please solve quickly ​

Please Solve Quickly

Answers

Answer 1

total no of marbles = 10

no. of marbles which are not yellow = 9

9/10

hope it helps...!!!


Related Questions

The performance of a cyclist in a race is affected by whether it rains or not that day. The probability the cyclist crashes is 5/8 when it rains and 1/8 when it's dry. On a given day the probability of rain is 1/3 . What is the probability that the cyclist doesn't crash on any given day? please help me

Answers

To solve this problem, we have to consider the fact that if the probability that the cyclist may crash due to some circumstance. The probability the cyclist doesn't crash at any given day is 3/8

Probability

The probability the cyclist crash when it's wet or dry will be the

[tex]P = P_w_e_t * P_d_r_y[/tex]

P(wet) = 5/8P(dry = 1/8

The probability the cyclist crash on any given day is

[tex]P = \frac{5}{8}*\frac{1}{8} =\frac{5}{64}[/tex]

we can subtract 1 from the value above to find the probability the cyclist doesn't crash at any given day

[tex]P = 1 - \frac{5}{64} \\P=\frac{3}{8}[/tex]

The probability the cyclist doesn't crash at any given day is 3/8

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If sin A = 3/8, find the value of cosec A - sec A.​

Answers

Answer:

[tex]\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}[/tex]

Step by step explanation:

[tex]\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\[/tex]

[tex]\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}[/tex]

[tex]\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}[/tex]

TIMED HURRY!! What is the sum of the series

possible answers
1,830
2,010
5,400
5,490

Answers

[tex]\\ \rm\Rrightarrow \sum^{60}_{n=1}3n[/tex]

It will form a arithmetic sequence as

[tex]\\ \rm\Rrightarrow 3(1)+3(2)+3(3)\dots 3(60)[/tex]

First term=a=3Last term=3(60)=180n=60

So

Summation

[tex]\\ \rm\Rrightarrow \dfrac{n}{2}(a+\ell)[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{60}{2}(3+180)[/tex]

[tex]\\ \rm\Rrightarrow 30(183)[/tex]

[tex]\\ \rm\Rrightarrow 5490[/tex]

Option D

Answer:

[tex]\mathsf {5,490}[/tex]

Step-by-step explanation:

[tex]\textsf {Given :}[/tex]

[tex]\lim_{1 \to \660} \sum3n[/tex]

[tex]\textsf {Finding the necessary :}[/tex]

[tex]\textsf {1. first term (a)}[/tex]

[tex]\implies \mathsf {a = 3(1) = 3}[/tex]

[tex]\textsf {2. final term}[/tex] [tex]\mathsf {(a_n)}[/tex]

[tex]\implies \mathsf {a_n = 3(60) = 180}[/tex]

[tex]\textsf {3. common difference (d)}[/tex]

[tex]\implies \mathsf {a_2 = 3(2) = 6}[/tex]

[tex]\implies \mathsf {d = a_2 - a_1 = 6 - 3 = 3}[/tex]

[tex]\textsf {Finding the sum of the series :}[/tex]

[tex]\implies \mathsf {S_n =\frac{n}{2}(a + a_n) }[/tex]

[tex]\implies \mathsf {S_6_0 = \frac{60}{2} (3 + 180)}[/tex]

[tex]\implies \mathsf {S_6_0 = 30 \times 183}[/tex]

[tex]\implies \mathsf {S_6_0 = 5,490}[/tex]

Math!! finding volume of prisms

Answers

The volume of the rectangular prism will be 16.2 cubic ft.

How to find the volume of a right rectangular prism?

Suppose that the right rectangular prism in consideration be having its dimensions as 'a' units, 'b' units, and 'c' units,

then its volume is given as:

V =  a x b x c unit^3

The dimensions of the given rectangular prism;

Length = 2.7ft

Width = 3 ft

Height = 2 ft

The volume of the rectangular prism

V =  a x b x c unit^3

V = 2.7 x 3 x 2

V = 16.2 cubic ft

Hence, the volume of the rectangular prism will be 16.2 cubic ft.

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Hello !!! please help me <3 will give brainle and 25 points please help !!!!

Answers

answer: 375

Step-by-step explanation:

panda bear caps: 25

they ordered 100 in total

25/100 = 1/4, a quarter

then you find a quarter of 1500

1500/4= 375

PLEASE HELP!! ITS URGENT!!

Find all solutions to the equation 3 cos (5t) + 3 = 2 in the interval

0≤t≤ radians.

a) 0.3821, 0.2462, 0.8745
b) 0.654
c) 0.3821, 0.8745
d) No solutions in the interval.

