please help with this practice question, thank you

Please Help With This Practice Question, Thank You

Answers

Answer 1
So the equation shown: y=x-6 is in slope intercept form (y=mx+b)
m is the slope and would be 1 in this equation.
b is the y intercept and would be -6 in this equation. Draw a dot at -6 on the y-axis and go right 1, up 1. Then down 1, left 1 to continue on the left side of the y axis

Related Questions

1. 3x-4=232. 9-4x=173.6(x-7)=364. 2(x-5)-8= 34Solve equations

Answers

1. 3x - 4 = 23

add 4 to both sides

3x - 4 + 4 = 23 + 4

3x = 27

Divide both sides by 3

3x/3 = 27/3

x = 9

2. 9 -4x = 17

subtract 9 from both sides

9 -9 -4x = 17 - 9

-4x = 8

Divide both sides by -4

-4x/-4 = 8/-4

x = -2

3. 6(x-7) = 36

Divide both sides by 6

x -7 = 6

add 7 to both sides

x - 7 + 7 = 6 + 7

x = 13

4. 2(x-5) -8 = 34

Expand

2x -10 -8 = 32

2x - 18 = 32

2x = 32 + 18

2x = 50

Divide both sides by 2

x =25

Simplify 2(x+8)+6x Write your answer in factored form

Answers

Answer:

8x + 16 is your answer

Step-by-step explanation:

X^2+6x+8 this would be your answer in factored form

HELP PLSSS
(Attached to image)

Answers

The inequality is lies between the 5.26 < 5.71

The correct option is (a)

Given,

From the figure,

To see the number line and determine the which of the expression is true.  

What is Inequality?

Inequality is defined as an equation that does not contain an equal sign.

Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

The number line goes from 5.0 to 6.0 with 9 labeled marks in between.

Each mark increases by point one

There are five labeled points.

A point labeled 5.04 is between 5.0 and 5.1.

A point labeled 5.26 is between 5.2 and 5.3.

A point labeled 5.4 is at the mark labeled 5.4

A point labeled 5.520 is between 5.5 and 5.6.

A point labeled 5.71 is between 5.7 and 5.8.

Then the ascending order of the number line will be :

5.04 < 5.26 < 5.4 < 5.52 < 5.71

Hence, The correct option is (a)i.e., 5.26 < 5.71

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David left $300 in an account that earns 5% on the money he originally deposited. When he collected his interest, he had earned $60 in interest. How long did he leave the money in the account?

Answers

The time that David left the money in the account would be = 4 years

What is an earned interest?

An earned interest is the amount of money that is regularly paid to an individual who invested a specific amount of money for a stipulated period of time.

The principal amount(p)= $300

The time (T)= X

The rate of interest yield (R)= 5 %

Simple interest( SI)= $ 60

Using the formula;

SI = P×T×R/100

Make T the subject of formula;

T = SI×100/P*R

T= 60×100/300×5

T= 6000/1500

T = 4 years.

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HELP PLEASE !!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

The equation of the line perpendicular to y = - (2 / 3) · x and the point (4, - 8) is y = (3 / 2) · x - 14.

How to determine the equation of a perpendicular line

Mathematically speaking, lines are represented by equations of the form y = m · x + b, where m and b are the slope and the intercept of the line. Additionally, two lines are perpendicular to each if the product of their slopes is equal to - 1.

First, we determine the slope of the perpendicular line:

m' = - 1 / m

m' = - 1 / (- 2 / 3)

m' = 3 / 2

Second, the intercept of the perpendicular line is:

b = y - m · x

b = - 8 - (3 / 2) · 4

b = - 8 - 6

b = - 14

Then, the equation of the perpendicular line is y = (3 / 2) · x - 14.

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Last year, 49% of business owners gave a holiday gift to their employees. A survey of business owners conducted this year indicates that 40% planned to provide a holiday gift to their employees. Suppose the survey results are based on a sample of 85 business owners.

b. Suppose the business owners in the sample do as they plan. Conduct a hypothesis test that can be used to determine whether the proportion of business owners providing holiday gifts had decreased from last year.

State the hypotheses.

Compute the test statistic and p-value.

c. Using a 0.01 level of significance, would you conclude that the proportion of business owners providing gifts decreased?

