Planets
Project: Scale Model of the Solar System

After doing the equation the total mass is 1.53×10^-3kg .

What is the magnetic force of attraction?

Similar poles or charges will typically repel one another. Thus, the two magnets will push against one another. Repulsion is the name given to a force that causes objects to move apart from one another.

between two or more comparable or similar charges there is a force. Similar charges are attracted to one another. Charges that share a similar appearance separate. Chemical bonding is characterized by repulsive forces.

Create a formula for the magnetic force to equal the normal force, and then enter the necessary values into the expression to obtain the mass.

FN=F

mg=µo I1 I2 L÷2πr

m=µo I1 I2 L÷2πrg

 = 4π×10^-7T-m/A (15A) (15A)(0.50m)÷2π(0.0015m)(9.8m/s²)

= 1413÷0.0923×10^-7

= 1.53×10^-3kg

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The given statement that 'The total magnification achieved using a 10x objective lens with a 10x eyepiece lens is 20x' is false.

A stereomicroscope is a good option for viewing large and opaque specimens.

The magnification of eyepiece is either 10x or 15x.

The magnification of objective lens can be 10x, 40x or 100x.

The total magnification is nothing but the multiplication of the magnification of eyepiece and the magnification of objective lens.

Given that, magnification of objective lens is 10x

Magnification of eyepiece lens is 10x

So, the total magnification is,

⇒ 10x × 10x = 100x

But the total magnification is given as 20x.

Thus, the given statement is false.

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surface gravity formula

[tex]g=\frac{GM}{r^{2} }[/tex]

[tex]g[/tex] is the surface gravity in m/s²

[tex]G[/tex] is the gravitational constant 6.67408x10⁻¹¹ m³/kgs²

[tex]M[/tex]  is the mass of the object in kg

[tex]r[/tex] is the radius of the object in  m

The Earth’s mass is 5.972x10²⁴kg,

Jupiter’s mass is 1.898x10²⁷ kg,

the Earth’s radius is 6371 km,

Jupiter’s radius is 69911 km

[tex]g=\frac{6.67408X10^{-11}X5.972X10^{24} }{(6.371X10^{6} )^{2} }[/tex]

[tex]g=9.82 m/s^{2}[/tex]

[tex]g=\frac{6.67408X10^{-11}X1.898X10^{27} }{(6.9911X10^{7} )^{2} }[/tex]

[tex]g=25.92 m/s^{2}[/tex]

conclusion

[tex]\frac{25.92}{9.82} = 2.63[/tex]

the surface gravity of Jupiter is 2.63 times that of Earth.

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Area T represents the distance travelled by the object whilst moving at a constant speed. Option (C) is correct.

The distance an object travels in a unit of time is its speed. Speed is a scalar quantity since it has simply magnitude and no direction. SI unit of speed is meter per second.

Hence, mathematically:

Speed = distance travelled/time interval.

Distance travelled = speed × time interval.

In the given graph, area T represents  constant speed × time interval. Hence, area T is equal to the distance travelled by the object moving at a constant speed.

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Answer:

[tex] \huge{\boxed{68,738.99 \: J}} [/tex]

Explanation:

The kinetic energy of the car can be found by using the formula

[tex] \bold{k = \frac{1}{2} \times m \times {v}^{2} \\ }[/tex]

m is the mass in kg

v is the velocity in m/s

From the question

m = 1854.5 kg

v = 8.61 m/s

[tex]k = \frac{1}{2} \times 1854.5 \times {8.61}^{2} \\ k = 927.25 \times 74.1321 \\ \\ k = 68738.989[/tex]

We have the final answer as

Answer:

Centripetal acceleration: [tex]1250\; {\rm m\cdot s^{-2}}[/tex].

Resultant force on the object should be [tex]12500\; {\rm N}[/tex].

(Assuming that the speed of the object is [tex]50\; {\rm m\cdot s^{-1}}[/tex].)

Explanation:

For an object that travels along a circle path of radius [tex]r[/tex] at a speed of [tex]v[/tex], (centripetal) acceleration will be [tex]a = (v^{2} / r)[/tex].

In this example, speed is [tex]v = 50\; {\rm m\cdot s^{-1}}[/tex] while the radius of the circular path is [tex]r = 2\; {\rm m}[/tex]. The (centripetal) acceleration of this object will be:

[tex]\begin{aligned}a &= \frac{v^{2}}{r} \\ &= \frac{(50\; {\rm m\cdot s^{-1}})^{2}}{(2\; {\rm m})} \\ &= 1250\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].

