please help me with this question

Answer:

3 x 10^3

Step-by-step explanation:

1.485 / 4.95 = 0.3

10^6 : 10^2 = 10^(6-2) = 10^4

0.3 x 10^4

3 x 10^3

The quotient of 1.485 x 10^6 and 4.95 x 10^2 expressed in science notation is 3 x 10^3

The number b shows the order, which is the most important figure for which scientific notation is used. It tells us how much order large or small a value is in powers of 10.

Its value in terms of power of 10 is known, which helps in easy comparison of quantities differing by a large value.

WE need to find the quotient of 1.485 x 10^6 and 4.95 x 10^2 expressed in science notation.

So we have;

1.485 / 4.95 = 0.3

Therefore,

10^6 : 10^2

= 10^(6-2)

= 10^4

Hence, the scientific notation written as;

0.3 x 10^4

= 3 x 10^3

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Answer:

-18

Step-by-step explanation:

You can basically just drop the plus sign and remove the parenthesis because the plus sign doesn't alter negatives.

-6+(-12)

-6-12= -18

Answer:-18

Step-by-step explanation:

Answer:

Area of length Vb = 25 square units

Area of segment Vb  = 26 square units

Step-by-step explanation:

Area of length Vb = theta/360 * 2πr  

Area of length Vb = 120/360 * 2*3.14 * 12  

Area of length Vb = 1/3 * 75.36  

Area of length Vb = 25 square units  

Ares of length Vb is 25.1 sq. units

Area of shaded portion = Area of sector VUB - Area of triangle VUB

Area of sector VUB = theta/360 * πr²

Area of sector VUB = 120/360 * 3.14*144

Area of sector VUB = 1/3 * 452.16

Area of sector VUB =150.72

Area of triangle VUB  = r²sintheta

Area of sector VUB = = 12²sin 120

Area of sector VUB = = 144(0.8660)

Area of sector VUB = 124.71

Area of the shaded segment = 150.72 - 124.71

Area of the shaded segment = 26.01

Area of the shaded segment = 26 sq. unitsAnswer:

Area of length Vb = 25 square units

Area of segment Vb  = 26 square units

Step-by-step explanation:

Area of length Vb = theta/360 * 2πr

Area of length Vb = 120/360 * 2*3.14 * 12

Area of length Vb = 1/3 * 75.36

Area of length Vb = 25 square units

Ares of length Vb is 25.1 sq. units

Area of shaded portion = Area of sector VUB - Area of triangle VUB

Area of sector VUB = theta/360 * πr²

Area of sector VUB = 120/360 * 3.14*144

Area of sector VUB = 1/3 * 452.16

Area of sector VUB =150.72

Area of triangle VUB  = r²sintheta

Area of sector VUB = = 12²sin 120

Area of sector VUB = = 144(0.8660)

Area of sector VUB = 124.71

Area of the shaded segment = 150.72 - 124.71

Area of the shaded segment = 26.01

Area of the shaded segment = 26 sq. units

Answer:

[tex]\sqrt{a} + \frac{2\sqrt{ya} }{a} - 2\sqrt{y}[/tex]

Step-by-step explanation:

Simplify each term.

The rationalized and simplified form of the expression (√a + 2√y) / (√a - 2√y) is (a + 4√ay + 4y) / (a - 4y).

To rationalize the denominator and simplify the expression (√a + 2√y) / (√a - 2√y), we can use a technique called rationalizing the denominator.

First, we multiply both the numerator and denominator by the conjugate of the denominator, which is (√a + 2√y). This is done to eliminate the square root in the denominator.

(√a + 2√y) / (√a - 2√y) * (√a + 2√y) / (√a + 2√y)

Expanding the numerator and denominator:

(√a * √a) + (√a * 2√y) + (2√y * √a) + (2√y * 2√y) / ((√a * √a) - (√a * 2√y) + (2√y * √a) - (2√y * 2√y))

Simplifying:

a + 2√ay + 2√ay + 4y / (a - 2√ay + 2√ay - 4y)

Combining like terms:

a + 4√ay + 4y / (a - 4y)

Therefore, the rationalized and simplified form of the expression (√a + 2√y) / (√a - 2√y) is (a + 4√ay + 4y) / (a - 4y).

