pls help! I'll give u 10 points and the brainlest answer!!!​

Answer:

Naphthalene is a non polar substance

Explanation:

In chemistry, the principle of like dissolves like is the over aching principle that controls the dissolution of one substance in another.

Naphthalene dissolves in diethyl ether because diethyl ether is a non polar solvent just as naphthalene is a nonpolar substance.

Since water is a polar solvent, it can not dissolves naphthalene at any pH because naphthalene is a nonpolar substance.

Answer:

What are we talking about here?

Explanation:

Answer:

valence electrons

Explanation:

other guy was close enough

Atoms of elements in the same group have the equal number of valence electrons. That is why they have similar chemical properties.

The chemical properties of elements depend on the number of valence electrons in their outermost shell. Those elements which are placed in the same group in the periodic table have the same number of valence electrons.

Therefore, elements present in the same group of the modern periodic table have similar chemical behavior.

The elements having a similar valence shell electronic configuration in their atoms are arranged in the same group of the periodic table. These valence electrons decide the chemical properties and reactivities of the chemical elements.

For example, all the elements in group 1 of the periodic table have one electron in their valence shell and all the elements present in group 17 have seven electrons in their valence shell.

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Answer:

22 is P

23 is C

24 is P

25 is C

26 is P

27 is P

28 is P

29 is C because youre using thermal heat and you cannot return to raw batter

Answer:

[tex]C_{3}H_4O_2[/tex]

Explanation:

Hello,

In this case, since the carbon of the initial compound is present in the carbon dioxide product, we can compute the mass and moles of carbon in the compound:

[tex]n_C=91.8g CO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2} =2.09molC\\\\m_C=91.8g CO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molC}{1molCO_2}*\frac{12gC}{1molC} =25.0gC[/tex]

Next, the mass and moles of hydrogen in the compound, is contained in the yielded amount of water, thus, we compute the mass and moles of hydrogen in the compound:

[tex]n_H=25.1gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =2.79molH\\\\m_H=25.1gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} *\frac{1gH}{1molH} =2.79gH[/tex]

In such a way, the mass of oxygen comes from the mass of the compound minus the mass of carbon and oxygen:

[tex]m_O=50.1g-25.0g-2.79g=22.31gO[/tex]

And the moles:

[tex]n_O=22.31gO*\frac{1molO}{16gO}=1.39molO[/tex]

Then, we compute the subscripts by diving the moles of C, H and O by the moles of oxygen as the smallest moles:

[tex]C:\frac{2.09}{1.39}=1.5 \\\\H:\frac{2.79}{1.39}=2\\ \\O:\frac{1.39}{1.39} =1[/tex]

After that, we write:

[tex]C_{1.5}H_2O[/tex]

Which must be shown in whole number only, thereby we multiply the subscripts by 2, so the empirical formula turns out:

[tex]C_{3}H_4O_2[/tex]

Best regards.

Answer:

F - O - S - Mg - Ba

Explanation:

as you move left to right on the periodic table the number of electrons increase.

The correct lists of the five atoms in order of increasing size smallest to

largest is :

D) F - O - S - Mg - Ba

The correct lists of the five atoms in order of increasing size smallest to

largest is F - O - S - Mg - Ba.

The atomic radius of a chemical element may be a degree of the measure of its molecule, as a rule the mean or commonplace remove from the center of the core to the furthest isolated electron.

The arrange will be:

As you move cleared out to right on the periodic table the number of electrons increment.

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Answer:

A. Cells are able to provide support

Answer:

Titanium [Ar] 3d2 4s2

Explanation:

Answer:

3.011 × 10²³

Explanation:

Given data:

Mass of oxygen produced = 8.05 g

Molecules of water decomposed = ?

Solution:

Balance chemical equation:

2H₂O   →   2H₂  + O₂

Number of moles of oxygen produced:

Number of moles = mass/molar mass

Number of moles = 8.05 g/ 32 g/mol

Number of moles = 0.25 mol

Now we will compare the moles of water with oxygen.