Answers

Using the z-distribution, it is found that:

b)

The hypotheses are: null [tex]H_0: p \geq 0.49[/tex], alternative [tex]H_1: p > 0.49[/tex]The test statistic is of z = -1.69.The p-value is of 0.0455.

c) There is not enough evidence to conclude that the proportion of business owners providing gifts decreased using a 0.01 significance level.

What are the hypotheses tested?

At the null hypotheses, it is tested if there is no evidence that the proportion decreased from 49%, that is:

[tex]H_0: p \geq 0.49[/tex]

At the alternative hypotheses, it is tested if there is evidence that the proportion decreased from 49%, that is:

[tex]H_1: p > 0.49[/tex]

What is the value of the test statistic?

The test statistic is given according to the following rule:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which the parameters are described as follows:

[tex]\overline{p}[/tex] is the sample proportion.p is the proportion tested at the null hypothesis.n is the sample size.

Considering that 40% of the sample of 85 planned to provide a gift, and the proportion tested is of 49%, the values of the parameters are given as follows:

[tex]\overline{p} = 0.4, p = 0.49, n = 85[/tex]

Hence the test statistic is given by:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.4 - 0.49}{\sqrt{\frac{0.4(0.6)}{85}}}[/tex]

z = -1.69.

What is the p-value of the test and what is the conclusion?

Considering a left-tailed test, as we are testing if the proportion is less than a value, with z = -1.69, using a z-distribution calculator, the p-value is of 0.0455.

Since the p-value of the test is greater than 0.01, there is not enough evidence to conclude that the proportion of business owners providing gifts decreased using a 0.01 significance level.

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A radioactive substance decays according to A=A0e−0.0028t, where A0 is the initial amount and t is the time in years. If A0=710 grams, find the time for the radioactive substance to decay to 366 grams. Round your answer to two decimal places, if necessary.

Answers

Solution

- The function given is:

[tex]A=A_0e^{-0.0028t}[/tex]

- We have been given:

[tex]\begin{gathered} A_0=710g \\ A=366g \end{gathered}[/tex]

- We are required to find the time for the radioactive substance to decay. That means we need to find the value of t in the equation.

- Thus, we have that:

[tex]\begin{gathered} 366=710e^{-0.0028t} \\ \text{ Divide both sides by 710} \\ \frac{366}{710}=e^{-0.0028t} \\ \\ \text{ Take the natural log of both sides} \\ \ln(\frac{366}{710})=\ln(e^{-0.0028t}) \\ \\ \ln(\frac{366}{710})=-0.0028t \\ \\ \text{ Divide both sides by -0.0028} \\ \\ \therefore t=\frac{1}{-0.0028}\ln(\frac{366}{710}) \\ \\ t=236.6541...\approx236.65\text{ years} \end{gathered}[/tex]

Final Answer

The answer is 236.65 years

Factories often add filler when making meatballs sold by the bag. One factory obtained 90 kg of beef from overseas. They want to add 1.4 oz of filler for each
pound of beef. How many ounces of filler will the factory need in order to make meatballs out of this shipment of beef?

Use 1 Ib=0.45 kg and do not round any
computations.

Answers

One factory that obtained 90 kg of total beef from overseas. The company needs 390 oz of meat filler to make meatballs out of this shipment of beef.

What are meat fillers?

In processed meat products, starches are frequently employed as fillers to bind water that would otherwise leak out of the product, increasing its texture and sensory qualities.

As cheap fillers or inferior fiber sources, items including corncobs, feathers, soy, cottonseed hulls, peanut hulls, citrus pulp, screening, weeds, straw, and cereal by-products are frequently used.

One factory that has obtained 135 kg of beef from overseas.

They want to add a total of 1.3oz of filler for each pound of beef.

Given is:

0.45 kg = 1 pound

So, 135 kg = 300 pounds

The company that wants to add a total of 1.3 oz of filler for each pound of beef.

So, for 300 pounds they will need = 390 oz of filler.

Therefore, the company needs 390 oz of filler.

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I will need help with this math problem it has three parts to it

Answers

a)The smaller break even quantity is 10

b)The quantity that must be sold to maximize the profit= 14.25

c)The maximum profit = $36.13

STEP - BY - STEP EXPLANATION

What to find?

