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Answer:

44

Step-by-step explanation:

The sum of the series [tex]\sum_{k=1}^4[/tex] (2k²−4) is 44.

The series is: [tex]\sum_{k=1}^4[/tex] (2k²−4)

Let's find the value of each term for k=1, k=2, k=3, and k=4, and then add them up:

For k=1:

2(1)² - 4 = 2(1) - 4 = 2 - 4 = -2

For k=2:

2(2)² - 4 = 2(4) - 4 = 8 - 4 = 4

For k=3:

2(3)² - 4 = 2(9) - 4 = 18 - 4 = 14

For k=4:

2(4)² - 4 = 2(16) - 4 = 32 - 4 = 28

Now, let's add all the terms:

-2 + 4 + 14 + 28 = 44

So, the sum of the series [tex]\sum_{k=1}^4[/tex] (2k²−4) is 44.

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Answer:

Yes, a sinusoidal function is a great way to model temperatures over a 24-hour period because the pattern of temperature changes tends to be cyclic.

A sinusoidal function can be written in the general form:

D(t) = A sin(B(t - C)) + D

where:

- A is the amplitude (half the range of the temperature changes)

- B is the frequency of the cycle (which would be `2π/24` in this case because the temperature completes a full cycle every 24 hours)

- C is the horizontal shift (which is determined by the fact that the minimum temperature occurs at 6 AM)

- D is the vertical shift (which is the average of the maximum and minimum temperature)

Given the information you've provided, let's fill in the specifics:

- The high temperature for the day is 95 degrees.

- The low temperature is 75 degrees at 6 AM.

The amplitude, A, is half the range of temperature changes. It's the difference between the high and the low temperature divided by 2:

A = (95 - 75) / 2 = 10

The frequency, B, is `2π/24` because the temperature completes a full cycle every 24 hours.

The horizontal shift, C, is determined by the fact that the minimum temperature occurs at 6 AM. The sine function hits its minimum halfway through its period, so we want to shift the function to the right by 6 hours to make this happen. In our case, this means C = 6.

The vertical shift, D, is the average of the maximum and minimum temperature:

D = (95 + 75) / 2 = 85

So the equation for the temperature, D, in terms of t (the number of hours since midnight) is:

D(t) = 10 sin((2π/24) * (t - 6)) + 85

This equation represents a sinusoidal function that models the temperature over a day given the information provided.

Answer:

B only

Step-by-step explanation:

Triangles A and C are similar, but not congruent to each other. Similar triangles have proportional sides and congruent angles, while congruent triangles have congruent sides and congruent angles.

Therefore, only B is correct

The question is asking for pairs of congruent triangles but lacks key information needed to accurately answer this, such as lengths or angles. Congruent triangles are identified in geometry based on either side-lengths or angles.

The question is about congruent triangles, which in mathematics means triangles that have the same size and shape. But to accurately answer which pairs show two congruent triangles, we need more information. The options provided include 'A', 'B', and 'C' but without knowing more about these elements (for example their lengths or angles), it is impossible to determine which are congruent. Congruent triangles are identified in geometry based on either side lengths (SSS: Side-Side-Side, SAS: Side-Angle-Side, ASA: Angle-Side-Angle) or angles (AAS: Angle-Angle-Side, HL: Hypotenuse-Leg for right triangles). Without this vital information, we cannot definitively answer the question. Be sure to verify all the properties required to prove two triangles congruent.

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Reason:

If CD was parallel to AB, then triangles CDE and ABE would be similar. In turn it would mean that EA/EC = EB/ED is a true proportion.

Let's calculate each side separately.

Both decimal values are approximate.

The two values don't match up which makes EA/EC = EB/ED to be false.

Since EA/EC = EB/ED is false, we know that triangles CDE and ABE are not similar. Therefore, CD is not parallel to AB.

Answer:

CD is not parallel to AB

Step-by-step explanation:

According to the Side Splitter Theorem, if a line parallel to one side of a triangle intersects the other two sides, then this line divides those two sides proportionally.

Therefore, if CD is parallel to AB, then EA : AC = EB : BD.

Substitute the values of the line segments into the equation:

[tex]\begin{aligned}EA : AC &= EB : BD\\\\28:20&=16:10\\\\\dfrac{28}{20}&=\dfrac{16}{10}\\\\1.4 &\neq 1.6\end{aligned}[/tex]

As 1.4 does not equal 1.6, then CD is not parallel to AB.

