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The May raw materials purchases for May in Rensing Ltd., in dollars terms, is $32,620.

The cost of raw materials purchased in May is determined by computing the required production units and multiplying the result by 2 units and the unit raw material cost.

                                     April     May      June

Sales                           2,520   2,440   2,390

Ending inventory       2,280    2,170    2,330

Goods available for

 sale                          4,800    4,610    4,720

Beginning inventory              2,280    2,170

Production units                     2,330

Raw materials purchases      4,660 (2,330 x 2)

Raw materials price per unit = $7

Total purchases of Raw Materials for May = $32,620 (4,660 x $7)

Thus, we can conclude that in May Rensing Ltd. purchased raw materials worth $32,620.

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Answer:

-4.7854909e+52

Step-by-step explanation:

how do i know

cuz i used a calculator

what evevn is your equation

The probability that the sample mean would be greater than 70.8 kilograms is given as follows:

0.1762 = 17.62%.

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The parameters for this problem are given as follows:

[tex]\mu = 70, \sigma = 8, n = 87, s = \frac{8}{\sqrt{87}} = 0.8577[/tex]

The probability is one subtracted by the p-value of Z when X = 70.8, hence:

Z = (70.8 - 70)/0.8577

Z = 0.93

Z = 0.93 has a p-value of 0.8238

1 - 0.8238 = 0.1762.

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Where the following triangle problem is given, note that:

A) α [tex]\approx[/tex] 11.0

β  β [tex]\approx[/tex] 9.4

B) 25.59 yrds

C) 0.38 yrds

A) To determine the near post angle and the far post angle when the striker is 24 yards from the near post

1/2 (24²) + 1/2 (28²) - 1/4(10²) = 655 (central line length formula)

Cos  α = (24² + 655 - 5²)/ (2 x 24 x √655)

= 0.98171498561

α = Cos ⁻¹ 0.98171498561

α = 10.973603643623608717848651724941

α [tex]\approx[/tex] 11.0° (Cosine Law)

For   28 yards from the far post.

Cos   β   = (28² + 655 - 5²)/ (2 x 28 x √655)

= 0.98659913977

 β  = Cos ⁻¹ 0.98659913977

 β  = 9.3905311636838307510867912796592

 β  [tex]\approx[/tex] 9.4°

B)  Distance between the goalie from the ball is

√655 = 25.592967784139454896443137575823

Distance  [tex]\approx[/tex] 25.59 yrds

C)  5-10 * ((24)/(24+28)) = 0.38 yrds (Angular Bisector Theorem)

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This is a linear programming problem with three constraints and two variables, where the objective is to minimize the expression 3x + 2y subject to the following constraints:

5x + y = 10

x + y = 6

x + 4y = 12

The first constraint represents a straight line in the x-y plane, the second constraint represents another straight line, and the third constraint represents yet another straight line. The feasible region is the region where all three constraints are satisfied simultaneously, which is the intersection of the three lines.

To solve this problem, you can use the method of substitution or elimination to solve for one variable in terms of the other in two of the equations, and then substitute this expression into the third equation to obtain a single equation in one variable. You can then solve for that variable, and use back-substitution to find the values of the other variable.

For example, using the first and second equations, you can solve for x in terms of y as follows:

x = 6 - y (from the second equation)

y = 10 - 5x (from the first equation)

Substituting y = 10 - 5x into the third equation, you get:

x + 4(10 - 5x) = 12

Simplifying this equation, you get:

-19x + 40 = 0

Solving for x, you get:

x = 40/19

Using x = 40/19 and the equation x + y = 6, you can solve for y as:

y = 6 - x = 6 - 40/19 = 94/19

Therefore, the minimum value of 3x + 2y subject to the given constraints is:

3(40/19) + 2(94/19) = 222/19

And the values of x and y that minimize this expression are:

x = 40/19 and y = 94/19.

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This is a linear programming problem with three constraints and two variables, where the objective is to minimize the expression 3x + 2y subject to the following constraints:

5x + y = 10

x + y = 6

x + 4y = 12

The first constraint represents a straight line in the x-y plane, the second constraint represents another straight line, and the third constraint represents yet another straight line. The feasible region is the region where all three constraints are satisfied simultaneously, which is the intersection of the three lines.