• The smaller break even quantity is

,

• The quantity that must be sold to maximize the profit

,

• The maximum profit.

Given:

C(x)= 13x + 370

R(x)=70x - 2x²

a) At the break even quantity, the revenue = cost, that is no profit and no loss.

R(x) = C(x)

So that we have;

70x - 2x² = 13x + 370

Re-arrange.

-2x² + 70x - 13x - 370 =0

-2x² +57x - 370 =0

2x² - 57x + 370 = 0

We can now solve the quadratic equation above.

Using the qudaratic formula

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

a=2 b=-57 c=370

Substitute the values into the formula and evaluate.

[tex]x=\frac{-(-57)\pm\sqrt[]{(-57)^2-4(2)(370)}}{2(2)}[/tex][tex]x=\frac{57\pm17}{4}[/tex][tex]Either\text{ x=}\frac{57+17}{4}=\frac{74}{4}=\frac{37}{2}[/tex]

Or

[tex]x=\frac{57-17}{4}=\frac{40}{4}=10[/tex]

x = 37/2 or x=10

We take the smaller value.

Hence, x=10

Therefore, the smaller break even quantity is 10.

b)To find the quantity that will maximize the profit, find the profit function.

p(x) = R(x) - C(x)

P(x) = 70x - 2x² - (13x +370)

= 70x - 2x² - 13x - 370

P(x) =-2x² + 57x - 370

Equate to zero

-2x² + 57x - 370 = 0

2x² - 57x + 370 =0

The maximum is at x = -b/2a

b= -57 and a=2

Substitute the values

x= - (-57) /2(2)

x= 57 /4

x= 14.25

c) To find the maximum profit, simply substitute x=14.25 into the profit function and simplify.

That is;

P(x) =-2x² + 57x - 370

P(14.25) =-2(14.25)² + 57(14.25) - 370

= -406.125 + 812.25 - 370

= 36.125

≈ 36.13

Hence, the maximum profit is $36.13

One-third of a number is at least four less than the number. Which inequality represents the number?

Answers

When one-third of a number is at least four less than the number, the inequality to represent the information is C. n ≥ 6.

What is an inequality?

It should be noted that an inequality is simply used to illustrate the expressions that aren't equal.

Let the number be n.

This will be illustrated as:

1/3n ≥ n - 4

Collect like terms

1/3n - n ≥ -4

-2/3n ≥ -4

Multiply through by -3/2

n ≥ -4 × -3/2

n ≥ 6

The value is n ≥ 6.

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PLEASE HELP!!!

Explain how the cosine of an angle in the second quadrant differs from the cosine of its reference angle in the unit circle.

Answers

Answer:

the second quadrant is negative but the reference angle is exactly the same but positive

Step-by-step explanation:

looking at 150 on the unit circle in the second quadrant you will see the cosine is negative square root 3 divided by 2 but the reference angle is 30 degrees and when we look at the cosine of that which is the x value of what we see it is positive square root of 3 divided by 2

Select the correct answer from each drop-down menu.
A triangle FGH, right angle at H is shown. Base GH has length labeled 3 units. Height FH has length labeled 4 units, and hypotenuse FG has length 5 units.

Use the figure to complete the following statements.

sin(F) =
cos(F) =
sin(G) =
cos(G) =

Answers

The value of given expressions will be sin(F) = 3/5, cos(F) = 4/5, sin(G) = 4/5 and cos(G) = 3/5.

A triangle may be defined as a closed figure having three sides and three angle, the sum of which is equal to 180°. A right-angled triangle is the one which has one angle as 90°. We consider a right-angled triangle FGH which is right-angled at H. The sine of any angle is given by the division of Perpendicular to its Hypotenuse. The cosine of any angle is given by the division of Base to its Hypotenuse. Now, we need to find

sin(F) = Perpendicular/Hypotenuse, for angle at F perpendicular will be GH and Hypotenuse will be FG. So, sin(F) = 3/5

cos(F) = Base/Hypotenuse, for angle at F Base will be FH and Hypotenuse will be FG. So, cos(F) = 4/5

sin(G) = Perpendicular/Hypotenuse, for angle at G perpendicular will be FH and Hypotenuse will be FG. So, sin(F) = 4/5

cos(G) = Base/Hypotenuse, for angle at G Base will be GH and Hypotenuse will be FG. So, cos(F) = 3/5

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Simplify using the laws of exponents. Leave your answer an exponential form. The box is to type in the exponent.

