pls help !!!!!! geometry

When [tex]sin(\theta) = -0.42[/tex] and [tex]\pi < \theta < 3\pi/2[/tex], the value of [tex]cos(\theta)[/tex] is approximately 0.9071.

To find the value of cos([tex]\theta[/tex]) given[tex]sin(\theta) = -0.42[/tex] and [tex]\pi < \theta < 3\pi/2[/tex], we can use the trigonometric identity:

[tex]sin^2(\theta) + cos^2(\theta) = 1[/tex]

Since we are given sin(theta) = -0.42, we can substitute this value into the equation:

[tex](-0.42)^2 + cos^2(\theta) = 1[/tex]

Simplifying:

[tex]0.1764 + cos^2(\theta) = 1[/tex]

Subtracting 0.1764 from both sides:

[tex]cos^2(\theta) = 0.8236[/tex]

Taking the square root of both sides (since cos(theta) is positive):

[tex]cos(\theta) = \sqrt{(0.8236)} \\cos(\theta) = 0.9071[/tex]

Therefore, when [tex]sin(\theta) = -0.42[/tex] and [tex]\pi < \theta < 3\pi/2[/tex], the value of [tex]cos(\theta)[/tex]is approximately 0.9071.

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The number of paperback copies sold is 366,300.

Let's solve the problem :

Calculate the number of hardback copies sold.

We are given that 35,000 hardback copies were sold before the paperback version was issued.

Calculate the number of paperback copies sold.

From the time the first paperback copy was sold until the last copy of the novel was sold, nine times as many paperback copies as hardback copies were sold.

Let's assume the number of hardback copies sold is H.

Therefore, the number of paperback copies sold would be 9H.

Set up the equation for the total number of copies sold.

The problem states that a total of 442,000 copies of the novel were sold in all. We can set up the equation as follows:

H + 9H + 35,000 = 442,000

Solve the equation for H.

Combining like terms, we have:

10H + 35,000 = 442,000

10H = 442,000 - 35,000

10H = 407,000

H = 40,700.

Calculate the number of paperback copies sold.

We already know that the number of paperback copies sold is 9 times the number of hardback copies sold.

Therefore, the number of paperback copies sold would be:

9H = 9 [tex]\times[/tex] 40,700 = 366,300

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Answer:

  A. The multiplication that takes place while distributing comes before addition and subtraction in order of operations.

Step-by-step explanation:

You want to know the error that adding -4+4 on the left and 1+1 on the right represents in the solution of the equation ...

The correct solution procedure would be to eliminate the parentheses using the distributive property as a first step:

  4x -6x +8 +4 = -x +3x +3 +1

Comparing this to Maricella's first step, we see that she ignored the step of using the distributive property to multiply the constants inside parentheses by the factor outside. The appropriate description of Maricella's mistake is ...

A. The multiplication that takes place while distributing comes before addition and subtraction in order of operations.

__

Additional comment

Adding like terms would give ...

  -2x +12 = 2x +4

  8 = 4x . . . . . . . . . . . add 2x-4 to both sides

  2 = x . . . . . . . . . . divide by 4

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Hello !

Answer:

[tex]\large \boxed{\sf \sum\limits^6_{k=3}(-2k+5)=-16}[/tex]

Step-by-step explanation:

We want to calculate the following sum :

[tex]\sf \sum\limits^6_{k=3}(-2k+5)[/tex]

Let's remember the following property :

[tex]\fbox{\begin{tabular}{1\textwidth}\star\ \underline{\sf Linearity:}\\ \sf \sum\limits^n_{k=n_0}(\alpha a_k+\beta b_k)=\alpha\sum\limits^n_{k=n_0} a_k+\beta \sum \limits^n_{k=n_0}b_k\end{tabular}}[/tex]

Now we can apply this property to our formula :

[tex]\sf \sum\limits^6_{k=3}(-2k+5)\\=-2\sf \sum\limits^6_{k=3}(k)+\sum\limits^6_{k=3}5[/tex]

Now we can calculate :

[tex]\sf \sum\limits^6_{k=3}(-2k+5)\\=-2(3+4+5+6)+(6-3+1)5\\=-2\times18+4\times 5\\=-36+20\\\boxed{\sf \sum\limits^6_{k=3}(-2k+5)=-16}[/tex]

Have a nice day ;)

Answer:

6b + 5n = 101

Step-by-step explanation:

The correct system of equations that can be used to find b, the number of bracelets Ily sold, and n, the number of necklaces she sold is:

b + n = 18

6b + 5n = 101

In this system, the first equation represents the total number of items sold, which is 18. Since b represents the number of bracelets and n represents the number of necklaces, the equation b + n = 18 reflects that the total number of bracelets and necklaces sold should add up to 18.

