Our Sun’s mass is 1.0 and our Earth’s mass is 2.0. The distance is standard as given on the simulation. Describe the path of the Earth.

Answers

Answer 1

Answer:

Earth orbits the Sun at an average distance of 149.60 million km (92.96 million mi), and one complete orbit takes 365.256 days (1 sidereal year), during which time Earth has traveled 940 million km (584 million mi).

Explanation:


Related Questions

PLS HELP ME!
A motorist is traveling 40ms-¹ and applies brakes and slow down at a rate of 2ms-² the available distance for the the motorist to stop is 400m will the motorist be able to stop?

Answers

Answer:

[tex] \underline{ \boxed{ yes}}\\[/tex]

Explanation:

[tex]given : initial \: velocity \: (u )= 40 {ms}^{ - 1} \\ given : final \: velocity \: (u )= 0 {ms}^{ - 1} \\ given : - (acceleration) \: (a_r) = 2 {ms}^{ - 2} \\ given : distance \: (s) \: = \: ? : \\ but \: {v}^{2} = {u}^{2} + 2( a)s\\ {0}^{2} = {40}^{2} + 2( - 2)s \\ - {40}^{2} = - 4s \\ s = \frac{ - {40}^{2} }{ - 4} \\ s = \frac{1600}{4} \\s = 400 \: m[/tex]

In the figure, if Q = 52 µC q =10 µC and d = 55 cm, what is the magnitude of the electrostatic force on q?​

Answers

Answer:

F = 15.47 N

Explanation:

Given that,

Q = 52 µC

q = 10 µC

d = 55 cm = 0.55 m

We need to find the magnitude of the electrostatic force on q. The formula for the electrostatic force is given by :

[tex]F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{52\times 10^{-6}\times 10\times 10^{-6}}{(0.55)^2}\\\\F=15.47\ N[/tex]

So, the magnitude of the electrostatic force is 15.47 N.

The magnitude of electrostatic force will be "15.47 N".

Electrostatic force

According to the question,

Charges, Q = 52 μC

                q = 10 μC

Distance, d = 55 cm, or

                   = 0.55 m  

Constant, k = 9 × 10⁹

We know the relation,

Electrostatic force, F = k [tex]\frac{q_1 q_2}{d^2}[/tex]

By substituting the values, we get

                                      = 9 × 10⁹ × [tex]\frac{10\times 10^{-6}}{(0.55)^2}[/tex]

                                      = 15.47 N

Thus the above answer is correct.

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A spring with k = 58 N/m hangs vertically next to a ruler. The end of the spring is next to the 17-cm mark on the ruler.
If a 2.5-kg mass is now attached to the end of the spring, and the mass is allowed to fall, where will the end of the spring line up with the ruler marks when the mass is at its lowest position?
Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

Explanation:

The force occurring on a spring F = mg

If x should be the expansion in the spring.

Then F = mg = -kx

where;

[tex]x = \dfrac{mg}{k}[/tex]

[tex]x = \dfrac{2.5 \ kg*9.81 \ m/s^2 }{58 \ N/m}[/tex]

x = 0.423 m

x = 42.3 cm

The final reading of the spring when the end of the spring lines up with the ruler mark is = 42.3 cm + 17 cm

= 59.3 cm

≅ 60 cm

In the equation for the gravitational force between two objects, which quantity must be squared?
•mi
•m2
•G
•d

Answers

Answer:

d

Explanation:

The quantity that must be squared in the equation of gravitational force is distance d.

According to the universal gravitational law, the square of the distance between two objects is inversely proportional to the force of gravity.

Therefore, the quantity to be squared is d

The formula is given as:

  Fg  = [tex]\frac{G m_{1} m_{2} }{d^{2} }[/tex]  

So d is the quantity that must be squared

Which of the following is a mood disorder?

phobic disorder

bipolar disorder

schizophrenia

conversion disorder

Answers

bipolar disorder is the answer

Answer:

bipolar disorder

Explanation:

bipolar disorder, is previously known as manic depression, is a mental disorder characterized by periods of depression and periods of abnormally elevated mood that last from days to weeks.