              O₂             :             H₂O

               1               :               2

              0.25         :            2×0.25 =0.5 mol

0.5 moles of water were decomposed.

Molecules of water decomposed:

1 mole = 6.022× 10²³ molecules of water

0.5 mol ×6.022× 10²³ molecules of water/ 1mol

3.011 × 10²³ molecules of water

Answer:During absorption and digestion, the carbohydrates in the food you eat are reduced to their simplest form, glucose. Excess glucose is then removed from the blood, with the majority of it being converted into glycoge, the storage form of glucose, by the liver's hepatic cells via a process called glycogenesis

Explanation:

Answer:

C. molten rock below Earth’s surface

Explanation:

Answer:

Each nerve cell is connected to the brain by electrical signals

Explanation:

Answer:

they said it above me

Explanation:

Answer:

0.42 g/cm3

Explanation:

Answer:

20/40=0.5 g/cm^3 becuase, mass/volume=density

Explanation:

Answer:

Fluorine is a non-metal, fills its shell by gaining one electron and becomes a negatively charged ion.

Explanation:

Fluorine have seven electrons in its outermost shell. This means that fluorine is located in Group 17(Halogens) in the Periodic Table. Note that halogens are non-metal elements. So fluorine is a non-metal.

Fluorine fills its shell by gaining one electron because it only needs one electron to achieve stable octet electron arrangement. ( it's easier to gain one electron than to lose all seven electrons in the outermost shell)

As fluorine atom gain one electron to achieve stable octet electron arrangement, its number of electrons becomes greater than its number of protons. So it becomes a negatively charged ion.

Answer:

7

Explanation:

Let x represent the number of moles of water in the hydrated salt i.e MgSO₄.xH₂O

The following data were obtained from the question:

Mass of MgSO₄.xH₂O = 1.547 g

Mass of anhydrous MgSO₄ = 0.7554 g

Mole of H₂O = x =?

Next, we shall determine the mass of water, H₂O in the hydrated salt, MgSO₄.xH₂O. This can be obtained as follow:

Mass of MgSO₄.xH₂O = 1.547 g

Mass of anhydrous MgSO₄ = 0.7554 g

Mass of H₂O =?

Mass of H₂O = (Mass of MgSO₄.xH₂O) – (Mass of anhydrous MgSO₄)

Mass of H₂O = 1.547 – 0.7554

Mass of H₂O = 0.7916 g

Finally, we shall determine the value of the x as illustrated below:

Mass of MgSO₄.xH₂O = 1.547 g

Molar mass of MgSO₄.xH₂O = 24 + 32 + (16×4) + x[(2×1) + 16]

= 24 + 32 + 64 + x(2 + 16)

= 120 + 18x

Mass of H₂O = 0.7916 g

Molar mass of xH₂O = 18x

Molar Mass of xH₂O/ Molar mass of MgSO₄.xH₂O = mass of xH₂O /Mass of MgSO₄.xH₂O

18x/ 120 + 18x = 0.7916/1.547

Cross multiply

0.7916 (120 + 18x) = 18x × 1.547

94.992 + 14.2488x = 27.846x

Collect like terms

94.992 = 27.846x – 14.2488x

94.992 = 13.5972x

Divide both side by 13.5972

x = 94.992 / 13.5972

x = 7

Thus, the formula for the hydrated salt, MgSO₄.xH₂O is MgSO₄.7H₂O

Number of moles of water, H₂O in the hydrated salt MgSO₄.7H₂O is 7.

The number of moles of attached water molecules is 7.