The group of individuals fitting a description is called option D: Population, this is because, in statistics, a population is seen as am entire group of individuals, items, or elements that tends to have or share a common characteristics.

The term "population" describes the complete group of people or things that you are interested in investigating. It is the group of individuals or thing(s) about which you are attempting to draw conclusions.

There are infinite and finite populations. A population with a set quantity of people or things is said to be finite. An endless population is one that has an infinite amount of people or things.

Therefore, the correct option is D

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See full text below

A group of individuals fitting a description is the _____

Which of the term below fit the description above.

A.census

B.sample

C.parameter

D.population

Using the concept of scale factor, the value of t in polygon s is:  7.2

The amount by which the shape is expanded or contracted is referred to as the scale factor. This is usually utilized when 2D shapes such as circles, triangles, squares and rectangles need to be enlarged. If y = Kx is an equation, K is the scaling factor for x.

From the given image, since Polygon s is a scaled copy of polygon R, then we can say that using the concept of scale factor, we have:

9/t = 12/9.6

t = (9 * 9.6)/12

t = 7.2

Thus, we can be sure that is the value of t of the polygon S using the concept of scale factor

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The journal entries for the given transactions are as follows:

Cash A/c Dr. 40,000

Furniture A/c Dr. 5,000

Motor Car A/c Dr. 12,000

Stock A/c Dr. 20,000

To Capital A/c 77,000

Bank A/c Dr. 15,000

To Cash A/c 15,000

Purchase A/c Dr. 9,000

To Sen's A/c 9,000

Basu's A/c Dr. 6,000

To Sales A/c 6,000

Stationery A/c Dr. 200

To Cash A/c 200

Cash A/c Dr. 2,000

To Dalal's A/c 2,000

Travelling Expenses A/c Dr. 600

To Cash A/c 600

Drawings A/c Dr. 1,000

To Bank A/c 1,000

Cash A/c Dr. 3,000

To Bank A/c 3,000

Sen's A/c Dr. 8,800

To Bank A/c 8,800

Freight and Clearing A/c Dr. 400

To Cash A/c 400

Bank A/c Dr. 6,000

To Basu's A/c 6,000

Journal entries for the given transactions are as follows:

Pater commenced business with 40,000 cash and also brought into business furniture worth ₹5,000; Motor car valued for ₹12,000 and stock worth ₹20,000.

Cash A/c Dr. 40,000

Furniture A/c Dr. 5,000

Motor Car A/c Dr. 12,000

Stock A/c Dr. 20,000

To Capital A/c 77,000

Deposited ₹15,000 into State Bank of India.

Bank A/c Dr. 15,000

To Cash A/c 15,000

Bought goods on credit from Sen for ₹9,000.

Purchase A/c Dr. 9,000

To Sen's A/c 9,000

Sold goods to Basu on Credit for ₹6,000.

Basu's A/c Dr. 6,000

To Sales A/c 6,000

Bought stationery from Ram Bros. for Cash ₹200.

Stationery A/c Dr. 200

To Cash A/c 200

Sold goods to Dalal for ₹2,000 for which cash was received.

Cash A/c Dr. 2,000

To Dalal's A/c 2,000

Paid ₹600 as travelling expenses to Mehta in cash.

Travelling Expenses A/c Dr. 600

To Cash A/c 600

Patel withdrew for personal use ₹1,000 from the Bank.

Drawings A/c Dr. 1,000

To Bank A/c 1,000

Withdrew from the Bank ₹3,000 for office use.

Cash A/c Dr. 3,000

To Bank A/c 3,000

Paid to Sen by cheque ₹8,800 in full settlement of his account.

Sen's A/c Dr. 8,800

To Bank A/c 8,800

Paid ₹400 in cash as freight and clearing charges to Gopal.

Freight and Clearing A/c Dr. 400

To Cash A/c 400

Received a cheque for ₹6,000 from Basu.

Bank A/c Dr. 6,000

To Basu's A/c 6,000

These journal entries represent the various transactions and their effects on different accounts in the accounting system.

They serve as the initial records of the financial activities of the business and provide a basis for further accounting processes such as ledger posting and preparation of financial statements.

