please help i don't understand it (timed)

The value of x in the given composite figure is 11.31 units.

In accordance with the Pythagorean theorem, the square of the length of the hypotenuse (the side that faces the right angle) in a right triangle equals the sum of the squares of the lengths of the other two sides. If you know the lengths of the other two sides of a right triangle, you may apply this theorem to determine the length of the third side. By examining whether the sides of a triangle satisfy the Pythagorean equation, it can also be used to assess whether a triangle is a right triangle. Pythagoras, an ancient Greek mathematician, is credited with discovering the theorem, therefore it bears his name.

The given figure can be divided into a rectangle and a triangle.

The dimensions of the triangle are:

h = 18 - 10 = 8 units

b = 8

Now, using the Pythagoras Theorem we have:

x² = 8² + 8²

x² = 64 + 64

x² = 128

x = 11.31

Hence, the value of x in the given composite figure is 11.31 units.

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Therefore, the probability that a randomly selected passenger has a waiting time less than 2.75 minutes is 0.55.

Since the waiting times between subway departure schedule and passenger arrival are uniformly distributed between 0 and 5 minutes, the probability density function of the waiting time can be expressed as:

f(x) = 1/5 for 0 <= x <= 5

0 otherwise

To find the probability that a randomly selected passenger has a waiting time less than 2.75 minutes, we need to calculate the area under the probability density function from 0 to 2.75:

P(X < 2.75) = ∫[0, 2.75] f(x) dx

= ∫[0, 2.75] (1/5) dx

= (1/5) [x]_[0, 2.75]

= (1/5) * 2.75

= 0.55

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Since the least square curve fit method is a flexible method for approximating the best fit to a given set of data points using several mathematical models, all of these models are suitable.

The applicable model for the least square curve fit depends on the type of data being analyzed. In this case, the question mentions a sinusoidal model as one of the options. Therefore, a least square curve fit can fit data points to a sinusoidal model, which includes sine and cosine functions. However, it may not necessarily be able to fit the data points to an exponential model, polynomial model of appropriate order, or power curve.
Least square curve fit can fit the data points to the following models:

a) sinusoidal model (including sine and cosine functions)
b) exponential model
c) polynomial model of appropriate order
d) power curve ([tex]y=c1x^(c2)[/tex])

All of these models are applicable because the least square curve fit method is a versatile technique for approximating the best fit to a given set of data points using different mathematical models.

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Since the least square curve fit method is a flexible method for approximating the best fit to a given set of data points using several mathematical models, all of these models are suitable.

The applicable model for the least square curve fit depends on the type of data being analyzed. In this case, the question mentions a sinusoidal model as one of the options. Therefore, a least square curve fit can fit data points to a sinusoidal model, which includes sine and cosine functions. However, it may not necessarily be able to fit the data points to an exponential model, polynomial model of appropriate order, or power curve.
Least square curve fit can fit the data points to the following models:

a) sinusoidal model (including sine and cosine functions)
b) exponential model
c) polynomial model of appropriate order
d) power curve ([tex]y=c1x^(c2)[/tex])

All of these models are applicable because the least square curve fit method is a versatile technique for approximating the best fit to a given set of data points using different mathematical models.

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The function y = x(100 - x²) is increasing on the intervals (-∞, -10/√3) ∪ (10/√3, ∞), and decreasing on the interval (-10/√3, 10/√3).

To determine the intervals on which the function y = x(100 - x^2) is increasing or decreasing, we need to find its first derivative and determine its sign.

y' = 100 - 3x²

To find the critical points, we set y' = 0 and solve for x:

These are the critical points.

Now, we test the intervals between them:

Therefore, the function is

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the value of the given double integral is 150

To evaluate this double integral, we first identify it as the volume of a solid. In this case, the region r represents a rectangle in the xy-plane with dimensions 6 units (from x = -3 to x = 3) and 5 units (from y = 3 to y = 8). The given integral represents the volume of a rectangular prism, where the height is given by the constant value 5.