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Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]\huge\boxed{2\sqrt{3}}[/tex]

»»————-　★　————-««  

Here’s why:  

[tex]\boxed{\text{Simplifying the square root of 12}}\\\\\rightarrow\sqrt{12}\\\\\text{4 can be factored out of 12.}\\\\\rightarrow\sqrt{4(3)}\\\\\text{Two '2's can be factored out of 4.}\\\\\rightarrow\sqrt{2*2*3}\\\\\rightarrow\sqrt{2^2(3)}\\\\\text{Pulling out the terms from under the radical...}\\\\\rightarrow\boxed{2\sqrt{3}}[/tex]

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

y>-2x-3

Step-by-step explanation:

I think, not sure.

Answer:

Step-by-step explanation:

3) (21²-6²)½ = 20.1 cm

4) (10²+7²)½ =12.2 cm

5) (6.5²-2.7²)½ = 5.9 cm

Answer:

I'm not sure but if you want the answer download Socratic it will definitely help you find the answer.

Answer:

X is equal to 4

Answer: D!!

Step-by-step explanation:

You need a common denominator (bottom number) to subtract!

Answer:

d

Step-by-step explanation:

I think it is D. Hopfully.

Step-by-step explanation:

x + 7 = 92

x = 92 - 7

x = 85

The value of x is 85

Answer:

J or the last one

Step-by-step explanation:

Other two wouldn't work since -37 is the least and 37% is 0.37 which is less than 0.72

whats the rest of the question?

Step-by-step explanation:

answer of number 5

length=7cm

breadth=9 cm

height=6 cm

volume=?

we know

v =l×b×h

=7×9×6

=378

so, the volume is 378 cm

Answer:

cone, radius is 3^2 x pi x 7/3 = 65.98

Step-by-step explanation:

Step-by-step explanation:

a) unsuitable - the precision should have been about 0.030 kg (about an ounce)

b) unsuitable - the stopwatch should have a precision of 0.001 s

c) just about right, although I wouldn't mind it if its precision is of 0.05 mm

d) unsuitable - color matching requires much finer control so I would go with 1/8 cup precision.

Answer:

Range.

Step-by-step explanation:

In Computer programming, a variable can be defined as a placeholder or container for holding a piece of information that can be modified or edited.

Basically, variable stores information which is passed from the location of the method call directly to the method that is called by the program.

For example, they can serve as a model for a function; when used as an input, such as for passing a value to a function and when used as an output, such as for retrieving a value from the same function. Therefore, when you create variables in a function, you can can set the values for their parameters.

Furthermore, the set of all values that a function will return as outputs is called the range of the function.

This ultimately implies that, the range of a function is simply a complete set of possible values that are generated from a dependent variable after a domain has been substituted. Thus, a range is the resulting values from a data set when all the possible input values have been substituted.

Answer:

[tex]sin(A+B) = \frac{1431}{1769}[/tex]

Step-by-step explanation:

sin(A+B) = sinA cosB + cosA sinB ------(1)

[tex]given : cos A = \frac{20}{29}, \ sinB = \frac{60}{61}[/tex]

First we will find sinA and cosB

[tex]We \ know \ sin^2 A + cos^2A = 1\\\\sin^2 A = 1 - cos^2A = 1 - (\frac{20}{29})^{2} = \frac{841-440}{841} = \frac{441}{841}\\\\sinA =\frac{21}{29}[/tex]

[tex]sin^2B +cos^2B = 1\\\\cos^2B = 1 - sin^2B = 1 - (\frac{60}{61})^2 = \frac{3721-3600}{3721} = \frac{121}{3721}\\\\cosB = \frac{11}{61}[/tex]

Substitute all values in (1)

[tex]sin(A+B) =sinAcosB + cosAsinB[/tex]

