Answers
Answer:
1st
Vertex
we have
f(x)=x²-18x+88
let
y=x²-18x+88
comparing above equation with ax²+bx+c
we get
a=1
b=-18
c=88
now
vertex(x,y)=(-b/2a,f(-b/2a))
x=(18/2×1)=9
y=f(9)=9²-18×9+88=7
SO
VERTEX(X,Y)=(9,7)
=
#1
y=x²-18x+88x coordinate of vertex
-b/2a18/29y coordinate
y=9²-18(9)+88y=81+88-162y=7Option C.
#2
y=x²-9x-36y intercept
y=0-36=-36(0,-36)
x inetercepts
x²-9x-36=0x²-12x+3x-36=0(x-12)(x+3)=0x=12,-3(12,0)U(-3,0)
#3
y=-x²+3x+12Find dy/dx
-2x+3f'(x)=0<=>x=3/2
For increasing
-2x+3>0x<3/2For decreasing
x>3/2F(x) is increasing on (-oo,3/2)
F(x) is decreasing on (3/2,oo)
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Answers
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Road shimmer
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Answers
Answer:
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Answer:
C.Step-by-step explanation:
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Step-by-step explanation:
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Answers
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Answer:
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Have a wonderful day!
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Answer:
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3.
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Answers
Explanation:
Answer:
Answers = a , c, d, e
Step-by-step explanation:
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About Absolute Value:
Absolute value is the distance from 0 on the number line.
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The number -5 is also 5 units from the 0, except from the opposite side
Absolute value states that negative numbers have a positive absolute value and a positive number has a positive absolute value.
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
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which expression below has a value in between 0 and 1?
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