The given double integral of 5 da represents the volume of a solid over the rectangular region r = {(x, y) | −3 ≤ x ≤ 3, 3 ≤ y ≤ 8}.

To evaluate this double integral, we integrate the given constant 5 over the given region:

∬r 5 da = ∫₃⁸ ∫₋³³ 5 dx dy

Integrating with respect to x first, we get:

∫₋³³ 5 dx = 5x ∣₋³³ = 5(3) - 5(-3) = 30

Substituting this value and integrating with respect to y, we get:

∫₃⁸ 30 dy = 30y ∣₃⁸ = 30(8) - 30(3) = 150

Therefore, the value of the given double integral is 150.

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Answer:

  right

  D.  6.3 m

Step-by-step explanation:

You want to know if the given triangle is acute, obtuse, or right, and the value of x.

The red icon in the corner indicates the triangle is a right triangle. The Pythagorean theorem applies, so ...

  x² = 4.8² +4.1² = 39.85

  x = √39.85 ≈ 6.3

The value of x in this right triangle is about 6.3 m.

__

Additional comment

The triangle cannot be solved for the remaining side unless you know at least one angle. The marked right angle is sufficient to let you solve for x.

Answer:

➛ The given triangle is a right angle triangle.

➛ Option D) 6.3 in is the correct answer.

Step-by-step explanation :

Here we can see that the one angle of triangle is 90⁰. Therefore, it's a right angle triangle.

Now, Here we have given that the base and altitude of triangle and we need to find the hypotenuse of triangle.

So, by using Pythagoras Theorem we will find the hypotenuse of triangle :

[tex] \sf{\longrightarrow{{(Hypotenuse)}^{2} = {(Altitude)}^{2} + {(Base)}^{2}}}[/tex]

Substituting all the given values in the formula to find hypotenuse :

[tex] \sf{\longrightarrow{{(x)}^{2} = {(4.1)}^{2} + {(4.8)}^{2}}}[/tex]

[tex] \sf{\longrightarrow{{(x)}^{2} = {(4.1 \times 4.1)} + {(4.8 \times 4.8)}}}[/tex]

[tex] \sf{\longrightarrow{{(x)}^{2} = {(16.81)} + {(23.04)}}}[/tex]

[tex] \sf{\longrightarrow{{(x)}^{2} = 16.81 + 23.04}}[/tex]

[tex] \sf{\longrightarrow{{(x)}^{2} = 39.85}}[/tex]

[tex] \sf{\longrightarrow{x = \sqrt{39.85}}}[/tex]

[tex]\sf{\longrightarrow{\underline{\underline{x \approx 6.3 \: in}}}}[/tex]

Hence, the value of x is 6.3 in.

Answer:

^5-144p^3 = p^3(p^2-144)= p^3(p-12)(P +12

a) To find the value of β that satisfies limt→[infinity]y(t) = 0, we can first find the general solution of the differential equation. So the value(s) of β for which the solution y(t) is never equal to 0 for all t is [tex]β ∈ (-∞, -2) U (-2/3, ∞)[/tex]

The characteristic equation is [tex]r^2 + r - 2 = 0[/tex], which has roots r = 1 and r = -2.

Therefore, the general solution is[tex]y(t) = c1e^t + c2e^-2t.[/tex]

Using the initial conditions y(0) = 2 and y'(0) = β, we can solve for the constants c1 and c2:

[tex]c1 + c2 = 2[/tex]

[tex]c1 - 2c2 = β[/tex]

Solving this system of equations, we get [tex]c1 = 2 - β/3[/tex] and [tex]c2 = β/3.[/tex]

Therefore, the solution is y(t) =[tex](2 - β/3)e^t[/tex] + [tex]β/3)e^-2t[/tex]. To satisfy limt→[infinity]y(t) = 0, we need the coefficient of e^t to be 0, which gives us 2 - β/3 = 0. Solving for β, we get β = 6.

So the value of β that satisfies limt→[infinity]y(t) = 0 is β = 6.

b) To find the value(s) of β for which the solution y(t) is never equal to 0 for all t, we can use the fact that the discriminant of the characteristic equation determines the nature of the roots.

