Please help me I would most definitely appreciate it!

Velocity can be represented in horizontal and vertical components

The horizontal component form of the velocity is 12.5 mph

The given parameters are:

Velocity = 25 mph

Angle = 60 degrees

The horizontal component form of the velocity is then calculated as:

[tex]v_x = 25 * \cos(60)[/tex]

Evaluate the product

[tex]v_x = 12.5[/tex]

Hence, the horizontal component form of the velocity is 12.5 mph

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Answer:

14 pints were drank

Step-by-step explanation:

22 pints - 8 pints =

Answer:

14 pints

Step-by-step explanation:

22 - 8 is 14 pints, now just convert the pints to cups, that would be 28 cups since 1 pint is 2 cups so 14 x 2 is 28, hope this helps

[tex] \frac{5}{6} [/tex]

Answer:

-84

Step-by-step explanation:

Let the number be x. Then we have,

[tex]\frac{x}{-7}[/tex] (the quotient of a number and -7)

[tex]\frac{x}{-7}-2[/tex] (decreased by 2)

[tex]\frac{x}{-7}-2=10[/tex] (is 10)

Now we can solve for x,:

[tex]\frac{x}{-7}-2=10[/tex]

[tex]\frac{x}{-7}=12[/tex]

[tex]x=-84[/tex]

So, the original number is -84

Answer:

-84

Step-by-step explanation:

[tex]\frac{n}{-7}[/tex] -2 = 10

add 2 to each side to get:

[tex]\frac{n}{-7}[/tex] = 12

multiply each side by -7 to get:

n = -84

Answer:

B. card I'' increased by 1.2986 = 13 more than card H's

Step-by-step explanation:

Answer:

the regions whose populations have 9 as the power include Africa and Asia.

Step-by-step explanation:

Answer:

africa and asia

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

1 + 2 = 3

1+ 3 = 4

2+ 3 = 5

there are only two ways of getting an odd number

Answer:

Aviva deposited $4,000

Step-by-step explanation:

Given:

Solving:

We'll create an equation to find the amount of money Aviva deposited.

D = 240(50/3)

D = the amount of money she has deposited.

50/3 represents 94% of D.
Since 240 is 6% of the deposit Aviva has deposited, multiplying 50/3 by 240 will equal 100% of D.

Solve:

4,000 = 240(50/3)

The amount of money Aviva deposited is $4,000.

*This is one method to solve.

Answer:

15 children

Step-by-step explanation:

30÷2

=15

therefore there is 15 adults and 15 children

Answer:

11700 m²

Step-by-step explanation:

Split the shape in two. One rectangle 150x30 and one triangle 180x80.

Find the areas of both and add them:

A = bh + 1/2bh

A = 150(30) + 1/2(180)(80)

A = 4500 + 7200

A = 11700

Answer:

Angle C prime

Step-by-step explanation:

First design and sketch it:

Make a rectangle with corners C D E and F. 90 degrees each. Now rotate it 45 degrees to the left. Angle D is diagonally from Angle C.

I hope this helps! :)

Answer:

-4

Step-by-step explanation:

(-12) - (-5) = -7

-7 + 3 = -4

Answer:

-4

Step-by-step explanation:

HOPE IT HELPED U

Answer:

4 and 5

Step-by-step explanation:

Answer:

x >= 1/5

Step-by-step explanation:

2 + 5x >= 3

5x >= 1

x >= 1/5

Answer:

option b

Step-by-step explanation:

413 is the same as a number decreased by 11 because when you say 11 is decreased by a number that means we are subtracting a number from 11 but when you say a number is decreased by 11 it means 11 is being subtracted from a certain number to give 413

I Hope this helps

Answer:

$180

Step-by-step explanation:

  Simple interest → ( principal * rate of interest * time in years ) ÷ 100

Here the principal is $3,000, rate of interest is 12%, years in years will be

(6/12) = 0.5 years

Using the formula:

Interest charge →  ( 3,000 * 12  * 0.5 ) ÷ 100

                          → ( 18000 ) ÷ 100

                          → $180

[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

As we observe the points, we can conclude that :

Translation along x axis is ~

[tex]\qquad \sf  \dashrightarrow \: 1 - ( - 3)[/tex]

[tex]\qquad \sf  \dashrightarrow \:1 + 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:4 \: \: units \: \: towards \: \: left[/tex]

Translation along y axis ~

[tex]\qquad \sf  \dashrightarrow \: - 8 - ( - 13)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 8 + 13[/tex]

[tex]\qquad \sf  \dashrightarrow \:5 \: \: units \: \: towards \: \: down[/tex]

So, same goes with translation of (-5 , 9)

[tex]\qquad \sf  \dashrightarrow \: x \: \:coordinate = - 5 - 4 = - 9[/tex]

[tex]\qquad \sf  \dashrightarrow \: y \: \:coordinate = 9 - 5 = 4[/tex]