For an object of mass [tex]m[/tex], the resultant force to achieve acceleration [tex]a[/tex] is [tex]F(\text{net}) = m\, a[/tex]. In this example, [tex]m = 10\; {\rm kg}[/tex] while [tex]a = 1250\; {\rm m\cdot s^{-2}}[/tex]. The required resultant force will be:

[tex]\begin{aligned}F(\text{net}) &= m\, a \\ &= (10\; {\rm kg})\, (1250\; {\rm m\cdot s^{-2}}) \\ &= 12500\; {\rm kg \cdot m\cdot s^{-2}} \\ &= 12500\; {\rm N} \end{aligned}[/tex].

The action that best describes the camera motion in the scenes directly prior to the Old Man's Defiant hand gesture is: "Zooming in and out" (Option C)

Some interesting camera motions are:

Note that the different camera motions described above are important because they allow filmmakers to convey mood and emotion, create visual interest, and guide the audience's attention within a scene.

For example, a static shot can create a sense of calm or stability, while a handheld shot can create a sense of intimacy or instability. A panning shot can follow the action and keep the audience engaged, while a zoom shot can draw attention to a specific part of the scene.

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Full Question:

What best describes the camera motion in the scenes directly prior to the old man's defiant hand gesture?

O Static and secured on a tripod

O Moving chaotically

O Zooming in and out

O Filming at 96 frames a second

According to the given statement [tex]\sqrt{2h}[/tex] and [tex]2\sqrt{3h}[/tex] and is the angular momentum of a hydrogen atom.

Momentum may be viewed as a body's "power" while it is moving, or the amount of force it can exert on another body. For instance, a slow-moving bowling ball might have the same acceleration as a baseball being thrown fast.

Briefing:

The angular momentum of a hydrogen atom can be defined as:

[tex]L=\sqrt{l(l+1)}h,[/tex]

where l represents the orbital quantum number which defines the subshells s, p, d, f.

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The initial vertical velocity of the object is 2.5 m/s .

Initial Velocity, denoted as u, is the velocity at time period t = 0. It is the speed at which motion first occurs. There are four equations for starting velocity: (1) The starting velocity is expressed as u = v - at if time, acceleration, and final velocity are given.

Keep in mind that the INITIAL VERTICAL VELOCITY of the projectile is equal to ZERO because it is launched horizontally.

Given,

base  =1m

height = 2.5

vertical velocity =2.5/1

The initial vertical velocity of the object is 2.5 m/s .

A projectile's initial velocity has both a horizontal component and a vertical component if it is thrown at an angle to the horizontal. The projectile's displacement horizontally as a result of velocity is shown by the horizontal velocity component (vx).

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acceleration during the constant speed is the  friction acceleration which is 3 ms^-2.

Accelaration is the eate of the change of the velocity of an object with respect by time.

Accelaration (a) id the reason that change in velocity over to the change in time.

Represented by the equation to a= ∆v/∆t. This is allowa you to measure how fast velocity by the changes in meters per second squars (m/s^2).

Here mass is 14 KG box

Here friction force applied by the  because of rough place so that it stopped in 2 seconds

So acceleration by friction is negative sense and 6/2 or 3 ms^-2

So static frictional force is = 14×3 or 54 which is greater  than the  applied force

So the acceleration during the constant speed is the  friction acceleration which is 3 ms^-2.

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The reflected pulse will be equal to or less than incident pulse when wave pulse on a string reflects from a boundary.

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Answer:

Heat Loss = Heat Gain

(60 - T) K1 M1 = (T - 10) K2 M2

M1 = metal        M2 = liquid

K1 = metal         K2 = liquid

(60 - T) K1 * 1 = (T - 60) K2 * 5

60 K1 - T K1 = 5 T K2 - 300 K2

T (5 K2 + K1) = 300 K2 + 60 K1

T = (300 K2 + 60 K1) / (5 K2 + K1)

Need to find largest T

(probably ethanol and iron - you will need to check)

The propagation speed of the waves is v = 1.1009 m/s

Waves' progression and transformation through space and time. The article will examine several definitions in addition to the usual one for wave propagation.

There are numerous crests and troughs that sound waves travel over. II Sound waves need a physical medium to travel through. III The movement of particles is thought to be responsible for the propagation of sound waves.

Transverse waves include electromagnetic waves like X-rays, radio waves, and visible light. Electric and magnetic fields moving in a perpendicular direction make up these waves. The best examples of longitudinal waves, which vibrate parallel to the direction of the wave, are sound waves.