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Answer:

p =1 0

Step-by-step explanation:

x³(x - y)⁹ - y³(x - y)⁹ = (x - y)⁹[x³ - y³]

= (x - y)⁹(x - y)(x² + y² + xy)

= (x - y)¹⁰(x² + y² + xy)

where p = 10 and q = 1

Answer:

p = 10

Step-by-step explanation:

Given expression:

[tex]x^3(x-y)^9 - y^3(x-y)^9[/tex]

Factor out the common term (x - y)⁹:

[tex](x-y)^9(x^3- y^3)[/tex]

[tex]\boxed{\begin{minipage}{5cm}\underline{Difference of two cubes}\\\\$x^3-y^3=(x-y)(x^2+y^2+xy)$\\\end{minipage}}[/tex]

Rewrite the second parentheses as the difference of two cubes.

[tex](x-y)^9(x-y)(x^2+y^2+xy)[/tex]

[tex]\textsf{Apply\:the\:exponent\:rule:} \quad a^b\cdot \:a^c=a^{b+c}[/tex]

[tex](x-y)^{9+1}(x^2+y^2+xy)[/tex]

[tex](x-y)^{10}(x^2+y^2+xy)[/tex]

Comparing the rewritten original expression with the given expression:

[tex](x-y)^{10}(x^2+y^2+xy)=(x-y)^p(x^2+y^2+qxy)[/tex]

We can see that [tex](x-y)^p[/tex] corresponds to [tex](x-y)^{10}[/tex] in the given expression.

Therefore, we can conclude that p = 10.

Gabby can get €23.73 for £21 when using the exchange rate of £1 = €1.13.

To calculate how many euros Gabby can get for £21, we need to use the exchange rate of £1 = €1.13.

To find the number of euros, we multiply the amount in pounds (£21) by the exchange rate (€1.13):

£21 * €1.13 = €23.73

Therefore, Gabby can get €23.73 for £21 when using the exchange rate of £1 = €1.13.

This means that for every pound exchanged, Gabby will receive €1.13. So, by multiplying the amount in pounds (£21) by the exchange rate (£1 = €1.13), we can determine the equivalent amount in euros.

It's important to note that exchange rates can fluctuate, and the rate provided here is just an example. When exchanging currency, it's always advisable to check the current exchange rates as they may vary. Additionally, some currency exchange services may charge fees or have different rates, so it's essential to consider those factors as well.

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Answer:

Step-by-step explanation:

pic is not clear

Answer:

4/3

Step-by-step explanation:

1/3:(1/4) = (1/3)/(1/4) = 1/3*4 = 4/3

The square root of m^6 is always positive.

The square root of m^6 can be calculated by dividing the exponent 6 by 2, since taking the square root is equivalent to raising a number to the power of 1/2.

In this case, m^6 divided by 2 gives us m^3.

Thus, the square root of m^6 is m^3.

This means that if we square m^3, the result will be m^6.

It is important to understand that the square root operation yields the positive root, so the square root of m^6 is always positive.

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First, we need to calculate the area of the room Jenny is tiling, which appears to be in the shape of a rectangle. The area is calculated by multiplying the length and width of the rectangle. If the measurements provided (2.6m and 11m) are for the length and width, then the area of the room would be:

Area = length x width

Area = 2.6m x 11m

Area = 28.6 m²

Next, we need to calculate how many packs of tiles Jenny needs to buy. Given that each pack covers an area of 3m², we divide the total area by the area each pack covers:

Number of packs needed = total area / area covered by one pack

Number of packs needed = 28.6m² / 3m² ≈ 9.53 packs

Since Jenny can't buy a fraction of a pack, she needs to purchase 10 packs of tiles.

The tiles are marked at £18.60, so before the discount, the total cost of the tiles would be:

Total cost = number of packs x price per pack

Total cost = 10 packs x £18.60 = £186

Jenny has a discount card which gives her a 25% discount off the marked price. The discount amount can be calculated as:

Discount = total cost x discount rate

Discount = £186 x 25% = £46.5

So, the cost of the tiles after the discount is:

Discounted price = total cost - discount

Discounted price = £186 - £46.5 = £139.5

Jenny has £100 to spend on the tiles. The extra amount Jenny needs is the difference between the cost of the tiles after the discount and the amount she has:

Extra amount needed = discounted price - amount Jenny has

Extra amount needed = £139.5 - £100 = £39.5

The question asks for the answer in pence, and there are 100 pence in a pound, so:

Extra amount needed in pence = extra amount needed in pounds x 100

Extra amount needed in pence = £39.5 x 100 = 3950 pence

Therefore, Jenny needs an extra 3950 pence to buy the tiles.