               [tex]=(\frac{21}{29} \times \frac{11}{61} )+ (\frac{20}{29}\times \frac{60}{61})\\\\=\frac{231}{1769} + \frac{1200}{1769}\\\\= \frac{1431}{1769}[/tex]

Answer:

$509.97 is Rosa's regular pay

Answer:

A

Step-by-step explanation:

Given

sinθ = [tex]\frac{4}{5}[/tex] = [tex]\frac{opposite}{hypotenuse}[/tex]

This is a 3- 4- 5 triangle

with opposite = 4, adjacent = 3 and hypotenuse = 5

Since θ is in second quadrant then cosθ < 0

cosθ = [tex]\frac{adjacent}{hypotenuse}[/tex] = - [tex]\frac{3}{5}[/tex] → A

Answer:

Solution given:

A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm

and

base[b]PR=60cm.

perpendicular [P]= QR

by using Pythagoras law

h²=p²+b²

80²=QR²+60²

QR²=80²-60²

QR=[tex]\sqrt{2800}[/tex]

QR=20[tex]\sqrt{7}[/tex]=52.9=53cm

QR=53cm.

Answer:21

Step-by-step explanation:

Answer:

Im pretty sure its 21

Step-by-step explanation:

21

Im sorry if its wrong

Answer:

No

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

10+10=20

20+10=30

30+0=30

Answer:

x = -3

Step-by-step explanation:

Step-by-step explanation:

Rewrite the expression using only positive exponents. Then, evaluate the expression. 3^{-2}

Answer:

[tex]\huge\boxed{\sf Probability = \frac{3}{8} }[/tex]

Step-by-step explanation:

[tex]\displaystyle Probability = \frac{Number \ of \ codes \ with \ 2 \ 0s}{Total \ number \ of \ codes}[/tex]

According to the fundamental principle of counting, to find the total number of codes, we need to multiply the number of options we have for each digits by the number of digits. Hence, we have two options for each digit ( 1 and 0 ) and we have 4 digits. So,

= 2 * 2 * 2 * 2

= 16 possible codes (Total)

Now, Codes with two zeroes:

= 0101,0011,1100,1010,1001,0110 (Maximum number of codes for 2 0s)

Hence, The probability:

Probability = 6 / 16

Probability = 3 / 8

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

12%

Step-by-step explanation:

As per the provided information in the given question, we have :

We are asked to calculate,

As we know that,

[tex] \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{Price \; increase}{Original \; price} \times 100 \Bigg ) \; \%}} \\ [/tex]

→ Price increase = New price - Original price

→ Price increase = Rs. ( 53.76 - 48 )

→ Price increase = Rs. 5.76

Substituting values,

[tex] \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{5.76}{48} \times 100 \Bigg ) \; \%}} \\ [/tex]

[tex] \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{576}{4800} \times 100 \Bigg ) \; \%}} \\ [/tex]

[tex] \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{57600}{4800} \Bigg ) \; \%}} \\ [/tex]

[tex] \\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{576}{48} \Bigg ) \; \%}} \\ [/tex]

[tex] \\ \longrightarrow \bf{\quad\underline { \% \; increase = 12\; \%}} \\ [/tex]

Therefore, percentage increase is 12 %.

Answer:

48

Step-by-step explanation:

[tex]a = 12, \ b = 6, \ c = 3\\\\b^2 - c^2 + (a+ b+c) = 6^2 - 3^2 + (12 +6+3) = 36-9+21 = 48[/tex]

Answer:

2-12+(++)

b^{2}-1c^{2}+(a+b+c)

b2−1c2+(a+b+c)

Simplify: 1

Eliminate redundant parentheses

2−12+(++)

b^{2}-1c^{2}+(a+b+c)

b2−1c2+(a+b+c)

2−12+++

b^{2}-1c^{2}+a+b+c

b2−1c2+a+b+c

Solution: 2−12+++

b^{2}-1c^{2}+a+b+c

b2−1c2+a+b+c

Answer:

44

Step-by-step explanation:

the steps are in the pic above