The formula is

v = fλ

given distance is 5.45 m

and the number of times the bridge is shaken is 3 times

this implies

v = 3 / 5.45 × 2

v = 1.1009 m/s

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The center of mass must be found in order to analyze issues involving the flow of matter when subjected to forces, or dynamics.

Motion is the alteration of a skin's position or orientation over time. The movements of people and animals is just one illustration of how everything in the cosmos is always moving. In addition, the fundamental building block of matter, the atom, is likewise constantly in motion.

Motion is the free flow of a body in relation to time. For instance, the fan, the carpet's dust blowing off of it, the water running from the faucet, a ball rolling about, a moving car, etc. Even just the universe is always changing.

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The gravitational force of attraction between two objects is 2.964 x 10⁻9 N. So, the correct option is D.

Gravitational force is defined as the force of attraction experienced by a body due to the gravity of earth.

Here,

Mass of each body,

m₁ = m₂ = 5 kg

Distance between the masses, r = 0.75 m

The equation for gravitational force is given by,

F = Gm₁m₂/r²

where G is the gravitational constant.

Therefore,

F = (6.67 x 10⁻¹¹x 5 x 5)/(0.75)²

F = 166.75 x 10⁻¹¹/0.5625

F = 2.964 x 10⁻9 N

Hence,

The gravitational force of attraction between two objects is 2.964 x 10⁻9 N.

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The ball should be tossed with speed 10 m/s in order for it to take 2 second to return to the level from which it was tossed.

The Time of flight of projectile motion is defined as the total time taken during ascent and fall to the ground.

Here, time of flight is given 2 seconds. So, Time of ascent is 1 second. Time of ascent is time taken to reach the highest height.

We have to apply the formula

v= u +at

At the maximum height, v =0 m/s.

0 = u - 10×1

So, u = 10 m/s

So, our answer depends on the value of g. If we take the value of g as 9.8, then speed required will be 9.8 m/s

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Answer:hope this helps

pleasee i need the brainliest

Explanation: Warm air rises and is replaced by cooler air from the surrounding area. The warm air eventually cools off, falling down and replacing more warm air. This causes a constant upward flow sometimes called a thermal that allows large birds to soar without effort.

The centripetal force that a child with a mass of 45 kg feel when standing 1.0 m from the outer edge of the carousel is 127.9 N.

The centripetal force of the child is the inward force that must maintain the circular motion of the child at the given point in the circular axis without falling.

Mathematically, the formula for centripetal force is given as;

Fc = ma

where;

The centripetal acceleration of the child is calculated as;

a = v²/r

where;

a = (ω²r²) / r

a = ω²r

where;

ω = 7.2 rev/min = 7.2 rev/min x 2π rad/rev x 1 min/60s = 0.754 rad/s

Fc = ma

Fc = m(ω²r)

Fc = 45(0.754² x 5)

Fc = 127.9 N

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The angular speed increase by a factor of 2 i.e. option (a). 2 is correct

The rate of change of angular displacement is referred to as angular speed. Radian per second is used to measure angular speed. Both angular velocity and angular speed are represented using the same formula.

Utilizing the angular momentum conservation law,

Li = Lf

Thus ,Li is the initial angular momentum and Lf the final angular momentum are, respectively.

L = IW, where I is the inertia momentum and W is the angular velocity, can also be used to determine angular momentum.

so, [tex]IiWi = IfWf[/tex]

[tex]L_{f} =\frac{1}{2} L_{i}[/tex]

According to the given condition, then from above two equation,

[tex]L_{i}W_{f} = \frac{1}{2}L_{i}W_{f}[/tex]

[tex]2W_{i} = W_{f}[/tex]

Thus the angular speed of the skater is factor of 2.

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The temperature rise of the iron is 13.33°C

Calorimetry is the science of measuring the heat absorbed or evolved during the course of a chemical reaction or change of state.

The heat gained or released during a calorimetry procedure can be calculated as follows:

Q = mc∆T

Where;

According to this question, a 5kg block of iron with a specific heat capacity of 450 J/kg °C recieves 0.03 MJ of energy. The change in temperature can be calculated as follows:

30,000J = 5 × 450 × ∆T

30000 = 2250∆T

∆T = 30000 ÷ 2250

∆T = 13.33°C

Therefore, 13.33°C is the temperature rise.

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This water wave passes past while a floating leaf cycles down and up three times in a second. The wave's velocity will be 2 hertz.

Use this illustration The amount of waves that travel through a fixed location in a specific amount of time is known as frequency. The duration of a wave passing is therefore half a second. If so, the rate is 2 Hertz per second. Four Hertz is the frequency if 240 waves per hour are sent.