In this case, the characteristic equation is r^2 + r - 2 = 0, which has roots r = 1 and r = -2. These are distinct real roots, so the general solution is y(t) = [tex]c1e^t + c2e^-2t.[/tex]

For y(t) differential equation to never be equal to 0 for all t, we need both constants c1 and c2 to be nonzero. Using the initial condition y(0) = 2, we get c1 + c2 = 2.

Using the second initial condition y'(0) = β, we get c1 - 2c2 = β.

Solving these equations, we get [tex]c1 = (2β + 4)/5[/tex] and [tex]c2 = (6 - β)/5.[/tex]

Therefore, y(t) is never equal to 0 for all t if and only if both c1 and c2 are nonzero, which is true if and only if the coefficients satisfy the inequality (2β + 4)(6 - β) ≠ 0. Solving this inequality, we get [tex]β ∈ (-∞, -2) U (-2/3, ∞).[/tex]

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The area of the circle in polar coordinates is 16π square units.

To calculate the area of the circle in polar coordinates, we can use the following steps:

Step 1:   Convert the equation of the circle from rectangular coordinates to polar coordinates.

In polar coordinates, the conversion formulas are:

x = r * cos(θ)

y = r * sin(θ)

Given the equation of the circle as r = 8 * cos(θ), we can rewrite it in polar coordinates as:

r = 8 * cos(θ)

Step 2:   Determine the limits of integration for θ.

The limits of integration for θ will depend on the range of values that allow the circle to be fully traced out.

Since r = 8 * cos(θ), the maximum value of r occurs when cos(θ) is at its minimum value, which is -1.

Therefore, the circle is fully traced out when θ ranges from 0 to π.

Step 3:   Set up the integral to calculate the area.

The area of a circle in polar coordinates is given by the formula:

A =  ∫[r(θ)]² * (1/2) dθ

Plugging in r = 8 * cos(θ), and the limits of integration for θ as 0 to π, we get:

A = ∫[8 * cos(θ)]² * (1/2) dθ from θ = 0 to θ = π

Simplifying, we get:

A = (1/2) * ∫[64 * cos²(θ)] dθ from θ = 0 to θ = π

Step 4:    Evaluate the integral and calculate the area.

Usingen trigonometric idtity, cos²(θ) = (1 + cos(2θ))/2, we can rewrite the integral as:

A = (1/2) * ∫[64 * (1 + cos(2θ))/2] dθ from θ = 0 to θ = π

Simplifying further, we get:

A = (1/4) * ∫[64 + 64 * cos(2θ)] dθ from θ = 0 to θ = π

Now we can integrate term by term:

A = (1/4) * [64θ + 32 * sin(2θ)] from θ = 0 to θ = π

Plugging in the limits of integration, we get:

A = (1/4) * [64π + 32 * sin(2π)] - (1/4) * [0 + 32 * sin(0)]

Since,

sin(0) = 0 and sin(2π) = 0, we can simplify further:

A = (1/4) * 64π

Finally, we can simplify and express the area in terms of π:

A = 16π

So, the area of the circle with the equation r = 8 * cos(θ) in polar coordinates is 16π square units.

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The solution to the system of equations is (x, y) = (1, 3).

We have,

We use the elimination method on the two equations:

-3x + 4y = 9

2x + 4y = 14

We can eliminate y by subtracting the second equation from the first equation:

-3x + 4y - (2x + 4y) = 9 - 14

Simplifying the left side and the right side, we get:

-5x = -5

Dividing both sides by -5, we get:

x = 1

Let's use the first equation:

-3x + 4y = 9

Substituting x = 1.

-3(1) + 4y = 9

Simplifying and solving for y.

4y = 12

y = 3

Therefore,

The solution to the system of equations is (x, y) = (1, 3).

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The correct answer is option C, which includes the sets Z⁺, Z⁻, and {0}. These sets are non-overlapping and together they cover all of the integers in Z, forming a partition. (C)

Z⁺ includes all positive integers, Z⁻ includes all negative integers, and {0} includes only the number 0. Each integer in Z belongs to exactly one of these sets.