The second equation represents the total amount of money Ily earned from selling bracelets and necklaces. Since bracelets were sold for $6 each and necklaces for $5 each, the equation 6b + 5n = 101 represents the total amount of money earned, which is $101.

Therefore, the correct system of equations is:

b + n = 18

6b + 5n = 101

An estimate of 20 people took longer than 325 minutes to complete the race.

To estimate the number of people who took longer than 325 minutes to complete the race, we need to use the cumulative frequency distribution.

The cumulative frequency of a class interval is obtained by adding up the frequencies of all the class intervals up to and including that interval. The sum of the frequencies for each class interval is known as the cumulative frequency.In this case, the cumulative frequency distribution is given as follows:

Class Interval  |  Frequency  |  Cumulative Frequency250 - 200  |  5  |  5200 - 150  |  12  |  12150 - 100  |  18  |  30100 - 50  |  11  |  4050 - 0  |  4  |  44Total: 50

Now, to estimate the number of people who took longer than 325 minutes to complete the race, we need to look at the cumulative frequency that corresponds to 325 minutes.

From the table, we can see that the cumulative frequency of the class interval 300-400 minutes is 30. This means that 30 people took between 100 and 400 minutes to complete the race.

Therefore, the number of people who took longer than 325 minutes is the difference between the total number of people who took between 100 and 500 minutes and the number of people who took between 100 and 325 minutes. This can be calculated as follows:50 - 30 = 20.

Hence, an estimate of 20 people took longer than 325 minutes to complete the race.

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The probable question may be:

Estimate the number of people who took longer than 325 minutes to complete the race, given the following cumulative frequency distribution:

Cumulative frequency:

250-

200-

150-

100-

50-

0

Time to complete a race:

100 200 300 400 500

Time (minutes).

[tex]\displaystyle \text{To solve this problem, let's assume the distance of the run is denoted by 'x' miles, and the distance of the bicycle race is denoted by '48 - x' miles.}[/tex]

[tex]\displaystyle \text{We can use the formula: time} = \text{distance/velocity to find the time taken for each segment of the race.}[/tex]

[tex]\displaystyle \text{For the run:}[/tex]

[tex]\displaystyle \text{Time taken} = \text{Distance/Velocity}[/tex]

[tex]\displaystyle t_1 = \frac{x}{5}[/tex]

[tex]\displaystyle \text{For the bicycle race:}[/tex]

[tex]\displaystyle \text{Time taken} = \text{Distance/Velocity}[/tex]

[tex]\displaystyle t_2 = \frac{48 - x}{23}[/tex]

[tex]\displaystyle \text{Given that the total time for the race is 6 hours, we can write the equation:}[/tex]

[tex]\displaystyle t_1 + t_2 = 6[/tex]

[tex]\displaystyle \text{Substituting the expressions for } t_1 \text{ and } t_2, \text{ we get:}[/tex]

[tex]\displaystyle \frac{x}{5} + \frac{48 - x}{23} = 6[/tex]

[tex]\displaystyle \text{To solve this equation, we can simplify it by multiplying through by the common denominator, which is 115:}[/tex]

[tex]\displaystyle 23x + 5(48 - x) = 6 \times 115[/tex]

[tex]\displaystyle \text{Simplifying further:}[/tex]

[tex]\displaystyle 23x + 240 - 5x = 690[/tex]

[tex]\displaystyle 18x = 450[/tex]

[tex]\displaystyle x = \frac{450}{18}[/tex]

[tex]\displaystyle x = 25[/tex]

[tex]\displaystyle \text{Therefore, the distance of the run is 25 miles, and the distance of the bicycle race is } 48 - 25 = 23 \text{ miles.}[/tex]

Answer:

Step-by-step explanation:

$28 for 1st hr and $20per hr after that:

t = 28 +  20(h-1)

$30 for 1st hr and $20per hr after that:

t = 30 + 20(h-1)

t - 30 - 20(h-1)

The solutions to the quadratic equation 2x² + 6x - 10 = x² + 6 are -8 and 2.