To solve this problem, you can use the method of substitution or elimination to solve for one variable in terms of the other in two of the equations, and then substitute this expression into the third equation to obtain a single equation in one variable. You can then solve for that variable, and use back-substitution to find the values of the other variable.

For example, using the first and second equations, you can solve for x in terms of y as follows:

x = 6 - y (from the second equation)

y = 10 - 5x (from the first equation)

Substituting y = 10 - 5x into the third equation, you get:

x + 4(10 - 5x) = 12

Simplifying this equation, you get:

-19x + 40 = 0

Solving for x, you get:

x = 40/19

Using x = 40/19 and the equation x + y = 6, you can solve for y as:

y = 6 - x = 6 - 40/19 = 94/19

Therefore, the minimum value of 3x + 2y subject to the given constraints is:

3(40/19) + 2(94/19) = 222/19

And the values of x and y that minimize this expression are:

x = 40/19 and y = 94/19.

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The distance for boat is,

=  43.2 miles

Given that;

Edward and Diana walked to the dock at 2 miles per hour, jumped into the boat, and motored to Dillion at 10 miles per hour

Now, For Walk DATA:

Rate = 2 mph ; time = x hrs.

Then, distance = 2x miles

For Boat DATA:

Rate = 10 mph ; time = 5 - x hrs

Then, distance = 10 (5 - x) miles

Hence, We can formulate;

distance + distance = 12 miles

2x + 10 (5 - x) = 20

2x + 50 - 10x = 20

30 = 8x

x = 3.6

Hence, Boat time ,

5 - x = 5 - 3.6 = 1.4 hr (boat time)

And, The value of Boat distance = 12x = 12 x 3.6 = 43.2 miles

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To find the margin of error, we can use the formula: E = z√((p(1-p))/n)

where z is the z-score for a 99% confidence level, p is the sample proportion, and n is the sample size.

From the table of standard normal distribution, the z-score for a 99% confidence level is 2.576.

Plugging in the values, we get:

E = 2.576√((0.696(1-0.696))/664) ≈ 0.0385

So the margin of error is 0.0385.

To find the confidence interval, we can use the formula:

p ± E

where p is the sample proportion and E is the margin of error.

Plugging in the values, we get:

0.696 ± 0.0385

So the 99% confidence interval for the true proportion of all Americans that say "the future of the nation is a significant source of stress for me" is (0.6575, 0.7345). In interval notation, this can be written as [0.6575, 0.7345].

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Step-by-step explanation:

If Sarah buys the oil and oil filter separately, she would spend:

Cost of oil = $37.54

Cost of oil filter = $9.47

Total cost = $37.54 + $9.47 = $47.01

Therefore, Sarah can save:

Coupon price - Total cost = $49.95 - $47.01 = $2.94

So, Sarah can save $2.94 by doing the oil change herself instead of using the coupon.

The other angle that is congruent to  ∠DFA is: ∠BFC

Congruent angles are defined as two or more angles that are said to be identical to each other. This means that the measure of these angles is equal to each other. These type of angles do not make any difference in the congruence of angles, which tells us that they can be acute, obtuse, exterior, or interior angles.

Now, we want to find the angle that is congruent to ∠DFA.

By inspection, we can see that ∠BFC is an opposite angle to ∠DFA.

We know that Opposite angles are the two angles opposite each other when two lines cross. They can also be called vertical angles due to sharing a vertex, which is the point where the two lines connect. Opposite angles always have the same measurement, making them congruent.

Thus, ∠BFC is congruent to  ∠DFA.

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Answer:

arc PTR = 277°

Step-by-step explanation:

PS is the diameter of the circle , then arc PS = 180°

arc PTR = PS + SR = 180° + 97° = 277°

Answer:

arc PTR = 277°

Step-by-step explanation:

PS is the diameter of the circle , then arc PS = 180°

arc PTR = PS + SR = 180° + 97° = 277°

The end behavior of f(x) is described as follows:

The end behavior of a function is given by the limit of the function is the input x goes to either negative infinity or positive infinity.