Answers

All solutions to the equation 3 cos (5t) + 3 = 2 in the interval from 0 to π will be 0.3821, 0.2462, and 0.8745. Then the correct option is A.

What is trigonometry?

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The equation is given below.

3 cos (5t) + 3 = 2

By simplifying the equation, then we have

3 cos 5t = -1

   cos 5t = -1/3

Then the value of t will be

5t = 1.91063, 1.12096, 4.3725

 t = 0.3821, 0.2462, 0.8745

Then the correct option is A.

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Which system of equations has a solution of (-2,-2,-2)?
OA
s+y=0
3-==-2
s+y=z=-4
OB. 31 - y = -8
y - 3z = -8
2 + y + z = -8
OC.
1 + 2y = -6
y + 2z = -6
I-y-z = 2
OD. 1-2y + z = 0
2y +9z = -20
I= y + z = 0

Answers

The system of equations that have a solution of (-2,-2,-2) is (b) x + 2y = -6, y + 2z = -6 and x - y - z = 2

How to determine the system of equations?

The attached figure represents the proper format of the equations.

The solution is given as:

(x,y,z) = (-2,-2,-2)

To determine the system of equation, we simply substitute the values of x, y and z in the equations in the options.

So, we have:

Option 1:

x + y = 0

y - z = -2

x + y - z = -4

Evaluate

x + y = 0

-2 - 2 = 0 --- False

This means that this system of equations do not have a solution of (-2,-2,-2)

Option 2:

x + 2y = -6

y + 2z = -6

x - y - z = 2

Evaluate

x + 2y = -6

-2 + 2 * -2 = -6 --- True

y + 2z = -6

-2 + 2 * -2 = -6 ---- True

x - y - z = -2

-2 + 2 + 2 = 2

This means that this system of equations have a solution of (-2,-2,-2)

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Which pair of angles are vertical angles? 6 and 5 2 and 3 1 and 3 5 and 8

Answers

Answer:

1 and 3  

Step-by-step explanation:

1 and 3 are vertical angles

Find k.
10 mi
60⁰
K
30⁰

Answers

K is 90. It’s a 30,60,90

How many tickets did Airon sell in 2018?

Answers

Answer:

11320 is the answer .hope i help you

Find the amplitude of this function.​

Answers

The amplitude is 2.5

Equation:

the equation to find the amplitude is (max-min) / 2.

using this equation, it would be (4 - (-1)) / 2

5 / 2 = 2.5

solve these algebraic fractions please with explanation would be great ​

Answers

Answer:

look above

Step-by-step explanation:

hope it helps

y inversely proportional to x
when y=,x=9
work out an equation connecting y and x

Answers

What does y equal to? I think you had a typo

f(4)=
V
If g(x) = 2, x =
V

Answers

By looking at the given graph, we can see that:

f(4) = -10g(x) = 2 if x = 0.

How to identify the value of the function?

First, we want to find the value f(4). To get that, we need to look at the graph and see the y-value of the function f(x) when x = -4.

By looking at the graph, we can see that f(4) = -10.

Now we know that g(x) = 2, and we want to find the value of x.

Then we need to see the x-value such that g(x) = 2, by looking at the graph of g(x), we can see that it is equal to 2 in the vertex, which is at x = 0.

Then g(x) = 2 when x = 0.

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If the dimensions of the following cylinder are doubled, what will be the surface area of the new cylinder? 1,406.72 in. 2 2,813.44 in. 2 1,607.68 in. 2 5,626.88 in. 2

Answers

Based on the calculations, the surface area (SA) of a cylinder is equal to: B.  2,813.44 in.²

How to calculate surface area of a cylinder?

Mathematically, the surface area (SA) of a cylinder can be calculated by using this formula:

SA = 2πrh + 2πr²

Where:

h is the height.r is the radius.

The dimensions of this new cylinder would be equal to:

Radius = 8 × 2 = 16 in.

Height = 6 × 2 = 12 in.

Substituting the given parameters into the formula, we have;

SA = (2 × 3.14 × 16 × 12) + 2 × 3.14 × 16²

SA = 1,205.76 + 1,607.68

SA = 2,813.44‬ square inches.

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Complete Question:

If the dimensions of the following cylinder are doubled, what will be the surface area of the new cylinder? Radius: 8 in and Height: 6 in.

Group of answer choices.