Given the quadratic equation in the question:

2x² + 6x - 10 = x² + 6

First, reorder the quadratic equation in standard form:

2x² + 6x - 10 = x² + 6

2x² - x² + 6x - 10 - 6 = x² - x² + 6 - 6

2x² - x² + 6x - 10 - 6 = 0

x² + 6x - 10 - 6 = 0

x² + 6x - 16 = 0

Next, factor the equation using the AC method:

( x - 2 )( x + 8 ) = 0

Equate each factor to 0 and solve for x:

( x - 2 ) = 0

x - 2 = 0

x = 2

( x + 8 ) = 0

x + 8 = 0

x = -8

Therefore, the solutions are -8 and 2.

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Answer:

Assuming Miguel rolled up his sleeping bag tightly and neatly, the length and circumference of the sleeping bag can help us estimate the length of string needed to tie it up.

Let's say the length of the sleeping bag is 6 feet and the circumference (distance around) is 3 feet. To tie it up, Miguel would need to wrap the string around it 2-3 times, depending on how long the string is and how tight he ties the knot.

So, we can estimate that he used about 12-18 feet of string (i.e. 2-3 times the circumference). In inches, that would be about 144-216 inches of string (i.e. 12-18 feet * 12 inches/foot).

Keep in mind that this is just an estimate and the actual amount of string used may vary depending on the factors mentioned above.

Step-by-step explanation:

The answer is:

3x + 12

Work/explanation:

To simplify this expression, we will use the distributive property:

[tex]\sf{3(x+4)}[/tex]

Distribute the 3:

[tex]\sf{3\cdot x + 3 \cdot 4}[/tex]

[tex]\sf{3x+12}[/tex]

Therefore, the value of x that solves the equation is 2/7, after eliminating the fractions and solving the resulting equation.

To eliminate fractions in the equation 6 - 3x + (1/2)x = x + 5, we can multiply each term by a number that will clear the denominators. In this case, the denominator is 2 in the term (1/2)x. The least common multiple (LCM) of 2 is 2 itself, so we can multiply each term by 2 to eliminate the fraction.

By multiplying each term by 2, we get:

2 * (6 - 3x) + 2 * ((1/2)x) = 2 * (x + 5)

Simplifying this expression, we have:

12 - 6x + x = 2x + 10

Now, the equation is free of fractions, and we can proceed to solve it.

Combining like terms, we have:

12 - 5x = 2x + 10

To isolate the variable terms, we can move the 2x term to the left side by subtracting 2x from both sides:

12 - 5x - 2x = 10

Simplifying further:

12 - 7x = 10

Next, we can move the constant term to the right side by subtracting 12 from both sides:

12 - 7x - 12 = 10 - 12

Simplifying again:

-7x = -2

Finally, we solve for x by dividing both sides by -7:

x = (-2) / (-7)

Simplifying the division of -2 by -7 gives us the solution:

x = 2/7

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The x- and y-intercept values in the graph for the function f and in the table for the function g(x), indicates that the correct option is option C

The x-intercept is the point at which the y-value is 0, and the coordinates of the point is specified as the x-intercept.

The x-intercept is the point at which the x-value is 0, and the coordinates of the point is specified as the y-intercept

The question compares the x- and y-intercepts of the graph and the function in the table

The x-intercept of the function f in the graph are; (0, 3)

The y-intercept of the function f in the graph are; (4, 0)

The function g(x) in the table indicates that the x- and y-intercepts are;

The value of g(x) is 0 at the ordered pair (1, 0), therefore, the x-intercept of g(x) is (1, 0)

The value of x is 0 at the ordered pair (0, 4), therefore, the function, g(x) has a y-intercept at the point (0, 4)

Therefore, the function f and g have different intercepts, but the value in the table and the graph indicates that as x approaches infinity, the y-value, approaches -1, the correct option is therefore, option C

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In a Production Possibility Curve (PPC) with product output Y on the vertical axis and product output X on the horizontal axis the following points are described as follows.

- Point Q represents an unemployment rate of 100 percent. It is located at the origin, where both axes intersect, indicating no product output due to complete unemployment.

- Point R signifies full employment and is located at the maximum product output on the X-axis, showing the economy's capacity when all resources are fully utilized.

- Point S indicates where the US economy typically operates, within the usual range of product output levels on the X-axis, reflecting a balanced unemployment rate that includes frictional and structural unemployment.

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There are no zero pairs in the expression.

To calculate the number of zero pairs in statement 9 + (-16), we need to clarify the expression and determine any matching positive and negative numbers.

In this respect, 9 and -16 have unlike signs. To simplify, we can rewrite the expression as 9 - 16, which is similar to adding the opposite of 16.

Here, let's look for zero pairs. A zero pair incorporate a positive and negative number that cancel each other out and occur in a sum of zero.

