy are perfect because with digital waves no information gets lost in the transfer of data, and there is no additional noise added to the copy.

Analog refers to audio recorded using methods that replicate the original sound waves. Digital audio is recorded by taking samples of the original sound wave at a specified rate.

Explanation:

i dont need $5

i wrote this using information from go ogle and some from brai nly. I hope it helps.

Answer:

Noise does not affect the digital signal, making it more reliable.                               This information is transmitted digitally, making it more reliable

Explanation:

Just did it on Ape.x

This information is transmitted digitally, making it more reliable. Noise does not affect the digital signal, making it more reliable. The correct options are B and D.

The transfer and reception of data in the form of a digital bitstream or a digitized analogue signal transmitted through a point-to-point or point-to-multipoint communication channel is known as data transmission and reception, or, more broadly, data communication or digital communications.

Because digital switching systems are substantially less expensive than analogue switching systems, digital transmission is used to achieve high reliability.

However, the analogue signals that make up the majority of speech, radio, and television must be used for digital transmission.

This information is more dependable because it is conveyed digitally. The digital signal is unaffected by noise, increasing its dependability.

Thus, B and D are the correct options.

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Answer:

A. 1600 kilojoules

Explanation:

Looking at the graph, at 4 meters, we can guess the energy transferred would be around 1500 kilojoules. 1600 kilojoules is the closest to that value, so A would be the best choice.

Answer:

False

Explanation:

A single concave lens has the opposite effect of a magnifying glass.

Answer:

The energy used for the 30-day period is 4878000 kilojoules.

Explanation:

According to the power bill, 1355 kilowatt-hours was used over a 30-day period. A kilowatt-hour is equal to 3600 kilojoules. Then, we calculate the energy used, measured in kilojoules, is determined by simple rule of three:

[tex]E = 1355\,kWh\times \frac{3600\,kJ}{1\,kWh}[/tex]

[tex]E = 4878000\,kJ[/tex]

The energy used for the 30-day period is 4878000 kilojoules.

Complete question is;

What is the electrical potential at the surface of gold nucleus? The radius of a gold atom is 6.6 × 10​^(-5) m and atomic number z = 79.

Answer:

172.36 × 10^(-5) V

Explanation:

We are given;

Radius; r = 6.6 × 10^(-5) m

Atomic number; Z = 79

Formula for Electric potential here is;

V = kZe/r

Where;

e is charge on proton = 1.6 × 10^(-19) C

k has a constant value of 9 × 10^(9) N⋅m²/C²,

​Thus;

V = (79 × 1.6 × 10^(-19) × 9 × 10^(9))/(6.6 × 10^(-5))

V = 172.36 × 10^(-5) V

In order to find the formula for net force, multiply both sides by mass.

Newton's second law of motion states that the rate of change of momentum is directly proportional to the force applied.

Given is the acceleration as the ratio of net force and mass.

We can write acceleration as -

a = F[net]/m

If we have to find the formula for net force, we will multiply both sides by mass (m). Therefore -

a x m = (F[net]/m) x m

am = F[net]

or

F[net] = ma

Therefore, in order to find the formula for net force, multiply both sides by mass.

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Answer:

y = 14238 m.    the height of the rocket is much less than this distance therefore the plan will not work.

Explanation:

Let's analyze this exercise, so that the Martian's plan works, the vertical height of the body must be zero when it is more than half of the way to the planet Mars, this is so that Mars attracts it and can arrive.

Let's calculate the maximum height of the launch

          [tex]v_{y} ^2 = v_{oy}^2 - 2 g y[/tex]

at the highest point [tex]v_{y}[/tex] = 0

          y = v_{oy}² / 2g

          y = (v₀ sin θ)² / 2g

let's calculate

          y = (1250 sin 25)² /2 9.8

          y = 14238 m

In the exercise, indicate that the distance to Mars is h = 321770 m, half of this distance is

          h / 2 = 160885 m

therefore the height of the rocket is much less than this distance therefore the plan will not work.

The height reached is low, so it is not necessary to take into account the variation of g with height