So, the required coordinates of the image under same translation is ~

[tex]\qquad \sf  \dashrightarrow \:(-9, 4)[/tex]

Answer:

Please help look at the image I need help with number 4. I already did the line plot for number 3 and the data in on the chart. Thank you! :)

Answer:

Answer: ¾

Step-by-step explanation:

» From the trigonometric identities:

[tex]{ \tt{ \sin {}^{2} \theta + \cos {}^{2} \theta = 1 }}[/tex]

» Substitute to the formular:

[tex]{ \tt {( \frac{ \sqrt{7} }{4} )}^{2} + { \cos }^{2} \theta = 1 } \\ \\ { \tt{ \frac{7}{16} + { \cos}^{2} \theta = 1 }} \\ \\ { \tt{ \cos {}^{2} \theta = 1 - \frac{7}{16} }} \\ \\ { \tt{( \cos\theta) {}^{2} = \frac{9}{16} }} \\ \\ { \tt{ \sqrt{ {( \cos \theta}^{2}) } = \sqrt{( \frac{9}{16}) } }} \\ \\ { \tt{ \cos \theta = \frac{ \sqrt{9} }{ \sqrt{16} } }} \\ \\ { \boxed{ \tt{ \cos \theta = \frac{3}{4} }}}[/tex]

Answer:D

Step-by-step explanation:

D

Answer:

I think the answer is letter C.15

Correct me if im wrong

#Thank you

Ratio compares two quantities. The amount of water that will be needed to dissolve 14 grams of calcium carbonate is 1000 liters.

Given to us

The solubility of calcium carbonate is 14.

We know that to dissolve 14 milligrams of calcium carbonate we will need 1 liter of water. therefore, the ratio of water and calcium carbonate can be written as,

[tex]\rm \dfrac{calcium\ carbonate}{water} = \dfrac{14\ milligram}{1\ liter}[/tex]

We need to find the amount of water needed to dissolve 14 grams of water, therefore, we will convert grams to milligrams,

1 gram = 1000 milligram

14 gram = 14,000 milligram

Using the same ratio,

[tex]\rm \dfrac{14,000\ milligram}{water} = \dfrac{14\ milligram}{1\ liter}[/tex]

[tex]\rm {water} = \dfrac{14000\ milligram \times 1\ liter}{14\ milligram}[/tex]

water = 1000 liters

Hence, the amount of water that will be needed to dissolve 14 grams of calcium carbonate is 1000 liters.

Learn more about Ratio:

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Answer:

the zeroes are -2 and 8

Step-by-step explanation:

[tex]-x^2 +6x+16\\\implies -(x^2-6x-16)\\\implies -(x+2)(x-8)[/tex]

Therefore, the zeroes are -2 and 8

Answer:

   -2.5 m/s^2

Step-by-step explanation:

From 2 seconds to 8 seconds (the last 6 seconds), the speed decreased from 15 m/s to 0. The average acceleration is ...

  (-15 m/s)/(6 s) = -2.5 m/s^2

Answer:

8 • 20m - 29

Step-by-step explanation:

this might be right

Answer:

[tex]4p^2q-4q+8p[/tex]

Step-by-step explanation:

[tex](12p^2q+p-3pq^2)-(4q-7p+8p^2q-3pq^2)[/tex]

Apply rule [tex]-(-a)=a[/tex] and [tex]-(a)=-a[/tex]:

[tex]\implies 12p^2q+p-3pq^2-4q+7p-8p^2q+3pq^2[/tex]

Collect like terms:

[tex]\implies 12p^2q-8p^2q-3pq^2+3pq^2-4q+7p+p[/tex]

Combine like terms:

[tex]\implies 4p^2q-4q+8p[/tex]

Answer:

Step-by-step explanation:

Quotient meaning:

Equation:

Solve:

Multiples:

Answer:

Answer:

634

Step-by-step explanation:

The total percent of decrease in price of the shares of Selena's stock which Selena first buys and then sold is 11.5 percent.

Percentage decrease in a number is the ratio of total decrease in the original value of a number to the decreased value in the percentage form.

Given information-

The total stock buy by the Selena in $32.

The total stock sold by the Selena in $28.32.

As the total stock buy by the Selena in $32, and the total stock sold by the Selena in $28.32. Thus the total decrease in the price of stock is,

[tex]C_s=32-28.32\\C_s=3.68[/tex]

Thus the total decrease in the price of stock is $3.68.

As the cost price of the stock is $32 and the total decrease in the price of stock is $3.68. Thus the total percent of decrease in the price of the stock is,

[tex]\Delta C_s=\dfrac{3.68}{32}\times100\\\Delta C_s=11.5[/tex]

Thus the total percent of decrease in the price of the stock is 11.5 percent.

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Answer:

1.4

Step-by-step explanation:

= 7/5 × 2/2

= 14/10

=1.4