Answers

Use the next property:

[tex]\frac{a^m}{a^n}=a^{m-n}[/tex][tex]\frac{x^8}{x^2}=x^{8-2}=x^6[/tex]Then, the given expression simplified is equal to x^6

I need help with this question but no one is helping me! Can someone please help me​

Answers

Answer: 36.00%

60% can be written as 0.60 and/or 6/10, which simplifies to 3/5 for easier operations. The probability of 2 students both drink coffee with breakfast can be shown as 0.60 • 0.60 = 0.36. This means there is a 36% chance of both students drinking coffee with breakfast in the morning.

Step-by-step explanation:

if g(x) = 1/2|x|-6 and h(x)=x-4 Which expression is equivalent to h(g(x))?

1/2|x| - 2
1/2|x-4| -6
1/2|x|-10
1/2|x-10|

Answers

h(g(x)) is equivalent to the expression 1/2|x|-10

What will the expression be?

Given g(x) = 1/2|x|-6 and h(x) = x-4

h(g(x)) = h(1/2|x|-6)              

Put the value of g(x) in the expression

Now, evaluate the expression using the  definition of h(x) by replacing x in x-4 with 1/2|x|-6:

h(g(x)) = 1/2|x|-6 - 4 = 1/2|x|-10

Since  h(g(x)) = 1/2|x|-10. Therefore, 1/2|x|-10 is the expression equivalent to h(g(x)) so the third option is the answer.

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help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Answers

Answer:

-0.07

Step-by-step explanation:

Find the average

Fill in the missing parts to these two column proofs:

Answers

According to the picture:

For the first statement

[tex]AB\cong CD[/tex]

The reason is: Given.

This is because it is given in the information to solve the problem.

The second statement must be:

[tex]BC\cong DA[/tex]

And the reason is also: Given.

For the third statement:

[tex]AC\cong AC[/tex]

The reason is the Reflexive property.

The fourth statement must be:

[tex]\Delta ABC=\Delta ADC[/tex]

The reason is Side Side Side congruence postulate.

The fifth statement must be:

[tex]\measuredangle ABC=\measuredangle CDA[/tex]

The reason is congruent triangles definition.

Convert 39 yards into miles. Round your answer to the nearest hundredth.

Answers

The conversion from yards to miles is given by:

[tex]1\text{ mile }\to1760\text{ yards}[/tex]

The conversion factor is:

[tex]\frac{1\text{ mile}}{1760\text{ yards}}[/tex]

Now, if we want to know how many miles are 39 yards, we multiply 39 yards by the conversion factor:

[tex]39\text{ yards }\cdot\frac{1\text{ mile}}{1760\text{ yards}}\approx0.02\text{ miles}[/tex]

4. What common characteristics will two parabolas in the family f(×) = a(× - 4)(× - 8) have?

Answers

• The Same roots

,

• The same axis of symmetry

1) If we compare two parabolas from this family, like:

[tex]\begin{gathered} f(x)=-1(x-4)(x-8) \\ g(x)=2(x-4)(x-8) \end{gathered}[/tex]

Note that the difference is in the leading coefficient "a".

2) Both parabolas will have the same roots, the same x-intercepts:

[tex]x_1=4,x_2=8[/tex]

In addition to this, we can state that both will share the same axis of symmetry:

[tex]\begin{gathered} f(x)=-1(x-4)(x-8) \\ f(x)=\quad -x^2+12x-32_{} \\ h=\frac{-12}{2(-1)}=6 \end{gathered}[/tex]

As well as:

[tex]\begin{gathered} g(x)=2(x-4)(x-8) \\ g(x)=2x^2-24x+64 \\ h=\frac{24}{2(2)}=6 \end{gathered}[/tex]

Hence, the answer is:

0. Same roots

,

1. Same axis of symmetry

Refer to this diagram for the next five statements. Write the correct postulate, theorem, property, or definition that justifies the statement below the diagram.

