please help w the question in the pic, thanksss!

Answer: x=2

Step-by-step explanation:

15x-10=10 + 6+ 2x

15x-2x=20+6

13x=26

X=2

Answer:

x = 2

Step-by-step explanation:

2.5(6x - 4) = 10 + 4(1.5 + 0.5x)

Distribute the 2.5

15x - 10 = 10 + 4(1.5 + 0.5x)

Distribute the 4

15x - 10 = 10 + 6 + 2x

Combine like terms

15x - 10 = 16 + 2x

Add 10 to both sides

15x = 26 + 2x

Subtract 2x from both sides

13x = 26

Divide both sides by 13x

x = 2

Answer:

60 cm^2

Step-by-step explanation:

let are of big figure be x .

area of small figure / area of big figure = 15 / 18

50/x = 15/18

do cross multiplication

x*15 = 18*50

x = 900/15

x = 60 cm^2

Answer:

The mean increases by 2.

Step-by-step explanation:

Answer:

4/12

Step-by-step explanation:

add up all the marbles, and take how many blue marbels there are and put both numbers in fraction form

Answer:

Fluffy is longer than Muffy

Step-by-step explanation:

There are 1000 millimeters in a meter

Fluffy = 2000 millimeters

Muffy = 900 millimeters

Fluffy is longer than Muffy

2000 > 900

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Fluffy is longer than Muffy

There are 1000 millimeters in a meter

There are 1000 millimeters in a meterFluffy = 2000 millimeters

There are 1000 millimeters in a meterFluffy = 2000 millimetersMuffy = 900 millimeters

There are 1000 millimeters in a meterFluffy = 2000 millimetersMuffy = 900 millimetersFluffy is longer than Muffy

There are 1000 millimeters in a meterFluffy = 2000 millimetersMuffy = 900 millimetersFluffy is longer than Muffy2000 > 900

Given:

Consider the expression is:

[tex]\sqrt{-9}[/tex]

To find:

The equivalent expression.

Solution:

We have,

[tex]\sqrt{-9}[/tex]

It can be written as:

[tex]\sqrt{-9}=\sqrt{-1\times 9}[/tex]

[tex]\sqrt{-9}=\sqrt{-1}\times \sqrt{9}[/tex]

[tex]\sqrt{-9}=i\times 3[/tex]                 [tex][\because \sqrt{-1}=i][/tex]

[tex]\sqrt{-9}=3i[/tex]

The expression [tex]3i[/tex] is equivalent to the given expression.

Therefore, the correct option is A.

Given:

The height, in feet, of each rocket at t seconds after launch is given by the polynomial equations:

Rocket A: [tex]-15t^2+100t[/tex]

Rocket B: [tex]-14t^2+85t+3[/tex]

To find:

The equation to find the "difference" in height of Rocket A and Rocket B.

Solution:

The difference in height of Rocket A and Rocket B is:

Difference = Height of Rocket A - Height of Rocket B

[tex]\text{Difference}=(-15t^2+100t)-(-14t^2+85t+3)[/tex]

[tex]\text{Difference}=-15t^2+100t+14t^2-85t-3[/tex]

[tex]\text{Difference}=(-15t^2+14t^2)+(100t-85t)-3[/tex]

[tex]\text{Difference}=-t^2+15t-3[/tex]

Therefore, the difference in height of Rocket A and Rocket B is [tex]-t^2+15t-3[/tex].

Answer:

Step-by-step explanation:

-6 and up going left

Answer:

B

Step-by-step explanation:

mulitiply by 2

Answer:

63

Step-by-step explanation:

mark me brainliest plzzz

[tex]\sf\purple{The\:value\:of\:x\:is\:63.}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] \frac{3}{8} = \frac{x}{168} \\ \\ ✒ \: \frac{3 \times 168}{8} = x \\ \\ ✒ \: \frac{504}{8} = x \\ \\✒ \: 63 = x[/tex]

Therefore, the value of [tex]x[/tex] is 63.