Mass of hydrated MgSO4 = 1.547 grams

Mass of anhydrous MgSO4 = 0.7554 grams

Number of moles of hydrated MgSO4 = 1.547 grams/120 + 18x

Number of moles of anhydrous MgSO4 = 0.7554 grams /120

Number of moles of anhydrous salt = Number of moles of hydrated salt

0.7554 grams /120 = 1.547 grams/120 + 18x

0.7554(120 + 18x) = 1.547 × 120

90.6 + 13.6x = 185.6

185.6 - 90.6 /13.6 = x

x = 7

The number of moles of attached water molecules is 7.

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Answer:

Approximately [tex]0.551\; \rm J\cdot kg^{-1} \cdot \left(^\circ\! C \right)^{-1}[/tex].

Explanation:

The specific heat of a material is the amount of energy required to increase unit mass (one gram) of this material by unit temperature (one degree Celsius.)

Calculate the increase in the temperature of this sample:

[tex]\Delta T = (116.9 - 24.3)\; \rm ^\circ\! C= 92.6\; \rm ^\circ\! C[/tex].

The energy that this sample absorbed should be proportional the increase in its temperature (assuming that no phase change is involved.)

It took [tex]2911\; \rm J[/tex] of energy to raise the temperature of this sample by [tex]\Delta T = 92.6\; \rm ^\circ\! C[/tex]. Therefore, raising the temperature of this sample by [tex]1\; \rm ^\circ\! C[/tex] (unit temperature) would take only [tex]\displaystyle \frac{1}{92.6}[/tex] as much energy. That corresponds to approximately [tex]31.436\; \rm J[/tex] of energy.

On the other hand, the energy required to raise the temperature of this material by [tex]1\; \rm ^\circ\! C[/tex] is proportional to the mass of the sample (also assuming no phase change.)

It took approximately [tex]31.436\; \rm J[/tex] of energy to raise the temperature of [tex]57.07\; \rm g[/tex] of this material by [tex]1\; \rm ^\circ C[/tex]. Therefore, it would take only [tex]\displaystyle \frac{1}{57.07}[/tex] as much energy to raise the temperature of [tex]1\; \rm g[/tex] (unit mass) of this material by [tex]1\; \rm ^\circ \! C\![/tex]. That corresponds to approximately [tex]0.551\; \rm J[/tex] of energy.

In other words, it takes approximately [tex]0.551\; \rm J[/tex] to raise [tex]1\; \rm g[/tex] (unit mass) of this material by [tex]1\; \rm ^\circ \! C[/tex]. Therefore, by definition, the specific heat of this material would be approximately [tex]0.551\; \rm J\cdot kg^{-1} \cdot \left(^\circ\! C \right)^{-1}[/tex].

Answer:

7836.6 J

Explanation:

The following data were obtained from the question:

Heat of fusion (Hf) = 0.148 KJ/g

Mass (m) = 52.95 g

Heat (Q) required =..?

The heat (Q) required to melt the sample of nephthalene can be obtained as follow:

Q = m·Hf

Q = 52.95 × 0.148

Q = 7.8366 KJ

Finally, we shall convert 7.8366 KJ to Joule (J) in order to obtain the desired result. This can be obtained as follow:

1 kJ = 1000 J

Therefore,

7.8366 KJ = 7.8366 KJ × 1000 J / 1 KJ

7.8366 KJ = 7836.6 J

Therefore, 7.8366 KJ is equivalent to 7836.6 J

Thus, 7836.6 J of heat energy is required to melt the sample of nephthalene.

The heat required for melting of 52.95 g of naphthalene has been 7.8366 kJ.

The heat of fusion has been the energy required by 1g for the change in the substance.

The heat required to melt naphthalene can be given as:

Heat = mass × Heat of fusion

The given mass = 52.95 g

The heat of fusion = 0.148 kJ/g

The heat required can be given as:

Heat = 0.148 × 52.95 kJ

Heat = 7.8366 kJ.

The heat required for melting of 52.95 g of naphthalene has been 7.8366 kJ.