Given: ∠MRS ≅ ∠MRO

m∠MRO + m∠MRS = m∠SRO

Answers

This statement is justified by the angle addition postulate.

(+2) The
The ratio of
women children = 11:3 and the
ratio of
men children = 5:2
Find the ratio of men:women

Answers

The ratio of both men and women 15:22

What is Ratio ?

A ratio displays the multiplicity of two numbers. For instance, if a dish of fruit contains eight oranges and six lemons, the ratio of oranges to lemons is eight to six. The ratio of oranges to the overall amount of fruit is 8:14, and the ratio of lemons to oranges is 6:8.

Given,

The ratio of men and children = 5:2

The ratio of women and children = 11:3

To find the ratio of men and women we have to divide both the ratio:

men/children/women/children

or,

men/children x children/women

putting the values

=5/2 x 3/11

=15/22

Hence, the ratio of men:women is 15:22

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Joshua opened a bank account with some money he had saved. During the month, he made deposits of $25 and $40, and he made withdrawals of $15 and
$35. At the end of the month, he had $170 in his account. How much money did he have when he opened the account?

A $285
B $155
C $55
D $15

Answers

Initially, Joshua had $155 in his account.

How to find the initial amount?

Deposits of $25 and $40

Withdrawals = $15, $35

At the end of the month, he had $170 in his account.

Solution:

Let x be the amount of money he had initially.

Then,

x + 25 + 40 - 15 -35 = 170

x + 65 - 50 = 170

x = 170 + 50 - 65

x = 220 - 65

x = 155

Therefore, initially, he had $155 in his account.

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Question: how do I figure out if a number is rational or irrational

Answers

A number is said to be rational if it can be written or transformed into the p/q form, where p and q are integers and q is a non-zero number; if it cannot be written in this form, it is said to be irrational.

Any number that can be written or stated in the p/q form, where p and q are integers and q is a non-zero number, is said to be rational.

A number that is irrational, on the other hand, cannot be stated in p/q form, and its decimal expansion is non-repeating and non-terminating.

Example: √2, √7, √11

Hence we get the required answer.

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The area of a trapezoid is A = 12 (b 1 + b 2)h. Which equation represents the area of a trapezoid when solved for b 1?

Answers

If the area of a trapezoid is A = [tex]\frac{1}{2} (b_{1}+ b_{2})h[/tex], then the equation represents the value of [tex]b_{1}[/tex] is [tex]b_{1}=\frac{2A}{h}-b_{2}[/tex]

The trapezoid is a quadrilateral with at least one pair of parallel sides is called trapezoid. There are four vertices and four edges in the trapezoid.

The area of the trapezoid  A = [tex]\frac{1}{2} (b_{1}+ b_{2})h[/tex]

Where [tex]b_{1}[/tex] and [tex]b_{2}[/tex] are the length of the parallel sides of  the trapezoid

h is the height of the trapezoid

A = [tex]\frac{1}{2} (b_{1}+ b_{2})h[/tex]

Move 1/2  to other side

[tex](b_{1}+ b_{2})h[/tex] = 2A

Move h to other side

[tex](b_{1}+ b_{2})[/tex]  = [tex]\frac{2A}{h}[/tex]

Move [tex]b_{2}[/tex]  to other side

[tex]b_{1}=\frac{2A}{h}-b_{2}[/tex]

Hence, if the area of a trapezoid is A = [tex]\frac{1}{2} (b_{1}+ b_{2})h[/tex], then the equation represents the value of [tex]b_{1}[/tex] is [tex]b_{1}=\frac{2A}{h}-b_{2}[/tex]

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A bag contains 120 marbles. Some are red and the rest are black. There are 19 red marbles for every black marble. How many red marbles are in the bag?

A bag contains 120 marbles. Some are red and the rest are black. There are 19 red marbles for every black marble. How many red marbles are in the bag?

Answers

The number of red marbles in the bag is 114 .

in the question ,

it is given that ,

total number of marbles in the bag = 120 marbles

let the number of red marbles [tex]=[/tex] r

let the  number of black marbles [tex]=[/tex] b

so , According to the question

b + r = 120   ...eqn(1)

also given that for every black marble there is 19 red marbles

which is represented by , r = 19b

Substituting  r = 19b in eqn (1) , we get

b + 19b = 120

simplifying further , we get  

20b = 120

b = 6

and r = 19(6) = 114

Therefore , The number of red marbles in the bag is 114 .