[tex]{ \bf{ \underbrace{To\:verify:}}}[/tex]

[tex] \frac{3}{8} = \frac{63}{168}\\ \\✒ \: 0.375 = 0.375 \\ \\✒ \: L.H.S.=R. H. S [/tex]

Hence verified. ✔

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the prisms and the riddle are not given.

The riddle aspect of the question cannot be attempted, else there are clues.

So, I will give a general rule on how to calculate the surface areas of prisms.

For rectangular prisms, the surface area is:

[tex]Area = 2*(Length * Width + Length * Height + Width * Height)[/tex]

For the attached rectangular prism, the area is:

[tex]Area = 2 *(10*11 + 11 * 15 + 10 * 15)[/tex]

[tex]Area = 2 *(425)[/tex]

[tex]Area = 850m^2[/tex]

For triangular prisms, the surface area is:

[tex]Area = L + 2 * B[/tex]

Where

[tex]L \to[/tex] Lateral Area

[tex]B \to[/tex] Base Area

The area of the attached triangular prism is:

[tex]L = (a + b + c) * h[/tex]

[tex]L = (6 + 8 + 10) * 12[/tex]

[tex]L = 24 * 12[/tex]

[tex]L = 288[/tex]

[tex]B = \frac{1}{2} * bh[/tex]

[tex]B = \frac{1}{2} * 6 * 8[/tex]

[tex]B = 24[/tex]

So, we have:

[tex]Area = L + 2 * B[/tex]

[tex]Area = 288 + 2 * 24[/tex]

[tex]Area = 288 + 48[/tex]

[tex]Area = 336ft^2[/tex]

Answer:

Step-by-step explanation:

3 = 1(1 + x)^4

let q = 1 + x

3 = q^4

ln(3)  = 4  ln(q)

ln(3)/4 = ln(q)

.274 = ln(q)

q = e^.274 = 1.316

x = .316

Future amount = 48(1+.316)^4

Future amount = 143.96

Answer:

5.74

Step-by-step explanation:

The value of AC in the given right triangle is 5.74 units.

Pythagorean theorem, the well-known geometric theorem that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle) - a² + b² = c².

Given that, the right triangle ABC, AB = 4 and BC = 7.

According to Pythagoras theorem,

AC² = AB²+BC²

AC² = 7²+4²

AC = √33 = 5.74

Hence, The value of AC in the given right triangle is 5.74 units.

For more references on Pythagoras theorem, click;

https://brainly.com/question/343682

#SPJ2

Answer:

261.5 ft^2

Step-by-step explanation:

Surface Area of a rectangular prism = Length x Width x Height

= 8.5ft x 6ft x 5.5ft

= 261.5 ft

Answer:

B.

Step-by-step explanation:

28 is not a multiple of 13.

9514 1404 393

Answer:

Step-by-step explanation:

A tangent makes a right angle with the radius to the point of tangency. Hence ∠PAO is 90°. The ratio of the short side (OA) of the right triangle OAP to the hypotenuse (OP) is 5 : 10 = 1 : 2. These are the ratios found in a 30°-60°-90° triangle, so we know that ∠APO = 30°.

OP is a bisector of angle APB, so that angle is 60°. Angle AOB is the supplement to angle APB, so ∠AOB = 120°.

__

As we said above, triangle OAP is a 30°-60°-90° triangle, so its side lengths have the ratios 1 : √3 : 2. This means PA = PB = 5√3 ≈ 8.7.

Hope this helps please mark me brainliest

Answer:

x = -3

Answer:

The triangles are congruent  by HL

Step-by-step explanation:

The triangles are right triangles so we can use either HL ( hypotenuse leg) or LL (leg leg) if we know that two sides are congruent

We know one leg is equal to the other by the red line.  The hypotenuse is the same since it is the same line.

The triangles are congruent  by HL

Answer:

1260

hope this helps

have a good day :)

Step-by-step explanation:

Step-by-step explanation:

2 x 2 x 3 x 3 x 5 x 13

= 2340

................