Answer:

31.  m∠E = 56.1°

32.  c = 24.9 inches

Step-by-step explanation:

The Law of Sines relates the lengths of the sides of a triangle to the sines of its angles. It states that the ratio of the length of a side of a triangle to the sine of the opposite angle is constant for all three sides of the triangle.

[tex]\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}$\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}[/tex]

Given values of triangle DEF:

To find m∠E, substitute the values into the Law of Sines formula and solve for E:

[tex]\dfrac{\sin D}{d}=\dfrac{\sin E}{e}[/tex]

[tex]\dfrac{\sin 81^{\circ}}{25}=\dfrac{\sin E}{21}[/tex]

[tex]\sin E=\dfrac{21\sin 81^{\circ}}{25}[/tex]

[tex]E=\sin^{-1}\left(\dfrac{21\sin 81^{\circ}}{25}\right)[/tex]

[tex]E=56.1^{\circ}\; \sf(nearest\;tenth)[/tex]

Therefore, the measure of angle E is 56.1°, to the nearest tenth.

See the attachment for the accurate drawing of triangle DEF.

[tex]\hrulefill[/tex]

The law of cosines relates the lengths of the sides of a triangle to the cosine of one of its angles.

[tex]\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines} \\\\$c^2=a^2+b^2-2ab \cos C$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}[/tex]

From inspection of triangle ABC:

To find the length of side c, substitute the values into the Law of Cosines formula and solve for c:

[tex]c^2=a^2+b^2-2ab \cos C[/tex]

[tex]c^2=13^2+15^2-2(13)(15) \cos 125^{\circ}[/tex]

[tex]c^2=169+225-390 \cos 125^{\circ}[/tex]

[tex]c^2=394-390 \cos 125^{\circ}[/tex]

[tex]c=\sqrt{394-390 \cos 125^{\circ}}[/tex]

[tex]c=24.8534667...[/tex]

[tex]c=24.9\; \sf inches\;(nearest\;tenth)[/tex]

Therefore, the length of side c is 24.9 inches, to the nearest tenth.

Answer: 6+9x or 9x + 6

Step-by-step explanation:

Multiply 3 by each of the numbers inside the parentheses

The answer is:

Work/explanation:

To simplify this expression, we will use the distributive property:

[tex]\sf{3(2+3x)}[/tex]

Distribute the 3:

[tex]\sf{3\cdot2+3\cdot3x}[/tex]

Simplify

[tex]\sf{6+9x}[/tex]

Answer:

To evaluate -15 + 7 - (-8), we can simplify the expression by first removing the double negative.

-15 + 7 + 8 = 0

Therefore, the answer is 0.

Step-by-step explanation:

The answer is:

Work/explanation:

Remember the integer rule,

[tex]\bullet\phantom{4444}\sf{a-(-b)=a+b}[/tex]

Similarly

[tex]\sf{-15+7-(-8)}[/tex]

[tex]\sf{-15+15}[/tex]

Simplify fully.

[tex]\sf{0}[/tex]

The percent increase in recreational boating participation over the sixteen-year period is approximately 8.72%. This means that the number of participants increased by around 8.72% from 52.7 million to 57.3 million.

To determine the percent increase in recreational boating participation over the sixteen-year period, we can use the following formula:

Percent Increase = ((New Value - Old Value) / Old Value) * 100

Using the given information, we have an old value of 52.7 million and a new value of 57.3 million.

Percent Increase = ((57.3 million - 52.7 million) / 52.7 million) * 100

= (4.6 million / 52.7 million) * 100

= 0.0872 * 100

= 8.72%

This increase indicates a positive trend in recreational boating, reflecting a growing interest in this activity over time. Factors such as improved accessibility, marketing efforts, and increasing disposable income may have contributed to this upward trend.

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The area of the green part of the tree is 55. 5cm²

The formula for area of a triangle is given as;

Area = 1/2bh

Substitute the values, we have;

Area = 1/2 × 6 × 7

Area = 21cm²

Area of trapezium is expressed as;

Area = a + b/2 h

Substitute the values, we have;

Area = 5 + 7/2 (3) + 4 + 7/2 (3)

expand the bracket, we have;

Area = 18 + 16.5

Area = 34.5 cm²

Total area = 34.5 + 21 = 55. 5cm²

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A. The distribution of X can be represented as X ~ N(μ, σ). B. 1918 is the sample mean. C. The probability that a randomly selected district had fewer than 2009 votes for President Clinton is approximately 0.5641.

D. The probability is approximately 0.0725.

E. The first quartile for votes for President Clinton is approximately 1544.

a. The distribution of X is normally distributed. Therefore, the distribution of X can be represented as X ~ N(μ, σ), where μ is the mean and σ is the standard deviation.

b. In this context, 1918 is the sample mean. It represents the average number of votes per district in the sample of 40 election districts in Alaska.

c. To find the probability that a randomly selected district had fewer than 2009 votes for President Clinton, we need to calculate the z-score and then use the standard normal distribution table (or a calculator with a normal distribution function). The z-score can be calculated as follows:

z = (x - μ) / σ

where x is the value we're interested in (2009 votes), μ is the population mean (1918 votes), and σ is the standard deviation (554 votes).

z = (2009 - 1918) / 554 ≈ 0.164

Using the standard normal distribution table or a calculator, we can find that the probability corresponding to a z-score of 0.164 is approximately 0.5641.

Therefore, the probability that a randomly selected district had fewer than 2009 votes for President Clinton is approximately 0.5641.

d. To find the probability that a randomly selected district had between 1955 and 2056 votes for President Clinton, we need to calculate the z-scores for both values and then use the standard normal distribution table.

For 1955 votes:

z1 = (1955 - 1918) / 554 ≈ 0.066

For 2056 votes:

z2 = (2056 - 1918) / 554 ≈ 0.248

Using the standard normal distribution table or a calculator, we can find the cumulative probabilities corresponding to z1 and z2. Then, we subtract the cumulative probability for z1 from the cumulative probability for z2 to find the probability between these two values.

P(1955 < X < 2056) = P(X < 2056) - P(X < 1955)

Using the standard normal distribution table or a calculator, we can find these probabilities and subtract them to find the desired probability.

P(1955 < X < 2056) = P(X < 2056) - P(X < 1955)

≈ 0.5989 - 0.5264

≈ 0.0725

So, the probability is approximately 0.0725.

e. The first quartile corresponds to the 25th percentile of the distribution. To find the first quartile for votes for President Clinton, we need to find the value of X such that 25% of the districts have fewer votes.

Using the standard normal distribution table or a calculator, we can find the z-score corresponding to the 25th percentile, which is -0.6745. Then we can calculate the value of X using the z-score formula:

-0.6745 = (X - 1918) / 554

Solving for X:

X - 1918 = -0.6745 × 554

X - 1918 = -374.167

X ≈ 1543.833

Rounding to the nearest whole number, the first quartile for votes for President Clinton is approximately 1544.

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The concept of equidistant points or lines is fundamental in geometry and plays a significant role in many geometric constructions and properties.

In geometry, an "equidistant" point is a point that is at the same distance from other points or lines. This concept is often used in various geometric constructions and proofs.

For example, in a circle, the center of the circle is equidistant from all points on the circumference. This property is what defines a circle.

In terms of lines, an equidistant point can be found by drawing perpendicular bisectors. A perpendicular bisector of a line segment is a line that is perpendicular to the segment and divides it into two equal parts. The point where the perpendicular bisectors of a triangle intersect is called the circumcenter, and it is equidistant from the vertices of the triangle.

Another example is the concept of an equidistant curve. In some cases, there may be a curve or path that is equidistant from two fixed points. This curve is called the "locus of points equidistant from two given points" and is often referred to as a "perpendicular bisector" when dealing with line segments.

All things considered, the idea of equidistant points or lines is essential to geometry and is important to many geometrical constructions and features.

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Answer:

a. 36.65 in

b. 14.14 km²

Step-by-step explanation:

Solution Given:

a.

Arc Length = 2πr(θ/360)

where,

Here Given: θ=150° and r= 14 in

Substituting value

Arc length=2π*14*(150/360) =36.65 in

b.

