PLEASE HELP FAST!!!!!

Answer:

7>h

Step-by-step explanation:

Answer:

[tex]area \: = \frac{165}{360} \times \pi {8}^{2} \\ = 92.1533845053 \\ = 92 \: in^{2} [/tex]

Answer:

C 80 R36

Step-by-step explanation:

See attached image for explanation.

Answer:

18% and 0.18

Step-by-step explanation:

converting fraction 9/50 as a percent leaves u with 18%

Answer: 120m

Step-by-step explanation:

Let the height of the building be represented by x.

Since the height of a tower is 15m more than tiwce the height of a building, the height of the tower will be:

= (2 × x) + 15

= 2x + 15

Since the tower is 255m tall, therefore,

2x + 15 = 255

2x = 255 - 15

2x = 240

x = 240/2

x = 120

The height of the building is 120m

Answer:

Complex roots

Step-by-step explanation:

Given

[tex]8v^2 + 8 = -11v[/tex]

Required

The type of solution

Rewrite as:

[tex]8v^2 +11v+ 8 = 0[/tex]

To determine the type of solution, we simply calculate the discriminant (D)

[tex]D = b^2 - 4ac[/tex]

Where

[tex]a = 8;\ \ \ b =11\ \ \ c = 8[/tex]

So, we have:

[tex]D = 11^2 - 4 * 8 * 8[/tex]

[tex]D = 121 - 256[/tex]

[tex]D = -135[/tex]

The above value implies that:

[tex]D<0[/tex]

When [tex]D<0[/tex], the solution of the equation is: complex roots

Answer:

B

Step-by-step explanation:

the slope is 0

the y intercept is ( 0,4 )

Answer:

78

Step-by-step explanation:

[tex]nC_k = \frac{n!}{k!(n-k)!}[/tex]

[tex]13 C_{11} = \frac{13!}{11! \times (13-11)!}[/tex]

        [tex]= \frac{13!}{11! \times 2!}[/tex]

       [tex]= \frac{ 1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9 \times 10\times 11 \times 12 \times 13}{(1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9 \times 10\times 11 )\times ( 1 \times 2)}[/tex]

        [tex]=\frac{12 \times 13}{2} \\\\= 6 \times 13\\\\=78[/tex]

Answer:

prime factorization of 225 = 32•52.

Step-by-step explanation:

The number 225 is a composite number so, it is possible to factorize it. 225 can be divided by 1, by itself and at least by 3 and 5.

A composite number is a positive integer that has at least one positive divisor other than one or the number itself. In other words, a composite number is any integer greater than one that is not a prime number.

Answer:

Carrier A is 2,104 feet and Carrier B is 2,094 feet.

Step-by-step explanation:

Since there are two aircraft carriers, A and B, and carrier A is longer in length than the carrier B, and the total length of these two carriers is 4198 feet, while the difference of their lengths is only 10 feet, to determine the length of each aircraft carrier, the following calculation must be performed:

(4,198 - 10) / 2 = X

4.188 / 2 = X

2,094 = X

2,094 + 10 = 2,104

2,094 + 2,104 = 4,198

Therefore, Carrier A is 2,104 feet and Carrier B is 2,094 feet.

Answer:

- 0.125

Step-by-step explanation:

Given the equation :

(0.020(5/4) + 3 ((1/5) – (1/4)))

0.020(5/4) = 0.025

3((1/5) - (1/4)) = 3(1/5 - 1/4) = 3(-0.05) = - 0.15

0.025 + - 0.15 = 0.025 - 0.15 = - 0.125

Answer:

$17,535

Step-by-step explanation:

 Original (old) salary:  $16,700/year

+ raise:                          0.05($16,700/year) = $835/year

---------------------------------------------------------------------------------

 New salary:  Original salary plus amount of raise:

                        $16,700/year + $835/year   =  $17,535

A faster but still valid approach to finding the new salary involves multiplying the original salary by 1.05:

1.05($16,700) = $17,535.  Here the '1.00' represents the original salary and the '0.05) the raise.

Answer: 33.4

Step-by-step explanation:

Answer:

40°

Step-by-step explanation:

Isolate x. Complementary angles sum up to 90°, so that’s where you start

35+(x+13) = 90

35+(x+15)-35 = 90-35 (subtract 35)

x+15=55

x+15-15=55-15 (subtract 15)

x=40

To find the secong angle’s measure, just substitute x for 40. 40+15=55

I can’t draw a diagram, but two angles put together with measurements 40° and 55° should do the trick

Answer:

C

Step-by-step explanation:

173.6 • 9= 1562.4

Answer:

[tex]x=5,\\AC=14[/tex]

Step-by-step explanation:

Since one triangle is inscribed in another, the two triangles are similar. As marked in the diagram, the sides of the larger triangle are exactly two times larger than the corresponding sides of the smaller triangle.

Therefore, we have:

[tex]2(x+2)=4x-6,\\2x+4=4x-6,\\10=2x,\\x=\boxed{5}[/tex]

Since AC is marked by [tex]4x-6[/tex]:

[tex]AC=4(5)-6,\\AC=20-6,\\AC=\boxed{14}[/tex]

Answer:

120 yards is the answer to the equation

Answer:

3 mi of fencing would be required to enclose this field.

Step-by-step explanation:

Here we are finding the perimeter of a field with given length and width.  We apply the perimeter formula P = 2L + 2W.  Substituting the given dimensions, we get:

P = 2(1 mi) + 2(0.5 mi), or

P = 2 mi + 1 mi = 3 mi

3 mi of fencing would be required to enclose this field.

Answer:

15840 feet of fencing = Perimeter = 15840ft

However, if fencing is 6ft or 10ft we need to divide by the length of each fence for panels.

See bold.

Step-by-step explanation:

6ft fencing = 5280/6 = 880 fences one length

880 x 2 = 1760 6ft fences 2 sides

0.5 x 1760 = 880

1760+ 880 = 2640 fences each 6ft

Total feet of fence = 2640 x 6 =15840 feet of fencing

Answer:

the first one

Step-by-step explanation:

Hope this helps!

Answer: it is a linear line

Step-by-step explanation:

They both together make 0

Use the following property below:

[tex] \large \boxed{ \sqrt[n]{a} \times \sqrt[n]{a} \times \sqrt[n]{a} = { (\sqrt[n]{a}) }^{3} }[/tex]

Therefore,

[tex] \large{ \sqrt[7]{x} \times \sqrt[7]{x} \times \sqrt[7]{x} = { (\sqrt[7]{x}) }^{3} }[/tex]

Then we use next property.

[tex] \large{ \sqrt[n]{ {a}^{m} } = {a}^{ \frac{m}{n} } }[/tex]

Hence,

[tex] \large{ \sqrt[7]{ {x}^{3} } = {x}^{ \frac{3}{7} } }[/tex]

Answer

Answer:

[tex]\sec A =\frac{\sqrt{13}}{3}[/tex]

Step-by-step explanation:

Given

[tex]\tan A = 2/3[/tex]

Required

[tex]\sec\ A[/tex]

First, we have:

[tex]\tan A = \frac{x}{y}[/tex]

Where

[tex]x \to oppo site\\[/tex]

[tex]y \to adja cent[/tex]

[tex]z \to hypotenuse[/tex]

So:

[tex]\tan A = \frac{x}{y} =\frac{2}{3}[/tex]

By comparison:

[tex]x = 2; y =3[/tex]

Using Pythagoras, we have:

[tex]z^2 = x^2 +y^2[/tex]

[tex]z^2 = 2^2 +3^2[/tex]

[tex]z^2 = 13[/tex]

[tex]z = \sqrt{13[/tex]

[tex]\sec A =\frac{z}{y}[/tex]

[tex]\sec A =\frac{\sqrt{13}}{3}[/tex]

Answer:

[tex]y < - 1[/tex]

Step-by-step explanation:

[tex]y < - 4 + 3[/tex]

[tex]y < - 1[/tex]

[tex] \sf \: y < - 4 + 3 \\ \sf \: y < - 1[/tex]

[tex] \sf \: Just \: add \: - 4 \: and \: 3 \: and \: you \: \\ \sf will \: get \: the \: inequality \: in \: the \: simplest \: form.[/tex]

Answer:

0.3

Step-by-step explanation:

Go left to right for each digit, which one is greater. They all have a decimal so for right now we can’t eliminate any. Next digit we two 2s a 0 and a 3. Whch number is greater? The three! So the greatest number is 0.3.

Answer:

C) 143

D) 37

E) 74

Step-by-step explanation:

C) 180 - 37 = 143

D) 180 - 143 = 37

E) 180 - 37 - 69 = E

Answer:

The quadratic function represented by the graph is [tex]y = x^{2}-6\cdot x + 8[/tex].

Step-by-step explanation:

Parabolae are defined by second order polynomials, that is, a polynomial of the form:

[tex]y = a\cdot x^{2} + b\cdot x + c[/tex] (1)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]a, b, c[/tex] - Coefficients.

By Algebra, we know can calculate the set of all coefficients based on the knowledge of three distinct points. According to the graph, we have the following points: [tex](x_{1}, y_{1}) = (2, 0)[/tex], [tex](x_{2}, y_{2}) = (4, 0)[/tex] and [tex](x_{3}, y_{3}) = (6, 8)[/tex], and the resulting system of linear equations is:

[tex]4\cdot a + 2\cdot b + c = 0[/tex] (2)

[tex]16\cdot a + 4\cdot b + c = 0[/tex] (3)

[tex]36\cdot a + 6\cdot b + c = 8[/tex] (4)

The solution of the system of linear equations is:

[tex]a = 1, b = -6, c = 8[/tex]

Hence, the quadratic function represented by the graph is [tex]y = x^{2}-6\cdot x + 8[/tex].

Answer:

We know that:

H(x) = |1 - x^3|

and:

We want to write H(x) as  f( g(x) ) , such that for two functions:

So we want to find two functions f(x) and g(x) such that:

f( g(x) ) = |1 - x^3|

Where neither of these functions can be an identity function.

Let's define g(x) as:

g(x) = x^3 + 2

And f(x) as:

f(x) = | A - x|

Where A can be a real number, we need to find the value of A.

Then:

f(g(x)) = |A - g(x)|

and remember that g(x) = x^3 + 2

then:

f(g(x)) = |A - g(x)| = |A - x^3 - 2|

And this must be equal to:

|A - x^3 - 2| =  |1 - x^3|

Then:

A = 3

The functions are then:

f(x) = | 3 - x|

g(x) = x^3 + 2

And H(x) =  f( g(x) )

Answer:

Step-by-step explanation:

Answer:

The normal overlaps with the diameter, so it passes through the center.

Let's find the center of the circle:

The center is:

Since the line passes through (-g, -f) the equation of the line becomes:

This is the required condition

Rewrite equations and find centers and radius of both circles.

Circle 1

Circle 2

The distance between two centers is same as sum of the radius of them:

Sum of radiuses:

Since they are same we have:

Square both sides:

Square both sides:

Divide both sides by a²b²c²:

Proved

Answer:

Answer is in the picture