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Answer:

Required heat = 2,259.36 N (approx)

Explanation:

Given:

Mass = 135 g

Specific heat (c) =4.184 J/gC

Change in temperature ΔT = 27-23 = 4 c

Find:

Required heat

Computation:

Q = mcΔT

Q = (135)(4.184)(4)

Required heat = 2,259.36 N (approx)

The heat transferred by the chemical reaction to the reservoir of a calorimeter containing 135 g of dilute aqueous solution is 2259.36 J

To solve this question, we'll begin by calculating the change in the temperature of the reservoir. This can be obtained as follow:

Initial temperature (T₁) = 23 °C

Final temperature (T₂) = 27 °C

ΔT = T₂ – T₁

ΔT = 27 – 23

Finally, we shall determine the heat transferred to the reservoir.

Change in temperature (ΔT) = 4 °C

Mass (M) = 135 g

Specific heat capacity (C) = 4.184 J/gºC

Q = MCΔT

Q = 135 × 4.184 × 4

Therefore, the heat transferred by the chemical reaction to the reservoir of a calorimeter containing 135 g of dilute aqueous solution is 2259.36 J

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Answer:

1.08 × 103 K

hope this helps :)

Explanation:

Answer:

pH = 10.113

Explanation:

Here, we can find pOH first:

pOH = [tex]-log([OH^-])[/tex] = 3.886.

Then, we can find pH which is 14 - pOH. We then get the answer above.

Then, we can find pH which is 14 - pOH. We then get the answer above.

The pH of acid is between 0-7 on pH scale while for base pH range is from 7-14. Thus the pH of 1.3×10⁻⁴  M  bleach solution is 10.62.

pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. More the value of hydronium ion concentration, more will be the solution acidic.

On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. pH depend on the temperature. At room temperature pH scale is between 0 to 14. pH of neutral solution is 7

The concentration of bleach solution  is 1.3×10⁻⁴ M

Concentration of OH⁻=1.3×10⁻⁴ M

Mathematically,

pOH=-log[OH⁻]

Substituting the values

pH=-log[1.3×10⁻⁴]

    =  3.886.

pH+ POH=14

pH=14-3.886.=10.62

Therefore,  the pH of 1.3×10⁻⁴  M  bleach solution is 10.62.

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Answer:

Mass of calcium carbonate decompose 49g.

Explanation:

Given data:

Mass of CaO = 28.00 g

Mass of CO₂ = 21.97 g

Mass of calcium carbonate decompose = ?

Solution:

Chemical equation:

CaCO₃     →    CO₂ + CaO

Number of moles of  CO₂:

Number of moles = mass/molar mass

Number of moles = 21.97 g / 44 g/mol

Number of moles = 0.49 mol

Number of moles of  CaO:

Number of moles = mass/molar mass

Number of moles = 28.00 g / 56.1 g/mol

Number of moles = 0.49 mol

Now we will compare the moles of CaCO₃ with CaO and CO₂ .

                                CO₂                 :           CaCO₃

                                   1                    :             1

                                 0.49                :            0.49

                                 CaO                :           CaCO₃  

                                    1                    :             1

                                  0.49                :            0.49

Mass of CaCO₃ decompose:

Mass = number of moles × molaer mass

Mass = 0.49 mol × 100.1 g/mol

Mass = 49 g

Answer:

CaO

Explanation:

Al2(SO4)3 aluminium sulfate

This question is incomplete, the complete question is;

Tonksite is a solid at 300.00K.  At 300.00 K its enthalpy of sublimation is 66.00 kJ/mol. The sublimation pressure at 300.00 K is 5.00 × 10⁻⁴ atm

Calculate the sublimation pressure of the solid at the melting point of 400.00 K assuming that the enthalpy of sublimation is not a function of temperature.