In the expression 9 - 16, there are no identical positive and negative numbers.

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The transformed matrix, after interchanging R1 and R2, is:

2 9 4 5

8 -2 1 7

1 4 -4 9

To interchange rows R1 and R2, we swap the positions of the first and second rows in the matrix. This operation can be performed by physically swapping the rows or by using the properties of matrix operations. Let's apply this row operation to the given matrix:

Original matrix:

8 -2 1 7

2 9 4 5

1 4 -4 9

Interchanging R1 and R2, we get:

2 9 4 5

8 -2 1 7

1 4 -4 9

After switching R1 and R2, the modified matrix is:

2 9 4 5

8 -2 1 7

1 4 -4 9

In the transformed matrix, the original first row (8 -2 1 7) becomes the second row, and the original second row (2 9 4 5) becomes the first row. The remaining rows (R3) remain unchanged.

Therefore, R1 and R2 are switched, and the resulting matrix is:

2 9 4 5

8 -2 1 7

1 4 -4 9

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The three arithmetic means between 10 and 130 are 40, 70, and 100.

To find the three arithmetic means between 10 and 130, we need to calculate the common difference between consecutive terms.

The common difference (d) can be found using the formula:

d = (last term - first term) / (number of terms - 1)

In this case, the first term is 10, the last term is 130, and we need to find three arithmetic means.

d = (130 - 10) / (3 + 1) = 120 / 4 = 30

Now, we can calculate the three arithmetic means by adding the common difference to the previous term:

First arithmetic mean = 10 + 30 = 40

Second arithmetic mean = 40 + 30 = 70

Third arithmetic mean = 70 + 30 = 100

So 40, 70, and 100 are the three arithmetic means between 10 and 130.

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Step-by-step explanation:

87,959 ==> 88,000 is the nearest hundred

The answer is:

Work/explanation:

When rounding to the nearest hundredth, round to 2 decimal places (DP).

Which means we should round to 5.

5 is followed by 9, which is greater than or equal to 5. So, we drop 9 and add 1 to 5 :

87. 96

The numeral 7,001 eight is equal to 3585 in base ten.

To convert the numeral 7,001 in base eight to base ten, we need to multiply each digit by the corresponding power of eight and sum them up.

Starting from the rightmost digit, we have:

[tex]1 * 8^0 = 1\\0 * 8^1 = 0\\0 * 8^2 = 0\\7 * 8^3 = 3584[/tex]

Adding these values together, we get:

1 + 0 + 0 + 3584 = 3585

Therefore, the numeral 7,001eight is equal to 3585 in base ten.

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Answer:

[tex]\frac{3}{7}[/tex] <  [tex]\frac{3}{5}[/tex]

Step-by-step explanation:

[tex]\frac{3}{7}[/tex] ? [tex]\frac{3}{5}[/tex]

We have to get both fractions with the same denominator to compare them.

[tex]\frac{3}{7}[/tex] = [tex]\frac{15}{35}[/tex]

[tex]\frac{3}{5}[/tex] = [tex]\frac{21}{35}[/tex]

[tex]\frac{15}{35} < \frac{21}{35}[/tex]

So, [tex]\frac{3}{7}[/tex] <  [tex]\frac{3}{5}[/tex]

The exact value of sec(-135°) is 1.

To find the exact value of sec(-135°), we need to use the relationship between secant and cosine functions.

The secant function is defined as the reciprocal of the cosine function:

sec(theta) = 1 / cos(theta).

We know that the cosine function has a period of 360°, which means that cos(theta) = cos(theta + 360°) for any angle theta.

In this case, we want to find sec(-135°). Since the cosine function is an even function (cos(-theta) = cos(theta)), we can rewrite sec(-135°) as sec(135°).

Now, let's focus on finding the value of cos(135°). The cosine function is negative in the second and third quadrants.

In the second quadrant, the reference angle is 180° - 135° = 45°. The cosine of 45° is equal to √2/2.

Therefore, cos(135°) = -√2/2.

Now, we can find sec(135°) using the reciprocal property:

sec(135°) = 1 / cos(135°).

Substituting the value of cos(135°), we have:

sec(135°) = 1 / (-√2/2).

To simplify further, we multiply the numerator and denominator by -2/√2:

sec(135°) = -2 / (√2 * -2/√2).

Simplifying the expression:

sec(135°) = -2 / -2,

sec(135°) = 1.