A 0.1ohm resistor has power rating 5w. is the resistor safe when conducting a current of 10A.​

Answers

Answer:

1.5 Amp is rated for 5 W so it would not be possible

some waves can only travel through matter. What is this matter called?

Answers

A water wave is an example of a mechanical wave. A wave that can travel only through matter is called a mechanical wave.

1.How much work does it take to get a 2Kg ball moving 15m/s if it starts from rest?

2. If a force of 235N was added to the ball, through what distance would this force have to act to give the ball a velocity of 15m/s

Answers

Well Hmm how much you tell me it’s your work lol

Ashudent drops an object from rest above a force plate that records information about the force exerted on the object as a function of time during the time interval in which the objects in contact with the force plate Which of the following measurements should the student take in addition to the measurements from the force platit. to determine the change in momentum of the object from immediately before the collision to immediately after the collision?
A The mass of the object
B The final speed of the object MOH 5000
C The distance fallen by the object
D The student has enough information to make the determination

Answers

Answer:

A The mass of the object

Explanation:

i hope it's helpful

A bar magnet was placed underneath a sheet of paper where a pile of iron filings sits. In the presence of the energy stored in the magnetic field, the iron filings arranged themselves, creating lines of force. How do the energy and the lines of force change when a stronger bar magnet is used?

The answer is "The energy increases, and the lines of force are denser"

Answers

Answer:

The energy increase, and the lines of force are denser

Explanation:

The rest of the answers

1.) The field energy will increase.

3.) It points toward the field of earths magnetic poles.

4.) l, ll, and lll only

5.) ll, lV, l, lll

Based on the information given, the energy and the lines of force change as the energy increases, and the lines of force are dense.

Energy

In physics, it should be noted that energy is the quantitative property which must be transferred to a body or physical system to perform work on the body.

From the information, the bar magnet was placed underneath a sheet of paper where a pile of iron filings sits and in the presence of the energy stored in the magnetic field, the iron filings arranged themselves, creating lines of force. Therefore, when a stronger bar magnet is used, the energy increases and the lines of force are denser.

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A 5 cm diameter orfice discharges fluid from a tank with a head of 5 meters. The discharge rate, Q, is measured at 0.015 m^3/s. The actual velocity at the vena contracta is 9 m/s. The coefficient of discharge is nearest to:________

Answers

Answer:

[tex]\mathbf{ C_d = 0.86}[/tex]

Explanation:

Given that:

diameter of the orifice D = 5 cm = 5 × 10⁻² m

discharge rate Q = 0015 m³/s

Actual velocity V = 9 m/s

By using the formula

[tex]Q = C_d \times A \times \sqrt{2gh}[/tex]

where;

[tex]v = \sqrt{2gh}[/tex] = 9  m/s

[tex]Q = C_d \times A \times v}[/tex]

where;

[tex]A = \dfrac{\pi D^2}{4}[/tex]

[tex]A = \dfrac{\pi (5 \times 10^{-2} ) ^2}{4}[/tex]

[tex]A = 0.00196 \ m^2[/tex]

Again,

[tex]Q = C_d \times A \times v}[/tex]

[tex]0.015 = C_d \times 0.00196 \times 9[/tex]

[tex]C_d = \dfrac{0.015 }{ 0.00196 \times 9}[/tex]

[tex]\mathbf{ C_d = 0.86}[/tex]

Hence, the coefficient of discharge [tex]\mathbf{ C_d = 0.86}[/tex]

please help thank you

Answers

Answer:

[tex]\theta \approx 59.036^{\circ}[/tex], [tex]T_{2} \approx 23.324\,N[/tex]

Explanation:

First we build the Free Body Diagram (please see first image for further details) associated with the mass, we notice that system consist of a three forces that form a right triangle (please see second image for further details): (i) The weight of the mass, (ii) two tensions.