A. 1,406.72 in.²

B.  2,813.44 in.²

C. 1,607.68 in.²

D. 5,626.88 in.²

a lateral edge of a right prism ïs 6cm and the perimeter of its base is 20cm find area of its lateral surface​

Answers

The area of a 2D form is the amount of space within its perimeter. The lateral area of the right prism is 120 cm².

What is an area?

The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm², m², and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.

Given the perimeter of the base of the right prism is 20 cm, while the lateral height is 6 cm. Therefore, the lateral area of the right prism is,

Lateral Area of Right Prism = 6cm × 20cm = 120cm²

Hence, the lateral area of the right prism is 120 cm².

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The pendulum of an antique clock has been damaged and needs to be
replaced. If the original pendulum completed one swing every 1.5 seconds,
how long should the new pendulum be? Use the formula:
T= 2.
1980
OA. 351 centimeters
OB. 0.25 centimeters
O C. 55.9 centimeters
O D. 234.8 centimeters

Answers

If the original pendulum completed one swing every 1.5 seconds. How long should the new pendulum be is: C. 55.9 centimeters.

How long should the new pendulum be

Using this formula

T=2π√I/g

Where:

T=1.5 seconds

l =length of pendulum

g= acceleration of gravity=9.8m/s²

Let plug in the formula

1.5 seconds=2π√I/9.8

l/9.8=0.05699

l=0.05699×9.8

l=0.5585

l=55.9 centimeters (Approximately)

Therefore How long should the new pendulum be is: C. 55.9 centimeters.

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What additional piece of information is needed to show that DEF andPQR are congruent by ASA?

Answers

Answer:

B) Angle D is congruent to Angle P

Step-by-step explanation:

In order for the triangles to be congurent due to ASA, we need to know two pairs of congruent angles and one pair of congruent sides. We have one pair of sides and angles, so we only need another angle pair, therefore eliminating C and D, which are giving sides. If we chose option A we would get SAA property since it's supposed to be read clockwise. The only option left is option B.

Have a nice day!

I WILL GIVE BRAINLIEST
My mother pays my brother twice as much allowance each week as she pays me because he cleans the bathrooms. Together we get $24 each week. How much is my brother's allowance each week?

A. $4.00

B. $8.00

C. $16.00

D. $24.00

Answers

Answer:

C is the answer

Step-by-step explanation:

16+ (16/2)=16+8=24

Find the range of the following equation for the domain {-4, 0, 3} f (x) = -2x^2 -3

Answers

The range of the function is {-34, -2, -20}

How to determine the range?

The function is given as:

f(x) = -2x^2 - 2

The domain is {-4, 0, 3}

Substitute the domain values in the function.

f(-4) = -2(-4)^2 - 2 = -34

f(0) = -2(0)^2 - 2 = -2

f(3) = -2(3)^2 - 2 = -20

This means that the range of the function is {-34, -2, -20}

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A jazz concert brought in $153,500 on the sale of 7,500 tickets. If the tickets sold for $15 and $25 each, how many of each type of ticket were sold?
The number of $15 tickets is

Answers

Answer:

the answr is 87 jistg ebcaujse

Step-by-step explanation:

3,500 tickets were sold for $15 each and 4,600 tickets were sold for $25 each.

Let x be the number of $15 tickets and y be the number of $25 tickets.

We know that:

x + y = 7,500 (the total number of tickets sold)

15x + 25y =  153,500 (the total amount of money made from ticket sales)

We can use the first equation to express y in terms of x:

y = 7,500  - x

We can substitute this expression of y into the second equation:

15x + 25(7,500  - x) = 153,500

Solving for x:

15x + 25(7,500) - 25x =  153,500

15x + 187500 - 25x =  153,500

-10x = -34,000

x = 3400

Therefore, 3,400 tickets were sold for $15 each and  7,500 - 3,500 = 4000 tickets were sold for $25 each.

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27-(2c+3) = 2(c + 7) + c

Answers

Answer:

c=2

Step-by-step explanation:

We can first take out the parenthesis: 27-2c-3=2c+14+c. We can combine: -2c+24=3c+14. Then, we can subtract 14 from both sides: -2c+10=3c. Then, we can add 2c on both sides: 10=5c. To find c, we can do 10/5=2.

find the area of the partial circle. use 3.14 for pi.

Answers

Radius=1cm=r

Thats a semi circle

Area

πr²/2π(1)²/2π/23.14/21.57cm²

If you walk 6 blocks east, 2 blocks north, 3 blocks west and 4 blocks south, then what is the total distance you travel?

