Pls answer correctly thnks
Solve the linear equation by elimination:
-5x+3y=10
2x+5y=-35
And explain

Thanks!

Answers

Answer 1

[tex]-5x+3y = 10~~~~ .....(i)\\\\2x+5y =-35~~~ ....(ii)\\\\\text{Multiply equation (ii) by}~ \dfrac 35~ \text{ and do (ii) -(i)}\\\\\\\dfrac 35(2x+5y) - (-5x+3y) = \dfrac 35}(-35) - 10\\\\\implies \dfrac{6x}5 +3y + 5x -3y = -21-10 = -31\\\\\implies \dfrac{6x + 25x}5 = -31\\\\\implies 31x = -31 \times 5\\\\\implies x = -5\\\\\text{Substitute }~x=-5~ \text{in equation (ii):}\\\\2(-5) +5y =-35\\\\\implies -10 +5y = -35\\\\\implies 5y = -35 +10 = -25\\\\\implies y = - \dfrac{25}5 = -5[/tex]

[tex]\text{Hence,}~ \textbf{(x,y) = (-5, -5)}[/tex]

Answer 2
Ok done. Thank to me:>
Pls Answer Correctly ThnksSolve The Linear Equation By Elimination:-5x+3y=102x+5y=-35And ExplainThanks!

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Answers

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Answers

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[tex]Hiya![/tex]

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Check the picture below.

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[tex]\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-\frac{1}{10}}x^2\stackrel{\stackrel{b}{\downarrow }}{+\frac{3}{5}}x\stackrel{\stackrel{c}{\downarrow }}{+8} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)[/tex]

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Ok done. Thank to me:>

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Answers

9+6= 15
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