The requested tension and angle can be found by the following trigonometrical and geometrical expressions:

[tex]\theta = \tan^{-1} \frac{W}{T_{2}}[/tex] (1)

[tex]T_{1} = \sqrt{W^{2}+T_{2}^{2}}[/tex] (2)

Where:

[tex]W[/tex] - Weight of the mass, measured in newtons.

[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Tensions from the mass, measured in newtons.

If we know that [tex]W = 20\,N[/tex] and [tex]T_{2} = 12\,N[/tex], then the requested values are, respectively:

[tex]\theta = \tan^{-1} \frac{20\,N}{12\,N}[/tex]

[tex]\theta \approx 59.036^{\circ}[/tex]

[tex]T_{2} = \sqrt{(20\,N)^{2}+(12\,N)^{2}}[/tex]

[tex]T_{2} \approx 23.324\,N[/tex]

Place the left charge at the 2 cm position and the right one at the 4 cm position. Vary the left and right charge to the values provided below and record the resulting forces.

Left Charge Righ Charge Resulting force(N)
1μC 4μC
4μC 1μC
2μC 2μC
1μC 2μC
1μC 8μC
2μC 8μC

Answers

Answer:

Explanation:

Force between two charges can be expressed as follows

F = k q₁ q₂ / d²

q₁ and q₂ are two charges , d is distance between them , k is a constant whose value is 9 x 10⁹

distance between charges is fixed which is 4 -2 = 2 cm = 2 x 10⁻² m

force between 1μC and  4μC

= 9 x 10⁹ x 1 x 4 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 4μC and  1μC

= 9 x 10⁹ x 4 x 1 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 2μC and  2μC

= 9 x 10⁹ x 2 x 2 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 1μC and  2μC

= 9 x 10⁹ x 1 x 2 x 10⁻¹² / ( 2 x 10⁻² )²

= 4.5 x 10 = 45 N

force between 1μC and  8μC

= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²

= 18 x 10 = 180 N

force between 2μC and  8μC

= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²

= 36 x 10 = 360 N

Left Charge   Right Charge Resulting force(N)

1μC                     4μC                  90 N

4μC                   1μC                    90 N

2μC                  2μC                    90 N

1μC                    2μC                   45 N

1μC                  8μC                    180 N

2μC                  8μC                  360 N

i’ll mark you brainlist :)

Answers

Ndnxhxnxjzmsmamsmzmnx
i’m famous. follow me at faithwilliamss

Starting from the front door of your ranch house, you walk 50.0 m due east to your windmill, and then you turn around and slowly walk 30.0 m west to a bench where you sit and watch the sunrise. It takes you 27.0 s to walk from your house to the windmill and then 47.0 s to walk from the windmill to the bench. For the entire trip from the front door to the bench, what are your :

a. average velocity
b. average speed

Answers

Answer:

Explanation:

Total displacement for entire trip = final position - initial position

= 50 m - 30 m = 20 m

Total time = 27 + 47 = 74 s

Average velocity = Total displacement / total time

= 20 / 74 = .27 m /s

Total distance covered in entire trip = 50 + 30 = 80 m

Total time = 74 s

Average speed = Total distance covered / total time

= 80 / 74 = 1.08 m /s .

A tangent line drawn on a velocity-time graph has a rise of 19 m/s and a run of 4.0 m/s. How large is the acceleration? What type of acceleration Is this?​

Answers

Answer:

Acceleration = 4.8 m/s²

Explanation:

Given:

Change in velocity = 19 m/s

Change in time = 4 s

Find:

Acceleration

Computation:

Acceleration = Change in velocity / Change in time

Acceleration = 19/4

Acceleration = 4.8 m/s²

Positive acceleration

Many scientific studies have found that colds are caused by viruses. What is this? *

Fact
Interpretation
Analysis
Opinion

Answers

Answer:

Analysis

Explanation:

Because you must Analysis each and every cold too find out which virus caused this.