Answers

Answer:

6 + 2 + 3 + 4 = 15

so 15 blocks

a block is about 0.05 miles

so 15 blocks in miles is 0.75 miles

0.75 or 3/4 miles = 1320 yards

If sin A = 4/5 find the value of cot A + tan A.​

Answers

Answer:

2.08

Step-by-step explanation:

[tex]sin^{-1} 4/5 = 53.13\\tan 53.13 = 1.33\\cot 53.13 = 0.75\\1.33 + 0.775 = 2.08[/tex]

Answer:

The answer is 2

Step-by-step explanation:

[tex]Cot(x)=\frac{1}{tan(x)} =\frac{Cos(x)}{Sin(x)}[/tex]

[tex]Tan(x) = \frac{Sin(x)}{Cos(x)}[/tex]

[tex]Cos(\frac{\pi }{2} -x)=sin(x)[/tex]

This means that
[tex]\frac{\cos \left(\frac{\pi }{2}-\frac{4}{5}\right)}{\sin \left(\frac{4}{5}\right)}+\frac{\sin \left(\frac{4}{5}\right)}{\cos \left(\frac{\pi }{2}-\frac{4}{5}\right)}[/tex]

This will be a long one to solve
-> apply cos identity to right side

[tex]\frac{\cos \left(\frac{\pi }{2}-\frac{4}{5}\right)}{\sin \left(\frac{4}{5}\right)}+\frac{\sin \left(\frac{4}{5}\right)}{\cos \left(\frac{\pi }{2}\right)\cos \left(\frac{4}{5}\right)+\sin \left(\frac{\pi }{2}\right)\sin \left(\frac{4}{5}\right)}[/tex]

-> simplify according to unit circle

[tex]\frac{\cos \left(\frac{\pi }{2}-\frac{4}{5}\right)}{\sin \left(\frac{4}{5}\right)}+1[/tex]

->apply cos identity again

[tex]\frac{\cos \left(\frac{\pi }{2}\right)\cos \left(\frac{4}{5}\right)+\sin \left(\frac{\pi }{2}\right)\sin \left(\frac{4}{5}\right)}{\sin \left(\frac{4}{5}\right)}+1[/tex]

If you apply for unit circle numbers,

you will get 2

I do not recommend using a calculator for these questions, but instead, turn the form into [tex]sin\frac{\pi }{2}[/tex] other base unit circle locations, and most likely this is the method that your teacher counts as "right."
when using a calculator, it tends to "round" the number, which result in a inaccurate answer

Question 7(Multiple Choice Worth 1 points)
(02.05 LC)

Given f(x) and g(x) = f(x + k), use the graph to determine the value of k.

Two lines labeled f of x and g of x. Line f of x passes through points 0, 4 and negative 4, 0. Line g of x passes through points negative 9, 0 and negative 4, 5.

−4
−5
4
5

Answers

The value of k based on the information given will be k = 2.

How to calculate the value?

It should be noted that the line of f(x) passes through the point (-4, 0) and (0, 4). The line of g(x) goes through (-2, 0) and (0, 4).

The slope of x will be:

= (4 - 0)/(0 + 4)

= 4/4

= 1

By using slope point form, y = kx + 4.

Substitute x = 2.

g(-2) = -2k + 4 = 0

2k = 4

k = 4/2 = 2

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In Question 1 and Question 2, what is the distance from the center if the circle to a point on the circle? Take this idea a step further: what is the
relationship between the center of any circle and the points that lle on the circle?

Answers

Step-by-step explanation:

I don't see question 1 and 2.

but it did be way for you : the distance from the verge of a circle to a point on the circle is always the radius.

that is the whole concept of a circle : it is the line (or curve) of all points that have the same, constant distance r from a single point.

Which function has the same domain as y= 2√x?
Y = √2x
Oy=2³√x
Oy=√x-2
O y = ³√x-2

Answers

The function that has the same domain as y= 2√x is (a) y = √2x

How to determine the function?

The function is given as:

y= 2√x

The above function is a square root function.

All square root functions have the same domain when they are not translated.

This means that

y = √2x has the same domain as y= 2√x  because it is not translated

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Simplify this expression.
7
12
43
36
37
36
es
A)
B)
C)
D)
11
12
003
8
33

Answers

d

Step-by-step explanation:

Libby built a fence that was 56ft for over 4 days, she built the same length each day. how many inches of fence did libby build each day?

Answers

Each day she built 14ft of fence which is equal to 168in .
Other Questions
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