Option A, ZZ⁻ and {0}, is not a partition because it includes 0 in both sets, violating the requirement that sets in a partition be non-overlapping.

Option B, Z and Z⁻, also does not form a partition because it does not include any positive integers. Option D, Z⁺ and Z⁻, does not include {0} and therefore does not cover all of the integers in Z.(C)

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Tom ran from his home to the bus stop and waited. He realized that he had missed the bus so he walked home. The correct distance time graph describing this is graph G.

The distance that an object has come in a certain amount of time is displayed on a distance-time graph.  The graph that shows the results of the distance vs time analysis is a straightforward line graph. When analysing the motion of bodies, we work with the distance-time graph.

A distance-time graph related to a body's motion can be created if we measure a body's motion's distance and time and plot the resulting data on a rectangle graph. Tom ran from his home to the bus stop and waited. He realized that he had missed the bus so he walked home. The correct distance time graph describing this is graph G.

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Your question is incomplete but most probably your full question was,  

The distance in the east direction Mr. Jackamonis after Ms Follis walks 5 feet directly north and the distance between them is 13 feet, obtained using Pythagorean Theorem is 12 feet

Pythagorean Theorem states that the square of the length of the hypotenuse side of a right triangle is equivalent to the sum of the squares of the lengths of the other two sides of the right triangle.

Let a represent the length of the hypotenuse side, and let b and c represent the lengths of the other two sides, then according to the Pythagorean Theorem, we get;

a² = b² + c²

The direction Ms. Follis walks = 5 feet directly north

The direction Mr. Jackamonis walks = Directly east

The distance between Ms. Follis and Mr. Jackamonis = 13 feet apart

The distance Mr. Jackamonis walks, d, can  be found using Pythagorean Theorem as follows;

13² = 5² + d²

Therefore;

d² = 13² - 5² = 144

d = √(144) = 12

d = ± 12

Distances are measured using natural numbers, therefore;

d = 12 feet

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The value of x in the inscribing circle is 12.

We are given that;

∠RTN as an inscribed angle and ∠RWN as a central angle that subtend the same arc.

We have:

m∠RTN = 21​m∠RWN

Plugging in the given values, we get:

(2x+3)∘=21​(54)∘

Simplifying, we get:

2x+3=27

Subtracting 3 from both sides, we get:

2x=24

Dividing both sides by 2, we get:

x=12

Therefore, by the inscribing circle the answer will be 12.

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To prove that δqrev in equation 6.1 is not an exact differential, we can use the criterion developed in math chapter d. The criterion states that if a differential equation is exact, then its partial derivatives must satisfy the condition ∂M/∂y = ∂N/∂x.

In equation 6.1, δqrev is defined as δqrev = TdS. If we express δqrev in terms of its partial derivatives, we get:
∂(δqrev)/∂S = T
∂(δqrev)/∂T = S

Now, let's calculate the partial derivatives of ∂(∂(δqrev)/∂S)/∂T and ∂(∂(δqrev)/∂T)/∂S:
∂(∂(δqrev)/∂S)/∂T = ∂T/∂S = 0 (since T does not depend on S)
∂(∂(δqrev)/∂T)/∂S = ∂S/∂T = 0 (since S does not depend on T)

Since these partial derivatives are equal to zero, we can conclude that δqrev is not an exact differential, as it does not satisfy the condition ∂M/∂y = ∂N/∂x.

Therefore, we have proven that δqrev in equation 6.1 is not an exact differential.

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Okay, let's break this down step-by-step:

* f(x) = -4x3 + 15 (this is the original function)

* We want to find f(x) when x = 3

* So substitute 3 in for x:

f(3) = -4(3)3 + 15

f(3) = -81 + 15

f(3) = -66

Therefore, f(x) = -66 when x = 3.

[tex]\sf f(3)=-66.[/tex]

[tex]\sf f(3)=-4(3)^{3} +15\\ \\[/tex]

[tex]\sf f(3)=-4(3*3*3) +15\\\\\sf f(3)=-4(27) +15[/tex]

[tex]\sf f(3)=-81+15[/tex]

[tex]\sf f(3)=-66.[/tex]

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either the additivity nor the homogeneity properties are satisfied, L(x) is not a linear transformation from R³ to R².

To determine if L(x) is a linear transformation from R³ to R², we need to check if it satisfies the two properties of linear transformations:

1. Additivity: L(x + y) = L(x) + L(y)
2. Homogeneity: L(cx) = cL(x), where c is a scalar.

Given L(x) = (1 + x₁, x₂)ᵀ, let x = (x₁, x₂, x₃) and y = (y₁, y₂, y₃). Also, let cx = (cx₁, cx₂, cx₃).

Now let's check both properties:

1. Additivity:

L(x + y) = L((x₁ + y₁, x₂ + y₂, x₃ + y₃)) = (1 + (x₁ + y₁), x₂ + y₂)ᵀ

L(x) + L(y) = (1 + x₁, x₂)ᵀ + (1 + y₁, y₂)ᵀ = (2 + x₁ + y₁, x₂ + y₂)ᵀ

Since L(x + y) ≠ L(x) + L(y), the additivity property is not satisfied.

2. Homogeneity (this step is not necessary, as the additivity property already failed, but let's check it for completeness):

L(cx) = L((cx₁, cx₂, cx₃)) = (1 + cx₁, cx₂)ᵀ

cL(x) = c(1 + x₁, x₂)ᵀ = (c + cx₁, cx₂)ᵀ

Since L(cx) ≠ cL(x), the homogeneity property is also not satisfied.

Since neither the additivity nor the homogeneity properties are satisfied, L(x) is not a linear transformation from R³ to R².

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The function f(x) that satisfies f ''(x) = 24x³ − 15x² + 8x is:

f(x) = (6/5)x⁵ - (5/4)x⁴ + (4/3)x³ + C₁x + C₂ [where C₁ and C₂ are arbitrary constants].

Integration is a fundamental concept in calculus that involves finding the antiderivative or the indefinite integral of a function.

More specifically, integration is the process of determining a function whose derivative is the given function.

To find f(x) from f ''(x), we need to integrate f ''(x) twice, since the first antiderivative will give us the derivative of the function f(x), and the second antiderivative will give us f(x) up to two arbitrary constants of integration.

First, we integrate f ''(x) with respect to x to get the first antiderivative f '(x):

f '(x) = ∫ f ''(x) dx = 24∫ x³ dx - 15∫ x² dx + 8∫ x dx

f '(x) = 24(x⁴/4) - 15(x³/3) + 8(x²/2) + C₁

f '(x) = 6x⁴ - 5x³ + 4x² + C₁

where C₁ is the constant of integration.

Next, we integrate f '(x) with respect to x to get f(x):

f(x) = ∫ f '(x) dx = ∫ (6x⁴ - 5x³ + 4x² + C₁) dx

f(x) = (6/5)x⁵ - (5/4)x⁴ + (4/3)x³ + C₁x + C₂

where C₂ is the constant of integration.

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The function f(x) that satisfies f ''(x) = 24x³ − 15x² + 8x is:

f(x) = (6/5)x⁵ - (5/4)x⁴ + (4/3)x³ + C₁x + C₂ [where C₁ and C₂ are arbitrary constants].

Integration is a fundamental concept in calculus that involves finding the antiderivative or the indefinite integral of a function.

More specifically, integration is the process of determining a function whose derivative is the given function.

To find f(x) from f ''(x), we need to integrate f ''(x) twice, since the first antiderivative will give us the derivative of the function f(x), and the second antiderivative will give us f(x) up to two arbitrary constants of integration.

First, we integrate f ''(x) with respect to x to get the first antiderivative f '(x):

f '(x) = ∫ f ''(x) dx = 24∫ x³ dx - 15∫ x² dx + 8∫ x dx

f '(x) = 24(x⁴/4) - 15(x³/3) + 8(x²/2) + C₁

f '(x) = 6x⁴ - 5x³ + 4x² + C₁

where C₁ is the constant of integration.

Next, we integrate f '(x) with respect to x to get f(x):

f(x) = ∫ f '(x) dx = ∫ (6x⁴ - 5x³ + 4x² + C₁) dx

f(x) = (6/5)x⁵ - (5/4)x⁴ + (4/3)x³ + C₁x + C₂

where C₂ is the constant of integration.

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A function notation for two hours after the open, there are 108 people in the auditorium is N(2) = 108.

A function notation for the number of people in the auditorium 3 hours after the doors open is the same as the number of people in the auditorium 5 hours after the doors open is N(3) = N(5).

In Mathematics, a function refers to a mathematical expression which can be used for defining and showing the relationship that exist between two or more variables in a data set.

This ultimately implies that, a function typically shows the relationship between input values (x-values or domain) and output values (y-values or range) of a data set, as well as showing how the elements in a table are uniquely paired (mapped).

Based on the information provided, the number of people in the auditorium can be represented by this function notation;

N(t)

Where:

t represents number of hours.

After 2 hours, we have:

N(2) = 108.

For the last statement, we have:

N(3) = N(5).

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If function f(x)=10(3)2x−2, then f(0) = 10/9.

Explanation:

Step 1: To evaluate f(0), we can substitute x with 0 in the given function f(x) = 10(3)^(2x-2).

f(0) = 10(3)^(2(0)-2) = 10(3)^(-2)

Step 2: Now we know that a^(-n) = 1/a^n. So, we can rewrite 3^(-2) as 1/3^2.

f(0) = 10 * (1/3^2) = 10 * (1/9)

Finally, f(0) = 10/9.

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The correct option to the above question is Wakeboarding with a central angle of 39.6°.

A central angle is an angle formed by two radii (lines) in a circle, where the vertex of the angle is at the centre of the circle and the sides of the angle intersect the circle. In other words, it is an angle that spans from the centre of a circle to a point on the circle's circumference.

According to the given information:

To calculate the central angle for each lake activity in a circle graph, we need to find the percentage of campers who chose each activity out of the total number of campers surveyed (100). Then we can convert that percentage to degrees using the formula:

Central angle (in degrees) = Percentage * 360°

Let's calculate the percentages for each activity:

Kayaking: 15 campers out of 100, so the percentage is 15%.

Wakeboarding: 11 campers out of 100, so the percentage is 11%.

Windsurfing: 7 campers out of 100, so the percentage is 7%.

Waterskiing: 13 campers out of 100, so the percentage is 13%.

Paddleboarding: 54 campers out of 100, so the percentage is 54%.

Now, let's calculate the central angle for Wakeboarding:

Central angle for Wakeboarding = Percentage of Wakeboarding * 360°

Central angle for Wakeboarding = 11% * 360°

Central angle for Wakeboarding= 39.6°

So, Wakeboarding has a central angle of 39.6° in the circle graph, which is the activity with the highest percentage of campers surveyed. Therefore, the correct answer is "Wakeboarding".

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The formula for the probability mass function of X, the number of tagged fish in the researcher's sample, can be represented as P(X=x) = (C(80, x) * C(520, 15-x)) / C(600, 15).

Explanation:

Given that: A lake contains 600 fish, eighty (80) of which have been tagged by scientists. A researcher randomly catches 15 fish from the lake.

To Find a formula for the probability mass function of X, the number of fish in the researcher's sample which is tagged, Follow these steps:

Step 1: To find the probability mass function (PMF) for X, the number of tagged fish in the researcher's sample, you can use the hypergeometric distribution formula. In this scenario:

N = Total number of fish in the lake (600)
K = Number of tagged fish in the lake (80)
n = Number of fish in the researcher's sample (15)
x = Number of tagged fish in the researcher's sample (X)

Step 2: The PMF formula for the hypergeometric distribution is:

P(X=x) = (C(K, x) * C(N-K, n-x)) / C(N, n)

where C(a, b) represents the number of combinations of selecting b items from a total of items.