It’s weird because Interpretation and Analysis have the meaning of examination

Describe an experiment to show that the maximum attractive property is at the poles of
a magnet?​

Answers

Answer:

Take a bar magnet and place a steel pin at some distance. ... Now, bring the steel pin near the pole of the bar magnet. We notice that pin sticks to the magnet. This experiment shows that maximum magnetic force acts at the poles of the magnet.

Explanation:

hope that is help

How does the water cycle influence weather in central Wisconsin?

Answers

Answer:

The water cycle describes how water evaporates from the surface of the earth, rises into the atmosphere, cools and condenses into rain or snow in clouds, and falls again to the surface as precipitation.The water cycle involves the exchange of energy, which leads to temperature changes.

Answer:

so be more specific please

A swift moving hawk is moving due west with a speed of 30 m/s; 5.0 s later it is moving due north with a speed of 20 m/s.
(A) What are the magnitude and direction of Δvav vector during this 5 s interval? and
(B) What are the magnitude and direction of vector aav during this 5 s interval?

Answers

Answer:

See explanation

Explanation:

Now we have;

vi = (-30, 0) m/s

vf = (0, 20) m/s

Δvav= vf - vi= (30, 20) m/s

magnitude of Δvav= √30^2 + 20^2 = 36.0 m/s

Direction = tan-1(20/30) = 33.69°

For aav

aav= Δvav/t = (30/5, 20/5) = (6,4) m/s^2

magnitude of  aav = √6^2 + 4^2 = 7.2 m/s^2

direction of aav = tan-1(4/6) = 33.69°

b. What would the momentum be if the mass of the bowling ball were doubled and its velocity still was 3 m/s?​

Answers

Answer:

Twice.

Explanation:

The momentum of an object is given by :

p = mv

Where

m is mass and v is the velocity

If the mass of the ball were doubled, m'=2m and v'=v=3 m/s

New momentum,

p'=m'v'

p'=2m × v

p'=2mv

or

p'=2p

So, the new momentum becomes twice the initial momentum.

Energy stored in the nucleus of an atom which releases energy through
fission or fusion *

Answers

Nuclear energy: energy stored within the nucleus of an atom; energy released from a fission or fusion reaction.

Hope this helps!

A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2. The typical reaction time for an alert driver is 0.8 s versus 3 s for a sleepy driver. Assuming a typical car length of 5 m, calculate the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver. Group of answer choices

Answers

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V  = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver  will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length  n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

7Which of the following terms describes how glaciers move?
A Quickly
B Gradually
C Aggressively
D Rapidly

Answers

Answer:

D is the answer  I think (0 w 0 )

Explanation:

The  glaciers move gradually. Hence, option (C) is correct.

What is glacier?

A glacier is a long-lasting mass of heavy ice that is perpetually moving. When the ablation of snow is greater than the accumulation over a long period of time, frequently centuries, a glacier forms.

As it slowly flows and deforms under forces brought on by its weight, it gains distinctive features like crevasses and seracs. Cirques, moraines, and fjords are the result of the erosion of rock and debris from its substrate as it travels.

The considerably thinner sea ice and lake ice that form on the surface of bodies of water are not the same as glaciers, which form only on land and may flow into water bodies.

The huge ice sheets, commonly referred to as "continental glaciers," in the polar areas of the planet contain 99 percent of the planet's glacial ice.

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If an atom of oxygen has an atomic number of eight that means...…
E. there are 8 protons
F. there are 8 neutrons
G. it weighs 8 amu
H. it is in group 8

Answers

E is your answer! protons and the atomic number will always be the same
E us your answer. there are 8 protons.

give two examples of uses of the expansion and contraction of materials

Answers

if we hold a very hot glass tumbler under cold water, it cracks. This is because the outer surface of the glass comes in direct contact with cold water and contracts more as compared to the inner surface. We observed that water expanded on heating.

Railway tracks consist of two parallel metal rails joined together. Small gaps, called expansion gaps, are deliberately left between the rails as there is an expansion of the rails in hot weather. Water expands on heating.