The function for this problem is given as follows:

f(x) = 4(5/7)^x.

It is an exponential function with base with absolute value less than 1, hence the end behavior is given as follows:

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Answer:

A) 5x+32=67

Rebecca is 7, Mary is 15, and Jill is 45

Step-by-step explanation:

Rebecca is x years old.

If Mary is 8 years older than Rebecca, Mary's age is 8 more than x.

We can write Mary's age as:

x+8

Jill is three times older than Mary.

This means that Jill's age is equal to three times x+8.

We can write Jill's age as:

3(x+8)

Use the distributive property.

3(x+8)=

3x+24

So, Jill's age (in terms of x) is 3x+24.

The sum of their ages is 67, so if we add all of their ages, we will get 67.

x+(x+8)+(3x+24)=67=

5x+32=67

Not sure if you want this solved, but here it is:

5x+32=67=

5x=35=

x=7

Let's find Mary's age.

x+8=

7+8=

15.

Now, let's find Jill's age.

3x+24=

3(7)+24=

21+24=

45.

So, Rebecca is 7, Mary is 15, and Jill is 45.

The two values which are located at the same point on a number line as required to be determined are; 4/1 and 4.

It follows from the task content that the answer choice which represents two values located at the same point on the number line be determined.

On this note, such two values must be equivalent.

Hence, by observation; the answer choice which represents two equivalent values is; 4/1 and 4 and they represent values located at the same point on the number line.

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The equivalent speed in still water for the boat is 30.26 km/h.

The equivalent speed of the boat in still water is calculated as follows;

The boat needs to travel North at 30 km/h,

The speed of the wave = 4 km/h

The equivalent speed of the boat in still water is calculated by applying Pythagoras theorem;

v² = (4 km/h)² + (30 km/h)²

v = √ [(4 km/h)² + (30 km/h)²]

v = 30.26 km/h

Thus, the equivalent speed of the boat is calculated by applying vector addition principle.

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Answer:18

Step-by-step explanation:18

The balance at the end of the month was $7046.93.

To determine the balance at the end of the month, we need to:

Data

Starting balance = $9145.87

Deposits = $2783.71

Interest earned = $11.15

Checks written = $4871.90

Maintenance fee = $12

Balance at the end of the month will be:

= Starting balance + Deposits + Interest earned - Checks written - Maintenance fee

= $9145.87 + $2783.71 + $11.15 - $4871.90 - $12

= $7046.93.

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The minimum variance unbiased estimator of the parameter,λ of a poisson population is λ = Σxi/n.

Variance is a measure of how spread out a set of data is. In statistics, it is the average of the squared differences from the mean of a set of values. It is calculated by taking the sum of the squared deviations from the mean and dividing it by the number of data points.

Let X1, X2, ..., Xn be a random sample from a Poisson distribution with mean λ. The likelihood function is given by:

[tex]L(\lambda | x) = \pi[e^{(-\lambda)} \lambda^{(xi)} / xi!][/tex]

Taking the natural logarithm and differentiating with respect to λ:

ln L(λ | x) = -nλ + ln(λ) Σxi - Σln(xi!)

d/dλ ln L(λ | x) = -n + Σxi/λ

Setting the derivative equal to zero and solving for λ, we get:

λ = Σxi/n

This is the sample mean of the Poisson distribution, which is an unbiased estimator of λ. Moreover, using the Cramer-Rao lower bound, we can show that it is also the minimum variance unbiased estimator of λ.

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The expression for the area of the compound shape in cm² is 2x^2 + 11x - 6.

To find the expression for the area of the compound shape, we need to first calculate the individual areas of Shape A and Shape B, and then add them together.