Area of the sector of a circle = (θ/360°) * πr².

where,

Here  θ = 45° and r= 6km

Substituting value

Area of the sector of a circle = (45/360)*π*6²=14.14 km²

Answer:

[tex]\textsf{a)} \quad \overset{\frown}{AC}=36.65\; \sf inches[/tex]

[tex]\textsf{b)} \quad \text{Area of sector $ABC$}=14.14 \; \sf km^2[/tex]

Step-by-step explanation:

The formula to find the arc length of a sector of a circle when the central angle is measured in degrees is:

[tex]\boxed{\begin{minipage}{6.4 cm}\underline{Arc length}\\\\Arc length $= \pi r\left(\dfrac{\theta}{180^{\circ}}\right)$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the angle measured in degrees.\\\end{minipage}}[/tex]

From inspection of the given diagram:

Substitute the given values into the formula:

[tex]\begin{aligned}\overset{\frown}{AC}&= \pi (14)\left(\dfrac{150^{\circ}}{180^{\circ}}\right)\\\\\overset{\frown}{AC}&= \pi (14)\left(\dfrac{5}{6}}\right)\\\\\overset{\frown}{AC}&=\dfrac{35}{3}\pi\\\\\overset{\frown}{AC}&=36.65\; \sf inches\;(nearest\;hundredth)\end{aligned}[/tex]

Therefore, the arc length of AC is 36.65 inches, rounded to the nearest hundredth.

[tex]\hrulefill[/tex]

The formula to find the area of a sector of a circle when the central angle is measured in degrees is:

[tex]\boxed{\begin{minipage}{6.4 cm}\underline{Area of a sector}\\\\$A=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\ \phantom{ww}$\bullet$ $\theta$ is the angle measured in degrees.\\\end{minipage}}[/tex]

From inspection of the given diagram:

Substitute the given values into the formula:

[tex]\begin{aligned}\text{Area of sector $ABC$}&=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (6)^2\\\\&=\left(\dfrac{1}{8}\right) \pi (36)\\\\&=\dfrac{9}{2}\pi \\\\&=14.14\; \sf km^2\;(nearest\;hundredth)\end{aligned}[/tex]

Therefore, the area of sector ABC is 14.14 km², rounded to the nearest hundredth.

Answer:

D. 48

Step-by-step explanation:

When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.

56 = 1/2(160 - ?)

112 = 160 - ?

? = 160 - 112 = 48

Answer:

(2, 7) and (-6, -1)

Step-by-step explanation:

y = x + 5

y = x² + 5x − 7

Equatig the above,

x² + 5x − 7 = x + 5

⇒ x² + 4x −12 = 0

⇒ x² + 6x - 2x - 12 = 0

⇒ x(x + 6) - 2(x + 6) = 0

⇒  (x - 2)(x + 6) = 0

⇒ x = 2 or x = -6

Eq(1) : y = x + 5 (given)

When x = 2

y = 2 + 5 = 7

Point : (2, 7)

When x = -6

y = -6 + 5 = -1

Point: (-6, -1)

Answer:

measure of arc JL = 55°

measure of angle PKJ = 27.5°

11. Yes, the information provided can be used to conclude that C is on the perpendicular bisector of AB because CE bisects AB.

12. Yes, the information provided can be used to conclude that C is on the perpendicular bisector of AB because C is equidistant from AB.

In Mathematics and Geometry, a perpendicular bisector divides or bisects a line segment exactly into two (2) equal halves, in order to form a right angle with a magnitude of 90° at the point of intersection.

Question 11.

By critically observing the geometric shape, we can logically deduce that there is enough information to conclude that C is on the perpendicular bisector of AB because CE bisects AB:

AC ≅ BC

CD ≅ CD

AE ⊥ EC

Question 12.

By critically observing the geometric shape, we can logically deduce that there is enough information to conclude that C is on the perpendicular bisector because C is equidistant from line segment AB.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

8cm

Step-by-step explanation:

perimiter A = 11+11+4+4=30

perimiter B = 4+4+8+8=24

24+30=54

perimeter c =4+8+8+4+11+7+4=46

so perimiter of c is 8cm shorter than A and B total

hope this helps

Answer:

-21

Step-by-step explanation:

2+7-8-13-4-5

9-30

-21

Hope it's helpful.