please help anyone i need to pass summer school

Using the combination formula, it is found that 35 different combination of teams can make it to the playoffs.

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, 4 students are taken from a set of 7, hence the number of combinations is given by:

[tex]C_{7,4} = \frac{7!}{4!3!} = 35[/tex]

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Sorry don't no the answer

sorry if I kwon the answer

I telling u the answer

Answer:

135°

Step-by-step explanation:

That triangle in the corner is an right angle isosceles triangle as that line the midpoint of both sides :

the base angle of this triangle (x) will be :

180 = 90 + 2x

90 = 2x

x= 45

Angles on a straight line add up to 180. So to work out a :

180 = 45 + a

135 = a

Hope this helped and brainliest please

Answer:

place the decimal number over its place value

Step-by-step explanation:

For example in 0.4 the four is in the tenths place, so we place 4 over 10 like 4/10

Answer:

Step-by-step explanation:

Example:

   4.52

[tex]4.52 =\dfrac{4.52}{1}[/tex]

In 4.52, there are two decimal places. So multiply the numerator and denominator by 100

[tex]\dfrac{4.52*100}{1*100}=\dfrac{452}{100}=\dfrac{452 \div 4}{100 \div 4}=\dfrac{113}{25}[/tex]

(3x-2)^2

squares area is 2 times its side length, since all the sides are the same. if the side length is 3x-2, take its second power

Answer:

a) Length= (x+2) and breadth=(x-1) b) 4 m^2 c) R1000

Answer:

answers in photo / +explanation

Step-by-step explanation:

a)

length: x+2

width/breadth: x-1

b)

length: 4m

width/breadth: 1m

area: 4m²

c)

R1000

Answer:

hope you can understand

Answer:

'''

Step-by-step explanation:

The average rate of a function is 81 if a quadratic function with a vertex at (6, 8).

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

Quadratic function with a vertex at (6, 8).

It is required to find the average rate of the function:

Here the data table is not given, so we are assuming the value of a function:

At x = 13 is 196

f(13) = 144

At x = 14 is 225

f(14) = 225

The average rate of a function:

= [f(14) - f(13)]/(14 - 13)

= [225 - 144]/(1)

= 81

Thus, the average rate of a function is 81 if a quadratic function with a vertex at (6, 8).

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Answer:

neither can be factored any further but if it is (9x^4) - (16y^4) it can be factored down to ((3x^2)+(4y^2)) ((3x^2)+(4y^2))

Step-by-step explanation:

Answer:

C (3,6)

Step-by-step explanation:

So the zeroes are the points that the loop goes through on the x-axis

so three and six

Using it's concept, it is found that the percent increase in the amount of iron per serving was of 50%.

It is given by the increase divided by the initial value, and subtracted by 100%.

In this problem:

Hence the percent increase is given by:

P = 0.6/1.2 x 100% = 50%.

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Answer:

-2

Step-by-step explanation:

[tex](5 \times 1) - 7 \\ 5 - 7 \\ - 2[/tex]

The response that represents the 86th percentile is 7.884

The response that represents the 55th percentile is 5.69

The response that represents the first percentile 3.85

mean = 5.4

sd = 2.3

p(X>x) = 0.86

find the value of z using the NORMSINV function in excel with a probability of 0.86

z = 1.080

x = mean + sd*z

= 5.4 + 2.3 * 1.080

= 7.88

mean = 5.4

sd = 2.3

p(X>x) = 0.55

find the value of z using the NORMSINV function in excel with a probability of 0.55

z = 0.1257

x = mean + sd*z

= 5.4 + 2.3 * 0.1257

= 5.69

c. The first quartile is 25%

z = -0.6745

5.4 + 2.3 * -0.6745

= 5.4-1.551

= 3.85

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Answer:

r > -69

Step-by-step explanation:

13 - r < 82

subtract 13 from both sides

13 - r - 13 < 82 - 13

- r < 69

to flip the inequality sign, multiply both side by -1 to make r positive:

- r (-1) < 69 (-1)

r > -69

        [tex]\rule{50}{1}\large\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}[/tex]

    13-r<82

      [tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}[/tex]

   First of all, we need to isolate r (get r by itself). What I Mean by that is

       We need to get r by itself on one side of the inequality.

      So it should look something like this:-

     r<___

So r is all by itself.

How will we get r by itself? Well, First of all, we need to subtract 13 on both sides:-

[tex]\longmapsto\bf{-r < 82-13[/tex]

Simplifying,

[tex]\longmapsto\bf{-r < 69}[/tex]

Now, is r by itself? Nopes, There's also a minus sign next to it , which indicates that r is multiplied by -1.

So we do the opposite operation and divide both sides by -1:-

(watch what happens)

[tex]\longmapsto\bf{r > -69}[/tex]

The inequality sign changed from "less than" to "greater than".

This happened because we divided by a negative number on both sides.

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[tex]\rule{300}{1}[/tex]

Answer:

The answer is the third bullet. (number 3)

Step-by-step explanation:

5(x+2)
1. Distributive property
2. Multiply
(5*x) + (5*2)
(5x)+(10)
Remove parenthesis

5x+10 ;

Therefore, 5(x+2) = 5x+10

Hopefully this helps! :3

Answer:

You should raise one side 14 inches

Step-by-step explanation:

I used a right angle triangle calculater at this sight

https://www.calculator.net/right-triangle-calculator.html

Recall that the derivative of a function f(x) at a point x = c is given by

[tex]\displaystyle f'(c) = \lim_{x\to c} \frac{f(x) - f(c)}{x - c}[/tex]

By substituting h = x - c, we have the equivalent expression

[tex]\displaystyle f'(c) = \lim_{h\to0} \frac{f(c+h) - f(c)}h[/tex]

since if x approaches c, then h = x - c approaches c - c = 0.

The two given limits strongly resemble what we have here, so it's just a matter of identifying the f(x) and c.

For the first limit,

[tex]\displaystyle \lim_{h\to0} \frac{\sin\left(\frac\pi3 + h\right) - \frac{\sqrt3}2}h[/tex]

recall that sin(π/3) = √3/2. Then c = π/3 and f(x) = sin(x), and the limit is equal to the derivative of sin(x) at x = π/3. We have

[tex](\sin(x))' = \cos(x)[/tex]

and cos(π/3) = 1/2.

For the second limit,

[tex]\displaystyle \lim_{a\to0} \frac{e^{2a} - 1}a[/tex]

we observe that e²ˣ = 1 if x = 0. So this limit is the derivative of e²ˣ at x = 0. We have

[tex]\left(e^{2x}\right)' = e^{2x} (2x)' = 2e^{2x}[/tex]

and 2e⁰ = 2.

The number of lines of symmetry for the given figure will be 4.

Symmetry is described in geometry as a balanced and proportionate likeness between two halves of an object.

As we know that similarity is defined as when the image is divided into two halves and one portion is completely overlapped by the other.

So in the given figure, the figure can be divided into two halves by drawing four lines along with the arrows and along with the corners. In all cases, the two halves overlap with the other.

Therefore the number of lines of symmetry for the given figure will be 4.

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Answer:

48

Step-by-step explanation:

66*2=132

180-132=48

Hope this helps!

If not, I am sorry.

The median of the data is 5 if the all class widths are 1, option (C) is correct.

A median is a middle number in a series of numbers that have been arranged to lift, and it might be more informative of the set of data than the average. When there are extremes in the sequences that might affect the average of the numbers, the median is sometimes employed instead of the mean.

In the histogram, 15 data values are given:

1, 2, 2, 3, 3, 3, 4, 5, 6, 6, 7, 7, 7, 8, 9

The mid-value is 5 which is on the 8th place

Thus, the median of the data is 5 if the all class widths are 1, option (C) is correct.

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Answer:

there are 75 colors of each candy

Step-by-step explanation:

300÷4=75

.✎let's answer it :3

question ⇩

✎ The area of a newspaper page (opened up) is about 640.98 square inches. Determine the length and width of the page if its length is about 1.25 times its width.

The area of a newspaper page (opened up) is about 640.98 square inches. Determine the length and width of the page if its length is about 1.25 times its width.The width of the page is ___ inches.

hope it helps

correct me if I am wrong

Based on the quadrilaterals given, the types of angles that we see are Acute and Obtuse.

Acute angles are those that are less than 90° and these are shown in the trapezium quadrilateral.

Obtuse angles are higher than 90° and so are drawn outwards as seen in the parallelogram.

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We will get the areas of each one of the given triangles:

7) A = 12.69 mm²

8) A = 19.21 in²

9) A = 16.81 yd²

7) First, we have an equilateral triangle, where all the sides measure 5.4mm

For an equilateral triangle of side length S, the area is:

[tex]A = \frac{\sqrt{3} }{4}S^2[/tex]

In this case, S = 5.4 mm, replacing we get:

[tex]A = \frac{\sqrt{3} }{4}(5.4mm)^2 = 12.62 mm^2[/tex]

8) Now we have two equal sides and one different. The general area of a triangle of base B and height H is:

A = B*H/2.

In this case, the base measures 3.4 in.

To get the height, let's divide the triangle into two right triangles, such that one cathetus is 3.4in/2 = 1.7 in.

The hypotenuse measures 5.9 in

And the other cathetus is the height of the triangle.

Then, by using the Pythagorean theorem, we see that the height is:

[tex]H = \sqrt{(5.9 in)^2 - (1.7in)^2} = 5.65 in[/tex]

Then the area of this triangle is:

[tex]A = (3.4 in)*(5.65 in)/2 = 19.21 in^2[/tex]

9) Here the base measures 8.2 yds, and the height 4.1 yds, so the area is just:

[tex]A = (4.1 yd)*(8.2 yd)/2 = 16.81 yd^2[/tex]

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The probability that the dog that's selected will weigh less than 30 pounds will be 55%.

From the information given, it was stated that 45% of the dogs weigh more than 30 pounds. Therefore, the probability that the dog that's selected will weigh less than 30 pounds will be:

= 1 - 45%

= 55%

The probability that it weighs more than 30 pound given that it has long fur will be 27%.

The events are independent since the occurence of one doesn't affect the other one.

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