One cycle per second, or hertz, is the SI unit for frequency (Hz). Cycles per second are represented as a hertz.

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Answer:

[tex] \huge{\boxed{3675 \: N}} [/tex]

Explanation:

The force acting on the tow truck can be found by using the formula

[tex] \bold{F = mass × acceleration} [/tex]

From the question

mass = 1225 kg

acceleration= 3 m/s²

F = 1225 × 3 = 3675

We have the final answer as

Answer:

Below

Explanation:

V = IR

V/R = I  

    Now you can see that if you decrease R, you will need to decrease V to have the same value of I

Train must move with equal speed as of platform in opposite direction i order to maintain zero relative velocity.

Velocity is the speed in which something move in a paticular Direction.

From the question it is given that

relative velocity between platform and train = 0

since relative velocity of train with respect to platform is given by

where,  is the velocity of train and  is the velocity of platform

⇒ vt = vp

since platform is always at stationary i.e.,

thus train velocity  = 0

Therefore, train does not move

If, Platform is moving then train must move with equal speed as of platform in opposite direction.

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Poor circulation is not a benefit of stretching.

How many minutes of stretching should a person perform before participating in physical activities?

Stretching for 5 to 10 minutes is probably enough for most activities. It's important, however, to adequately stretch all the muscles you'll be using. Three benefits of stretching before a workout include increased blood flow.

What are the 5 benefits of stretching?

Which benefit comes with flexibility?

Activities that lengthen and stretch muscles can help you prevent injuries, back pain, and balance problems. A well-stretched muscle more easily achieves its full range of motion.

Thus, poor circulation is the correct option.

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0.017 is the probability that tab A won’t fit into slot B

Probability is related to possibility. Random event generation is the subject of this branch of mathematics. Values ​​range from 0 to 1. Probabilities are built into mathematics to predict the likelihood of certain events.

P(tab A won't fit into slot B) = P (A>B)

                                                = P( A-B > 0)

Given that, A ≈ N(30,0.5)   B ≈ N(32, 0.8)

Here,

E (A-B) = 30-32 = -2

V(A-B) = V(A) + V(B) = (0.5)² + (0,8)²

                                   = 0.89

SD (A-B) = [tex]\sqrt{0.89}[/tex]

So, (A-B) ≈ N (-2, 0.9433)

P( A-B > 0) = 1 - P(A-B ≤ 0)

= 1 - P [(A - B +2 / 0.9433) ≤ (+2 / 0.9433)]

= 1 - P (Z₁ ≤ 2.12)

= 1 - 0.98300

= 0.017

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The acceleration of the luggage across the airport is 0.42 m/s².

The acceleration of the luggage across the airport is calculated by applying Newton's second law of motion as follows;

Mathematically, the Newton's second law of motion is given as;

F(net) = ma

where;

F - Ff = ma

where;

33.3  - 12.3  = 50a

21 = 50a

a = 21/50

a = 0.42 m/s²

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The complete question is below:

Jadee pulls a piece of luggage across the airport, notices that she is lagging behind her parents and wants to catch up for a short amount of time. She pulls with a horizontal force of 33.3 N. The force due to friction for the luggage is 12.3 N and the mass of the luggage is 50.0 kg. find the acceleration of the luggage.

According to sect 110.12 (A) in the NEC, unused knockouts and other openings in electrical boxes and cabinets are required to be closed.

What do you understand by national electrical code?

A United States standard for the secure installation of electrical wiring and equipment is the National Electrical Code (NEC), also known as NFPA 70. It is a component of the National Fire Protection Association's National Fire Codes series (NFPA). While the NEC does not represents a U.S. law, NEC use is typically mandated by state or municipal legislation, as well as in many jurisdictions outside of the United States. The NEC standardizes and codifies the specifications for secure electrical installations. The "authority having jurisdiction" checks to see if these minimum requirements have been met.

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The force required to extend or compress a spring, divided by the lengthening or shortening of the spring, is known as the spring constant.

A vertical spring with mass M that is attached steadily lowers to its equilibrium position. This causes the spring x to lengthen. Suppose the same thing was still tied to the same vertical spring, but it was allowed to fall suddenly instead.

The maximum velocity is equal to the amplitude times the angular frequency, or v max=A v max = A, since the sine function oscillates between -1 and +1. The mass is travelling toward x=+A when the maximum velocity occurs at the equilibrium location (x=0).

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Answer:

As little as 10 percent of the energy at any trophic level is transferred to the next level; the rest is lost largely through metabolic processes as heat.

Explanation: