please help me. ill give you brainliest if you help me (please only answer if you have the right one)

Answer:

Its A

Explanation:

Energy Production in the Mitochondria because of the lack of less oxygen you would want to build up more ways to get more energy production going

Energy Production in the Mitochondria because of the lack of less oxygen one want to build up more ways to get more energy production.

Resultant force is a  summation of all force which act on a point or object. It will be either negative or positive i.e if we takes on direction is positive then other three direction will be taken in negative and then add all force so the outcome is called resultant force acting on a object. Mass is a physical quantity which is measured in kilograms . It will neither depend on any other quantity.

It is also doesn't depend on acceleration due to gravity like weight is depend on acceleration due to gravity but mass is not .Weight is varies from one place to another place but mass doesn't depend on place or position.

Therefore, Energy Production in the Mitochondria because of the lack of less oxygen one want to build up more ways to get more energy production.

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Answer:

The temperature and the pressure both increase as we go deeper within the Earth, toward its core.

Explanation:

Answer:I think it would start moving

Explanation:

Answer:

between a ball and a car

Explanation:

lol i am just as baffled as you luv

Answer:

[tex]u_2 = -5m/s[/tex]

Explanation:

Given

Before Collision

Toyota

[tex]mass = m_1 = 400kg[/tex]

[tex]iniital\ velocity = u_1 =10m/s[/tex]

Chevy

[tex]mass = m_2=800kg[/tex]

[tex]initial\ velocity = u_2 = ??[/tex]

After Collision

Both Toyota and Chevy

[tex]final\ velocity = v = 0m/s[/tex]

Required

Determine the initial velocity of Chevy

This question will be answered using the following law of conservation of momentum which states that:

[tex]m_1u_1 + m_2u_2 = (m_1 + m_2)v[/tex]

Substitute values for m1, m2, u1 and v

[tex]400 * 10 + 800 * u_2 = (400 + 800) * 0[/tex]

[tex]4000 + 800u_2 = (1200) * 0[/tex]

[tex]4000 + 800u_2 = 0[/tex]

Collect Like Terms

[tex]800u_2 = 0 - 4000[/tex]

[tex]800u_2 = -4000[/tex]

Divide through by 800

[tex]\frac{800u_2 = -4000}{800}[/tex]

[tex]u_2 = \frac{-4000}{800}[/tex]

[tex]u_2 = -5m/s[/tex]

The velocity of Chevy before collision was 5m/s in the opposite direction of Toyota

Answer:

im pretty sure its d

Explanation:

Answer: the first is positive and second is equal

Explanation:

Answer: 1. Positive

Explanation:

Because there is negative charges and positive charges

Answer:

6.19*10^-3 J

Explanation:

Just took the test. Kiss me

Answer:

x = 65.68 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}^{2}=v_{o}^{2}-2*a*x[/tex]

where:

Vf = final velocity = 0 (comes to stop)

Vo = initial velocity = 17 [m/s]

a = desaceleration = -2.2 [m/s²]

x = displacement [m]

Now replacing, we have:

[tex](0)^{2}=(17)^{2}-2*(2.2)*x\\4.4*x = 289\\x = 65.68 [m][/tex]

Answer:

75kg=165.346697lbs

Explanation: F A T

Answer:

11250 N

Explanation:

From the question given above, the following data were obtained:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

Friction and normal force are related by the following equation:

F = μR

Where:

F is the frictional force.

μ is the coefficient of static friction.

R is the normal force.

With the above formula, we can calculate the frictional force acting on the car as follow:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

F = μR

F = 0.75 × 15000

F = 11250 N

Therefore, the frictional force acting on the car is 11250 N

Answer:

Distance =400m

Time=20s

As we know that

[tex]{\boxed{\sf speed \dfrac {Distance {}_{(d)}}{Time {}_{(t)}}}}[/tex]

[tex]\LARGE\leadsto\sf speed=\dfrac {400}{20}[/tex]

[tex]\LARGE\leadsto\sf 20m/s[/tex]

Answer:

The length of the bond is determined by the number of bonded electrons (the bond order). The higher the bond order, the stronger the pull between the two atoms and the shorter the bond length. Generally, the length of the bond between two atoms is approximately the sum of the covalent radii of the two atoms.

Explanation:

Answer:

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

Kinetic energy is simply defined as energy possed by a body in motion. Mathematically, it is expressed as:

K.E = ½mv²

Where:

K.E is the kinetic energy

m is the mass of the object

v is the velocity of the object.

Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 1250 × 20²

K.E = 625 × 400

K.E = 250000 J

Therefore, the kinetic energy of the automobile is 250000 J

The three isotopes of carbon are C-12, C-13, and C-14. The carbon isotope 14C, which is the most commonly used radioactive cosmogenic isotope, can be used to date occurrences that took place within the last 60,000 years or so.

There are three types of carbon isotopes. Carbon-12 (12C) is by far the most prevalent isotope of carbon and it has six neutrons in relation to its six protons. Carbon-13 (13C), the second-heaviest carbon isotope, has seven neutrons. Since neither 12C nor 13C undergoes radioactive decay over time, they are both referred to as stable isotopes. The nucleus of the rare carbon-14 (14C) isotope has eight neutrons. This isotope, in contrast to 12C and 13C, is unstable or radioactive. A 14C atom will eventually transform into a stable byproduct.

The process of radiocarbon dating, also known as carbon dating or carbon-14 dating, uses the characteristics of radiocarbon (14C), a radioactive isotope of carbon, to estimate the age of an object made of organic material.

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Answer:

Q = 364.25 kcal

Explanation:

In this question, we will have to calculate the heat absorptions for different steps of temperature rise and phase change. And then we will ad them to calculate total heat absorbed.

1. RISE IN TEMPERATURE OF ICE:

First, the temperature of ice will be increased from - 10°C to 0 °C. Heat absorbed during this process will be given as:

Q₁ = mC₁ΔT₁

where,

Q₁ = Heat absorbed while increasing temperature of ice = ?

m = mass of ice = 0.5 kg

C₁ = specific heat of ice = 0.5 kcal/kg k

ΔT₁ = change in temperature of ice = 0 - (-10) = 10 k

Therefore,

Q₁ = (0.5 kg)(0.5 kcal/kg.k)(10)

Q₁ = 2.5 kcal

2. MELTING OF ICE:

Now, the melting of ice will occur at 0°C and the heat absorbed during this process will be:

Q₂ = m(Latent Heat of Fusion of Ice)

where,

Q₂ = heat Absorbed during melting of ice = ?

Therefore,

Q₂ = (0.5 kg)(79.7 kcal/kg)

Q₂ = 39.85 kcal

3. RISE IN TEMPERATURE OF WATER:

Now, the temperature of water will be increased from 0°C to 100 °C. Heat absorbed during this process will be given as:

Q₃ = mC₃ΔT₃

where,

Q₃ = Heat absorbed while increasing temperature of water = ?

m = mass of water = 0.5 kg

C₃ = specific heat of water = 1 kcal/kg k

ΔT₃ = change in temperature of ice = 100 - 0 = 100 k

Therefore,

Q₃ = (0.5 kg)(1 kcal/kg.k)(100 k)

Q₃ = 50 kcal

4. VAPORIZATION OF WATER:

Now, the vaporization of water will occur at 100°C and the heat absorbed during this process will be:

Q₄ = m(Latent Heat of Vaporization of Water)

where,

Q₄ = heat Absorbed during vaporization of water = ?

Therefore,

Q₄ = (0.5 kg)(539 kcal/kg)

Q₄ = 269.5 kcal

5. RISE IN TEMPERATURE OF STEAM:

Now, the temperature of steam will be increased from 100°C to 110 °C. Heat absorbed during this process will be given as:

Q₅ = mC₅ΔT₅

where,

Q₅ = Heat absorbed while increasing temperature of steam = ?

m = mass of steam = 0.5 kg

C₅ = specific heat of steam = 0.48 kcal/kg k

ΔT₅ = change in temperature of ice = 110 - 100 = 10 k

Therefore,

Q₅ = (0.5 kg)(0.48 kcal/kg.k)(10 k)

Q₅ = 2.4 kcal

Hence, the total heat absorbed to change 0.5 kg of ice at - 10°C into steam at 110°C will be:

Q = Q₁ + Q₂ + Q₃ + Q₄ + Q₅

Q = 2.5 kcal + 39.85 kcal + 50 kcal + 269.5 kcal + 2.4 kcal

Q = 364.25 kcal

Answer:

Both upward and downward forces are equal

Explanation:

When an object is acted upon by two vertical forces ; upward and downward, and the object moved at a constant speed, then the net force acting upon the object is zero(upward force + downward force = 0). This is because an object will only move at a constant velocity if the opposing forces cancels each other out. Since the falling object is already in motion, and maintaining a constant velocity, there is no for required to keep the body in motion and as such the Velocity at which the body is moving remains constant.

