PLEASE HELP ME ASAP ITS IMPORTANT

Answer:

install and configure on the server DHCP (Dynamic Host Configuration Protocol)

Explanation:

In this scenario, you should install and configure on the server DHCP (Dynamic Host Configuration Protocol), this protocol automatically assigns each individual PC a unique IP address and DNS server information. This protocol has various configuration options such as being able to set a range for the IP addresses so that they can be used by different devices in the system. It also allows you to directly set the subnet and passage gateway so that all of the workstations can quickly communicate with one another and quickly be targeted by the administration.

Answer:

Lack of global control.

Explanation:

An operating system is a system software pre-installed on a computing device to manage or control software application, computer hardware and user processes.

This ultimately implies that, an operating system acts as an interface or intermediary between the computer end user and the hardware portion of the computer system (computer hardware) in the processing and execution of instructions.

Some examples of an operating system on computers are QNX, Linux, OpenVMS, MacOS, Microsoft windows, IBM, Solaris, VM etc.

There are different types of operating systems (OS) used for specific purposes and these are;

1. Batch Operating System.

2. Multitasking/Time Sharing OS.

3. Multiprocessing OS.

4. Single User OS.

5. Mobile OS.

6. Real Time OS .

7. Distributed OS.

8. Network OS.

A network operating system (NOS) can be defined as specialized computer operating system that are designed primarily for use on network devices such as routers, switches, workstations, which are mainly connected to a local area network.

Generally, the biggest limitation of a network operating system (NOS) is lack of global in terms of memory, process, device, and file management.

Answer:

1. First sentence

2. Paraphrase

Explanation:

Just took it

Answer:

Explanation:

Based on the information provided in the question, the best rules that the technician should add to the firewall would be the following

Permit 10.10.10.0/24 0.0.0.0 -p tcp --dport 443

Permit 10.10.10.0/24 192.168.1.15/24 -p udp --dport 53

This is because port 443 is used for "Secure webs services" while UDP port 53 is used for queries and domain name resolution. Both of which are the main configurations that the security technician needs to obtain.

Answer:

data = [75, 0.2, 95, 0.35, 85, 0.15]

print (f'Average weight: {sum(data) / len(data)}')

Explanation:

This is python algorithm for finding average weight. To get average weight, you sum up all data involved and divide that amount by the number of data provided.

First party insurance: Loss due to laptop theft, loss due to interruption in business activities due to website failure

Third party insurance: cost of lawsuits filed against the policyholder, fees of a special programmer investigating a cyber fraud, expenses of providing notifications of the cyber attack to clients and employees

Answer:

A Web client typically refers to the Web browser in the user's machine or mobile device. It may also refer to extensions and helper applications that enhance the browser to support special services from the site.

hope this helps

have a good day :)

Explanation:

Answer:

Explanation:

#include<iostream>

#include<iomanip>

#include<vector>

using namespace std;

double getAverage(const vector<double> amounts)

{

   double sum = 0.0;

   for (int i = 0; i < amounts.size(); i++)

       sum += amounts[i];

   return(sum / (double)amounts.size());

}

int getMinimum(const vector<double> amounts)

{

   double min = amounts[0];

   int minIndex = 0;

   for (int i = 0; i < amounts.size(); i++)

   {

       if (amounts[i] < min)

       {

           min = amounts[i];

           minIndex = i;

       }

   }

   return minIndex;

}

int getMaximum(const vector<double> amounts)

{

   double max = amounts[0];

   int maxIndex = 0;

   for (int i = 0; i < amounts.size(); i++)

   {

       if (amounts[i] > max)

       {

           max = amounts[i];

           maxIndex = i;

       }

   }

   return maxIndex;

}

int main()

{

   vector<string> months;

   vector<double> rainfalls;

   months.push_back("January");

   months.push_back("February");

   months.push_back("March");

   months.push_back("April");

   months.push_back("May");

   months.push_back("June");

   months.push_back("July");

   months.push_back("August");

   months.push_back("September");

   months.push_back("October");

   months.push_back("November");

   months.push_back("December");

   cout << "Input 12 rainfall amounts for each month:\n";

   for (int i = 0; i < 12; i++)

   {

       double amt;

       cin >> amt;

       rainfalls.push_back(amt);

   }

   cout << "\nMONTHLY RAINFALL AMOUNTS\n";

   cout << setprecision(2) << fixed << showpoint;

   for (int i = 0; i < 12; i++)

       cout << left << setw(11) << months[i] << right << setw(5) << rainfalls[i] << endl;

   cout << "\nAVERAGE RAINFALL FOR THE YEAR\n" << "Average: " << getAverage(rainfalls) << endl;

   int minIndex = getMinimum(rainfalls);

   int maxIndex = getMaximum(rainfalls);

   cout << "\nMONTH AND AMOUNT FOR MINIMUM RAINFALL FOR THE YEAR\n";

   cout << months[minIndex] << " " << rainfalls[minIndex] << endl;

   cout << "\nMONTH AND AMOUNT FOR MAXIMUM RAINFALL FOR THE YEAR\n";

   cout << months[maxIndex] << " " << rainfalls[maxIndex] << endl;

   return 0;

}

Answer:

try this

Explanation:

MSG1 DB 10,13,'enter any string:-$'

MSG2 DB 10,13,'converted string is:-$'

P1 LABEL BYTE

M1 DB 0FFH

L1 DB?

P11 DB 0FFH DUP<'$'>

DATA ENDS

DISPLAY MARCO MSG

MOV AH,9

LEA DX,MSG

INT 21H

ENDM

CODE SEGMENT

ASSUME CS: CODE,DS:DATA

START:

MOV AX,DATA

MOV DS,AX

DISPLAY MSG1

LEA DX,P1

MOV AH,0AH

INT 21H

DISPLAY MSG2

LEA SI,P1

MOV CL,L1

MOV CH,0

CHECK:

CMP[SI],61H

JB DONE

CMP[SI],5BH

UPR: SUB[SI],20H

DONE: INC SI

LOOP CHECK

DISPLAY P11

MOV AH,4CH

INT 21H

CODE ENDS

END START

Answer:

Answer: A. Cell

Explanation:

A cell is the point on the worksheet that results from the intersection of a column and a row.

This is why cells can be identified by the column and row that they are the result of. For instance, a cell can be called "A12" which is also known as its "address". This means that it is a result of the intersection of "Column A" and "Row 12".

Answer:

Explanation:

The Rectangle and Point class is not provided in this question but was found online. Using that code as guidance I created the following method named contains. This method takes in a Point object and checks to see if the x-axis point is inside the parameters of the Rectangle class and then checks the same for the y-axis. If it is inside the Rectangle then the method returns true otherwise it returns false.

def contains(self, point):

       return self.width > point.x >= self.corner.x and self.height > point.y >= self.corner.y

Answer:

Label the field

sort records

adjust the column width

set where to get lookup fields

Explanation:

Answer: B) Parent-to-child

Answer:

What is another name for the one-to-many relationship?

child-to-parent

Correct Answer: parent-to-child( B)

student-to-teacher

teacher-to-student

Explanation:

Answer:

C. Douglas Engelbart

Explanation:

Answer: C

Explanation:

Answer:

The modified SQL code is as follows:

SELECT Title, ReleaseDate FROM movie WHERE Rating = "PG-13" and ReleaseDate >  '2008-02-01'

Explanation:

The syntax of an SQL select statement is:

SELECT c1, c2, c...n FROM table WHERE condition-1, AND/OR condition-n

In this query, we are to select only the title and the release date.

So, we have:

SELECT Title, ReleaseDate

The table name is Movie.