Step 3: In this case, the probability mass function for X, the number of tagged fish in the researcher's sample, can be represented as:

P(X=x) = (C(80, x) * C(600-80, 15-x)) / C(600, 15)

P(X=x) = (C(80, x) * C(520, 15-x)) / C(600, 15)

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The only option that represents power of power exponents rule is option B: (x^a)^b = x^(ab)

The exponent of a number says how many times to use the number in a multiplication.

There are different laws of exponents such as:
Zero Exponent Law: a^0 = 1.

Identity Exponent Law: a^1 = a.

Product Law: a^m × a^n = a^(m+n)

Quotient Law: a^m/a^n = a^(m-n)

Negative Exponents Law: a^(-m) = 1/a^(m)

Power of a Power: (a^m)^n = a^(mn)

Power of a Product: (ab)^(m) = a^mb^m

Power of a Quotient: (a/b)^m = a^m/b^m

Using power of power exponents rule, we can say that only option B is correct because:

(x^a)^b = x^(ab)

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The coefficients of the polynomial are 6 and 15 and the width of the rectangle is 3x

Here, we have

3x³(2x² - x + 5)

Expand

6x⁵ - 3x⁴ + 15x³

So, the coefficients of the polynomial are 6, -3 and 15

Here, we have

Length = 4x⁵

The area is calculated as

Area = (4x⁵)²

Evaluate

Area = 16x¹⁰

Here, we have

Area = 12x²

Length = 4x

So, we have

Width = 12x²/4x

Evaluate

Width = 3x

Hence, the width of the rectangle is 3x

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The exponential distribution is a special case of the gamma distribution with alpha = 1, not 0.

False.

The exponential distribution is a special case of the gamma distribution when the shape parameter (alpha) is equal to 1, not 0.

The probability density function (pdf) of the gamma distribution with shape parameter alpha and rate parameter beta is:

f(x) = (1/((beta^alpha)*gamma(alpha))) * (x^(alpha-1)) * (e^(-x/beta))

When alpha = 1, this reduces to the exponential distribution with rate parameter lambda = 1/beta:

f(x) = lambda * e^(-lambda*x)

So the exponential distribution is a special case of the gamma distribution with alpha = 1, not 0.

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The y-intercept indicates that when the ball was released at t=0, it was thrown upward at 46 feet per second.

The equation given for the speed of a ball that is thrown straight up in the air is:

v(t) = 46 - 32t

where v is the velocity (feet per second) and t is the number of seconds after the ball is thrown.

The y-intercept of this equation is the value of v when t = 0. To find the y-intercept, we can substitute t = 0 into the equation:

v(0) = 46 - 32(0) = 46

So, the y-intercept of this equation is 46, which means that when the ball was released at t=0, it was thrown upward at 46 feet per second.

Therefore, option A is the correct answer: The y-intercept indicates that when the ball was released at t=0, it was thrown upward at 46 feet per second.

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If a function is given that h(t) = 2t^2 - t; t = 4, t = 8, then the net change between the given values of the variable is 92 and the average rate of change between the given values of the variable is 23.

Explanation:

Given that: Based on the provided function h(t) = 2t^2 - t and the given values of t = 4 and t = 8.

To determine the net change and average rate of change, follow these steps:

(a) The difference between the two h(x) values is the net change.

To find the net change, we need to evaluate the function at both values of t and then subtract the results:

Net change = h(8) - h(4)
Net change = (2(8)^2 - 8) - (2(4)^2 - 4)
Net change = (128 - 8) - (32 - 4)
Net change = 120 - 28
Net change = 92

(b) The ratio between the net change and the change between the two input values is used to calculate average net change or average rate of change. The average rate of change can be calculated using the same two points and the formula: f(b)-f(a) / b-a .