The area of Shape A is given by multiplying its length and width:

Area of Shape A = (x + 3) * (x + 2)

The area of Shape B is given by multiplying its length and width:

Area of Shape B = (x + 6) * (x - 2)

Now, we can add the two areas together to get the expression for the area of the compound shape:

Area of compound shape = Area of Shape A + Area of Shape B

= (x + 3) * (x + 2) + (x + 6) * (x - 2)

Expanding the above expression, we get:

= x^2 + 2x + 3x + 6 + x^2 + 6x - 12

= 2x^2 + 11x - 6

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Some poetic elements found in the poem are:

Poetic elements are described as  the devices used that characterize a piece of writing as a poem and  are integral to categorise a piece of writing as poetry, such as poetic meter and rhyme scheme.

In the poem, the author uses Imagery which is described as use of sensory details to create vivid mental images in the reader's mind.

The author made use of metaphor as a  comparison between two things that are not alike, in order to create an image or deepen understanding.

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The height of the building when the surveyor is standing that far is D.)41ft​

The tangent function would be best to use to find the height because we would be able to use the adjacent and and opposite.

Assuming that 5 feet is the height and the angle of elevation is 41. 7 degrees, and the distance of 40 feet, we have :

tan ( A ) = (h - x) / D

tan ( 41. 7° ) = ( h - 5 ) / 40

h - 5 = 40 x tan ( 41. 7 ° )

h - 5 = 40 x 0.8895

h = 35.58 + 5

= 40.58

= 41 feet

The height of the building is 41 feet.

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Billie made the error in the second step of the equation

Billie made an error in Step 2. She added 9 to one sides of the equation, but she should have added 9 to the left side only. The correct steps are as follows:

Step 1: x^2 + 6x = 16

Step 2: x^2 + 6x + 9 = 16 + 9

Step 3: (x + 3)^2 = 25

Step 4: x + 3 = ±√25

Step 5: x = -3 + 5, x = -3 - 5

Step 6: x = 2, x = -8

So, the correct solutions are x = 2 and x = -8.

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Okay, let's break this down step-by-step:

* Circle O has chords AB and CD that intersect at E

* AE = 3 inches

* BE = 8 inches

* CE is 2 inches longer than DE

So we know:

AE = 3 inches

BE = 8 inches

CE = DE + 2 inches

To find DE, we can use the Pythagorean theorem for any right triangle:

a^2 + b^2 = c^2

In this case:

3^2 + 8^2 = c^2

9 + 64 = 73

c = 8 inches

So the hypotenuse AE forms a right triangle with leg BE of length 8 inches.

Now we have the length of one leg (BE = 8 inches) and the hypotenuse (AE = 8 inches).

We can use the relation between leg, hypotenuse and sine to calculate the other leg (DE):

sin(A) = DE / 8

DE = 8 * sin(A)

Without knowing the angle A, we can make an estimate:

sin(A) ≈ A (for small A)

So DE ≈ 8A inches

Now we know:

CE = DE + 2 inches

And DE ≈ 8A inches

So: 8A + 2 = DE

=> DE = 10A

And since A is small, we can say: DE ≈ 10 * A inches

To summary, if AE = 3 inches and BE = 8 inches,

then DE ≈ 10 * A inches

DE is approximately 10 times some small angle A.

Does this make sense? Let me know if you have any other questions!

Answer:

In a 30°-60°-90° right triangle, the length of the longer leg is √3 times the length of the shorter leg.

A = (1/2)Pa

= (1/2)(2)(8/√3)(6)(8)

= (384√3)/3 = 128√3 = 221.7 units^2

A rational number between 8/10 and 1/8 is 37/80.

We know that a rational number between two rational numbers can be given by finding the average of the two given numbers:

The numbers are 8/10 and 1/8.

Let's simplify the fractions first:

8/10 = 4/5 (dividing both numerator and denominator by 2)

1/8 = 1/8 (already in simplest form)

Average = [tex](\frac{4}{5} + \frac{1}{8})/2[/tex]

              = [tex](\frac{(4*8) + (5*1)}{40} )/2[/tex]

             = [tex](\frac{37}{40}) /2[/tex]

             = [tex]\frac{37}{80}[/tex]

So, the rational number halfway between 8/10 and 1/8 is 37/80.

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Answer:

25

Step-by-step explanation:

range = largest number - smallest number

38-13=25