So, we have:

SELECT Title, ReleaseDate FROM movie

And the condition for selection is that:

Ratings must be PG-13

And the date must be later than February 1, 2008

This implies that:

Rating = "PG-13"

ReleaseDate >  '2008-02-01'

So, the complete query is:

SELECT Title, ReleaseDate FROM movie WHERE Rating = "PG-13" and ReleaseDate >  '2008-02-01'

Answer:

Tangible assets are physical like cash, inventory, vehicles, equipment, buildings and investments.

Explanation:

Answer:

The function is as follows:

def list_to_string(input_list,separator):

   output = ""

   for inp in input_list:

       output+=inp+separator

   output = output[:-1]

   return output

Explanation:

Given

See attachment for instruction

Required

A function to convert list to string

This defines the string

def list_to_string(input_list,separator):

This initializes the output to an empty string

   output = ""

This iterates through the input list

   for inp in input_list:

This concatenates every string in the list including the separator

       output+=inp+separator

This removes the last character of the string

   output = output[:-1]

This returns the output string

   return output

Answer:

a query that shows all customers, whether or not they placed an order

Explanation:

EDG 21

Answer:

The function is as follows:

def divisible_by(listi, n):

   mylist = []

   for i in listi:

       if i%n == 0:

           mylist.append(i)

   return mylist

   pass

Explanation:

This defines the function

def divisible_by(listi, n):

This creates an empty list

   mylist = []

This iterates through the list

   for i in listi:

This checks if the elements of the list is divisible by n

       if i%n == 0:

If yes, the number is appended to the list

           mylist.append(i)

This returns the list

   return mylist

   pass

Answer:

from random import *

print(random())

Explanation:

You can try this in any online python ide quicker than putting the question here!

Answer:

HTTP

Explanation:

I hope it helps u.

Mark Me as brainlist answer

Answer

The terms data and information can mean different things in different contexts, but the main differences between them are: Data is a collection of facts. Information is how you understand those facts in context. Data is unorganized, while information is structured or organized.

Answer:

Explanation:

The following recursive method is written in Java. It creates a simulation of the towers of Hanoi and outputs every step-by-step instruction on how to solve it. The output for the code can be seen in the attached picture below.

class Brainly {

   public static String hanoi(int numOfDisks, int startPeg, int endPeg) {

       int helpPeg;

       String sol1, sol2, MyStep, mysol;   // Contains moves

       if (numOfDisks == 1) {

           return "Move from " + startPeg + " to " + endPeg + "\n";

       } else {

           helpPeg = 6 - startPeg - endPeg;    // Because startPeg + helpPeg + endPeg = 6

           sol1 = hanoi(numOfDisks - 1, startPeg, helpPeg);

           MyStep = "Move from " + startPeg + " to " + endPeg + "\n";

           sol2 = hanoi(numOfDisks - 1, helpPeg, endPeg);

           mysol = sol1 + MyStep + sol2;     // + = String concatenation !

           return mysol;

       }

   }

   public static void main(String[] args) {

      String output = hanoi(3, 1, 3);

       System.out.println(output);

   }

}

Answer:

security hacker

Explanation:

security hackers are people who hack software to check for vulnerabilities. most of the time security hackers are white hat hackers who work to perform penetration tests to see if a software is secure.

tell me if this is wrong :)

Answer:

Compressed

Explanation:

I hope this helps!

Answer:

usable

Explanation:

open doesnt make any sense, neither does closed and compressed is wrong i chose it and got it wrong. Its usable

Answer:

option 2

Explanation:

Answer:

B. Kathy performs tasks common to the Engineering and Technology pathway and Sean and Joan perform tasks common to the Science and Math pathway.

Answer:

hope this helps

Explanation:

import java.util.Scanner;

public class Problem3 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter start value: ");

       int start = in.nextInt();

       System.out.print("Enter end value: ");

       int end = in.nextInt();

       if (start > end) {

           int temp = start;

           start = end;

           end = temp;

       }

       for (int i = start; i <= end; i++) {

           if (i % 2 == 1) {

               System.out.print(i);

               if (i == end || i + 1 == end) {

                   System.out.println();

               } else {

                   System.out.print(", ");

               }

           }

       }

   }

}