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An electronic store is having an 18% off sale on everything in the store to the nearest cent which of the following could represent regular prices and sale price of items in the store
during the sale choose all that apply

Answers

The following that represent the sales price and the regular prices are:

regular price: $55.43, sales price: $45.45

regular price: $29.99,  sales price: $24.59

regular price: $652.30, sales price: $534.89

What are the regular prices and the sales price?

Percentage is the fraction of a number out of hundred. The sign that is used to represent percentages is %.

When a discount is given on the price of an item, the price of the item would reduce by the given price or by the percent reduction.

Sales price = regular price x (1 - discount)

Sales price = regular price x (1 - 0.18)

Sales price = regular price x 0.82

Sales price when the initial price is $55.43: $55.43 x 0.82 = $45.45

Sales price when the initial price is $29.99: $29.99 x 0.82 = $24.59

Sales price when the initial price is $215.33: $215.33 x 0.82 = $176.57

Sales price when the initial price is $849.50: $849.50 x 0.82 = $696.59

Sales price when the initial price is $652.30: $652.30 x 0.82 = $534.89

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answers pleaseeee
im struggling

Answers

The answer is 3/4 and -2

Answer:

y=3/4x-2

Step-by-step explanation:

slope=3/4x

y-intercept=-2

what is 42/100 of x over 35%

Answers

The value of x in the expression 42/100 of x over 35% is 0.147.

What is an expression?

It should be noted that an expression is simply used to show the relationship between the variables or number given.

Therefore, the information will be expressed as:

42/100 × x/35%

= 42/100 × x/0.35

Cross multiply

100 × x = 0.35 × 42

100x = 14.7

Divide.

x = 14.7 / 100

x = 0.147

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Factories 6ax2-3ay-8bx2+4by

Answers

=[2[tex]x^{2}[/tex]-y][3a-4b] This is the factorized form of 6a[tex]x^{2}[/tex]-3ay - 8 b[tex]x^{2}[/tex] + 4by

What is factorization ?

To factorize a number, use the factorization formula. Factorization is the process of dividing a whole into components that, when multiplied together, equal the original number. The factorization approach simplifies any algebraic or quadratic equation by using the basic factorization formula, which represents the equations as the product of factors rather than expanding the brackets. Any equation may have an integer, a variable, or the algebraic expression itself as a factor.

6a[tex]x^{2}[/tex]-3ay - 8 b[tex]x^{2}[/tex] + 4by

Rearrange the expression

6a[tex]x^{2}[/tex] -8bx² -3ay +4by

2[tex]x^{2}[/tex][3a-4b] - y[3a-4b]

=[2[tex]x^{2}[/tex]-y][3a-4b]

This is the factorized form of 6a[tex]x^{2}[/tex]-3ay - 8 b[tex]x^{2}[/tex] + 4by

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solve each formula for the indicated letter. circle the letter next to your answer. write the letter in the box below.

Answers

(1) d = rt so, r = d/t

(2) a = F/m so, F = ma

(3) p = w/t so, t = w/p

(4) h = V/B so, B = V/h

(5) A = (abc)/(4r) so, r = (abc)/(4A)

(6) P/Q = R/S so, S = QR/P

(7) a = (v-i)/t so, v = at + i

(8) E/e = (R + r)/r so, e = Er/(R+r)

(9) 1/p + 1/q = 1/f so, f = (pq)/(p+q)

(10) 1/p + 1/q = 1/f so, p = qf/(q-f)

(11) 1/R = 1/r1 + 1/r2 so, R = (r1 r2)/(r1 + r2)

(12) 1/t = (1/a) + (1/b) so, b = (at)/(a - t)

(13) A/B = C/D so, C = AD/B

(14) A = h(a+b)/2 so, b = 2A/h - a

(15) V = Q/r1 - Q/r2 so, Q = Vr1 r2/(r2 - r1)

(16) u = F(P/T - E) so, P = (uT + EFT)/F

Other Questions
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