Answer:

the equation as intercept form is

y = 3x + 5

Answer:

x=-20

Step-by-step explanation:

x=-10•2

• means multipled

Answer:

B

Step-by-step explanation:

firstly as we know that,

nth term of an A.P. is n= a1 + (n-1)d

here d is -3 so, A1 = 1-(-3) = 4

so, 5th term = 4 + ( 5-1)( -3) = 4 + 4(-3) = 4 - 12 = -8

so the answer is -8 which is option B.

Hope this answer helps. I got a little help from my tutors on Gauthmath app which is really good. you can check it out too. :)

Answer: 68,819 rabbits

Step-by-step explanation:

First find the annual rate of growth that took the number of rabbits from 9,400 in 1998 to 32,000 in 2006.

Use the future value formula:

Number of years = 2006 - 1998 = 8 years

Future value formula:

Future value = Current value * ( 1 + rate) ^ number of years

Assume 2006 is the future and 1998 is present.

32,000 = 9,400 * (1 + r) ⁸

32,000 / 9,400 = (1 + r)⁸

(1 + r)⁸ = 3.404255319

1 + r = ⁸√3.404255319

r = ⁸√3.404255319 - 1

r = 16.55%

Use that rate to find the number of rabbits in 2011:

= Current value * (1 + rate) ^ number of years

Number of years = 2011 - 2006 = 5 years

= 32,000 * ( 1 + 16.55%)⁵

= 68,819 rabbits

Answer:

k = -2

Step-by-step explanation:

f(x) = (x − h)² + k

(h, k) is the (x, y) coordinate of the vertex

For a vertex of (4, -2)

h = 4

k = -2

Answer:

Let's define East as the positive x-axis and North as the positive y-axis.

If Michelle's initial position is (0, 0)m

We know that Nathasha is 50m due East of Michelle.

Then the position of Natasha is (50, 0)m

Now we know that Natasha walks 20m due North, then the new position of her's is:

(50, 0 + 20)m = (50, 20)m

While Michelle walks 10m due South (South would be the negative y-axis, then we subtract 10 meters)

Michelle's new position will be:

(0, 0 - 10)m = (0, -10)m

Now we want to know the distance and bearing of Michelle from Natasha.

First, remember that the distance between two points (a, b) and (c, d) is given by:

Distance = √( (a - c)^2 + (b - d)^2)

Then the distance between Michelle and Natasha is:

Distance = √( (50m - 0m)^2 + (20m - (-10m))^2)

Distance = √( (50m)^2 + (30m)^2) = 58.31m

Now to find the bearing you can see the image below:

Point B is Michelle's position and point A is Natasha's position.

To find the bearing, we can make a triangle rectangle as the one shown in the image:

Also remember the relation:

Tan(a) = (opposite cathetus)/(adjacent cathetus).

Where the opposite cathetus is the difference between the x-values of each position, this is:

opposite cathetus = 50m - 0m = 50m

And the adjacent cathetus is the difference between the y-values, this is:

adjacent cathetus = 20m - (-10m) = 30m

Then:

Tan(a) = 50m/30m

Tan(a) = 5/3

Now if we apply the inverse Tan function to both sides, Atan(x) we get:

Atan(Tan(a)) = Atan(5/3)

a = Atan(5/3) = 59°

So the bearing is of 59°.

Answer:

[tex] y = 6 \sqrt{3} \: units[/tex]

Step-by-step explanation:

In order to find the value of y, first we need to find the length of the perpendicular dropped from one of the vertices of the triangle to its opposite side.

By geometric mean theorem:

Length of the perpendicular

[tex] =\sqrt{9\times 3}[/tex]

[tex] =\sqrt{27}\: units [/tex]

Next, by Pythagoras theorem:

[tex] {y}^{2} = {9}^{2} + {( \sqrt{27} )}^{2} \\ \\ {y}^{2} = 81 + 27 \\ \\ {y}^{2} = 108 \\ \\ y = \sqrt{108} \\ \\ y = \sqrt{36 \times 3} \\ \\ y = \sqrt{ {6}^{2} \times 3} \\ \\ y = 6 \sqrt{3} \: units[/tex]