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Answer:

Step-by-step explanation:

Remember PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction)

35 - 12 : 2 + 8² =

35 - 6 + 64 =

93

Answer:

Independent

Step-by-step explanation:

Flipping a coin is independent of each flip.

Answer:

Independent

Step-by-step explanation:

The flipping of two coins are an independent event. The reason for this is that one coin flip does not affect the outcome of the other flip. An example of a dependent event would be coat sales and weather, as cold weather would affect the amount of coats sold.

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The proportion by which the later temperature exceeds the earlier temperature is 3/5 or 3:5.

To determine the proportion by which one temperature exceeds the other, we need to calculate the difference between the two temperatures and express it as a proportion of the starting temperature.

First, calculate the temperature difference between 7:00 am and 3:00 pm:

temperature difference = 24°C - 15°C = 9°C

Now, express the temperature difference as a proportion of the starting temperature (15°C).

Proportion = Temperature difference / Starting temperature

Proportion = 9/15

Proportion = 3/5

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Question in English

In a city the temperature was measured at 7:00 am and the value was 15°C, then it was measured at 3:00 pm the value was 24°C. Starting from the level of measurement of this variable, in what proportion does one temperature exceed the other, analyze your answer.

The present value of the stream of savings estimates is approximately $200,256.

To determine whether the firm should make the investment in new software, we need to calculate the present value of the stream of savings estimates and compare it to the cost of the software.

The present value (PV) of the savings estimates can be calculated using the formula:

[tex]PV = C1/(1+r)^1 + C2/(1+r)^2 + ... + Cn/(1+r)^n[/tex]

Where C1, C2, ..., Cn represent the savings in each year, r is the minimum annual return required (8% or 0.08), and n is the number of years (5).

Given the savings estimates in the table, we have:

C1 = $35,000

C2 = $45,000

C3 = $50,000

C4 = $55,000

C5 = $60,000

Plugging these values into the present value formula and using the minimum annual return rate of 8% (0.08), we can calculate:

[tex]PV = 35000/(1+0.08)^1 + 45000/(1+0.08)^2 + 50000/(1+0.08)^3 + 55000/(1+0.08)^4 + 60000/(1+0.08)^5[/tex]

Evaluating this expression, we find that the present value of the stream of savings estimates is approximately $200,256.

Since the present value of the savings estimates is greater than the cost of the software ($172,395), the firm should make this investment. The investment is expected to provide a return greater than the minimum required annual return of 8%.

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The present value of the stream of savings estimates is $149,622.

To determine if the firm should make the investment, we need to calculate the present value of the stream of savings estimates and compare it to the initial cost of the software.

The present value (PV) of the savings estimates can be calculated using the formula:

PV = C1/(1+r)¹ + C2/(1+r)² + ... + Cn/(1+r)ⁿ

Where:

PV = Present value

C1, C2, ..., Cn = Cash flows in each period

r = Discount rate (minimum annual return)

Given the savings estimates in the table over a 5-year period and a minimum annual return of 8% (0.08), we can calculate the present value as follows:

PV = $15,000/(1+0.08)¹ + $35,000/(1+0.08)² + $50,000/(1+0.08)³ + $45,000/(1+0.08)⁴ + $40,000/(1+0.08)⁵

PV = $13,888.89 + $30,864.20 + $41,152.46 + $34,682.34 + $29,034.09

PV = $149,621.98 (rounded to the nearest dollar)

The present value of the savings is higher than the initial cost of the software ($172,395), the firm should make this investment if it requires a minimum annual return of 8% on all investments.

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Answer:

| x | -7

---------------

x | x² | -7x

-4 | -4x | 28

x² - 11x + 28 = (x - 4)(x - 7)

Answer:

B. 0.65

Step-by-step explanation:

The closer the r value is to the number 1 or -1, the stronger the correlation.

For example:

0.99 > 0.01

-0.6 > 0.5

.43 < .76

.69 > .21

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The value of 408^5 is approximately 273,539,283,056,896. This is a large number that can be accurately calculated using a calculator or computer program.

To work out the value of 408^5, we need to perform the exponentiation calculation. In this case, 408 is the base, and 5 is the exponent.

Calculating large exponentiations like this can be time-consuming and prone to error if done manually. However, with the help of a calculator or computer, we can easily find the result.

Using a calculator or computer program, we can calculate 408^5 and obtain the value. The result is a very large number:

408^5 ≈ 273,539,283,056,896

Therefore, the value of 408^5 is approximately 273,539,283,056,896.

In decimal notation, the value is written as:

273,539,283,056,896

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Answer:

8

Step-by-step explanation:

i took the test mde 100