To determine the average rate of change, we need to divide the net change by the difference in the t values:

Average rate of change = Net change / (t2 - t1)
Average rate of change = 92 / (8 - 4)
Average rate of change = 92 / 4
Average rate of change = 23

So, the net change is 92 and the average rate of change is 23 between the given values of the variable.

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Answer:

1. sin(A) = [tex]\frac{4}{5}[/tex]

2. cos(A) = [tex]\frac{3}{5}[/tex]

3. tan(A) = [tex]\frac{4}{3}[/tex]

4. sin(B) = [tex]\frac{3}{5}[/tex]

5. cos(B) = [tex]\frac{4}{5}[/tex]

6. tan(B) = [tex]\frac{3}{4}[/tex]

Step-by-step explanation:

Use SOHCAHTOA:

Sine = Opposite/Hypotenuse, Cosine = Adjacent/Hypotenuse, Tangent = Opposite/Adjacent.

1. sin(A) = opposite of A / hypotenuse of A = [tex]\frac{4}{5}[/tex]

2. cos(A) = adjacent of A / hypotenuse of A = [tex]\frac{3}{5}[/tex]

3. tan(A) = opposite of A / adjacent of A = [tex]\frac{4}{3}[/tex]

4. sin(B) = opposite of B / hypotenuse of B = [tex]\frac{3}{5}[/tex]

5. cos(B) = adjacent of B / hypotenuse of B = [tex]\frac{4}{5}[/tex]

6. tan(B) = opposite of B / adjacent of B = [tex]\frac{3}{4}[/tex]

Derivative dy/dx by implicit differentiation is dy/dx = -2xy / (x^2 - 8y^3)

To find dy/dx using implicit differentiation, we differentiate both sides of the given equation with respect to x, using the chain rule for the terms involving y:

d/dx (x^2y - 2y^4) = d/dx (-6)

Using the product rule, we get:

2xy + x^2(dy/dx) - 8y^3(dy/dx) = 0

Now we can solve for dy/dx:

(dy/dx)(x^2 - 8y^3) = -2xy

dy/dx = -2xy / (x^2 - 8y^3)

So the derivative dy/dx can be expressed in terms of both x and y.

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6) The solution is:  x = 1, y = -4, z = -3

7) The solution is: x = 1, y = 3, z = 5/7

8) The solution to the system of equations is: x = -11, y = 0, z = -5.

A quadratic equation is a polynomial equation of the second degree, which means it has a degree of two.

6.) To solve the systems of equations, we can use the Gaussian elimination method.

We will rewrite this system in the augmented matrix form:

[ 3 -1 2 | -4 ]

[ 6 -2 4 | -8 ]

[ 2 -1 3 | -10]

[ 3 -1 2 | -4 ]

[ 0 0 -4/3 | 4 ]

[ 0 1/3 7/3 | -14/3]

Then, we can add (1/3) times the second row to the third row:

[ 3 -1 2 | -4 ]

[ 0 0 -4/3 | 4 ]

[ 0 1/3 21/9 | -10/3]

[ 3 -1 2 | -4 ]

[ 0 0 -4/3 | 4 ]

[ 0 3 7 | -30 ]

7.) We can rewrite this system in the augmented matrix form:

[ 1 1 -1 | 4 ]

[ 3 2 4 | -17 ]

[-1 5 1 | 8 ]

[ 1 1 -1 | 4 ]

[ 0 -1 7 | -29 ]

[ 0 6 0 | 12 ]

Then, we can multiply the second row by -1 and add it to the third row:

[ 1 1 -1 | 4 ]

[ 0 -1 7 | -29 ]

[ 0 0 -42 | -150]

8.) To solve for x, y, and z in the system of equations:

x + 5y - 2z = -1 (equation 1)

-x - 2y + z = 6 (equation 2)

-2x - 7y + 3z = 7 (equation 3)

(1) + (2): 3y - z = 5

2(1) + (3): 13y - z = 5

3y - z = 5 (equation A)

13y - z = 5 (equation B)

10y = 0

3(0) - z = 5

z = -5

x + 5(0) - 2(-5) = -1

x + 10 = -1

x = -11

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