Answer: the sublimation pressure of the solid at the melting point is  0.3727 atm

Explanation:

Given that;

T1 = 300 K

T2 = 400 K

H_sub = 66 kJ/mol = 66000 J/mol

P1 = 5.00 × 10⁻⁴ atm

p2 = ?

now using the expression

log( p2 / 5.00 × 10⁻⁴ ) = (H_sub / R ×  2.303 ) (( T2 - T1) / T1T2)

now we substitute of given values into the expression

log(p2/p1) = (66000 / 8.314 ×  2.303 ) (( 400 - 300) / 300 × 400 )

p2 = 0.3727 atm

therefore the sublimation pressure of the solid at the melting point is  0.3727 atm

Answer:

xanthophyll

xenobiotic

xenon

X group

x-rays

x-ray tube

Answer:The anwser is 5

Explanation:

Answer:

Explanation:

Length: Length is a measure of distance

Height:The measurement from base to top or (of a standing person) from head to foot.

Circumference:The enclosing boundary of a curved geometric figure, especially a circle

Perimeter: Length of the outline of a shape.

Diagonal:A line segment that goes from one corner to another, but is not an edge. So when we directly join any two corners (called "vertices") which are not already joined by an edge, we get a diagonal. Diagonals of Polygons.

Diameter: A straight line passing from side to side of any figure or body, through its center.

Answer:

I need more context. Maybe add a picture.

Explanation:

Answer:

Crown B

Explanation:

because the density of gold is 19.3 and the density of the crown is 19.29.   

Answer:

a) increases

b) decreases

c) does not change

d) increases

Explanation:

The vapour pressure of a liquid is dependent on;

I) the magnitude of intermolecular forces

II) the temperature of the liquid

Hence, when any of these increases, the vapour pressure increases likewise.

Similarly, the boiling point of a liquid depends on the magnitude of intermolecular forces present because as intermolecular forces increases, more energy is required to break intermolecular bonds.

Lastly, increase in surface area of a liquid does not really affect it's vapour pressure.

Answer:

Number of moles = 10.6 mol

Explanation:

Given data:

Molar mass of H = 1.008 g/mol

Molar mass of C = 12.01 g/mol

Molar mass of O = 16.00 g/mol

Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)

Number of moles of citric acid = ?

Solution:

Formula:

Number of moles = mass/molar mass

Now we will calculate the molar mass of citric acid:

C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)

C₆H₈O₇ = 72.06 + 8.064+112

C₆H₈O₇ = 192.124g/mol

Number of moles = 2030 g/ 192.124g/mol

Number of moles = 10.6 mol

The number of moles in a 2.03 kg sample of citric acid is :

- 10.6 mol

Given:

Molar mass of H = 1.008 g/mol

Molar mass of C = 12.01 g/mol

Molar mass of O = 16.00 g/mol

Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)

Number of moles of citric acid = ?

Formula:

Number of moles = mass/molar mass

The molar mass of citric acid:

C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)

C₆H₈O₇ = 72.06 + 8.064+112

C₆H₈O₇ = 192.124g/mol

Number of moles = 2030 g/ 192.124g/mol

Number of moles = 10.6 mol

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Answer:

1.b. distillation

2.d. evaporation

3.f. chromatography

4.c. decantation

5.a. filtration

6.e. centrifugation

Explanation:

1. Distillation is the process in which a homogenous mixture of liquid is separated on the basis of difference in boiling points of the substances.

2. Evaporation is the process in which water is converted into gas or vapor based on the boiling point of water or solid.

3. Chromatography is defined as the process used to pure substances from a mixture based on the flow rate of the fluid. The fluid mixture to be separated is called the mobile phase that flows on a stationary phase.

4. Decantation is defined as the process that separates mixtures in which water is poured off the substance to be separated or over solid.

5. Filtration is a separation process in which solids can be separated from liquids by pouring the mixture over a porous barrier.

6. Centrifugation is defined as the separation process that separates heterogeneous substances on the basis of densities in which centripetal acceleration allows substance with high density to move outward in the radial direction.