Answer:

When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero

Explanation:

plato

When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.

When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.

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Answer:

v = 8.56 [m/s]

Explanation:

The kinetic energy can be calculated by means of the following equation.

[tex]E_{k}=\frac{1}{2}*m*v^{2}[/tex]

where:

m = mass = 3 [kg]

v = velocity [m/s]

Ek = kinetic energy [J]

[tex]110 = \frac{1}{2} *3*(v^{2} )\\v^{2} = 220/3\\v=\sqrt{73.333}\\v=8.56[m/s][/tex]

Answer:

The period is 0.54 seconds

Explanation:

Period (T)

Is the time required for a rotating object to make one complete revolution around a circular path.

If it takes a time t to complete n revolutions, the period is:

[tex]\displaystyle T=\frac{t}{n}[/tex]

The rotating object spins n=24 times in t=13 seconds, thus its period is:

[tex]\displaystyle T=\frac{13}{24}[/tex]

T = 0.54 sec

The period is 0.54 seconds

The possible non-SI units to describe the rate of acceleration is the kilometers per hour squared. That is option 4.

Acceleration is the relationship that exists between velocity and time. It is defined as the change of velocity in both speed and direction with respect to time.

The formula for acceleration is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.

Velocity is defined as the rate of objects position with time.

The SI units of velocity = meter/seconds

Substitute for velocity in first equation:

a = meter/sec/sec

a = meter/sec²

But 1000meters = 1 Km

3600 secs = 1 hour

Therefore, the possible non-SI units to describe the rate of acceleration is the kilometers per hour squared.

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Answer:

distance = 27.95 [mi]

Explanation:

in order to solve this problem, we must use the appropriate conversion factor, i.e. a conversion factor that relates the kilometers to Miles.

[tex]1 [km] = 0.6214 [mill]\\45[km]*0.6212[\frac{mill}{1km} ]=27.95 [mill][/tex]

Answer:

Average speed = ( 2V + V1 + V2)/4

Explanation:

Given that a person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.

Since the distance is covered at equal intervals of time, and

Speed = distance/time

For the first half distance,

V = distance/t

Cross multiply

Distance = Vt

For the second half distance

(V1 + V2)/2 = distance/t

Distance = t(V1 + V2)/2

The average speed = total distance/ total time.

Average speed = [Vt + t( V1 + V2)/2] ÷ 2t

Average speed = (2Vt + V1t + V2t)/4t

Average speed = t( 2V + V1 + V2)/4t

Time t will cancel out

Average speed = ( 2V + V1 + V2)/4

Answer:

The answer is D.

Explanation:

You have to apply distance formula :

[tex]distance = speed \times time[/tex]

[tex]let \: d = 200,t = 4[/tex]

[tex]200 = s \times 4[/tex]

[tex]4s = 200[/tex]

[tex]s = 200 \div 4[/tex]

[tex]s = 50 \: m {s}^{ - 1} [/tex]

An eagle travels 200 meters in 4 seconds

Speed of the eagle

Distance=d=200m

Time=t=4s

[tex]{\boxed{\sf Speed ={\dfrac{Distance{}_{(d)}}{Time{}_{(t)}}}}}[/tex]

[tex]\qquad\quad {:}\longmapsto\sf Speed=\dfrac {200}{4}[/tex]

[tex]\qquad\quad {:}\longmapsto\sf Speed=50m/s [/tex]

[tex]\therefore{\underline{\boxed{\bf Speed\:of\:eagle=50m/s}}}[/tex]

Answer:

E =F.d =[1/2]mv^2

mad = [1/2]mv^2

d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0

So d = at^2/2

F = ma= 20a= 50 , a=5/2 and t=2

so d = [5/2][2^2]/2=5

Explanation:

Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.

Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

The given data in the problem is ;

W is the weight of the book sits on table = 5N

N is the normal force on the book

From the equilibrium equation ;

Weight -Normal force on the book  =0

Weight =Normal force on the book

The normal force on the book =5N

Hence the table exerts a force of 5 N on the book in order to be in stable condition.

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Answer:

Toothpaste

Because it is viscous

Answer: The mass would be 1000m3 and the volume would be 1000kg

Explanation:

Answer:

Avoid judging or criticizing your friend.

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