Kieran caught 18 more Pokémon on Saturday than
Noah did. Kieran caught 53 Pokémon. Write and solve
an equation to find how many Pokémon, p, Noah
caught on Saturday.

Answers

Answer:

Noah caught 35 Noah on Satuday.

Explanation:

Given that,

Kieran caught 53 Pokemon

Kieran caught 18 more Pokémon on Saturday than  Noah did.

Let Noah caught x Pokémon on Saturday.

ATQ,

18 + x = 53

Thie is the equation that can be used to find the value of x.

Subtract 18 from both sides.

18 + x -18 = 53 - 18

x = 35

Hence, Noah caught 35 Noah on Satuday.

You have now seen examples during lecture on how to calculate the electric field for a line of charge and a ring of charge - both uniformly distributed. This activity will ask you to solve for the electric field, on-axis, of a uniformly-charged disk sitting in the yz plane. Below is a picture of the situation of interest. Note: Treat it as a totally flat disk and ignore its thickness in the x direction. Also, let x be the distance between the center of the disc and point P.

Answers

Answer:

1/4πε₀[Hx/ (√x² + b²)^3/2]i.

Explanation:

So, without mincing words let's dive straight into the solution to the question above. There is need to determine the electric field on-axis of a uniformly-charged disk sitting.

The electric field in the x-component, dεₓ = 1/4πε₀[H/ x² + b²] cos .

Thus, the total electric field in the x-component, εₓ = 1/4πε₀ [ xdH/ (x^2 + b^2)^3/2.

Therefore, the electric field = 1/4πε₀ [ xdH/ (x^2 + b^2)^3/2i.

Where x=0

A girl walks 20.0 m east then 70.0 meters north. What is the girl’s displacement (mag. And direction)? What is the girl’s distance?

Answers

Explanation:

Given that,

A girl walks 20.0 m east then 70.0 meters north.

Displacement is the shortest path covered by an object. Let it is d. It is calculated as :

[tex]d=\sqrt{20^2+70^2} \\\\=72.80\ m[/tex]

For direction,

[tex]\theta=\tan^{-1}(\dfrac{70}{20})\\\\\theta=74.05^{\circ}[/tex]

Girl's distance = 20 m + 70 m

= 90 m

Hence, this is the required solution.

Precisely 1.00 s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 2.70 m/s2 , how much time passes after the police car is passed by a speeder and before the police car overtakes the speeder (assumed moving at constant speed)

Answers

Answer:

t=  16.75 s

Explanation:

We will solve this exercise using the kinematic expressions

corridor that goes at constant speed, suppose that its speed is v₁ = 20 m/s, it does not appear in the statement, we start counting the time when it passes the policeman.

           x₁ = v₁ t

The policeman starts from rest, so his initial velocity is zero and he has an acceleration a = 2.70 m /s², to use the same time counter we take into account that the policeman left at = 1.00 s after passing the corridor

           x₂ = v₀ (t-t₀) + ½ a (t-t₀)²

           x₂ = ½ a (t-1)²

at the point where the two meet, the position must be the same

           x₁ = x₂

          v₁ t = ½ a (t-1)²

          (t-1)² = [tex]\frac{2 v_1 t}{a}[/tex]

           t² - 2t + 1 - \frac{2 v_1 t}{a} +1 = 0

           t² - 2(1 + [tex]\frac{v_1}{a}[/tex]) t  +1

let's we solve the second degree equation

          t² - 2 ( 1 + [tex]\frac{20}{2.7}[/tex]) t + 1=0

          t² - 16.81 t +1=0

          t = [ 16.81 ± [tex]\sqrt{ 16.81^2 - 4 )}[/tex] ] /2

          t = [16.81 ± 16.695]/2

          t₁=  16.75 s

          t2= 0.06 s

Time t₂ is less than the reaction time of humans, so the correct answer is the first time

            t=  16.75 s

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