Please help me I don’t understand this question

Answer:

time

Explanation:

power = work done ÷ time

Using visual inspection and knowledge of linear regression , the inconsistent input is the last data point (30, 12.0).

Therefore, the inconsistent data point is (30, 12.0)

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Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

Pressure is related to Force, Volume and Density thus :

[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]

Using dimensional analysis :

Substituting the dimension into the relation :

[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]

[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]

Equating the power ;

a + c = 1 - - - (1)

a + 3b - 3c = - 1 - - - (2)

-2a = - 2

a = - 2/-2

a = 1

From (1)

1 + c = 1

c = 1 - 1 = 0

c = 0

From (2) :

1 + 3b - 3(0) = - 1

1 + 3b = - 1

3b = - 2

b = - 2/3

Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

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The representation of pressure is:

[tex]P=FV^{-\frac{2}{3} }[/tex]

Given that:

Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:

[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]

Hence:-

2 = -2a

a = 1

a + c = 1

1 + c = 1

c = 0

a + 3b - 3c = -1

1 + 3b - 3(0) = -1

3b = -2b = -2/3

Hence the representation of pressure is:

[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]

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Answer:

Explanation:

lThe mass of an object given only it's force and acceleration can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question

f = 195 N

a = 2.1 m/s

We have

[tex]m = \frac{195}{2.1 } = 92.857142... \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

a. 6

b. 6 m/s²

c. 300 m to the right

d. 30 secs

Explanation:

slope = rise /run

60-0/10-0

= 6

b. slope = acceleration = 6 m/s²

c. d=ut+1/2at²

t=10 (segment A last for 10 secs)

u - initial velocity = 0

so d = 0(10)+1/2*6*10²

=300 m

Answer:

B

Explanation:

I don't know but its b

Answer:

H = V t - 1/2 g t^2         V and g are in different directions

-8.2 = V * 6.2 - 1/2 * 10 * 6.2*2 = 6.2 V - 192.2

V = 184 / 6.2 = 29.7 m/s

Check: find time for ball to return to zero height

0 = 29.7 T - 5 T^2

T = 29.7 / 5 = 5.94 sec

The ball must have fallen 8.2 m in (6.2 - 5.94) sec = .26 sec

S = 29.7 * .26 + 5 * .26^2 = 8.1

Answer:

unfortunately we have not received a reply to the park yet but

Explanation:

mohamedz and he had killed him

The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].

The given parameters;

The initial and final momentum of the ball is calculated as;

[tex]P_i = m_ivi[/tex]

[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]

The initial and final kinetic energy of the ball is calculated as;

[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]

The change in the kinetic energy is calculated as;

[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]

Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].

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The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N

A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.

According  to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.

The centripetal force is the external force at work here and  It's the net force that propels the object in a circular motion.

Using the formula for calculating centripetal force:

[tex]\mathbf{F_c = mass (m) \times acceleration (a)}[/tex]

[tex]\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}[/tex]

[tex]\mathbf{F_c = 27 \ N}[/tex]

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We have that the the minimum coefficient of static friction  is mathematically given as

[tex]\mu= 0.235[/tex]

Generally the equation for the Force   is mathematically given as

[tex]F=n\mu\\\\Where\\\\n = mg\\\\Given\\\\Fc = m(vt2/R)\\\\Therefore\\\\\mu = vt2/gR\\\\\mu = 2.22/(9.8(2.1)) \\\\[/tex]

[tex]\mu= 0.235[/tex]

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Answer:

it prevents slipping on the grass while playing

Answer:

to keep their grip on the ground so they won't fall

Answer:

9) a) formula = h(ρ)g by default g=9.8m/s²

Pressure = 2×1000×9.8 = 19600Pa

b)

Answer:

Conduction

Explanation:

Because when a molecule is transferred to another molecule then this in going into direct contact

For example if we have a pan and it is boiling well the heat that is on the pan holder that stays in place and it won`t move anywhere else like there is Radiation and Convection but for this question the answer would be Conduction

Answer

Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.

Explanation:

Answer:

Additionally, the initial horizontal velocity may be calculated by measuring the diameter d of the ball and dividing the result by the amount of time t required for the ball to pass across the photogate. Vo = d/t is the formula.

Initial vertical velocity is the vertical component of the initial velocity: v 0 y = sin 0 sin 0 = (30.0 m/s) sin 45° = 21.2 m/s

Explanation:

Hope it helps:)

Answer:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

Explanation:

<3

Answer:

0n

Explanation:

Answer:

Explanation:

A wind is the horizontal movement of air from an area of high pressure to an area of lower pressure. Winds are caused by differences in air pressure. Most differences in air pressure are caused by unequal heating of the atmosphere

Answer:

The answer is False

Answer:

High water level during a tide is called High tide.

Low water level during a tide is called Low tide.

Answer:

Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.

Explanation:

If the acceleration on this vehicle is constant, the SUVAT equations would apply:

[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].

Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:

[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].

Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.

If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:

[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder   is mathematically given as

[tex]dl=\frac{Flo}{yA}[/tex]

[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=1.19064778*10^-^4[/tex]

Generally the equation for brass cylinder   is mathematically given as

[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=2.43*10^{-4}[/tex]

Therefore Total change in length

[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]

[tex]dl'=3.621*10^{-4}m[/tex]

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Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Answer:

potentiometer is a device used to measure potential difference across the circuit

Answer:

39.240 W

Explanation:

Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is [tex]w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J[/tex]

At this point we can simply apply the definition of power, that is [tex]P = \frac wt[/tex], to get the power of the engine is [tex]39.240 W[/tex]

Answer:

P=39200W

Explanation:

P=(mgh)/t

P=(40×9.8×1000)/10

P=39200W

Answer:

-34.8n

Explanation:

when object in free fall, only force is the Force by weight,

which is 34.8 and direction is down.

Answer:

Explanation:

Use simplified formula: